Physics Exam Quiz: Test Your Basics!

1. All electrically conductive parts of the vehicle (e.g., parts made of steel, (anodized) aluminum, any other metal parts, etc.) which are within 100mm of any tractive system or GLV component, and any driver harness mounting points, seat mounting points, and driver controls must have a resistance to GLV system ground below.

300 mOhms (measured with a current of 1A)

300 mOhms (measured with a current of 0.5A)

5 ohm

All electrically conductive parts of the vehicle that are within a certain proximity to certain components must have a resistance to the GLV system ground below a certain threshold. The correct answer is 300 mOhms (measured with a current of 1A), which means that the resistance of these parts should be below 300 mOhms when measured with a current of 1A. This ensures that the vehicle's electrical system functions properly and safely.

Explanation

All electrically conductive parts of the vehicle that are within a certain proximity to certain components must have a resistance to the GLV system ground below a certain threshold. The correct answer is 300 mOhms (measured with a current of 1A), which means that the resistance of these parts should be below 300 mOhms when measured with a current of 1A. This ensures that the vehicle's electrical system functions properly and safely.

2. What is the peak voltage value of a single-phase sinusoidal 600V AC RMS signal?

832.74

848.53

858.23

838.91

The peak voltage value of a single-phase sinusoidal AC signal can be calculated by multiplying the RMS value by the square root of 2. In this case, the RMS value is 600V, so the peak voltage value would be 600V * √2 = 848.53V.

Explanation

The peak voltage value of a single-phase sinusoidal AC signal can be calculated by multiplying the RMS value by the square root of 2. In this case, the RMS value is 600V, so the peak voltage value would be 600V * √2 = 848.53V.

3. The distance between a topmost point on the front hoop(on the centreline of the tube) and the point where the front hoop bracing is connected to the front hoop is 49 mm. When a driver has normally seated, the distance between the line drawn from the top of the main hoop to the front hoop's top is 75 mm. The main hoop is inclined 0.0827 radians in the direction of the driving wheels and the main hoop bracing is inclined 0.6454 radians in the opposite direction of the driving wheels. Will this pass TI?

Yes

No

Maybe

Can't say

The question provides information about the distances and inclinations of the main hoop and front hoop in a vehicle. However, it does not provide any specific criteria or regulations for passing TI (Technical Inspection). Therefore, without additional information about the TI requirements, it is uncertain whether the given measurements and inclinations would pass TI. Hence, the answer is "Maybe".

Explanation

The question provides information about the distances and inclinations of the main hoop and front hoop in a vehicle. However, it does not provide any specific criteria or regulations for passing TI (Technical Inspection). Therefore, without additional information about the TI requirements, it is uncertain whether the given measurements and inclinations would pass TI. Hence, the answer is "Maybe".

4. Which element is not allowed to be contained in AIRs?

Phosphorous

Silicon

Iron

Mercury

Helium

Mercury is not allowed to be contained in AIRs because it is a toxic and volatile element. It can easily vaporize and become a hazardous gas at room temperature. Therefore, it is not safe to include mercury in the composition of AIRs.

Explanation

Mercury is not allowed to be contained in AIRs because it is a toxic and volatile element. It can easily vaporize and become a hazardous gas at room temperature. Therefore, it is not safe to include mercury in the composition of AIRs.

5. Which one of the following is the right fit type for the following 1- Ball bearing into a bore 2- Tire on the rim 3- Lugnuts on studs

1- Interference, 2-Loose, 3-Loose

1-Loose, 2-Interference, 3-Loose

1-Interference, 2-Interference, 3-Loose

1-Interference, 2-Interference, 3-Line on line

1-Loose, 2-Loose, 3-Line on line

When fitting a ball bearing into a bore, an interference fit is required to ensure a tight and secure connection. Similarly, when fitting a tire on a rim, an interference fit is necessary to prevent the tire from slipping off. However, when fitting lugnuts on studs, a line on line fit is preferred as it allows for easy installation and removal of the lugnuts without compromising the stability of the connection.

Explanation

When fitting a ball bearing into a bore, an interference fit is required to ensure a tight and secure connection. Similarly, when fitting a tire on a rim, an interference fit is necessary to prevent the tire from slipping off. However, when fitting lugnuts on studs, a line on line fit is preferred as it allows for easy installation and removal of the lugnuts without compromising the stability of the connection.

