Bch211 - Exam 2

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  • 1/46 Questions

    True or false:  Enzymes, being proteins, are sensitive to temperature and will be denatured by high temperatures.

    • True
    • False
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Bch211 - Exam 2 - Quiz
About This Quiz

BCH211 - Exam 2 assesses key concepts in biochemistry, focusing on enzyme activity, metabolic processes, and the role of vitamins. It evaluates understanding of protein sensitivity to temperature, anabolism, enzyme inhibition, and optimal enzyme conditions.

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  • 2. 

    True or false:  Energy is generally consumed during anabolism

    • True

    • False

    Correct Answer
    A. True
    Explanation
    During anabolism, energy is consumed as the body builds complex molecules from simpler ones. Anabolic processes require energy input to synthesize substances like proteins, nucleic acids, and carbohydrates. This energy is obtained from the breakdown of ATP molecules, which release energy when their high-energy phosphate bonds are hydrolyzed. Therefore, it is correct to say that energy is generally consumed during anabolism.

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  • 3. 

    The value of Vmax changes in 

    • Competitive inhibition

    • Noncompetitive inhibition

    • Neither form of inhibition

    • Both forms of inhibition

    Correct Answer
    A. Noncompetitive inhibition
    Explanation
    In noncompetitive inhibition, the inhibitor binds to an allosteric site on the enzyme, causing a change in the enzyme's shape and reducing its activity. This means that the maximum velocity (Vmax) of the enzyme-catalyzed reaction is decreased, as the inhibitor is able to bind to the enzyme regardless of whether the substrate is present or not. Therefore, the value of Vmax changes in noncompetitive inhibition.

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  • 4. 

    Reactions requiring energy often occur with the simultaneous hydrolysis of

    • ATP

    • Acetyl CoA

    • Glucose

    • Pi

    Correct Answer
    A. ATP
    Explanation
    Reactions requiring energy often occur with the simultaneous hydrolysis of ATP. ATP is known as the energy currency of the cell and is used to fuel various cellular processes. Hydrolysis of ATP releases energy by breaking the high-energy phosphate bond, converting ATP into ADP (adenosine diphosphate) and inorganic phosphate (Pi). This energy is then utilized by the cell to perform various energy-requiring reactions, such as muscle contractions, active transport, and synthesis of macromolecules. Therefore, ATP is essential for providing the energy needed for cellular activities.

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  • 5. 

    True or false:  Aspirin acts as an reversible inhibitor of the COX 2 enzyme

    • True

    • False

    Correct Answer
    A. False
    Explanation
    Aspirin acts as an irreversible inhibitor of the COX 1 enzyme, not the COX 2 enzyme. It covalently modifies the enzyme, inhibiting its ability to produce prostaglandins and thromboxanes. This irreversible inhibition is what gives aspirin its long-lasting effects. COX 2 inhibitors, on the other hand, selectively target the COX 2 enzyme, reducing inflammation and pain without affecting COX 1 and its protective effects on the stomach lining.

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  • 6. 

    A metal ion required for enzyme activity is called

    • Proenzyme

    • A zymogen

    • A cofactor

    • A substrate

    Correct Answer
    A. A cofactor
    Explanation
    A metal ion required for enzyme activity is called a cofactor. Cofactors are non-protein molecules that bind to enzymes and are essential for their proper functioning. Metal ions, such as zinc, iron, and magnesium, can act as cofactors by assisting in catalytic reactions or stabilizing the enzyme's structure. Cofactors are necessary for the enzyme to perform its biological function efficiently and are often involved in key metabolic processes within cells.

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  • 7. 

    A short description of a diastereomer would be?

    • Diastereomers are those compounds that can only have 6 chiral carbons

    • Diastereomers are all of the isomers for compounds that can have two or more chiral centers

    • Diastereomers are isomers that only have 1 chiral center.

    • Diastereomers are isomers that are mirror images of the other

    Correct Answer
    A. Diastereomers are all of the isomers for compounds that can have two or more chiral centers
    Explanation
    Diastereomers are stereoisomers that have different configurations at one or more chiral centers, but are not mirror images of each other. This means that they can have two or more chiral centers, as stated in the correct answer. The other options are incorrect because they either limit the number of chiral carbons or incorrectly describe the relationship between diastereomers.

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  • 8. 

