Genetics Problem Test 2
Welcome to the electronic biology frontier classroom of the 21st century. The fact that living things inherit traits from their parents has been used since prehistoric times to improve crop plants and animals through selective breeding. The genetic problems found in this test are found on Mitchell's Cosmic Adventure science web site. Click on horizontal tab BIOLOGY and select LECTURE NOTES. Search for genetic topics; Genetic Practice Problems, Genetic Problem Solver, and WORKSHEETS.
- 1._____ genotypes are made of the same alleles.
- A.
Alleles
- B.
Dominant
- C.
Recessive
- D.
Heterozygous
- E.
Homozygous
- F.
Monohybrid
- 2.What are the possible blood types of the offspring of a cross between individuals that are type AB and type O? (Hint: blood type O is recessive)
- A.
A
- B.
B
- C.
O
- D.
AB
- 3.A pea plant is heterozygous for both seed shape and seed color. S is the allele for the dominant, spherical shape characteristic; s is the allele for the recessive, dented shape characteristic. Y is the allele for the dominant, yellow color characteristic; y is the allele for the recessive, green color characteristic. What will be the distribution of these two alleles in this plant's gametes? (HINT: there are mutliple correct answers for this question.)
- A.
25% - SY
- B.
25% - sY
- C.
25% - Sy
- D.
25% - sy
- E.
50% - SY
- F.
75% - sY
- G.
75% - SY
- 4.
A phenotype ratio of 9:3:3:1 in the offspring of a mating of two organisms heterozygous for two traits is expected when:- A.
The genes reside on the same chromosome
- B.
Each gene contains two mutations
- C.
the gene pairs assort independently during meiosis
- D.
Only recessive traits are scored
- 5.Which of the following genetic crosses would be predicted to give a phenotypic ratio of 9:3:3:1?
- A.
SSYY x ssyy
- B.
SsYY x SSYy
- C.
SsYy x SsYy
- D.
SSyy x ssYY
- E.
SSYy x SSYy
- 6.A test cross is used to determine if the genotype of a plant with the dominant phenotype is homozygous or heterozygous. If the unknown is homozygous, all of the offspring of the test cross have the __________ phenotype. If the unknown is heterozygous, half of the offspring will have the __________ phenotype.
- A.
Dominant, incomplete dominant
- B.
Recessive, dominant
- C.
Dominant, recessive
- D.
Codominant, complimentary
- E.
Same, same
- 7.
Manx cats are heterozygous for a dominant mutation that results in no tails (or very short tails), large hind legs, and a distinctive gait. The mating of two Manx cats yields two Manx kittens for each normal, long-tailed kitten, rather than three-to-one as would be predicted from Mendelian genetics. Therefore, the mutation causing the Manx cat phenotype is likely a(n) __________ allele.
- A.
Pleiotropic
- B.
Codominant
- C.
Epistatic
- D.
Lethal
- E.
Sex-linked
- F.
Completely dominant
- 8.
A genetic cross of inbred snapdragons with red flowers with inbred snapdragons with white flowers resulted in F1-hybrid offspring that all had pink flowers. When the F1 plants were self-pollinated, the resulting F2-generation plants had a phenotypic ratio of 1 red: 2 pink: 1 white. What is the genotypic ratio of the F2-generation plants?
- A.
0 : 1 : 0
- B.
1 : 1 : 1
- C.
1 : 2 : 1
- D.
1 : 3 : 1
- E.
2 : 4 : 2
- 9.
In humans, free earlobes (F) is dominant over attached earlobes (f). If one parent is homozygous dominant for free earlobes, while the other has attached earlobes can they produce any children with attached earlobes?
- A.
Yes; 75% will be attached earlobes
- B.
No; 100% will be free earlobes
- C.
Yes; 50% will be attached earlobes
- D.
No; 25% will be free and 75% attached earlobes
- 10.
In humans widow’s peak (W) is dominant over straight hairline (w). A heterozygous man for this trait marries a woman who is also heterozygous. How many children of 4 will have widow's peak?
- A.
4
- B.
3
- C.
2
- D.
1
- E.
None
- 11.In humans, brown-eye color (B) is dominant over recessive blue-eye color (b). A homozygous brown-eye male marries a heterozygous brown-eye female. What is the phenotypic ratio of their children?
- A.
2 - Brown-eye and 2 - blue-eye children
- B.
3 - Brown-eye and 1 - blue-eye children
- C.
4 - Brown-eye and 0 - blue-eye children
- D.
0 - Brown-eye and 4 - blue-eye children
- 12.In dogs, there is a hereditary deafness caused by a recessive gene, “d." A kennel owner has a female deaf mother homozygous for this condition. She was mated with a normal (homozygous) hearing male. What is the genotypic ratio for this hereditary deafness in the F1 generation of puppies?
- A.
1 [DD} : 2 [Dd] : 1 [dd]
- B.
2 [DD] : 2 [Dd]
- C.
2 [Dd] : 2 [dd]
- D.