6. Two team members are presenting the BPP. After the introduction, team member A forgets all his text. Luckily, team member B can finish the presentation by herself. After the presentation is completed, the competition judges have a few questions for the team members. Which statement is correct?

None of the team members may answer questions from the judges

Both team members may answer questions from the judges.

Only team members B may answer questions from the judges

Only team members A may answer a question from the judges

Both team members may answer questions from the judges because even though team member A forgot their text, team member B was able to finish the presentation by herself. This implies that both team members are knowledgeable about the topic and capable of answering questions.

Explanation

Both team members may answer questions from the judges because even though team member A forgot their text, team member B was able to finish the presentation by herself. This implies that both team members are knowledgeable about the topic and capable of answering questions.

7. In the skidpad event, team Rosberg runs the 20s, 18s, 19s, 21s in this particular order. The team during the last run forgot to stage the car. The 3rd run had 3 doo, the 2nd run had 1 doo and the 1st run had 2 doo. What are the points the team will get, the fastest time on track is 17.5 seconds? Note: Just input the numerical value of the answer. Ex: If its 9538256661 seconds, just input 9538256661

not-available-via-ai

Explanation

not-available-via-ai

Submit

8. A team has decided to use a metal matrix compound of mild steel in the vehicle. Does this classify as an alternative material?

Yes

No

Maybe

Can't say

Using a metal matrix compound of mild steel in the vehicle can be classified as an alternative material because it is different from the traditional material typically used in vehicles, which is usually just mild steel. The team's decision to use this alternative material suggests that they are exploring different options to enhance the vehicle's performance or characteristics.

Explanation

Using a metal matrix compound of mild steel in the vehicle can be classified as an alternative material because it is different from the traditional material typically used in vehicles, which is usually just mild steel. The team's decision to use this alternative material suggests that they are exploring different options to enhance the vehicle's performance or characteristics.

9. For business plan presentation a team was judged by a panel of three judges. the judge 1 awards 5,6,12,6,7,7,8,7 and 4 score for BPES, Novelty ,content,Finances,deep dive topic,demonstration,delivery,questions and general impression. The 2nd judge awards 7,7,13,6,5,7,9,7 and 5 score for BPES, Novelty ,content,Finances,deep dive topic,demonstration,delivery,questions and general impression while the 3rd judge awards 4,7,9,6,9,7,5,7 and 4 score for BPES, Novelty ,content,Finances,deep dive topic,demonstration,delivery,questions and general impression. If the highest score of the team participating in the finals is 72, what will be the score of the team in BPP?

60.28

58.98

57.68

62.76

Cannot be determined

not-available-via-ai

Explanation

not-available-via-ai

10. An extra member is added from the main hoop to the front hoop (above the side impact structure). Percy is the shortest driver of the team. The shaded part depicts the bodywork. Will this chassis pass TI?

Yes

No

Maybe

Can't say

The addition of an extra member from the main hoop to the front hoop above the side impact structure suggests that the chassis has been modified. However, the fact that Percy is the shortest driver of the team implies that the modification may not be suitable for all drivers. Therefore, it is likely that the chassis will not pass TI (Technical Inspection) as it may not meet the necessary safety requirements for all drivers.

Explanation

The addition of an extra member from the main hoop to the front hoop above the side impact structure suggests that the chassis has been modified. However, the fact that Percy is the shortest driver of the team implies that the modification may not be suitable for all drivers. Therefore, it is likely that the chassis will not pass TI (Technical Inspection) as it may not meet the necessary safety requirements for all drivers.

11. Opening the shutdown circuit must occur if the implausibility is persistent for more than ___ ms.

If the implausibility persists for more than 500 ms, it is necessary to open the shutdown circuit. This means that if the issue or problem continues for longer than half a second, the shutdown circuit needs to be activated to prevent further damage or malfunction. This is likely a safety mechanism to protect the system from any potential harm that may occur if the implausibility persists for an extended period of time.

Explanation

If the implausibility persists for more than 500 ms, it is necessary to open the shutdown circuit. This means that if the issue or problem continues for longer than half a second, the shutdown circuit needs to be activated to prevent further damage or malfunction. This is likely a safety mechanism to protect the system from any potential harm that may occur if the implausibility persists for an extended period of time.

Submit

12. For the front hoop bracings, one of the bracings is a pipe of diameter 29.27mm and the other is a tube of diameter 30.94mm. They have the same specifications. Are they in compliance with the rules?

