Genetics Problem Test 2
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DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. What are the phenotypes of rabbits that have this genotype: [Ggbb]? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
About This Quiz
Welcome to the electronic biology frontier classroom of the 21st century. The fact that living things inherit traits from their parents has been used since prehistoric times to improve crop plants and animals through selective breeding. The genetic problems found in this test are found on Mitchell's Cosmic Adventure science web site. Click on horizontal tab BIOLOGY and See moreselect LECTURE NOTES. Search for genetic topics; Genetic Practice Problems, Genetic Problem Solver, and WORKSHEETS.
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- 2.
DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. A male rabbit with the genotype [GgBb] is mated with a female rabbit with the genotype [GgBb]. Set up a dihybrid punnett square to determine the phenotypic & genotypic ratios of the F1 offspring. (Hint: please use a number from 0 to 16) How many out of 16 will have white hair and black eyes? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Explanation
The given question asks for the number of offspring out of 16 that will have white hair and black eyes. In rabbits, gray hair is dominant to white hair, so the genotype [Gg] will result in gray hair. Black eyes are dominant to red eyes, so the genotype [Bb] will result in black eyes. Since both parents have the genotype [GgBb], there is a 25% chance for each offspring to inherit the recessive alleles [gg] and [bb], resulting in white hair and black eyes. Therefore, 3 out of 16 offspring are expected to have white hair and black eyes.Rate this question:
- 3.
DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. A male rabbit with the genotype [GgBb] is mated with a female rabbit with the genotype [GgBb]. Set up a dihybrid punnett square to determine the phenotypic & genotypic ratios of the F1 offspring. (Hint: please use a number from 0 to 16) How many out of 16 will have white hair and red eyes? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Explanation
In the given dihybrid cross, the male rabbit has the genotype GgBb and the female rabbit also has the genotype GgBb. Since gray hair (G) is dominant over white hair (g) and black eyes (B) is dominant over red eyes (b), the F1 offspring can have the genotypes GG, Gg, BB, Bb, Gb, or gg, bb. However, only one genotype (gg, bb) will result in white hair and red eyes. Therefore, out of the 16 possible genotypes, only 1 will have white hair and red eyes.Rate this question:
- 4.
DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. What are the phenotypes of rabbits that have this genotype: [ggbb]? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Explanation
The genotype [ggbb] indicates that both alleles for hair color and eye color are recessive. Therefore, the phenotypes of rabbits with this genotype would be white hair and red eyes.Rate this question:
- 5.
DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. What are the phenotypes of rabbits that have this genotype: [GgBb]? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Explanation
The genotype [GgBb] indicates that the rabbit has one dominant allele for gray hair (G) and one recessive allele for white hair (g), as well as one dominant allele for black eyes (B) and one recessive allele for red eyes (b). Since gray hair is dominant over white hair and black eyes are dominant over red eyes, the phenotypes of rabbits with this genotype would be gray hair and black eyes.Rate this question:
- 6.
DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. A male rabbit with the genotype [GGbb] is mated with a female rabbit with the genotype [ggBb]. Set up a dihybrid punnett square to determine the phenotypic & genotypic ratios of the F1 offspring. (Hint: please use a number from 0 to 16) How many out of 16 have gray hair and black eyes? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Explanation
In a dihybrid cross, the F1 offspring inherit one allele from each parent for each trait. In this case, the male rabbit has the genotype GGbb, meaning it will pass on the dominant gray hair allele (G) and the recessive red eyes allele (b). The female rabbit has the genotype ggBb, meaning it will pass on the recessive white hair allele (g) and the dominant black eyes allele (B). When these alleles combine in the F1 offspring, 8 out of 16 will have the genotype GgBb, which corresponds to gray hair and black eyes.Rate this question:
- 7.
DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. A male rabbit with the genotype [GGbb] is mated with a female rabbit with the genotype [ggBb]. Set up a dihybrid punnett square to determine the phenotypic & genotypic ratios of the F1 offspring. (Hint: please use a number from 0 to 16) How many out of 16 have gray hair and red eyes? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Explanation
In the dihybrid punnett square, the male rabbit's genotype is [GGbb] and the female rabbit's genotype is [ggBb]. When crossing these genotypes, the possible genotypes of the F1 offspring are [GgBb], [Ggbb], [ggBb], and [ggbb]. Among these possibilities, only [ggBb] has gray hair (recessive) and red eyes (recessive). Therefore, out of the 16 possible F1 offspring, 8 of them will have gray hair and red eyes.Rate this question:
- 8.
In tomatoes, height is an incomplete dominant trait. A tall tomatoe plant has (t), short plants (s) medium height is (ts). If a homozygous tall plant is cross pollinated with a homozygous short plant. What is the phenotype of all F1 individuals?
Explanation
When a homozygous tall plant (tt) is crossed with a homozygous short plant (ss), all the offspring in the F1 generation will be heterozygous (ts) for the height trait. This means that they will have a combination of both alleles for tall and short height. Since height is an incomplete dominant trait, the heterozygous individuals will exhibit a phenotype that is intermediate between tall and short, which is medium height. Therefore, the phenotype of all F1 individuals will be medium height.Rate this question:
- 9.
DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. A male rabbit with the genotype [GGbb] is mated with a female rabbit with the genotype [ggBb]. Set up a dihybrid punnett square to determine the phenotypic & genotypic ratios of the F1 offspring. (Hint: please use a number from 0 to 16) How many out of 16 have white hair and red eyes? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Explanation
The male rabbit has the genotype GGbb, which means it has gray hair and red eyes. The female rabbit has the genotype ggBb, which means it has white hair and black eyes. When these two rabbits are crossed, all of the F1 offspring will inherit the dominant traits from both parents. Therefore, none of the F1 offspring will have white hair and red eyes, resulting in a phenotypic ratio of 0 out of 16.Rate this question:
- 10.
DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. A male rabbit with the genotype [GGbb] is mated with a female rabbit with the genotype [ggBb]. Set up a dihybrid punnett square to determine the phenotypic & genotypic ratios of the F1 offspring. (Hint: please use a number from 0 to 16) How many out of 16 have white hair and black eyes? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Explanation
In this dihybrid cross, the male rabbit has the genotype GGbb, which means it has gray hair (G) and red eyes (bb). The female rabbit has the genotype ggBb, which means it has white hair (gg) and black eyes (B). When these two rabbits are crossed, the possible genotypes of the offspring are Ggbb, GgBb, ggbb, and ggBb. However, none of these genotypes have the combination of white hair and black eyes. Therefore, the answer is 0 out of 16.Rate this question:
- 11.
DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. A male rabbit with the genotype [GgBb] is mated with a female rabbit with the genotype [GgBb]. Set up a dihybrid punnett square to determine the phenotypic & genotypic ratios of the F1 offspring. (Hint: please use a number from 0 to 16) How many out of 16 will have gray hair and black eyes? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Explanation
The genotype of the male rabbit is GgBb, which means it carries one dominant allele for gray hair (G) and one recessive allele for white hair (g), and one dominant allele for black eyes (B) and one recessive allele for red eyes (b). The genotype of the female rabbit is also GgBb. When these two rabbits are crossed, there are 16 possible combinations of alleles in the offspring. Out of these 16, 9 combinations will have the dominant alleles for gray hair (G) and black eyes (B), resulting in the phenotype of gray hair and black eyes.Rate this question:
- 12.
DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. A male rabbit with the genotype [GgBb] is mated with a female rabbit with the genotype [GgBb]. Set up a dihybrid punnett square to determine the phenotypic & genotypic ratios of the F1 offspring. (Hint: please use a number from 0 to 16) How many out of 16 will have gray hair and red eyes? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Explanation
The correct answer is 3 because in the given dihybrid cross, the genotype of the male rabbit is [GgBb] and the genotype of the female rabbit is also [GgBb]. Since gray hair [G] is dominant to white hair [g] and black eyes [B] is dominant to red eyes [b], both rabbits have the dominant alleles for both traits. Therefore, all of the F1 offspring will have gray hair and black eyes.Rate this question:
- 13.
