Kinematics Of A Particle (1)
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Lets play Kaun Banega Future Engineer Ya Doctor. . . . .
Kinematics or 1-d motions is an important syllabus for IIT-JEE.
- 1.
A balloon starts rising from rest from the ground with an acceleration of 1.25 m/s2. After 8s, a stone is released from the balloon. The stone will :
- A.
Cover a distance of 40 m
- B.
Have a displacement of 50 m
- C.
Reach the ground in 4s
- D.
Begin to move down after being released
Correct Answer
C. Reach the ground in 4sExplanation
The stone will reach the ground in 4 seconds because the acceleration due to gravity is constant and independent of the initial velocity of the stone. Therefore, the stone will fall with an acceleration of 9.8 m/s^2. Since the stone is released after 8 seconds, it will fall for an additional 4 seconds before reaching the ground.Rate this question:
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- 2.
The figure shows, the displacement-time graph of a particle moving on the X-axis.
- A.
The particle is continuously going in positive x direction
- B.
The particle is at rest
- C.
The velocity increases up to a time , and then becomes constant
- D.
The particle moves at a constant velocity up to a time , and then stops
Correct Answer
C. The velocity increases up to a time , and then becomes constantExplanation
For time t < t0 velocity of particle = constant positive value
for time t > t0 velocity = slope of graph = 0Rate this question:
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- 3.
A person standing near the edge of the top of building throws two balls A and B. The ball A is thrown vertically downward with the same speed. The ball A hits the ground with a speed and the ball b hits the ground with a speed. We have
- A.
VA>VB
- B.
VA
- C.
VA=VB
- D.
The relation between VA and VB depends upon the height of the building
Correct Answer
C. VA=VBExplanation
In both the cases use 3rd equation of motion.Rate this question:
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- 4.
The displace of a particle moving in a straight line is given by . Here s is in m and t is in seconds. The distance covered by the particle is first 5 seconds is :
- A.
10 m
- B.
26 m
- C.
24 m
- D.
16 m
Correct Answer
B. 26 mExplanation
We are required to find the distance and not the displacement.
o, total distance = |displacement from t = 0 to 3s| + |displacement from t = 3s to 5s|
=
= (Particle turns around at t = 3s)Rate this question:
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- 5.
A stone is released from a elevator going up with an acceleration a. The acceleration of the stone after the released is :
- A.
A upward
- B.
(g - a) upward
- C.
(g - a) upward
- D.
g downward
Correct Answer
D. g downwardExplanation
After the stone released, only a downward force of mg acts on to it. So its acceleration is g downwardsRate this question:
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- 6.
6 particles A, B, C, D, E, F are located at the vertices of a regular hexagon of side d. All particles move with the same speed v such that the velocity of A is directed towards B, that of B towards C and so on (F is direction towards A). After what time will the particle meet ?
- A.
2d/v
- B.
3d/v
- C.
2d/3v
- D.
D/v
Correct Answer
A. 2d/vExplanation
Sorry, no explanation at this point of time...Rate this question:
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- 7.
Acceleration-velocity graph of a particle moving in a straight line is as shown in the figure. The slope of velocity-displacement graph is
- A.
Increases linearly
- B.
Decreases linearly
- C.
is constant
- D.
increases parabolically
Correct Answer
C. is constantExplanation
a=kv
vdv/dx=kv
dv/dx=k
thus, slop =k, which is constantRate this question:
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- 8.
Particle A and B move as shown in figure. The minimum separation between A and B is :
- A.
10 m
- B.
7.92 m
- C.
0 m
- D.
8 m
Correct Answer
B. 7.92 mExplanation
We will analyze this relative to A.
A seen from A
Distance of B from A
Minimum value of =
Since D for
So, t and minimum value is 7.92 mRate this question:
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- 9.
An object may have
- A.
Varying speed without having varying velocity
- B.
Varying velocity without having varying speed
- C.
Nonzero acceleration without having varying velocity
- D.
Nonzero acceleration without varying speed
Correct Answer(s)
B. Varying velocity without having varying speed
D. Nonzero acceleration without varying speedExplanation
(A) Not possible So wrong
(B) Uniform circular motion So wrong
(C) Not possible So wrong
(D) Possiblein uniform circular motion. CorrectRate this question:
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- 10.
Mark the correct statements :
- A.
The magnitude of the velocity of a particle is equal to its speed
- B.
The magnitude of average velocity in an interval is equal to its average speed in that interval
- C.
It is possible to have a situation in which the speed of a particle is never zero but the average speed is not zero
- D.
It is possible to have a situation in which the speed of the particle is never zero but the average speed is interval is zero
Correct Answer
A. The magnitude of the velocity of a particle is equal to its speedExplanation
(A) is correct
(B) Avg. velocity and Avg speed
It is possible distance and displacement are not equal.
So Wrong
(C) As speed is zero always so distance traveled is 0 which means average speed must be 0
So Wrong
(D) As speed is non-zeroParticle covers some distance so average speed cannot be 0.
So WrongRate this question:
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Current Version
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Mar 13, 2024Quiz Edited by
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Aug 27, 2011Quiz Created by
Adityatech
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