Yes

No

Maybe

Can't say

The question provides information about the front hoop bracings, stating that one is a pipe with a diameter of 29.27mm and the other is a tube with a diameter of 30.94mm. It also mentions that they have the same specifications. However, it does not specify what the rules or compliance requirements are. Therefore, without knowing the specific rules or criteria that need to be met, it is impossible to determine whether the bracings are in compliance or not.

Explanation

The question provides information about the front hoop bracings, stating that one is a pipe with a diameter of 29.27mm and the other is a tube with a diameter of 30.94mm. It also mentions that they have the same specifications. However, it does not specify what the rules or compliance requirements are. Therefore, without knowing the specific rules or criteria that need to be met, it is impossible to determine whether the bracings are in compliance or not.

13. A steady DC current is flowing through a coil with an inductance of 248mH. The stored energy in the magnetic field is 431J. By how much does the current have to be increased, if the stored energy should be increased by 300J? All options given in Amps

17.824

76.78

17.82

17.822

76.77

76.87

The stored energy in a magnetic field is given by the formula E = 1/2 * L * I^2, where E is the energy, L is the inductance, and I is the current. In this case, the initial energy is 431J and the initial current is unknown. We can rearrange the formula to solve for the initial current: I = sqrt(2E/L). Plugging in the values, we get I = sqrt(2*431J/248mH). Solving this equation gives us the initial current as approximately 17.824 Amps. To increase the stored energy by 300J, we need to find the new current. Plugging in the new energy value of 731J into the formula, we get I = sqrt(2*731J/248mH), which gives us the new current as approximately 22.076 Amps. Therefore, the current needs to be increased by approximately 4.252 Amps.

Explanation

The stored energy in a magnetic field is given by the formula E = 1/2 * L * I^2, where E is the energy, L is the inductance, and I is the current. In this case, the initial energy is 431J and the initial current is unknown. We can rearrange the formula to solve for the initial current: I = sqrt(2E/L). Plugging in the values, we get I = sqrt(2*431J/248mH). Solving this equation gives us the initial current as approximately 17.824 Amps. To increase the stored energy by 300J, we need to find the new current. Plugging in the new energy value of 731J into the formula, we get I = sqrt(2*731J/248mH), which gives us the new current as approximately 22.076 Amps. Therefore, the current needs to be increased by approximately 4.252 Amps.

14. There are two aircraft made in the year 1920 the propeller of aircraft 1 is rotating in an anti-clockwise direction while the propeller of the other rotates in a clockwise direction. The aircraft takes right turn to what will happen to aircraft 1 and 2.

1 and 2 both will move up

1 will move up while 2 will move down

1 will move down while 2 will move up

1 and 2 both will move down

Since the propeller of aircraft 1 is rotating in an anti-clockwise direction, it will create a force that pushes the aircraft upwards. On the other hand, the propeller of aircraft 2 is rotating in a clockwise direction, which will create a force that pushes the aircraft downwards. Therefore, aircraft 1 will move up while aircraft 2 will move down.

Explanation

Since the propeller of aircraft 1 is rotating in an anti-clockwise direction, it will create a force that pushes the aircraft upwards. On the other hand, the propeller of aircraft 2 is rotating in a clockwise direction, which will create a force that pushes the aircraft downwards. Therefore, aircraft 1 will move up while aircraft 2 will move down.

15. A solid sphere of mass m and radius r is resting on a horizontal surface.A horizontal impulse of E is applied at a height h from the ground. Find the value of h so that sphere performs pure rolling motion after it has been struck.

To achieve pure rolling motion, the sphere must have both translational and rotational motion simultaneously. This means that the impulse applied at height h must provide enough torque to overcome the initial angular momentum of the sphere. The angular momentum depends on the moment of inertia, which for a solid sphere is (2/5)mr^2, and the angular velocity. Since the sphere is at rest initially, the angular velocity is zero. By applying the impulse at a height of 7r/5, the torque produced will be sufficient to set the sphere into pure rolling motion, with no slipping.

Explanation

To achieve pure rolling motion, the sphere must have both translational and rotational motion simultaneously. This means that the impulse applied at height h must provide enough torque to overcome the initial angular momentum of the sphere. The angular momentum depends on the moment of inertia, which for a solid sphere is (2/5)mr^2, and the angular velocity. Since the sphere is at rest initially, the angular velocity is zero. By applying the impulse at a height of 7r/5, the torque produced will be sufficient to set the sphere into pure rolling motion, with no slipping.

Submit