_____ genotypes are made of the same alleles.
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Alleles
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Dominant
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Recessive
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Heterozygous
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Homozygous
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Monohybrid
Correct Answer
A. HomozygousExplanation
Homozygous genotypes are made of the same alleles. This means that both alleles for a specific gene are identical. In other words, an individual with a homozygous genotype has two copies of the same allele, either dominant or recessive, for a particular trait. This is in contrast to heterozygous genotypes, where the individual has two different alleles for the same gene. Homozygosity can result in the expression of either the dominant or recessive trait, depending on the specific alleles present.Rate this question:
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- 14.
In dogs, there is a hereditary deafness caused by a recessive gene, “d." A kennel owner has a female deaf mother homozygous for this condition. She was mated with a normal (heterozygous) hearing male. The kennel owner can only sell normal hearing puppies. How many normal hearing puppies can he sell from a batch of 10?
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1
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2
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3
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4
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5
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6
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7
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8
Correct Answer
A. 5Explanation
The kennel owner can sell 5 normal hearing puppies from a batch of 10. This is because the female is homozygous for the deafness gene, meaning she only carries the recessive gene for deafness. The male is heterozygous, meaning he carries one copy of the deafness gene and one copy of the normal hearing gene. When they mate, there is a 50% chance that each puppy will inherit the deafness gene and a 50% chance they will inherit the normal hearing gene. Therefore, out of 10 puppies, approximately 5 are expected to be normal hearing and can be sold.Rate this question:
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- 15.
In humans, brown-eye color (B) is dominant over recessive blue-eye color (b). A homozygous brown-eye male marries a heterozygous brown-eye female. What is the phenotypic ratio of their children?
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2 - Brown-eye and 2 - blue-eye children
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3 - Brown-eye and 1 - blue-eye children
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4 - Brown-eye and 0 - blue-eye children
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0 - Brown-eye and 4 - blue-eye children
Correct Answer
A. 4 - Brown-eye and 0 - blue-eye childrenExplanation
The answer is 4 - Brown-eye and 0 - blue-eye children. This is because the homozygous brown-eye male can only pass on the dominant brown-eye allele (B) to his children, while the heterozygous brown-eye female can pass on either the dominant brown-eye allele (B) or the recessive blue-eye allele (b). However, since brown-eye color is dominant over blue-eye color, all the children will inherit at least one dominant brown-eye allele and will therefore have brown eyes. None of the children will inherit the recessive blue-eye allele, resulting in a phenotypic ratio of 4 - Brown-eye and 0 - blue-eye children.Rate this question:
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- 16.
A genetic cross of inbred snapdragons with red flowers with inbred snapdragons with white flowers resulted in F1-hybrid offspring that all had pink flowers. When the F1 plants were self-pollinated, the resulting F2-generation plants had a phenotypic ratio of 1 red: 2 pink: 1 white. What is the genotypic ratio of the F2-generation plants?
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0 : 1 : 0
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1 : 1 : 1
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1 : 2 : 1
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1 : 3 : 1
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2 : 4 : 2
Correct Answer
A. 1 : 2 : 1Explanation
The genotypic ratio of the F2-generation plants is 1:2:1 because the F1-hybrid offspring had pink flowers, which indicates that they were heterozygous for the flower color gene. When the F1 plants were self-pollinated, the possible genotypes of the F2-generation plants are RR, Rr, and rr. The ratio of these genotypes is 1:2:1, which corresponds to the genotypic ratio 1:2:1.Rate this question:
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- 17.
In tomatoes, height is an incomplete dominant trait. A medium height tomatoe plant has a genotype of(ts). It is pollinated with another medium height plant with a genotype of (ts). What are all possible genotypes of this genetic cross in the F1 generation?
