Data Test Chapter 2 V2 10.22

Physics

IUPAC

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| By Harry Brielmann

Harry Brielmann

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Quizzes Created: 13 | Total Attempts: 6,238

| Attempts: 140 | Questions: 19

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1. Which measurement uses proper S.I. Units?

3 feet

14 parsecs

28 ounces

3 meters

meters is the SI unit for distance, but all the others are not SI units. Feet should be meters, parsecs should be meters, ounces should be grams, or if you are really picky, kilograms.

Explanation

meters is the SI unit for distance, but all the others are not SI units. Feet should be meters, parsecs should be meters, ounces should be grams, or if you are really picky, kilograms.

Submit

About This Quiz

Data Test Chapter 2 v2 10.22 assesses knowledge in physics topics such as SI units, scientific notation, and calculations involving density and volume. It aims to enhance understanding of fundamental physics concepts and their practical applications.

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2. The volume of 1.24 pounds of aluminum is __________ cubic inches. (453.6 grams = one pound, density of Al = 2.70 g/cm3, 1.00 cubic inch = 16.39 cubic centimeters). suggestion: convert from pounds to grams to cubic centimeters then to cubic inches. Use scrap paper and make sure all your units cancel.

12.7

14.7

16.7

18.7

1.24 space p o u n d s cross times fraction numerator 453.6 space g r a m s over denominator 1 space p o u n d end fraction cross times fraction numerator 1 space c m cubed over denominator 2.7 space g r a m s end fraction cross times fraction numerator 1 space i n cubed over denominator 16.39 space c m cubed end fraction equals 12.7 space i n cubed

Explanation

1.24 space p o u n d s cross times fraction numerator 453.6 space g r a m s over denominator 1 space p o u n d end fraction cross times fraction numerator 1 space c m cubed over denominator 2.7 space g r a m s end fraction cross times fraction numerator 1 space i n cubed over denominator 16.39 space c m cubed end fraction equals 12.7 space i n cubed

Submit

3. $fraction numerator 3 space A p p l e s over denominator B e a r s end fraction space x space fraction numerator space 6 space C a r s over denominator A p p l e s end fraction space x space fraction numerator 4.3 space x space 10 cubed space D o g s over denominator C a r s end fraction space x fraction numerator 5 space E l v e s over denominator D o g s end fraction space x space fraction numerator 6 space F o x e s over denominator E l v e s end fraction space equals$ Which one do you like?

2322000

2322000 Foxes

2322000 Bears

2322000 Foxes/Bear

The given options are different choices for what the person likes. The answer "2322000 Foxes/Bear" suggests that the person likes both foxes and bears.

Explanation

The given options are different choices for what the person likes. The answer "2322000 Foxes/Bear" suggests that the person likes both foxes and bears.

Submit

4. In a mentos eruption experiment the measured eruption heights in three trials are 6.9, 6.71, and 7.25 bricks. What is the average height of the eruption in centimeters? Please report your answer using three significant figures. (1 brick = 6.50 cm)suggestion: take the average by adding up the data and dividing by exactly three. Consider how precise your answer should be.

41 centimeters

42.3 centimeters

43 centimeters

44.3 centimeters

45.2 centimeters

6.9 space b r i c k s space plus space 6.71 space b r i c k s space plus space 7.25 space b r i c k s equals space 20.86 space b r i c k s space obelus divided by space 3 equals space 6.95 space b r i c k s space cross times space fraction numerator 6.5 space c m over denominator 1 space b r i c k end fraction equals 45.2 space c m

Explanation

6.9 space b r i c k s space plus space 6.71 space b r i c k s space plus space 7.25 space b r i c k s equals space 20.86 space b r i c k s space obelus divided by space 3 equals space 6.95 space b r i c k s space cross times space fraction numerator 6.5 space c m over denominator 1 space b r i c k end fraction equals 45.2 space c m

Submit

5. $T h e space e q u a t i o n space b e l o w space i s space t h e space s o l u t i o n space t o space o n e space o f space t h e space q u e s t i o n s space l i s t e d space b e l o w. space S o l v e space t h e space p r o b l e m space a n d space f i n d space o u t space w h a t space q u e s t i o n space i s space b e i n g space a n s w e r e d. fraction numerator 3 space m i l e s space over denominator 1 space h o u r end fraction space x space 14 space h o u r s space plus fraction numerator 1 space m i l e over denominator 1 space s e c o n d end fraction space x space 3 space s e c o n d s space equals space$ Which one do you like?