    Which of the following enzyme properties is explained by the lock-and-key model?

    • High molecular weight

    • Specificity

    • Susceptibility to denaturation

    • High turnover rate

    Correct Answer
    A. Specificity
    Explanation
    The lock-and-key model explains the property of specificity in enzymes. According to this model, enzymes have a specific shape or "lock" that only fits with a specific substrate or "key". This means that enzymes can only catalyze specific reactions by binding to specific substrates. The lock-and-key model helps to explain why enzymes are highly specific in their function and can only interact with certain molecules, leading to the property of specificity.

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  • 9. 

    Which form of monosaccharides is preferred by human cells?

    • Both D and L

    • D

    • L

    • Neither D nor L

    Correct Answer
    A. D
    Explanation
    D-monosaccharides are preferred by human cells because they are easily metabolized and utilized for energy production. Human cells have specific enzymes that can only recognize and process D-monosaccharides, making them the preferred form. L-monosaccharides, on the other hand, are not recognized by these enzymes and cannot be efficiently metabolized by human cells. Therefore, D-monosaccharides are the preferred form for human cells.

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  • 10. 

    The region of an enzyme where the substrate molecule fits is called the

    • Substrate site

    • Primary site

    • Active site

    • Substrate bond

    Correct Answer
    A. Active site
    Explanation
    The active site of an enzyme is the specific region where the substrate molecule binds and undergoes a chemical reaction. This site is typically a small, three-dimensional pocket within the enzyme's structure that is complementary in shape to the substrate. The active site plays a crucial role in catalyzing the conversion of the substrate into a product by facilitating the necessary chemical reactions. It provides a favorable environment for the substrate to interact with the enzyme, promoting the formation of the transition state and lowering the activation energy required for the reaction to occur.

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  • 11. 

    What happens to the entropy when ATP is hydrolyzed to ADP?

    • Entropy doesn't change.

    • ATP has no entropy.

    • Entropy increases.

    • Entropy decreases.

    Correct Answer
    A. Entropy increases.
    Explanation
    When ATP is hydrolyzed to ADP, it undergoes a chemical reaction that releases energy. This release of energy leads to an increase in the number of possible microstates or arrangements of particles, resulting in an increase in entropy. Therefore, the correct answer is that entropy increases when ATP is hydrolyzed to ADP.

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  • 12. 
    The following compounds are enantiomers of each other - ProProfs

    The following compounds are enantiomers of each other

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 1
  • 13. 

    Which of the following terms is a general definition of an enzyme?

    • A catalyst

    • An activator

    • A carbohydrate

    • A lipid

    Correct Answer
    A. A catalyst
    Explanation
    An enzyme is a biological catalyst that speeds up chemical reactions in living organisms without being consumed in the process. It lowers the activation energy required for a reaction to occur, allowing it to happen more quickly. Enzymes are not activators, carbohydrates, or lipids, but rather a specific type of protein that plays a crucial role in various metabolic processes.

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  • 14. 

    The simplest carbohydrates are called

    • Polysaccharides

    • Oligosaccharides

    • Disaccharides

    • Monosaccharides

    Correct Answer
    A. Monosaccharides
    Explanation
    Monosaccharides are the simplest carbohydrates because they consist of a single sugar unit. They are the building blocks of more complex carbohydrates such as oligosaccharides and polysaccharides. Monosaccharides are small, soluble molecules that can be easily absorbed and used by the body for energy. Examples of monosaccharides include glucose, fructose, and galactose.

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  • 15. 

    21000 molecules were acted on by a single molecule of an enzyme in 15 minutes.  What is the turnover number?

    • 23

    • 84000

    • 480

    • 1400

    Correct Answer
    A. 1400
    Explanation
    The turnover number refers to the number of substrate molecules that an enzyme can convert into product per unit time. In this case, a single molecule of the enzyme acted on 21000 molecules of substrate in 15 minutes. Therefore, the turnover number can be calculated by dividing the number of substrate molecules (21000) by the time (15 minutes), which gives us 1400. This means that the enzyme is capable of converting 1400 substrate molecules into product per minute.

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  • 16. 