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Tt
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[tt]
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Ts
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[ts]
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Ss
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[ss]
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(ts)
Correct Answer(s)
A. [tt]
A. [ts]
A. [ss]Explanation
In tomatoes, height is an incomplete dominant trait. In the F1 generation, when a medium height tomato plant with a genotype of (ts) is pollinated with another medium height plant with a genotype of (ts), the possible genotypes of the offspring are [tt], [ts], and [ss]. The genotype [tt] represents a tall plant, [ts] represents a medium height plant, and [ss] represents a short plant. Since height is an incomplete dominant trait, the heterozygous genotype [ts] will display an intermediate height phenotype.Rate this question:
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- 18.
A dihybrid cross is one in which two characteristics are being tracked. In garden peas (G) green pod color and (R) for round seeds are completely dominant to (g) yellow pod color and (r) wrinkled seeds. If a male green pod and round seed plant is pollinated with a yellow pod and wrinkled seeds. What are the possible genotypes for male gamete combinations of the F1? (HINT: there are four possible correct answers.)
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[GR]
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[Gr]
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[gR]
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[gr]
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Green pod and round seeds
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Yellow pod and round seeds
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Green pod and wrinkled seeds
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Yellow pod and wrinkled seeds
Correct Answer(s)
A. [GR]
A. [Gr]
A. [gR]
A. [gr]Explanation
A dihybrid cross involves tracking two characteristics, in this case, green pod color and round seeds. The dominant alleles for these characteristics are represented by G and R, while the recessive alleles are represented by g and r. When a male plant with the genotype GGRR (green pod and round seeds) is pollinated with a female plant with the genotype ggrr (yellow pod and wrinkled seeds), the possible genotypes for the male gametes in the F1 generation are [GR], [Gr], [gR], and [gr]. This means that the male plant can produce gametes with different combinations of the dominant and recessive alleles for both characteristics.Rate this question:
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- 19.
A test cross is used to determine if the genotype of a plant with the dominant phenotype is homozygous or heterozygous. If the unknown is homozygous, all of the offspring of the test cross have the __________ phenotype. If the unknown is heterozygous, half of the offspring will have the __________ phenotype.
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Dominant, incomplete dominant
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Recessive, dominant
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Dominant, recessive
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Codominant, complimentary
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Same, same
Correct Answer
A. Dominant, recessiveExplanation
A test cross is used to determine if the genotype of a plant with the dominant phenotype is homozygous or heterozygous. If the unknown is homozygous, all of the offspring of the test cross have the recessive phenotype. If the unknown is heterozygous, half of the offspring will have the recessive phenotype.Rate this question:
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- 20.
In humans, free earlobes (F) is dominant over attached earlobes (f). If one parent is homozygous dominant for free earlobes, while the other has attached earlobes can they produce any children with attached earlobes?
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Yes; 75% will be attached earlobes
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No; 100% will be free earlobes
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Yes; 50% will be attached earlobes
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No; 25% will be free and 75% attached earlobes
Correct Answer
A. No; 100% will be free earlobesExplanation
If one parent is homozygous dominant for free earlobes (FF), it means that they only have the dominant allele for free earlobes. The other parent, who has attached earlobes (ff), can only pass on the recessive allele for attached earlobes. Since the dominant allele for free earlobes is always expressed when present, all of their children will inherit the dominant allele from the homozygous parent and have free earlobes. Therefore, the correct answer is that 100% of their children will have free earlobes.Rate this question:
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- 21.
In humans widow’s peak (W) is dominant over straight hairline (w). A heterozygous man for this trait marries a woman who is also heterozygous. How many children of 4 will have widow's peak?