If you travel at 3 meters per hour for 14 hours and then travel at 1 meter per second for... If you travel at 3 meters per hour for 14 hours and then travel at 1 meter per second for 3 seconds, how far did you travel?

If you travel at 3 miles per hour for 14 hours and then travel at 1 mile per second for... If you travel at 3 miles per hour for 14 hours and then travel at 1 mile per second for 3 seconds, how far did you travel?

If you travel at 3 miles per hour for 14 hours and then travel at 1 mile per second for... If you travel at 3 miles per hour for 14 hours and then travel at 1 mile per second for 3 seconds, for how many minutes did you travel?

If you travel at 3 miles per second for 14 hours and then travel at 1 mile per hour for... If you travel at 3 miles per second for 14 hours and then travel at 1 mile per hour for 3 seconds, how far did you travel?

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Explanation

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Submit

6. The human population on earth currently is approximately 7,125,000,000 people. Using scientific notation with the correct number of significant figures, this is ________________________________ people

note only four significant figures since there is no decimal place. And note that this is about 7 billion people, not 7 trillion To convert to scientific notation make your number between 1 and 10 by drawing a line, then count the placeholders to the decimal point: 7|125 000 000. = $7.125 space x space 10 to the power of 9 space p e o p l e... n o t e space t h a t space sin c e space t h e r e space i s space n o space d e c i m a l space p l a c e space i n space t h e space q u e s t i o n t h i s space a n s w e r space i s space r e p o r t e d space u sin g space o n l y space f o u r space s i g n i f i c a n t space f i g u r e s.$

Explanation

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7. Give the number of significant figures in the number 60,402,000

Leading zeros only tell where the significant figures are in relation to the decimal point, and therefore are insignificant.

Explanation

Leading zeros only tell where the significant figures are in relation to the decimal point, and therefore are insignificant.

Submit

8. If I have 12 g of grass and it takes up 30 cubic centimeters, what is the density of the grass?

0.4 g/cubic centimeter

2.5 g/cubic centimeter

360 g/cubic centimeter

The information provided is not sufficient to draw a conclusion

The density of a substance is calculated by dividing its mass by its volume. In this question, we are given that the mass of the grass is 12 g and it takes up 30 cubic centimeters of space. To find the density, we divide the mass (12 g) by the volume (30 cubic centimeters), which gives us a density of 0.4 g/cubic centimeter.

Explanation

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9. Solve:

fraction numerator 3.00 space A over denominator 1.00 space B end fraction space x space fraction numerator space 6.00 space C space over denominator 6.02 space x space 10 to the power of 23 A end fraction space x space fraction numerator 4.3 space x space 10 cubed D over denominator 1.00 space C end fraction space x fraction numerator 5.00 space E over denominator 1.00 space D end fraction space x space fraction numerator 6.00 space F over denominator 1.00 space E end fraction space equals

3.86 x 10^-18 F/B

3.86 x 10^-18 B

The given expression represents a value in scientific notation, where 3.86 is multiplied by 10 raised to the power of -18. This implies that the value is very small, as it is multiplied by a very small number (10^-18). The unit "F/B" indicates that the value represents a ratio or conversion factor between two quantities, with "F" representing the unit of the numerator and "B" representing the unit of the denominator. Therefore, the answer 3.86 x 10^-18 F/B suggests that the given expression represents a very small conversion factor or ratio between two quantities.

Explanation

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10. The SI unit for electric current is the __________

Volt

Ampersand

Watt

Ampere

Kilowatt hour

Stone

The SI unit for current is the ampere

Explanation

The SI unit for current is the ampere

Submit

11. The SI unit for amount is the __________

Mole

Quantity

Kilogram

Gram

The mole is the official SI unit for amount. It is a big number. Note that it is not the SI unit for mass, that is the gram.

Explanation

The mole is the official SI unit for amount. It is a big number. Note that it is not the SI unit for mass, that is the gram.

Submit

12. Which substance has a higher density?substance a: density = 4.02 milligrams per millilitersubstance b: density = 403 nanograms per microliter

Substance A

Substance B

substance a has a density of 1 gram per liter
but since there are 1000 nanograms in a microgram substance b is less dense.

Explanation

substance a has a density of 1 gram per liter
but since there are 1000 nanograms in a microgram substance b is less dense.

