JEE Main: Units, Dimensions And Error Analysis! Quiz
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Suppose refractive index is given as, where P and Q are constants and v is the speed of light and is the wavelength, then dimensions of Q are the same as that of
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Wavelength
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Volume
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Force
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Acceleration
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This JEE Main quiz focuses on Units, Dimensions, and Error Analysis, assessing knowledge of physical constants, wave equations, and dimensions in various physical contexts. It is designed for students preparing for engineering entrance exams, enhancing their understanding of fundamental physics concepts.
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- 2.
The Equation of stationary wave is then which of the following is false:
Correct Answer
A.Explanation
All the options must be checked to find out the wrong statement. First option is correct as and are dimensionless quantities. In second option x has the same units as that of i. e. meter. In third option has dimension [L-1T] which is the inverse of v [LT-1]. Now only fourth option is left which is incorrect as has the dimension [T-1], whereas has the dimension [L].
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- 3.
In the Equation the dimensional formula for will be
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MLT
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![JEE Main: Units, Dimensions And Error Analysis! Quiz - Quiz]()
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![JEE Main: Units, Dimensions And Error Analysis! Quiz - Quiz]()
Correct Answer
A.Explanation
The trigonometrical ratios are the dimensionless quantities so for the equation the term will be dimensionlessRate this question:
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- 4.
For any spring of spring constant k, the frequency of vibrations ‘f’ is given by the formula f = Xmakb, where X is a dimensionless constant. The value of ‘a’ and ‘b’ are, respectively:
Correct Answer
A.Explanation
f = Xmakb dimension of f = [T-1], Dimensions of m = [M], Dimensions of spring constant ‘k’ = [MT-2] and X is a dimensionless constant.[T-1] = [M]a [MT-2] b; [T-1] = [M]a+b[T]-2b, now comparing the powers on both sides,a+1 = 0; -2b = -1 so b=1/2 and a= -1/2.Rate this question:
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- 5.
What will be the dimensions of the mass, if C (velocity of light), g (acceleration due to gravity), and P (atmospheric pressure) are considered as the fundamental Quantities in the MKS system?
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C/g
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Pg
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PCg
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C/P
Correct Answer
A. C/PExplanation
Dimensional formula of velocity of light (C) = [LT-1]
Dimensional formula of acceleration due to gravity (g) = [LT-2]
Dimensional formula of atmospheric pressure (P) = [ml-1T-2],
Now let M = CagbPc; [M] = [LT-1] a [LT-2] b [ml-1T-2] c,
[M1] = [La+b-c] [T-a-2b-2c] [M c];
a+b-c = 0; -a-2b-2c = 0; c = 1; On solving the equations we get, a = 0, b = 1, c = 1,
so, M = Pg.
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- 6.
In Searle’s experiment to find Young’s modulus, the diameter of the wire is measured as d=0.050 cm, and the length of the wire is L = 100 cm. When a weight of 10.0 kg is placed, the extension in the wire was found to be 0.200 cm. The maximum permissible error (percentage) in Young’s modulus is:
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6.5
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4.3
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5.8
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4.9
Correct Answer
A. 4.9Explanation
In Searle’s Experiment, Young’s Modulus Y = where F is force, A is area, L is the original length and is the change in length due to force F. Here F = Mg and A = 4πd2 so Y = so the relative error in Y;Rate this question:
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- 7.
A physical Quantity V depends on time as V = V0 (1+ e), where is a constant and t is time, then which of the following is true:
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α is a dimensionless constant
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Has dimensions of T2
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α has dimensions of V
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Has dimensions of LT-2
Correct Answer
A. Has dimensions of T2Explanation
In the expression V = V0 (1+ ), the term has to be a dimensionless term as it is in the power of an exponential function so for being the dimensionless the dimensions of should be equal to the inverse of the dimensions of T-2 i.e. equal to the dimensions of T2.Rate this question:
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- 8.
The banking of roads is explained with the formula here v is the speed of the object, r is the radius of the curve formed and g is the gravitational acceleration. Choose the correct statement about this relation.
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Above expression may be dimensionally correct but numerically it is wrong
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Above expression is dimensionally as well as numerically correct
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Above expression is dimensionally as well as numerically wrong
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Above expression is dimensionally incorrect but numerically it is correct
Correct Answer
A. Above expression is dimensionally as well as numerically correctExplanation
The formula is tan dimensionally correct as both the sides are dimensionless. L.H.S. i.e. is a dimensionless trigonometrical ratio and is also dimensionless as the dimension of v2 and rg are same. Moreover this formula is proved with the help of various theorems and principals so it is also numerically correct.Rate this question:
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- 9.
The product of permittivity of free space and the permeability of free space has the dimensions equal to the:
Correct Answer
A.Explanation
Dimension of permittivity of free space ( ) = [M-1L-3T4A2]Dimension of permeability of free space ( ) = [MLT-2A-2]Product of and = [M-1L-3T4A2] [MLT-2A-2] = [L-2T2]Rate this question:
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- 10.
What will be the dimensions a b of according to the relation where E = is Energy, x is displacement and t is time?
Correct Answer
A.Explanation
In the equation E = the dimension of r.h.s. should be equal to the dimension of l.h.s. both sides must have the dimensions equal to the [ML2T-2]. Now as ‘a’ is added to t2 so the dimensions of ‘a’ will be equal to the dimensions of [T2]. For the dimension of ‘b’ [ML2T-2] = so from here b = [M-1L-3T4], now a b = [T2] [M-1L-3T4] = [M-1L-3T6].
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Quiz Review Timeline (Updated): Mar 19, 2023 +
Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.
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Current Version
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Mar 19, 2023Quiz Edited by
ProProfs Editorial Team -
Jul 31, 2014Quiz Created by
Tanmay Shankar
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