    The cyclic form of glucose results from the formation of

    • A hemiacetal

    • An acetal

    • An amide

    • An ester

    Correct Answer
    A. A hemiacetal
    Explanation
    The cyclic form of glucose is formed through the reaction of the aldehyde group with the hydroxyl group, resulting in the formation of a hemiacetal. In this reaction, the aldehyde group acts as the electrophile, while the hydroxyl group acts as the nucleophile. The reaction forms a cyclic structure with a hemiacetal linkage between the carbon atom of the aldehyde and the oxygen atom of the hydroxyl group. This cyclic form is important in glucose metabolism and plays a crucial role in various biological processes.

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  • 17. 
    Which of the following terms can be used correctly to fill the blank in the following equation?   - ProProfs

    Which of the following terms can be used correctly to fill the blank in the following equation?  

    • Zymogen

    • Cofactor

    • Substrate

    • Isozyme

    Correct Answer
    A. Cofactor
    Explanation
    A cofactor is a non-protein molecule or ion that is required for the proper functioning of an enzyme. It can bind to the enzyme and assist in the catalysis of a reaction. In the given equation, the blank is most likely referring to a molecule or ion that is needed for the enzyme to function, making "cofactor" the correct term to fill in the blank.

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  • 18. 

    Which of the following is true of a noncompetitive inhibitor?

    • Resembles the substrate

    • Binds at a site other than the active site

    • Reduces Km

    • Increases Vmax

    Correct Answer
    A. Binds at a site other than the active site
    Explanation
    A noncompetitive inhibitor is a molecule that binds to an enzyme at a site other than the active site. This means that it does not compete with the substrate for binding to the active site. Instead, it binds to a different site on the enzyme, causing a conformational change that affects the enzyme's activity. This type of inhibition does not affect the affinity of the enzyme for the substrate (Km), but it reduces the maximum rate of reaction (Vmax). Therefore, the correct answer is "binds at a site other than the active site."

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  • 19. 

    Which of the following is a disaccharide?

    • Sucrose

    • Glucose

    • Galactose

    • Fructose

    Correct Answer
    A. Sucrose
    Explanation
    Sucrose is a disaccharide because it is composed of two monosaccharides, glucose and fructose, joined together by a glycosidic bond. Disaccharides are carbohydrates that consist of two sugar molecules bonded together. Glucose, galactose, and fructose are monosaccharides, meaning they are single sugar molecules.

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  • 20. 

    Refer to Exhibit 6A.  "Hindrate" is an inhibitor of triose phosphate isomerase.  When it is added to cells at a concentration of 0.1 nM, the enzyme's Km for the substrate is unchanged, but the apparent Vmax is altered to 50nM/sec. 

    • This is an uncompetitive inhibitor

    • This is a noncompetitive inhibitor

    • This is a competitive inhibitor

    • This is an irreversible inhibitor

    Correct Answer
    A. This is a noncompetitive inhibitor
    Explanation
    Inhibition is classified as noncompetitive when the inhibitor binds to a different site on the enzyme than the substrate, and the binding of the inhibitor causes a change in the enzyme's conformation, rendering it unable to catalyze the reaction effectively. In this case, "Hindrate" is an inhibitor that alters the apparent Vmax of the enzyme without affecting the Km, indicating that it binds to a different site on the enzyme than the substrate. Therefore, the correct answer is that "Hindrate" is a noncompetitive inhibitor.

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  • 21. 

    The sign of Gibb's Free Energy is positive ("+") when energy is released

    • True

    • False

    Correct Answer
    A. False
    Explanation
    The sign of Gibbs Free Energy is negative ("-") when energy is released, not positive ("+"). This is because Gibbs Free Energy represents the maximum amount of work that can be obtained from a system at constant temperature and pressure. When energy is released, the system is becoming more stable and the Gibbs Free Energy decreases, resulting in a negative sign.

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  • 22. 

    The conditions required for maximum enzyme function are called:

    • Optimum conditions

    • Low pressure, high temperature

    • Room conditions

    • Standard conditions

    Correct Answer
    A. Optimum conditions
    Explanation
    The conditions required for maximum enzyme function are called "optimum conditions". These conditions refer to the specific pH, temperature, and substrate concentration at which an enzyme functions most efficiently. Enzymes are highly sensitive to changes in these factors, and any deviation from the optimum conditions can result in a decrease in enzyme activity. Therefore, maintaining the optimum conditions is crucial for maximizing enzyme function. The other options mentioned, such as low pressure, high temperature, room conditions, and standard conditions, are not specifically related to enzyme function and do not accurately describe the conditions required for maximum enzyme activity.