Submit

13. 1.2 milliseconds = _____________ minutes.

612,000 minutes

170. minutes

1.2 space m i l l i s e c o n d s space x space fraction numerator s e c o n d over denominator 1000 space m i l l i s e c o n d s end fraction space x space fraction numerator m i n u t e over denominator 60 space s e c o n d s end fraction space equals space 1.7 space x space 10 to the power of minus 5 end exponent space m i n u t e s ;<br /> 1.2 space i s space t h e space o n l y space p i e c e space o f space d a t a space g i v e n space s o space w e space r e p o r t space t h e space a n s w e r space t o space 2 space s i g n i f i c a n t space f i g u r e s<br /> g i v i n g space a space f i n a l space a n s w e r space o f space bold 1 bold. bold 7 bold space bold italic x bold space bold 10 to the power of bold minus bold 5 bold space end exponent bold italic m bold italic i bold italic n bold italic u bold italic t bold italic e bold italic s bold comma bold space bold italic o bold italic r bold space bold 0 bold. bold 000017 bold space bold italic m bold italic i bold italic n bold italic u bold italic t bold italic e bold italic s.

Explanation

1.2 space m i l l i s e c o n d s space x space fraction numerator s e c o n d over denominator 1000 space m i l l i s e c o n d s end fraction space x space fraction numerator m i n u t e over denominator 60 space s e c o n d s end fraction space equals space 1.7 space x space 10 to the power of minus 5 end exponent space m i n u t e s ;<br /> 1.2 space i s space t h e space o n l y space p i e c e space o f space d a t a space g i v e n space s o space w e space r e p o r t space t h e space a n s w e r space t o space 2 space s i g n i f i c a n t space f i g u r e s<br /> g i v i n g space a space f i n a l space a n s w e r space o f space bold 1 bold. bold 7 bold space bold italic x bold space bold 10 to the power of bold minus bold 5 bold space end exponent bold italic m bold italic i bold italic n bold italic u bold italic t bold italic e bold italic s bold comma bold space bold italic o bold italic r bold space bold 0 bold. bold 000017 bold space bold italic m bold italic i bold italic n bold italic u bold italic t bold italic e bold italic s.

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14. Aluminum has a density of 2.70 g/mL and zinc has a density of 7.13 g/ml. Therefore 10.0 g of zinc combined with 10.0 g of aluminum has a total volume of _______ L. (Be sure to give the total volume in liters, not milliliters).

5.11

.00511

5110

98.3

10 g x 1 mL/2.70 g + 10 g x 1 mL/7.13 mL = 5.106 mL = .005106 L; 3 SF so .00511 L

Explanation

10 g x 1 mL/2.70 g + 10 g x 1 mL/7.13 mL = 5.106 mL = .005106 L; 3 SF so .00511 L

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15.

begin mathsize 12px style Given space that space 6.02 space straight x space 10 to the power of 23 space hydrogen space atoms space have space straight a space mass space of space 1.007 space grams space What space is space the space mass space of space straight a space hydrogen space atom ? end style

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Explanation

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16. A balloon of helium with a volume of 22.40 milliliters contains 4.03 milligrams of helium. Based on this data, what is the density of helium? Please be sure to include your units using grams per millliter

0.170 grams per milliliter

0.180 grams per milliliter

180. grams per milliliter

The density of a substance is calculated by dividing the mass of the substance by its volume. In this case, the mass of the helium is given as 4.03 milligrams and the volume is given as 22.40 milliliters. To convert milligrams to grams, we divide by 1000. So, the mass of the helium is 0.00403 grams. Therefore, the density of helium is 0.00403 grams divided by 22.40 milliliters, which equals 0.180 grams per milliliter.

Explanation

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17. What is the length of the object below, assuming the ruler is based on centimeters? Be sure to answer with the correct level of precision.

1.3 cm

1.4 cm

1.35 cm

1.347 cm

The length of the object below is 1.35 cm because it is the only option that matches the given ruler precision of centimeters. The other options have either more or less precision than the given ruler.

Explanation

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18. If I travel at 60.2 miles per hour for 17.13 hours, then double my speed to 120.4 miles per hour for 4.00 hours, how many kilometers will I have traveled? (1609 meters = 1 mile)suggestion: calculate each distance in miles, combine them, then convert to meters. Use scrap paper and do it out.