# SAT Math, Weeks 1-4

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Quizzes Created: 2 | Total Attempts: 902
Questions: 20 | Attempts: 129  Settings  Take this quiz to see what you remember from our first few weeks in SAT Math! You are suggested to take this quiz without your notes.

• 1.

### If 25 is 40 percent of n, what is n?

• A.

10

• B.

20

• C.

32.5

• D.

62.5

• E.

160

D. 62.5
Explanation
If 25 is 40 percent of n, we can set up the equation 25 = 0.4n. To solve for n, we divide both sides of the equation by 0.4, which gives us n = 62.5. Therefore, the value of n is 62.5.

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• 2.

• A.

132

• B.

133

• C.

134

• D.

136

• E.

138

B. 133
• 3.

### On that same basketball team, a particular player made two shots for every three shots she missed, so each of the following can be the number of shots she took EXCEPT:

• A.

75

• B.

79

• C.

85

• D.

90

• E.

95

B. 79
Explanation
The player made two shots for every three shots she missed, which means that for every 5 shots she took, she made 2 and missed 3. Therefore, the number of shots she took must be a multiple of 5. Among the given options, 79 is not a multiple of 5, so it cannot be the number of shots she took.

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• 4.

### In a poll of 97 people, 25 people said they liked Daylight Savings Time, 34 said that they did not like Daylight Saving Time, and the others indicated they had no opinion. What fraction of people surveyed had no opinion?

• A.

25/97

• B.

28/97

• C.

31/97

• D.

34/97

• E.

38/97

E. 38/97
Explanation
The fraction of people surveyed who had no opinion can be calculated by subtracting the number of people who liked Daylight Savings Time and the number of people who did not like it from the total number of people surveyed. In this case, 97 - 25 - 34 = 38. Therefore, 38 out of 97 people surveyed had no opinion, which can be expressed as the fraction 38/97.

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• 5.

### If 15% of x equals 75% of y, which of the following expresses y in terms of x?

• A.

Y = 90% of x

• B.

Y = 45% of x

• C.

Y = 35% of x

• D.

Y = 25% of x

• E.

Y = 20% of x

E. Y = 20% of x
Explanation
If 15% of x equals 75% of y, it means that the value of y is larger than x. To find the expression for y in terms of x, we need to determine how much larger y is compared to x. Since 15% of x is equal to 75% of y, we can set up the equation 0.15x = 0.75y. To isolate y, we divide both sides of the equation by 0.75, giving us y = 0.2x. This means that y is equal to 20% of x, which is the correct answer.

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• 6.

### 6 cartridges of ink can print out 1500 pages. At that rate, how many cartridges are needed to print out 11,250 pages?

• A.

43

• B.

44

• C.

45

• D.

46

• E.

47

C. 45
Explanation
If 6 cartridges can print out 1500 pages, then each cartridge can print out 1500/6 = 250 pages. To print out 11,250 pages, we would need 11,250/250 = 45 cartridges.

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• 7.

### In a particular store, the ratio of phones to sales associates was 50 to 5. Additionally, the ratio of sales associates to headsets was 2 to 6. What was the ratio of headsets to phones?

• A.

2 to 17

• B.

1 to 5

• C.

3 to 10

• D.

6 to 19

• E.

4 to 7

C. 3 to 10
Explanation
The given information states that the ratio of phones to sales associates is 50 to 5. This can be simplified to 10 to 1. Additionally, the ratio of sales associates to headsets is 2 to 6, which simplifies to 1 to 3. To find the ratio of headsets to phones, we can multiply the two ratios together: (10/1) * (1/3) = 10/3, which can be simplified to 3 to 10. Therefore, the ratio of headsets to phones is 3 to 10.

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• 8.

### In an atlas, 5/4 inches represents 1200 miles. If the distance from Point A to Point B is 3900 miles, what is the distance between the two points on the atlas?

• A.

65/16 inches

• B.

4 inches

• C.

• D.

17/6 inches

• E.

