E1t7 Retake Preap 2016

The jogger is at rest during the interval DE because the graph shows a horizontal line at the y-axis, indicating that the jogger is not moving. In intervals AB, BC, and EF, the graph shows an upward or downward slope, indicating that the jogger is in motion.

The jogger has a constant negative velocity during the interval FG because the position-time graph shows a straight line with a negative slope in that interval. This indicates that the jogger is moving in the negative direction at a constant speed.

In the given graph, the jogger has a constant positive velocity during the interval BC. This is because the graph shows a straight line with a positive slope during that interval, indicating that the jogger is moving at a constant speed in the positive direction.

The speed of the jogger is decreasing during intervals AB and CD. This can be inferred from the given information that the jogger's speed is decreasing, which means the jogger is slowing down. Since the intervals AB and CD are the only intervals mentioned in the options where the jogger is not accelerating or maintaining a constant speed, it can be concluded that the speed is decreasing during these intervals.

The magnitude of the jogger's acceleration is the greatest during interval EF. This can be determined by looking at the graph provided. In interval EF, the graph shows a steep increase in the slope, indicating a rapid change in velocity. Since acceleration is the rate of change of velocity, a rapid change in velocity implies a large magnitude of acceleration. Therefore, interval EF has the greatest magnitude of acceleration.