1.
Klenow fragment lacks
Correct Answer
C. 5'→3' exonuclease activity
Explanation
Klenow Fragment is a fragment of DNA polymerase I. It was used in PCR
2.
Similarity between DNA polymerase and Glycogen synthase
Correct Answer
C. Either of the above
Explanation
processiivity is the ability to continue of continous addition without dissociating from its substrate.
3.
Basic protein that binds to DNA in spermatid
Correct Answer
B. Protamine
Explanation
protamines are small arginine-rich proteins helping in sperm head stabilization in the sperm head
4.
Signal recognition particle contains
Correct Answer
D. 7S RNA
Explanation
SRP is a ribonucleoprotein that binds to N-terminal signal sequence of the proteins to be associated with ER.
5.
Possibly more than 90% of genome is transcribed.
Correct Answer
A. True
Explanation
Not all of them are translated. Many of them are long non coding RNA, rRNA, snRNA, miRNA, SnoRNA, SiRNA.
6.
Carboxy terminal domain (CTD) of RNA polymerase is phosphorylated by
Correct Answer
D. TFIIH
Explanation
TFIIH has helicase and kinase activity. CTD phosphorylation is important for the elongation to begin.
7.
Special transcription factors bind to
Correct Answer
D. CAAT box
Explanation
others are cis-elements for binding of trans acting basal transcription factors.
8.
Which is NOT a DNA binding domain ?(Don't worry, No marks for this question)
Correct Answer
C. Helix-loop-helix
Explanation
Helix loop helix won't bind to DNA. It is a dimerization domain like leucine zipper. (Very important)
(ps I'll try to make a video for this topic)
9.
Which is a template independent DNA polymerase ?
Correct Answer
C. Terminal deoxynucleotidyl transferase
Explanation
Usually DNA & Polymerases need a template.
But certain polymerases are unique and can add nucleotides without a template.
10.
Sequence of an intron always starts and ends with(Don't worry, No marks for this question)
Correct Answer
A. GU,AG
Explanation
The correct answer is GU,AG. This is because the sequence of an intron always starts with GU and ends with AG. This is a consensus sequence that is recognized by the spliceosome, which is responsible for removing introns from pre-mRNA during the process of splicing. The GU at the 5' end of the intron is recognized by the U1 snRNP, while the AG at the 3' end is recognized by the U2AF protein. These sequences are essential for proper splicing and the removal of introns from the mRNA transcript.
11.
RNA splicing requires ATP hydrolysis.
Correct Answer
B. False
Explanation
As the number of phosphate-ester bond is unchanged, no energy is consumed.
12.
Instead of poly A tail histone pre-mRNA has stem-loop structure.
Correct Answer
A. True
Explanation
Fact !
13.
5S RNA is transcribed by
Correct Answer
C. RNA polymerase III
Explanation
All rRNAs are transcribed by RNAP I except 5sRNA.
14.
Self-splicing is mediated by (No marks for this question!!!)
Correct Answer
B. Guanosine
Explanation
Splicesome mediated splicing requires OH group of adenosine.
15.
Promoters of eukaryotic tRNA lie within the gene itself.
Correct Answer
A. True
Explanation
Intergenic promoters.
16.
Which amino acid(s) is/are coded by a single codon
Correct Answer
C. Both
Explanation
AUG for methionine and UGG for tryptophan
17.
ApoB48 & apoB100 production is due to
Correct Answer
B. MRNA editing
Explanation
CAA, 2152 nd nucleotide of 4536 long apoB100 mRNA is acted upon by cytosine deaminase to produce UAA, stop codon resulting in production of apoB48.
18.
Mirtrons are miRNAs located in introns
Correct Answer
A. True
Explanation
Fact !
19.
All ribonucleases are ribozymes
Correct Answer
B. False
Explanation
RNAse P is the only ribozyme among ribonucleases.
20.
During translation, initiator tRNA binds to
Correct Answer
B. P site
Explanation
initiator tRNA is the only tRNA that comes and binds to P site. All others will bind to A site.