13/5 inches

A. 65/16 inches
Explanation
In the given problem, it is stated that 5/4 inches represents 1200 miles. To find the distance between Point A and Point B on the atlas, we can set up a proportion. We know that 5/4 inches corresponds to 1200 miles, so we can set up the proportion: (5/4) inches / 1200 miles = x inches / 3900 miles. By cross-multiplying and solving for x, we find that x = (5/4) * (3900/1200) = 65/16 inches. Therefore, the distance between the two points on the atlas is 65/16 inches.

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• 9.

### While listening to the radio on the Internet for one hour, I became frustrated because fifteen minutes of that hour was spent dealing with buffering issues. But, let's look at the positive side: what percentage of my hour was spent listening to music and NOT dealing with buffering issues?

75
75 percent
75%
75 %
Explanation
The percentage of time spent listening to music and not dealing with buffering issues can be calculated by subtracting the percentage of time spent dealing with buffering issues from 100. In this case, if 15 minutes out of 60 minutes were spent dealing with buffering issues, then the percentage of time spent dealing with buffering issues is (15/60) x 100 = 25%. Therefore, the percentage of time spent listening to music and not dealing with buffering issues is 100 - 25 = 75%.

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• 10.

### The cost of a book was originally \$10. Its cost decreased by 15%, and then its cost decreased by an additional 30% the week after. What did its cost become?

5.95
\$5.95
Explanation
The cost of the book decreased by 15% initially, which means it became 85% of its original cost. Then, it decreased by an additional 30%, which means it became 70% of the cost after the first decrease. Therefore, the final cost of the book is 70% of 85% of the original cost, which is equal to \$5.95.

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• 11.

### In the election, there were eight candidates whose average age was 55 years old. If the candidates were 52, 50, 61, 36, 82, 57, x, and y years old, what must the average of x and y be?

• A.

47

• B.

48

• C.

49

• D.

50

• E.

51

E. 51
Explanation
Since the average age of the eight candidates is 55, the sum of their ages must be 55 multiplied by 8, which is 440. We know the ages of six candidates, which sum up to 52 + 50 + 61 + 36 + 82 + 57 = 338. To find the sum of x and y, we subtract 338 from 440, giving us 102. Since we are looking for the average, we divide 102 by 2, resulting in an average of 51. Therefore, the average of x and y must be 51.

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• 12.

### In 1980, Wyoming's population was 469,557. In 1990, Wyoming's population was 453,588. This means that from 1980 to 1990, Wyoming's population decreased by:

• A.

10%

• B.

5%

• C.

3.5%

• D.

3.4%

• E.

3.1%

D. 3.4%
Explanation
From 1980 to 1990, Wyoming's population decreased by 3.4%. This can be calculated by finding the difference between the two population numbers (469,557 - 453,588 = 15,969) and then dividing that difference by the initial population (15,969 / 469,557 = 0.034). Multiplying this by 100 gives us the percentage decrease, which is 3.4%.

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• 13.

### If y is inversely proportional to x and y = 42 when x = 7, what is the value of y when x = 42?

• A.

254

• B.

42

• C.

40

• D.

24

• E.

7

E. 7
Explanation
If y is inversely proportional to x, it means that as x increases, y decreases and vice versa. In this case, when x is 7, y is 42. Therefore, when x increases to 42, y will decrease to a value that is inversely proportional to 42. Since 7 is the only option that is less than 42, the value of y when x = 42 is 7.

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• 14.

### The amount of paper that John puts in his printer is directly proportional to the number of pages that he knows he will be printing. If he puts 500 pages in when he will be printing 400 pages, how many pages will he put in when he prints 24 pages?

• A.

19.2

• B.

20

• C.

30

• D.

50

• E.

9000

C. 30
Explanation
John puts in an amount of paper that is directly proportional to the number of pages he will be printing. This means that the ratio between the amount of paper and the number of pages remains constant. If he puts in 500 pages for 400 pages, the ratio is 500/400. To find out how many pages he will put in for 24 pages, we can set up a proportion: 500/400 = x/24. Solving for x, we find that x is equal to 30. Therefore, John will put in 30 pages when he prints 24 pages.

