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Kinematics is a branch of classical mechanics that describes the motion of points, bodies (objects), and systems of bodies (groups of objects) without considering the mass of each of the forces that caused the motion. It sounds confusing, right? Well, relax and take the quiz to test your knowledge of kinematics.
Questions and Answers
1.
Suppose a car is moving in a straight line and steadily increases its speed. It moves from 20 m/s to 30 m/s in the first second and from 30 m/s to 40 m/s in the second second. What is the car's acceleration?
A.
10 m/s/s
B.
30 m/s/s
C.
35 m/s/s
D.
40 m/s/s
Correct Answer A. 10 m/s/s
Explanation The car's acceleration can be calculated by finding the change in velocity over time. In this case, the car's velocity increases from 20 m/s to 30 m/s in the first second, resulting in a change in velocity of 10 m/s. The acceleration is then calculated by dividing the change in velocity by the time taken, which is 10 m/s divided by 1 second, resulting in an acceleration of 10 m/s/s.
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2.
An object travels 12 metres in the first second of travel, 12 metres again during the second second of travel and 12 metres again during the third second. Its acceleration is
A.
0 m/s/s
B.
12 m/s/s/
C.
4 m/s/s
D.
None of the above
Correct Answer A. 0 m/s/s
Explanation The object travels the same distance (12 meters) in each second of travel, indicating a constant velocity. Since acceleration is the rate of change of velocity, and the velocity is not changing, the acceleration is 0 m/s/s.
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3.
If an object has a negative velocity, that means it is
A.
Slowing down
B.
Going back towards
C.
Speeding up while going forward
D.
All of these
Correct Answer B. Going back towards
Explanation An object with a negative velocity indicates that it is moving in the opposite direction of its initial motion. Therefore, it is going back towards its starting point or going back towards the direction it came from.
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4.
A car accelerates at 3 m/s/s, assuming it starts from rest, how much time does it take to accelerate to speed of 45 m/s?
A.
135 seconds
B.
90 seconds
C.
15 seconds
D.
None of the above
Correct Answer C. 15 seconds
Explanation The car accelerates at a rate of 3 m/s/s. This means that its speed increases by 3 m/s every second. If the car starts from rest, it will take 5 seconds to reach a speed of 15 m/s (3 m/s * 5 s). Since we want to know how long it takes to reach a speed of 45 m/s, which is three times the speed of 15 m/s, it will take three times the time it took to reach 15 m/s. Therefore, it will take 15 seconds (5 s * 3) to accelerate to a speed of 45 m/s.
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5.
A man travels from his home 50m east to the bakery then 20 m south to the butchers, he retraces his steps back to the bakery and stops fora coffee.What is the distance he has traveled and what is his displacement?
A.
90m, 70, south
B.
90m east, 0
C.
70m, 20m north
D.
90m, 50m east
Correct Answer D. 90m, 50m east
Explanation The man initially travels 50m east to the bakery and then 20m south to the butchers. When he retraces his steps back to the bakery, he covers the same distance, so the total distance he has traveled is 50m + 20m + 50m = 120m. However, his displacement is the straight-line distance from his starting point to his ending point, which is 50m east. Therefore, his displacement is 50m east.
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6.
Which of the below shows only vector quantities?
A.
Distance and displacement
B.
Displacement, velocity and acceleration
C.
Speed and velocity
D.
Speed, velocity and acceleration
Correct Answer B. Displacement, velocity and acceleration
Explanation The answer is displacement, velocity, and acceleration because these are all vector quantities. A vector quantity has both magnitude and direction. Displacement is the change in position of an object in a specific direction. Velocity is the rate at which an object changes its position in a specific direction. Acceleration is the rate at which an object changes its velocity in a specific direction. On the other hand, distance, speed, and acceleration are scalar quantities as they only have magnitude and no specific direction.
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7.
The school bus speeds up from 20 m/s to 36 m/s in 4 seconds. What distance does the bus cover in this time frame?
A.
80 m
B.
112 m
C.
64 m
D.
144 m
Correct Answer B. 112 m
Explanation The distance covered by the bus can be calculated using the formula distance = average speed x time. In this case, the average speed can be found by taking the average of the initial and final speeds, which is (20 m/s + 36 m/s) / 2 = 28 m/s. The time is given as 4 seconds. Plugging these values into the formula, we get distance = 28 m/s x 4 s = 112 m. Therefore, the bus covers a distance of 112 m in this time frame.
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8.
A brick and a feather are dropped at the same time, from rest in a vacuum (a place where there is no air). The feather will reach the ground
A.
Sooner than the brick
B.
At the same time as the brick
C.
Later then the brick
D.
It depends on air resistance
Correct Answer B. At the same time as the brick
Explanation In a vacuum, there is no air resistance to slow down the objects. Therefore, both the brick and the feather will fall at the same rate and reach the ground at the same time. The force of gravity acting on both objects is the same, causing them to accelerate at the same rate.
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9.
The slope of a velocity-time graph tells you
A.
Maximum velocity
B.
Acceleration
C.
Distance traveled
D.
Where you are
Correct Answer B. Acceleration
Explanation The slope of a velocity-time graph represents the rate of change of velocity over time. Acceleration is defined as the rate of change of velocity, so the slope of a velocity-time graph gives us information about acceleration. Therefore, the correct answer is acceleration.
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10.
The area under a velocity - time graph represents the
A.
Acceleration
B.
Distance traveled
C.
Velocity
D.
Time
Correct Answer B. Distance traveled
Explanation The area under a velocity-time graph represents the distance traveled. This is because the area under the graph represents the displacement of an object, which is the total change in position. Therefore, by calculating the area under the graph, we can determine the distance traveled by the object.