0 [DD] : 4 [Dd] : 0 [dd]
- 13.In dogs, there is a hereditary deafness caused by a recessive gene, “d." A kennel owner has a female deaf mother homozygous for this condition. She was mated with a normal (heterozygous) hearing male. What is the genotypic ratio for this hereditary deafness in the F1 generation of puppies?
- A.
1 [DD} : 2 [Dd] : 1 [dd]
- B.
2 [DD] : 2 [Dd]
- C.
2 [DD] : 2 [Dd] : 2 [dd]
- D.
0 [DD] : 4 [Dd] : 0 [dd]
- E.
0 [DD] : 2 [Dd] : 2 [dd]
- 14.In dogs, there is a hereditary deafness caused by a recessive gene, “d." A kennel owner has a female deaf mother homozygous for this condition. She was mated with a normal (heterozygous) hearing male. The kennel owner can only sell normal hearing puppies. How many normal hearing puppies can he sell from a batch of 10?
- A.
1
- B.
2
- C.
3
- D.
4
- E.
5
- F.
6
- G.
7
- H.
8
- 15.
In tomatoes, height is an incomplete dominant trait. A tall tomatoe plant has (t), short plants (s) medium height is (ts). If a homozygous tall plant is cross pollinated with a homozygous short plant. What is the phenotype of all F1 individuals?
- 16.
In tomatoes, height is an incomplete dominant trait. A medium height tomatoe plant has a genotype of(ts). It is pollinated with another medium height plant with a genotype of (ts). What are all possible genotypes of this genetic cross in the F1 generation?
- A.
Tt
- B.
[tt]
- C.
Ts
- D.
[ts]
- E.
Ss
- F.
[ss]
- G.
(ts)
- 17.A dihybrid cross is one in which two characteristics are being tracked. In garden peas (G) green pod color and (R) for round seeds are completely dominant to (g) yellow pod color and (r) wrinkled seeds. If a male green pod and round seed plant is pollinated with a yellow pod and wrinkled seeds. What are the possible genotypes for male gamete combinations of the F1? (HINT: there are four possible correct answers.)
- A.
[GR]
- B.
[Gr]
- C.
[gR]
- D.
[gr]
- E.
Green pod and round seeds
- F.
Yellow pod and round seeds
- G.
Green pod and wrinkled seeds
- H.
Yellow pod and wrinkled seeds
- 18.A dihybrid cross is one in which two characteristics are being tracked. In garden peas (G) green pod color and (R) for round seeds are completely dominant to (g) yellow pod color and (r) wrinkled seeds. If a heterogyzous green pod and round seed plant is pollinated with a heterozygous green pod and round seed plant (which are F1 individuals). What are the possible phenotypes of the F2 generation plants?
- A.
Blue pod and wrinkled seeds
- B.
Blue pod and round seeds
- C.
Blue pod and sickle seeds
- D.
Green Pod and sickle seeds
- E.
Green pod and round seeds
- F.
Yellow pod and round seeds
- G.
Green pod and wrinkled seeds
- H.
Yellow pod and wrinkled seeds
- 19.A dihybrid cross is one in which two characteristics are being tracked. In garden peas (G) green pod color and (R) for round seeds are completely dominant to (g) yellow pod color and (r) wrinkled seeds. If a heterogyzous green pod and round seed plant is pollinated with a heterozygous green pod and round seed plant (which are F1 individuals). What is the phenotypic ratio of the F2 generation plants?
- A.
1 : 2 : 0
- B.
1 : 2 : 1
- C.
2 : 4 : 2
- D.
4 : 8 : 2
- E.
9 : 3 : 3 : 1
- F.
12 : 4 : 3 : 1
- 20.Which of the following genetic test subject would you use in genetics experiments when you must have 100 generations in 6 months?
- A.
Drosophila melanogaster
- B.
Asian Elephants
- C.
Human beings
- D.
Four O'Clocks
- E.
White mice
- 21.
You are designing a genetic experiment to test for eye color in Drosophila melanogaster (L). Choose favorable characterics that aided your decision to use fruit flies for this experiment. (HINT: there are multiple correct answers.)
- A.
Short life span
- B.
Easy to handle
- C.
High offspring number
- D.
High chromosome number
- E.
Requires small amount of space
- F.
Short gestation period
- G.
Has only 3 eye colors
- 22.DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. What are the phenotypes of rabbits that have this genotype: [Ggbb]? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
- 23.DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. What are the phenotypes of rabbits that have this genotype: [ggbb]? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
- 24.DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. What are the phenotypes of rabbits that have this genotype: [GgBb]? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
- 25.DIHYBRID CROSS: In rabbits, gray hair [G] is dominant to white hair [g]. Black eyes [B] is dominant to red eyes [b]. A male rabbit with the genotype [GGbb] is mated with a female rabbit with the genotype [ggBb]. Set up a dihybrid punnett square to determine the phenotypic & genotypic ratios of the F1 offspring. (Hint: please use a number from 0 to 16) How many out of 16 have gray hair and black eyes? (HINT: Please enter your answer in all lower case and separate phenotypes using the conjunction: and)
Related Topics
Back to top