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4
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3
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2
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1
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None
Correct Answer
A. 3Explanation
Since widow's peak (W) is dominant over straight hairline (w), the heterozygous man (Ww) has a 50% chance of passing on the widow's peak allele to each of his children. Similarly, the heterozygous woman (Ww) also has a 50% chance of passing on the widow's peak allele. Therefore, the probability of each child inheriting the widow's peak allele from both parents is 0.5 * 0.5 = 0.25. Since there are 4 children, approximately 3 of them are expected to have widow's peak.Rate this question:
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- 22.
A phenotype ratio of 9:3:3:1 in the offspring of a mating of two organisms heterozygous for two traits is expected when:
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The genes reside on the same chromosome
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Each gene contains two mutations
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the gene pairs assort independently during meiosis
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Only recessive traits are scored
Correct Answer
A. the gene pairs assort independently during meiosisExplanation
When the gene pairs assort independently during meiosis, it means that the alleles for each trait are randomly distributed into the gametes. This results in a 9:3:3:1 phenotype ratio in the offspring. This ratio indicates that there are four possible phenotypic outcomes, with the most common being a combination of both dominant traits, followed by combinations of one dominant and one recessive trait, two recessive traits, and both dominant traits.Rate this question:
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- 23.
In dogs, there is a hereditary deafness caused by a recessive gene, “d." A kennel owner has a female deaf mother homozygous for this condition. She was mated with a normal (homozygous) hearing male. What is the genotypic ratio for this hereditary deafness in the F1 generation of puppies?
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1 [DD} : 2 [Dd] : 1 [dd]
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2 [DD] : 2 [Dd]
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2 [Dd] : 2 [dd]
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0 [DD] : 4 [Dd] : 0 [dd]
Correct Answer
A. 0 [DD] : 4 [Dd] : 0 [dd]Explanation
The correct answer is 0 [DD] : 4 [Dd] : 0 [dd]. This is because the female is homozygous for the deafness gene (dd) and the male is homozygous for the normal hearing gene (DD). When they are mated, all of the offspring will inherit one copy of the deafness gene (Dd) from the mother and one copy of the normal hearing gene (D) from the father. Therefore, there will be no offspring with two copies of the normal hearing gene (DD) or two copies of the deafness gene (dd). The genotypic ratio is 0 [DD] : 4 [Dd] : 0 [dd].Rate this question:
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- 24.
In dogs, there is a hereditary deafness caused by a recessive gene, “d." A kennel owner has a female deaf mother homozygous for this condition. She was mated with a normal (heterozygous) hearing male. What is the genotypic ratio for this hereditary deafness in the F1 generation of puppies?
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1 [DD} : 2 [Dd] : 1 [dd]
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2 [DD] : 2 [Dd]
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2 [DD] : 2 [Dd] : 2 [dd]
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0 [DD] : 4 [Dd] : 0 [dd]
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0 [DD] : 2 [Dd] : 2 [dd]
Correct Answer
A. 0 [DD] : 2 [Dd] : 2 [dd]Explanation
The genotypic ratio for the hereditary deafness in the F1 generation of puppies is 0 [DD] : 2 [Dd] : 2 [dd]. This means that there will be no puppies with the homozygous dominant genotype (DD), two puppies with the heterozygous genotype (Dd), and two puppies with the homozygous recessive genotype (dd). This is because the female mother is homozygous recessive (dd) for the deafness gene, and the male is heterozygous (Dd).Rate this question:
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- 25.
Which of the following genetic crosses would be predicted to give a phenotypic ratio of 9:3:3:1?
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SSYY x ssyy
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SsYY x SSYy
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SsYy x SsYy
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SSyy x ssYY
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SSYy x SSYy
Correct Answer
A. SsYy x SsYyExplanation
The correct answer is SsYy x SsYy. This cross involves two heterozygous individuals (SsYy x SsYy), which means that each parent carries two different alleles for each gene. When these two individuals are crossed, their offspring have a 9:3:3:1 phenotypic ratio. This ratio is characteristic of a dihybrid cross where two genes are being considered, each with two alleles.Rate this question:
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- 26.
