Continuous Infusion Steady State

2.

A patient is receiving lidocaine iv infusion of 3 mg/min to control his ventricular tachycardia. The patient developed acute liver failure, and his physician was worried because the liver is the major organ responsible for lidocaine elimination. What will happen if the patient continued receiving the 3 mg/min lidocaine iv infusion after developing this liver failure ?

Lidocaine clearance will be lower and the s.s. concentration will be lower
Lidocaine clearance will be higher and the s.s. concentration will be lower
Lidocaine clearance will be lower and the s.s. concentration will be higher
Lidocaine clearance will be higher and the s.s. concentration will be higher

Correct Answer

A. Lidocaine clearance will be lower and the s.s. concentration will be higher

Explanation

If the patient continues to receive the lidocaine IV infusion after developing liver failure, their liver's ability to eliminate lidocaine will be compromised. As a result, the clearance of lidocaine from the body will be lower, meaning that it will take longer for the drug to be eliminated. This will lead to a higher steady-state (s.s.) concentration of lidocaine in the patient's bloodstream.

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3.

Procainamide was administered to a patient as a constant rate iv infusion of 2 mg/min to control his ventricular arrhythmia. The steady state procainamide concentration was found to be 4 mg/L. Because the patient condition was not controlled, the physician asked you to recommend an infusion rate that will increase the steady state plasma procainamide concentration in this patient to 6 mg/L. What will be your recommendation?

2 mg/min
4 mg/min
3 mg/min
6 mg/min

Correct Answer

A. 3 mg/min

Explanation

The steady state plasma procainamide concentration is directly proportional to the infusion rate. Since the desired steady state concentration is 6 mg/L and the current steady state concentration is 4 mg/L, an increase of 2 mg/L is required. To achieve this increase, the infusion rate needs to be increased by 1 mg/min (2 mg/L divided by 2 min). Therefore, the recommended infusion rate would be 3 mg/min.

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4.

Bretylium is an antiarrhythmic drug used in the treatment of ventricular arrhythmia. Its elimination rate constant in patients with renal insufficiency is 0.5 day-1, and its volume of distribution is 6 L/kg. How long it will take to reach steady state if a patient with renal insufficiency was started on a constant rate iv infusion of 90 mg/hr ?

1 week
2 week
2.5 days
5 days

Correct Answer

A. 1 week

Explanation

To calculate the time it will take to reach steady state, we can use the formula: Time to reach steady state = 4-5 half-lives. The half-life can be calculated using the elimination rate constant: Half-life = 0.693 / elimination rate constant. In this case, the half-life is approximately 1.386 days. Therefore, it will take approximately 4-5 half-lives, or 5.544-6.93 days, to reach steady state. Since the closest option is 1 week, the correct answer is 1 week.

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1

5.

The first-order elimination rate constant for dopamine is 4.2 hr^-1, for penicillin G is 1.2 hr^-1, for theophylline is 0.1 hr^-1, and for lidocaine is 0.5 hr^-1. Which of these drugs will reach steady state faster during the administration of a constant rate iv infusion ?

Dopamine
Penicillin G
Theophylline
Lidocaine

Correct Answer

A. Dopamine

Explanation

Dopamine will reach steady state faster during the administration of a constant rate iv infusion because it has the highest first-order elimination rate constant (4.2 hr-1) compared to the other drugs. A higher elimination rate constant indicates that the drug is eliminated from the body more quickly, allowing the drug concentration to reach steady state faster.

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1

6.

Procainamide is a class Ia antiarrhythmic drug that alters conduction in normal and ischemic cardiac tissues by sodium-channel blockade. What is the steady state procainamide concentration achieved during constant rate iv infusion of 2 mg/min if procainamide volume of distribution is 120 liters and elimination rate constant is 0.2 hr-1 ?

10 mg/l
5 mg/l
60 mg/l
1 mg/l

Correct Answer

A. 5 mg/l

Explanation

During a constant rate IV infusion, the steady state concentration of a drug is achieved when the rate of drug administration equals the rate of drug elimination. In this case, the elimination rate constant is given as 0.2 hr-1. The volume of distribution is 120 liters, which represents the apparent volume in which the drug is distributed throughout the body.

To calculate the steady state concentration, we can use the formula:

Steady state concentration = Rate of drug administration / Clearance

The rate of drug administration is given as 2 mg/min, which can be converted to mg/hr by multiplying by 60:

Rate of drug administration = 2 mg/min * 60 min/hr = 120 mg/hr

The clearance can be calculated by multiplying the elimination rate constant by the volume of distribution:

Clearance = 0.2 hr-1 * 120 L = 24 L/hr

Now we can substitute these values into the formula:

Steady state concentration = 120 mg/hr / 24 L/hr = 5 mg/l

Therefore, the correct answer is 5 mg/l.

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1

7.