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  • 23. 

    A monosaccharide used to form nucleic acids is

    • Ribose

    • Maltose

    • Galactose

    • Glucose

    Correct Answer
    A. Ribose
    Explanation
    Ribose is a monosaccharide that is used to form nucleic acids. Nucleic acids, such as DNA and RNA, are composed of nucleotides, which consist of a sugar molecule (ribose or deoxyribose), a phosphate group, and a nitrogenous base. Ribose is a key component of RNA, where it helps in the formation of the sugar-phosphate backbone of the molecule. Therefore, ribose is the correct answer as it is specifically involved in the synthesis of nucleic acids.

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  • 24. 

    Under saturation conditions, an enzyme-catalyzed reaction had a velocity V.  Which of the following would increase the rate of the reaction?

    • A decrease in enzyme concentration

    • A decrease in substrate concentration

    • An increase in enzyme concentration

    • An increase in substrate concentration

    Correct Answer
    A. An increase in enzyme concentration
    Explanation
    An increase in enzyme concentration would increase the rate of the reaction because enzymes act as catalysts, meaning they speed up the rate of a reaction without being consumed in the process. By increasing the concentration of enzymes, there are more available to catalyze the reaction, leading to a higher reaction rate. This is particularly true under saturation conditions, where the substrate concentration is already high enough that all available enzyme active sites are occupied. Therefore, increasing the enzyme concentration is the most effective way to further increase the rate of the reaction.

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  • 25. 

    In the induced-fit model of substrate binding to enzymes

    • The active site changes its conformation to fit the transition state.

    • The substrate changes its conformation to fit the active site.

    • The active site changes its conformation to fit the product.

    • The active site changes its conformation to fit the substrate.

    Correct Answer
    A. The active site changes its conformation to fit the transition state.
    Explanation
    In the induced-fit model of substrate binding to enzymes, the active site changes its conformation to fit the transition state. This means that the active site of the enzyme undergoes a structural change in order to accommodate the transition state of the substrate. This conformational change is crucial for the enzyme to properly bind and catalyze the reaction, as it allows for optimal interactions between the active site and the substrate's transition state. By adapting its shape to fit the transition state, the enzyme enhances the efficiency and specificity of the reaction.

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  • 26. 

    The theory that proposes a somewhat flexible enzyme conformation is the 

    • Induced-fit theory

    • Physically-fit theory

    • Expanding-fit theory

    • Lock-and-key theory

    Correct Answer
    A. Induced-fit theory
    Explanation
    The induced-fit theory suggests that enzymes can undergo conformational changes in order to accommodate the substrate. This means that the enzyme's active site is not rigidly shaped like a lock, but rather can change its shape to fit the substrate like a glove. This theory explains how enzymes can enhance the efficiency of chemical reactions by bringing the substrate molecules closer together and creating an optimal environment for the reaction to occur.

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  • 27. 

    Which of the following is a common function of many vitamins in the body?

    • Substrates

    • Activators

    • Apoenzymes

    • Coenzymes

    Correct Answer
    A. Coenzymes
    Explanation
    Coenzymes are small molecules that work together with enzymes to facilitate various biochemical reactions in the body. They assist enzymes in catalyzing reactions by acting as carriers of chemical groups or electrons. Many vitamins serve as precursors for coenzymes, meaning they are converted into coenzymes once inside the body. Therefore, coenzymes are a common function of many vitamins in the body, as they play a crucial role in ensuring the proper functioning of enzymes and metabolic processes.

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  • 28. 

    Which of the following is correctly called a complex carbohydrate?

    • Starch

    • Sucrose

    • Fructose

    • Lactose

    Correct Answer
    A. Starch
    Explanation
    Starch is correctly called a complex carbohydrate because it is made up of long chains of glucose molecules. Complex carbohydrates are polysaccharides, which means they consist of multiple sugar molecules bonded together. Starch is a common form of energy storage in plants and is found in foods like potatoes, rice, and bread. Sucrose, fructose, and lactose are all examples of simple carbohydrates, as they consist of one or two sugar molecules and are typically found in fruits, table sugar, and dairy products, respectively.

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  • 29. 