A dihybrid cross is one in which two characteristics are being tracked. In garden peas (G) green pod color and (R) for round seeds are completely dominant to (g) yellow pod color and (r) wrinkled seeds. If a heterogyzous green pod and round seed plant is pollinated with a heterozygous green pod and round seed plant (which are F1 individuals). What are the possible phenotypes of the F2 generation plants?
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Blue pod and wrinkled seeds
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Blue pod and round seeds
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Blue pod and sickle seeds
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Green Pod and sickle seeds
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Green pod and round seeds
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Yellow pod and round seeds
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Green pod and wrinkled seeds
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Yellow pod and wrinkled seeds
Correct Answer(s)
A. Green pod and round seeds
A. Yellow pod and round seeds
A. Green pod and wrinkled seeds
A. Yellow pod and wrinkled seedsExplanation
A dihybrid cross involves the inheritance of two characteristics. In this case, the characteristics are pod color (green or yellow) and seed shape (round or wrinkled). The dominant alleles for pod color are G (green) and for seed shape are R (round). The recessive alleles for pod color are g (yellow) and for seed shape are r (wrinkled). When a heterozygous green pod and round seed plant is crossed with another heterozygous green pod and round seed plant, the possible combinations of alleles in the F2 generation are: GGRR (green pod and round seeds), GgRR (green pod and round seeds), GGrr (green pod and wrinkled seeds), Ggrr (green pod and wrinkled seeds), ggRR (yellow pod and round seeds), ggRr (yellow pod and round seeds), ggrr (yellow pod and wrinkled seeds). Therefore, the possible phenotypes of the F2 generation plants are green pod and round seeds, green pod and wrinkled seeds, yellow pod and round seeds, and yellow pod and wrinkled seeds.Rate this question:
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- 27.
A dihybrid cross is one in which two characteristics are being tracked. In garden peas (G) green pod color and (R) for round seeds are completely dominant to (g) yellow pod color and (r) wrinkled seeds. If a heterogyzous green pod and round seed plant is pollinated with a heterozygous green pod and round seed plant (which are F1 individuals). What is the phenotypic ratio of the F2 generation plants?
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1 : 2 : 0
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1 : 2 : 1
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2 : 4 : 2
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4 : 8 : 2
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9 : 3 : 3 : 1
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12 : 4 : 3 : 1
Correct Answer
A. 9 : 3 : 3 : 1Explanation
In a dihybrid cross, two characteristics are being tracked. In this case, the characteristics are pod color (green or yellow) and seed shape (round or wrinkled). The dominant alleles for both characteristics are green pod color (G) and round seeds (R). The recessive alleles are yellow pod color (g) and wrinkled seeds (r).
When a heterozygous green pod and round seed plant (GgRr) is crossed with another heterozygous green pod and round seed plant (GgRr), the possible genotypes of the offspring are: GGRR, GgRR, GGRr, GGrr, GgRr, ggRR, ggRr, ggrr.
Out of these genotypes, the phenotypes of the F2 generation plants will be: green pod and round seeds (GGRR, GgRR, GGRr), green pod and wrinkled seeds (GGrr, GgRr), yellow pod and round seeds (ggRR, ggRr), yellow pod and wrinkled seeds (ggrr).
The phenotypic ratio of the F2 generation plants is therefore 9 (green pod and round seeds) : 3 (green pod and wrinkled seeds) : 3 (yellow pod and round seeds) : 1 (yellow pod and wrinkled seeds).Rate this question:
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- 28.
A pea plant is heterozygous for both seed shape and seed color. S is the allele for the dominant, spherical shape characteristic; s is the allele for the recessive, dented shape characteristic. Y is the allele for the dominant, yellow color characteristic; y is the allele for the recessive, green color characteristic. What will be the distribution of these two alleles in this plant's gametes? (HINT: there are mutliple correct answers for this question.)