A patient was admitted to the hospital because of acute myocardial infarction. After stabilizing his condition, he was given an iv loading dose of 150 mg lidocaine followed immediately by a constant rate iv infusion of 2 mg/min. What is the rate of lidocaine elimination at steady state ?

2 mg
75 mg/min
2 mg/min
150 mg/min

Correct Answer

A. 2 mg/min

Explanation

Lidocaine is a medication used to treat irregular heartbeats. In this scenario, the patient received a loading dose of 150 mg of lidocaine through an intravenous (IV) infusion. This loading dose is given to quickly reach a therapeutic level in the bloodstream. After the loading dose, a constant rate IV infusion of 2 mg/min is administered to maintain the desired lidocaine concentration in the body. At steady state, the rate of lidocaine elimination is equal to the rate of infusion, which is 2 mg/min. Therefore, the correct answer is 2 mg/min.

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1

8.

A patient is receiving a constant rate iv infusion of 60 mg/hr theophylline to control an acute episode of bronchial asthma. Theophylline steady state concentration during this infusion was 15 mg/L. Calculate the total body clearance of theophylline in this patient.

12 L/hr
0.25 L/hr
1 L/hr
4 L/hr

Correct Answer

A. 4 L/hr

Explanation

The total body clearance of a drug is the volume of plasma from which the drug is completely removed per unit time. In this case, the steady state concentration of theophylline is 15 mg/L, and the infusion rate is 60 mg/hr. By dividing the infusion rate by the steady state concentration, we can calculate the total body clearance. So, 60 mg/hr / 15 mg/L = 4 L/hr. Therefore, the total body clearance of theophylline in this patient is 4 L/hr.

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9.

A patient is receiving a constant rate iv infusion of 1 mg/kg/hr theophylline. At steady state the plasma theophylline concentration was 20 mg/L. Calculate theophylline total body clearance in this patient.

20 L/hr
0.05 L/hr/kg
0.2 L/hr
0.2 L/hr/kg

Correct Answer

A. 0.05 L/hr/kg

Explanation

Theophylline total body clearance can be calculated using the formula: Clearance = infusion rate / steady state concentration. In this case, the infusion rate is 1 mg/kg/hr and the steady state concentration is 20 mg/L. By substituting these values into the formula, we get: Clearance = 1 mg/kg/hr / 20 mg/L = 0.05 L/hr/kg. Therefore, the correct answer is 0.05 L/hr/kg.

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10.

Bretylium tosylate is an antiarrhythmic drug effective in the treatment of ventricular fibrillation. The half life of bretylium is 9 hours and its volume of distribution is 6 L/kg. What is the iv loading dose required to achieve plasma concentration of 1.5 mg/L in a 60-kg patient ?

300 mg
600 mg
900 mg
540 mg

Correct Answer

A. 540 mg

Explanation

Bretylium tosylate has a half-life of 9 hours and a volume of distribution of 6 L/kg. The loading dose required to achieve a plasma concentration of 1.5 mg/L can be calculated using the formula: loading dose = desired concentration × volume of distribution. In this case, the desired concentration is 1.5 mg/L and the volume of distribution is 6 L/kg. Since the patient weighs 60 kg, the volume of distribution would be 6 L/kg × 60 kg = 360 L. Therefore, the loading dose would be 1.5 mg/L × 360 L = 540 mg.

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Continuous Infusion Steady State

Quiz Preview

The first-order elimination rate constant for dopamine is 4.2 hr-1, for penicillin G is 1.2 hr-1, for theophylline is 0.1 hr-1, and for lidocaine is 0.5 hr-1. Which of these drugs will reach steady state faster during the administration of a constant rate iv infusion ?

A patient was admitted to the hospital because of acute myocardial infarction. After stabilizing his condition, he was given an iv loading dose of 150 mg lidocaine followed immediately by a constant rate iv infusion of 2 mg/min. What is the rate of lidocaine elimination at steady state ?

A patient is receiving a constant rate iv infusion of 60 mg/hr theophylline to control an acute episode of bronchial asthma. Theophylline steady state concentration during this infusion was 15 mg/L. Calculate the total body clearance of theophylline in this patient.

A patient is receiving a constant rate iv infusion of 1 mg/kg/hr theophylline. At steady state the plasma theophylline concentration was 20 mg/L. Calculate theophylline total body clearance in this patient.

Bretylium tosylate is an antiarrhythmic drug effective in the treatment of ventricular fibrillation. The half life of bretylium is 9 hours and its volume of distribution is 6 L/kg. What is the iv loading dose required to achieve plasma concentration of 1.5 mg/L in a 60-kg patient ?

The first-order elimination rate constant for dopamine is 4.2 hr^-1, for penicillin G is 1.2 hr^-1, for theophylline is 0.1 hr^-1, and for lidocaine is 0.5 hr^-1. Which of these drugs will reach steady state faster during the administration of a constant rate iv infusion ?