    The following represents the results of an experiment on a metabolic enzyme.  What is the optimum pH of this enzyme?

    • 5.5

    • 6.5

    • 9.5

    • 3.0

    Correct Answer
    A. 6.5
    Explanation
    The optimum pH of an enzyme refers to the pH at which the enzyme exhibits maximum activity. In this case, the correct answer is 6.5, indicating that the enzyme has the highest activity at pH 6.5. This suggests that the enzyme functions most efficiently under slightly acidic conditions.

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  • 30. 
    Draw the structure of B-D-Lactose in the Hawarth projection - ProProfs

    Draw the structure of B-D-Lactose in the Hawarth projection

    • Is this a reducing sugar? (YES)

    • 1 pt for placing the beta structure

    • 1 pt for the glycosidic linkage

    • 2 pts for each sugar

    Correct Answer
    A. Is this a reducing sugar? (YES)
    Explanation
    The given answer states that B-D-Lactose is a reducing sugar. This is because lactose contains a free anomeric carbon, which is the carbon that can open up and form a hemiacetal or hemiketal. In the case of lactose, the anomeric carbon is the carbon in the glucose residue. This carbon can undergo mutarotation, meaning it can interconvert between the alpha and beta forms, allowing it to reduce certain oxidizing agents. Therefore, B-D-Lactose is considered a reducing sugar.

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  • 31. 

    Which statement about enzymes is incorrect?

    • Enzymes can produce a reaction transition state with a reduced activation energy.

    • There are enzymes that interact with one enantiomer, but not the other.

    • Enzymes are not used up during the reaction in which they are involved

    • Enzymes can reduce the net energy of a reaction

    Correct Answer
    A. Enzymes can reduce the net energy of a reaction
    Explanation
    Enzymes can reduce the net energy of a reaction by lowering the activation energy required for the reaction to occur. They do this by stabilizing the transition state, making it easier for the reactants to reach the necessary energy level for the reaction to proceed. This allows the reaction to occur more quickly and efficiently. Enzymes themselves are not consumed or used up in the reaction, but rather they can be reused multiple times.

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  • 32. 

    If the y-intercept of a Lineweaver-Burk plot = 1.91 (sec/millimole) and the slope = 75.3L/sec, Km equals:

    • 0.0254 millimolar (mM)

    • 0.523 millimolar (mM)

    • 5.23 millimolar (mM)

    • 39.4 millimolar (mM)

    • 75.3 millimolar (mM)

    Correct Answer
    A. 39.4 millimolar (mM)
    Explanation
    The Lineweaver-Burk plot is used to determine the kinetic parameters of an enzyme-catalyzed reaction, including the Michaelis-Menten constant (Km). The y-intercept of the Lineweaver-Burk plot represents 1/Vmax, where Vmax is the maximum reaction rate. In this case, the y-intercept is 1.91 (sec/millimole), which means that 1/Vmax = 1.91 (sec/millimole). The slope of the plot represents Km/Vmax. Given that the slope is 75.3 L/sec, we can calculate Km by rearranging the equation: Km = slope / y-intercept = 75.3 L/sec / 1.91 (sec/millimole) = 39.4 millimolar (mM). Therefore, the correct answer is 39.4 millimolar (mM).

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  • 33. 

    Sugars which contain an aldehyde group that can be oxidized are called

    • Glycosides

    • Simple sugars

    • Reducing sugars

    • Oxidizing sugars

    Correct Answer
    A. Reducing sugars
    Explanation
    Sugars which contain an aldehyde group that can be oxidized are called reducing sugars. This is because the aldehyde group can undergo oxidation reactions, where it loses electrons and becomes oxidized. Reducing sugars are able to donate electrons to other molecules, making them good reducing agents. This property is important in various biological processes, such as glycolysis and the Maillard reaction. Glycosides are a different type of sugar compound that consist of a sugar molecule bonded to a non-sugar molecule. Simple sugars and oxidizing sugars do not specifically refer to sugars with an aldehyde group that can be oxidized.

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  • 34. 

    The structure below is shown in what anomeric form?

    • B (beta)

    • Cis

    • Trans

    • Alpha

    Correct Answer
    A. B (beta)
    Explanation
    The given structure is shown in the beta (B) anomeric form. Anomeric forms refer to the different spatial arrangements of a cyclic sugar molecule, specifically the orientation of the hydroxyl group attached to the anomeric carbon atom. In this case, the hydroxyl group is in the beta position, which means it is oriented in the opposite direction as the substituent attached to the anomeric carbon.