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25% - SY
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25% - sY
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25% - Sy
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25% - sy
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50% - SY
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75% - sY
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75% - SY
Correct Answer(s)
A. 25% - SY
A. 25% - sY
A. 25% - Sy
A. 25% - syExplanation
The distribution of alleles in this plant's gametes is determined by the process of meiosis, which involves the random assortment of chromosomes. Since the plant is heterozygous for both seed shape and seed color, it has two different alleles for each trait. During meiosis, these alleles segregate and recombine independently. Therefore, each allele has an equal chance of being included in a gamete. In this case, there are four possible combinations of alleles: SY, sY, Sy, and sy. Each combination has a 25% chance of occurring, resulting in an equal distribution of alleles in the plant's gametes.Rate this question:
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- 29.
What are the possible blood types of the offspring of a cross between individuals that are type AB and type O? (Hint: blood type O is recessive)
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A
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B
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O
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AB
Correct Answer(s)
A. A
A. BExplanation
When a person has blood type AB, it means they have both A and B antigens on their red blood cells. On the other hand, individuals with blood type O do not have any antigens on their red blood cells. Since blood type O is recessive, it means that in order for a person to have blood type O, they must have two copies of the O allele. When a person with blood type AB and a person with blood type O have offspring, there is a 50% chance that the child will inherit the A allele from the parent with blood type AB, resulting in blood type A. Similarly, there is a 50% chance that the child will inherit the B allele from the parent with blood type AB, resulting in blood type B. Therefore, the possible blood types of the offspring in this cross are A and B.Rate this question:
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- 30.
Which of the following genetic test subject would you use in genetics experiments when you must have 100 generations in 6 months?
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Drosophila melanogaster
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Asian Elephants
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Human beings
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Four O'Clocks
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White mice
Correct Answer
A. Drosophila melanogasterExplanation
Drosophila melanogaster would be the ideal genetic test subject for experiments that require 100 generations in 6 months because they have a short lifespan of around 2 weeks and can produce multiple generations in a short period of time. This allows for rapid breeding and the ability to study genetic changes and inheritance patterns over multiple generations within the given time frame.Rate this question:
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- 31.
Manx cats are heterozygous for a dominant mutation that results in no tails (or very short tails), large hind legs, and a distinctive gait. The mating of two Manx cats yields two Manx kittens for each normal, long-tailed kitten, rather than three-to-one as would be predicted from Mendelian genetics. Therefore, the mutation causing the Manx cat phenotype is likely a(n) __________ allele.
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Pleiotropic
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Codominant
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Epistatic
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Lethal
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Sex-linked
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Completely dominant
Correct Answer
A. LethalExplanation
The mutation causing the Manx cat phenotype is likely a lethal allele. This is because when two Manx cats mate, they produce two Manx kittens for each normal, long-tailed kitten, which is not the expected three-to-one ratio predicted by Mendelian genetics. This suggests that the mutation causing the Manx cat phenotype is lethal when present in a homozygous state, resulting in the death of the affected kittens before they are born or shortly after birth.Rate this question:
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- 32.
You are designing a genetic experiment to test for eye color in Drosophila melanogaster (L). Choose favorable characterics that aided your decision to use fruit flies for this experiment. (HINT: there are multiple correct answers.)
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Short life span
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Easy to handle
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High offspring number
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High chromosome number
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Requires small amount of space
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Short gestation period
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Has only 3 eye colors
Correct Answer(s)
A. Short life span
A. Easy to handle
A. High offspring number
A. Requires small amount of space
A. Short gestation periodExplanation
The favorable characteristics that aided the decision to use fruit flies for this experiment include their short life span, which allows for quick generation turnover and multiple experiments to be conducted in a shorter period of time. They are easy to handle, making it easier to manipulate and observe the flies during the experiment. Fruit flies also have a high offspring number, which increases the sample size and statistical power of the experiment. They require a small amount of space, making them suitable for laboratory settings with limited resources. Additionally, fruit flies have a short gestation period, allowing for faster generation of experimental data.Rate this question:
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Mar 21, 2023Quiz Edited by
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Mar 23, 2013Quiz Created by
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