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• 15.

### Which of the following numbers is between (5/8) and (5/7)?

• A.

5/9

• B.

10/17

• C.

6/10

• D.

31/50

• E.

7/10

E. 7/10
Explanation
The number 7/10 is between 5/8 and 5/7 because when comparing fractions, we can find a common denominator and compare the numerators. In this case, the common denominator is 40. 5/8 is equivalent to 25/40 and 5/7 is equivalent to 28/40. Therefore, 7/10 is greater than 5/8 and less than 5/7, making it the number that falls between the two given fractions.

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• 16.

### 500 million English speakers use the Internet. If every Internet user accesses the Internet through using Browser A, Browser B, Browser C, Browser D, Browser E, or some other browser, how many English-speaking Internet users do NOT use Browser A, B, C, D, or E? (see circle graph above)

• A.

33 million

• B.

34 million

• C.

35 million

• D.

36 million

• E.

37 million

E. 37 million
Explanation
If there are 500 million English speakers using the Internet, and they all use either Browser A, B, C, D, E, or some other browser, then the number of English-speaking Internet users who do not use Browser A, B, C, D, or E can be calculated by subtracting the total number of English-speaking Internet users who use Browser A, B, C, D, or E from the total number of English-speaking Internet users. Since the answer is 37 million, it means that there are 37 million English-speaking Internet users who do not use Browser A, B, C, D, or E.

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• 17.

### A box had seven boxes of dolls within it, and the boxes within the big box weighed a total of 235 pounds. One small box of 42 pounds was replaced by another small box of 28 pounds; further, another small box weighing 34 pounds was replaced by a small box that weighed 30 pounds. What is the new average weight of all seven of the small boxes within the big box?

31
31 pounds
31 lbs.
31 lbs
Explanation
The new average weight of all seven of the small boxes within the big box is 31 pounds. This is because the total weight of the boxes within the big box remains the same after the replacements. The weight of one small box decreased by 14 pounds (42 - 28) and the weight of another small box decreased by 4 pounds (34 - 30). These decreases in weight were compensated by the increases in weight of the new small boxes. Therefore, the average weight of the small boxes remains unchanged at 31 pounds.

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• 18.

### The average PSAT score of a group of 15 students was 195 -- if you take away the two students who scored a 131 and a 145, what was the approximate average of the rest of the class?

• A.

194

• B.

204

• C.

210

• D.

225

• E.

240

B. 204
Explanation
The approximate average of the rest of the class can be calculated by finding the average of the remaining 13 students' scores. To do this, we need to subtract the scores of the two students who scored 131 and 145 from the total score of the class. The total score of the class without these two students is 195 * 15 - 131 - 145 = 2925 - 131 - 145 = 2649. To find the average, we divide this total by the number of remaining students, which is 13. Therefore, the approximate average of the rest of the class is 2649 / 13 = 203.77, which can be rounded to 204.

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• 19.

### A particular refrigerator houses only apple juice boxes and orange juice boxes. The ratio of apple juice boxes to orange juice boxes in a refrigerator is 4 to 5. If there are 81 juice boxes in the (really, really large) refrigerator, how many apple juice boxes are there?

• A.

32

• B.

36

• C.

42

• D.

56

• E.

65

B. 36
Explanation
The ratio of apple juice boxes to orange juice boxes is 4 to 5. This means that for every 4 apple juice boxes, there are 5 orange juice boxes. If we let x represent the number of apple juice boxes, then the number of orange juice boxes would be (5/4)x. We know that the total number of juice boxes is 81, so we can set up the equation x + (5/4)x = 81. Solving this equation, we find that x = 36. Therefore, there are 36 apple juice boxes in the refrigerator.

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• 20.

### If w is 20% of x, x is 40% of y, and y is 25% of z, what is w in terms of z?

• A.

W = 28.33% of z

• B.

W = 22.5% of z

• C.

W = 20% of z

• D.

W = 2% of z

• E.

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