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  • 35. 

    Structurally, glycogen is most similar to 

    • Sucrose

    • Amylopectin

    • Amylose

    • Cellulose

    Correct Answer
    A. Amylopectin
    Explanation
    Glycogen is a polysaccharide that serves as a storage form of glucose in animals. Structurally, glycogen is most similar to amylopectin. Both glycogen and amylopectin are highly branched polysaccharides composed of glucose units. They have a similar structure with many branches, allowing for efficient storage and release of glucose molecules when needed. Sucrose, amylose, and cellulose have different structures and are not as similar to glycogen as amylopectin is.

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  • 36. 
    If the reaction AB has G = +15 Joule/mol and the reaction BC has G = -25 Joule/mol, the overall energy change AC will be   - ProProfs

    If the reaction AB has G = +15 Joule/mol and the reaction BC has G = -25 Joule/mol, the overall energy change AC will be  

    • -40 Joule/mol

    • -15 Joule/mol

    • -10 Joule/mol

    • -2540 Joule/mol

    • You cannot tell from the given data

    Correct Answer
    A. -10 Joule/mol
    Explanation
    The overall energy change for the reaction AC can be determined by adding the individual energy changes of the reactions AB and BC. Since the energy change of AB is +15 Joule/mol and the energy change of BC is -25 Joule/mol, the overall energy change of AC would be +15 Joule/mol + (-25 Joule/mol) = -10 Joule/mol.

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  • 37. 

    A Lineweaver-Burk plot is useful in the analysis of enzymatic reactions because

    • It is easier to see whether points deviate from a straight line than from a curve

    • It is not affected by the presence of inhibitors

    • It can be used whether or not the enzyme displays Michaelis-Menten kinetics

    • It can work with allosteric enzymes

    Correct Answer
    A. It is easier to see whether points deviate from a straight line than from a curve
    Explanation
    The Lineweaver-Burk plot is useful in the analysis of enzymatic reactions because it allows for easier identification of points that deviate from a straight line compared to a curve. This is important in determining the validity of the data and assessing the accuracy of the experimental results. By plotting the reciprocal of the reaction rate against the reciprocal of the substrate concentration, any deviations from a straight line can be easily observed, indicating potential errors or inconsistencies in the data.

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  • 38. 

    Competitive inhibitors have this effect:

    • Changing the value for Vmax

    • This type of inhibitor both changes the Km and interferes with substrate binding

    • Modifying the Km value

    • Interfering with substrate binding

    • All of these are correct

    Correct Answer
    A. This type of inhibitor both changes the Km and interferes with substrate binding
    Explanation
    Competitive inhibitors are molecules that compete with the substrate for binding to the active site of an enzyme. They do not change the maximum velocity (Vmax) of the enzyme-catalyzed reaction, but they do affect the affinity of the enzyme for the substrate, resulting in an increase in the apparent Km value. Additionally, competitive inhibitors interfere with substrate binding by occupying the active site, preventing the substrate from binding and reducing the enzyme's catalytic activity. Therefore, the correct answer is "This type of inhibitor both changes the Km and interferes with substrate binding."

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  • 39. 

    Which of the following inhibitors binds to the enzyme at a site other than the active site?

    • Irreversible inhibitor

    • Noncompetitive inhibitor

    • Competitive inhibitor

    • All of these

    • Non of these

    Correct Answer
    A. Noncompetitive inhibitor
    Explanation
    A noncompetitive inhibitor is an inhibitor that binds to an enzyme at a site other than the active site. This means that it does not compete with the substrate for binding to the active site, but instead binds to a different site on the enzyme. This binding alters the enzyme's shape and function, preventing the substrate from binding and inhibiting the enzyme's activity. Therefore, a noncompetitive inhibitor is the correct answer because it binds to the enzyme at a site other than the active site.

