SAT Math Quizzes Online & Trivia

The correct answer to this question is A, -5. This answer is found by using the order of operations of math. The acronym PEMDAS is used to represent the order. P stands for parentheses, E for exponents, M for multiplication, D for division, A for addition, and S for subtraction. In school, the saying Please Excuse My Dear Aunt Sally is used to remember the order. Following the order of operations, the parenthetical values of this question are solved first. Once the costs in between the parentheses are addressed, the rest of the equation can be completed, which gives us the answer -5.

The answer is clearly 2- if one side is 11 and the other is 7 the 3rd side must be long enough to reach look at the possible length of the 3rd side- if the 7 is on one side of the 11 side and the x is on the other if x were 2 then even with angels of 0 degrees the 7 side would not connect with the x side​to make a triangle the sum of the 2 smaller sides must equal more than the largest side7+2 <11

-5First, use the order of operations to find the parenthetical value of (2 $ 1), which is 21-3 or -1 Next, plug in -1 for (2 $ 1) to find 3 $ -1 = 3 -1 - (3 - 1) = -3 - 2 = -5

Age of Tom(T)=4+kAge of Marianne(M)=4Given: In two years age of Kate will be Twice as old as Marianne.Twice the age of Mariannein two years=2+2(M) =2+2(4) Age of Kate =10Age of Tom=4+k =4+10 =14

1. 142. 11One side of a triangle must not exceed the sum of the other two sides in length. 11 is greater than 3 + 7, so 11 cannot be a side.

Incorrect John. The actual answer can be solved through the formula I just derived. n! - ((n + 1 - m) (n-m)! m!) = x. In this situation, n is the size of the group m is the size of the two who cannot stand next to each other and x is the number of situations that they form a line in which they are not next to each other. In the beginning of the equation n! stands for the total number of situations a group can form a line. From that you subtract the number of times that they stand next to each other in said line. In this section (n + 1 - m) accounts for how many ways within the group 2 people can line up. (Ex: AB is the group that cannot stand by each other so ABCD CABD CDAB.) Now to account for how many times the group can align with them as a group of 1 you use (n - m)! because this essentially pairs them as one and accounts for the alignment of the other people in the situation. Finally to account for how the two may align amongst themselves when standing next to each you may use m!. So the number of times in which they would stand next to each otherwould be 12 of the 24 total possible choices in this situation. There may be a way to simplify this answer, but I did not look into that aspect.

Works only D if a=3 and b= -10 so in B |3-10|=7and 3-(-10)=13 so 7<13.B is correct. But in D it is also correct: |3+10|=13 and 3-10=-7 13>-7 So we should take both <0 if a=-1 and b=-2 then D is correct |-1+2|=1and -1-2=-3 1>-3 but B is wrong: |-1-2|=3 and -1+2=1 3>1 but it said that should be 3<1 which is of course wrong so D is the only correct answer

-5First, use the order of operations to find the parenthetical value of (2 $ 1), which is 21-3 or -1 Next, plug in -1 for (2 $ 1) to find 3 $ -1 = 3 -1 - (3 - 1) = -3 - 2 = -5

492(x-3)=142x-6=14 +6=+62x=20DIVIDE BY 2x=10input 10 for x. 10^2-6•10+9100-60+9=49

There are actually nine diagonals are possible in a hexagon.

|a^2 + b^2 - 1|

$0.03With 2 pennies, there's no way to make three cents.1 penny= 1 cent2 pennies= 2 cents2 pennies and any coin bigger= goes over 5 cents