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11.
What does the position - time graph show from 0 - 15 seconds?
A.
A person accelerates from rest to 60 m/s in 10 seconds and then travels at a constant velocity for 5 seconds.
B.
A person climbs up a hill to 60 metres then sits on top of the hill for 5 seconds.
C.
A person walks with a constant velocity for 60 metres in a positive direction in 10 seconds then remains still for 5 seonds.
Correct Answer C. A person walks with a constant velocity for 60 metres in a positive direction in 10 seconds then remains still for 5 seonds.
Explanation The position-time graph shows that the person walks with a constant velocity for 60 meters in a positive direction in 10 seconds, as indicated by the straight line with a positive slope. After reaching the 60-meter mark, the person remains still for 5 seconds, which is represented by the flat line on the graph. This matches the description given in the answer.
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12.
After 15 seconds select from below which one best describes this position-time graph
A.
The person turns around and takes 25 seconds to walk 40 m past their original postion before turning around again and taking 15 seconds to return back to where they first started
B.
The person starts to slow down until they reach -40 m/s then start to speed up again.
C.
The person climbs down the other side of the hill, it takes them 25 seconds and then they start to climb the next hill
Correct Answer A. The person turns around and takes 25 seconds to walk 40 m past their original postion before turning around again and taking 15 seconds to return back to where they first started
Explanation The correct answer describes a position-time graph where the person starts at the origin, moves forward for 25 seconds to a position 40 m away, then turns around and moves back to the origin in 15 seconds. This is represented by a line sloping upwards for the first 25 seconds, then sloping downwards for the next 15 seconds, forming a V-shaped graph. The person does not reach a speed of -40 m/s or climb down a hill, as stated in the other options.
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13.
Which graph shows an object at rest?
A.
Graph A
B.
Graph B
C.
Graph C
D.
Graph d
Correct Answer C. Graph C
Explanation Graph C shows an object at rest because the position of the object remains constant over time. The graph shows a horizontal line, indicating that there is no change in the object's position. This suggests that the object is not moving and is therefore at rest. Graphs A, B, and D all show changes in position over time, indicating that the object is in motion rather than at rest.
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14.
Which graph shows constant velocity in a positive direction?
A.
Graph A
B.
Graph B
C.
Graph C
D.
Graph D
Correct Answer D. Graph D
Explanation Graph D shows constant velocity in a positive direction because the line on the graph is straight and has a positive slope. A straight line indicates that the object is moving at a constant speed, while the positive slope indicates that the object is moving in the positive direction. Therefore, Graph D represents constant velocity in a positive direction.
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15.
The symbol used to represent the acceleration due to gravity is
Correct Answer g
Explanation The symbol "g" is used to represent the acceleration due to gravity. This symbol is derived from the word "gravity" and is commonly used in physics equations to denote the acceleration experienced by objects in free fall near the surface of the Earth. The value of "g" is approximately 9.8 m/s² and is a constant for a given location on Earth.
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16.
Assuming there is no air resistance, as an object falls freely, its
A.
Velocity increases
B.
Acceleration increases
C.
Both A & B
D.
None of the above
Correct Answer A. Velocity increases
Explanation As an object falls freely without any air resistance, its velocity increases. This is because gravity pulls the object downward, causing it to accelerate. As time passes, the object's speed and velocity increase due to the constant acceleration. Therefore, the correct answer is that the velocity increases.
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17.
A rock is thrown over a cliff, each second the rock falls
A.
A larger distance than the second before it
B.
With the same average speed
C.
With the same instantaneous speed
D.
The same distance as the second before
Correct Answer A. A larger distance than the second before it
Explanation The correct answer is "a larger distance than the second before it". This is because when a rock is thrown over a cliff, it accelerates due to the force of gravity. As a result, its speed increases with time, causing it to cover a larger distance in each subsequent second compared to the previous second. Therefore, the rock falls a larger distance with each passing second.
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18.
Ten seconds after starting from rest, a free falling object will have a velocity of about
A.
10 m/s
B.
50 m/s
C.
100 m/s
D.
500 m/s
Correct Answer C. 100 m/s
Explanation After ten seconds of free fall, an object will have a velocity of approximately 100 m/s. This is because the acceleration due to gravity is constant, and the object's velocity will increase by 9.8 m/s every second. Therefore, after ten seconds, the object will have accelerated to a velocity of approximately 98 m/s. Considering rounding and other factors, the velocity is estimated to be around 100 m/s.
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19.
Convert 80 km/h into m/s
A.
0.22 m/s
B.
22.22 m/s
C.
222.22 m/s
D.
0.0022 m/s
Correct Answer B. 22.22 m/s
Explanation To convert km/h to m/s, we need to multiply the given value by 1000/3600, since there are 1000 meters in a kilometer and 3600 seconds in an hour. Therefore, 80 km/h multiplied by 1000/3600 equals 22.22 m/s.
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20.
An abseiler needs to find how high a cliff is. He drops a small rock over the side, it takes 6 seconds before it hits the ground. Using 9.8 m/s/s for gravity, how high is the cliff?
Correct Answer 176.4m 176.4 m 176m 176 m
Explanation The abseiler can determine the height of the cliff using the equation of motion for free fall. The equation is given by h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity (9.8 m/s^2), and t is the time taken for the rock to hit the ground (6 seconds). Plugging in the values, we get h = (1/2)(9.8)(6^2) = 176.4 meters. Therefore, the height of the cliff is 176.4 meters.
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