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  • 40. 
    The carbohydrate below may be classified as - ProProfs

    The carbohydrate below may be classified as

    • A ketohexose

    • An aldopentose

    • A ketopentose

    • An aldohexose

    Correct Answer
    A. A ketopentose
    Explanation
    The given carbohydrate can be classified as a ketopentose because it is a five-carbon sugar with a ketone functional group. Ketopentoses have a ketone group (C=O) attached to one of the carbon atoms in the sugar molecule. This distinguishes them from aldopentoses, which have an aldehyde group (CHO) attached to one of the carbon atoms. The classification as a ketopentose indicates the specific structure and functional group present in the carbohydrate.

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  • 41. 

    The synthesis of an enzyme in response to a cellular need is called

    • Allosteric production

    • Feedback control

    • Biofeedback

    • Enzyme induction

    Correct Answer
    A. Enzyme induction
    Explanation
    Enzyme induction refers to the synthesis or production of an enzyme in response to a cellular need. When the cell requires a particular enzyme to perform a specific function or to respond to changes in its environment, it can induce the production of that enzyme. This process allows the cell to regulate its enzyme levels and adapt to different conditions. Allosteric production, feedback control, and biofeedback are not accurate terms to describe this phenomenon.

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  • 42. 

    The structure given below has what type of glycosidic linkage?

    • A (1-4)

    • B (1-4)

    • B (1-6)

    • A (1-6)

    Correct Answer
    A. A (1-4)
    Explanation
    The given structure has a glycosidic linkage between the first carbon of one sugar molecule and the fourth carbon of the adjacent sugar molecule. This type of linkage is called an alpha-1,4-glycosidic linkage.

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  • 43. 
    A polysaccharide containing B(14) linkages is - ProProfs

    A polysaccharide containing B(14) linkages is

    • Glycogen

    • Amylopectin

    • Amylose

    • Cellulose

    Correct Answer
    A. Cellulose
    Explanation
    Cellulose is a polysaccharide that contains B(14) linkages. It is a major component of plant cell walls and provides structural support to plants. Unlike glycogen, amylopectin, and amylose, which are all composed of glucose molecules linked by alpha(1-4) glycosidic bonds, cellulose is made up of glucose molecules linked by beta(1-4) glycosidic bonds. This difference in linkage results in a different structure and function for cellulose compared to the other polysaccharides listed.

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  • 44. 

    The following structure is shown in 

    • A D form

    • Neither D nor L

    • Both D and L

    • An L form

    Correct Answer
    A. A D form
    Explanation
    The correct answer is "a D form". This means that the structure shown is in the D form configuration. The D form refers to the spatial arrangement of certain molecules, particularly sugars. In the D form, the hydroxyl group (-OH) on the highest-numbered chiral carbon is on the right side. This is in contrast to the L form, where the hydroxyl group is on the left side. Therefore, based on the given information, the structure shown is in the D form configuration.

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  • 45. 

    If an inhibitor changes the slope of the Lineweaver-Burk graph, but not the x-intercept, it is this type of inhibition:

    • You cannot tell from the data given

    • Competetive

    • Irreversible inhibition

    • Non-competitive

    • More than one answer is correct

    Correct Answer
    A. Non-competitive
    Explanation
    If an inhibitor changes the slope of the Lineweaver-Burk graph, but not the x-intercept, it indicates non-competitive inhibition. In non-competitive inhibition, the inhibitor binds to a different site on the enzyme than the substrate, and both the enzyme-substrate complex and the enzyme-inhibitor complex are formed. This type of inhibition does not compete with the substrate for binding to the enzyme and therefore does not affect the x-intercept, which represents the affinity of the enzyme for the substrate. The change in slope indicates that the inhibitor affects the reaction rate without affecting the affinity of the enzyme for the substrate.

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  • 46. 

    Lineweaver Burke - If everything else has a higher slope, anything lower than it represents the activation space.  everything above it represents the inhibition space Gibbs free energy  delta G(negative - ) = spontaneous delta G(positive +) = nonspontaneous

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 1
    Explanation
    The Lineweaver Burke plot is used to analyze enzyme kinetics. It plots the reciprocal of the reaction rate against the reciprocal of the substrate concentration. In this plot, the slope of the line represents the enzyme's activity. If everything else has a higher slope, anything lower than it represents the activation space, indicating that the reaction is spontaneous. On the other hand, everything above it represents the inhibition space, indicating that the reaction is nonspontaneous. Therefore, option 1 is the correct answer.

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  • Mar 21, 2023
    Quiz Edited by
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  • Dec 16, 2013
    Quiz Created by
    Grj2010
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