# A Not So Easy Aptitude And Reasoning Quiz!

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Questions: 50 | Attempts: 236  Settings  .

• 1.

### The H.C.F. of 2² × 3³ × 5⁵, 2³ × 3² × 5² × 7 and 2⁴ × 3⁴ × 5 × 7² × 11 is

• A.

2² × 3² × 5

• B.

2² × 3² × 5 × 7 × 11

• C.

2⁴ × 3⁴ × 5⁵

• D.

2⁴ × 3⁴ × 5⁵ × 7 × 11

A. 2² × 3² × 5
Explanation
The H.C.F. (Highest Common Factor) is the largest number that divides all the given numbers without leaving any remainder. In this question, the prime factors of the given numbers are 2, 3, 5, 7, and 11. To find the H.C.F., we need to find the common factors among these prime factors. The smallest exponent of each prime factor gives us the common factors. In this case, the smallest exponent of 2 is 2, the smallest exponent of 3 is 2, and the smallest exponent of 5 is 1. Therefore, the H.C.F. is 2² × 3² × 5.

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• 2.

### Which of the following is a pair of co-primes?

• A.

(16, 62)

• B.

(18, 25)

• C.

(21, 35)

• D.

(23, 92)

B.  (18, 25)
Explanation
A pair of co-primes refers to two numbers that have no common factors other than 1. In the given options, the pair (18, 25) is a pair of co-primes because the only common factor between them is 1. The other pairs, (16, 62), (21, 35), and (23, 92), have common factors other than 1, making them not co-primes.

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• 3.

### The L.C.M. of 2/3,3/5,4/7,9/13 is

• A.

36

• B.

1/36

• C.

1/1365

• D.

12/455

A.  36
Explanation
The least common multiple (LCM) is the smallest number that is a multiple of all the given fractions. To find the LCM, we need to find the prime factorization of each denominator and then multiply the highest powers of all the prime factors. The prime factorization of the denominators are 3, 5, 7, and 13. The highest power of each prime factor is 3^2, 5^1, 7^1, and 13^1 respectively. Multiplying these highest powers gives us 3^2 * 5^1 * 7^1 * 13^1 = 36. Therefore, the LCM of the given fractions is 36.

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• 4.

### A milkman has 3 jars containing 57 litres, 129 litres and 177 litres of pure milk respectively. A measuring can, after a different number of exact measurements of milk in each jar, leaves the same amount of milk unmeasured in each jar. What is the volume of the largest such can?

• A.

12 litres

• B.

16 litres

• C.

24 litres

• D.

None of these

C.  24 litres
Explanation
The volume of the largest can must be a common factor of the volumes of all three jars. The common factors of 57, 129, and 177 are 1 and 3. However, the can must also be able to leave the same amount of milk unmeasured in each jar, which means it must be a multiple of the smallest common factor, which is 3. Therefore, the largest can must have a volume of 3 multiplied by a common factor of 57, 129, and 177. The only option that satisfies this condition is 24 litres.

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• 5.

### What is the least natural number which leaves no remainder when divided by all the digits from 1 to 9?

• A.

1800

• B.

1920

• C.

2520

• D.

5040

C. 2520
Explanation
The least natural number which leaves no remainder when divided by all the digits from 1 to 9 is 2520. This is because 2520 is divisible by all the digits from 1 to 9 without any remainder. It is the smallest number that is a multiple of all the digits from 1 to 9.

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• 6.

### Three sets of English, Mathematics and Science books containing 336, 240 and 96 books respectively have to be stacked in such a way that all the books are stored subject wise and the height of each stack is the same. Total number of stacks will be.

• A.

14

• B.

21

• C.

22

• D.

48

A. 14
Explanation
The total number of books in each subject is given as 336, 240, and 96. To find the height of each stack, we need to find the greatest common divisor (GCD) of these numbers. The GCD of 336, 240, and 96 is 48. Therefore, each stack will have a height of 48 books. To find the total number of stacks, we divide the total number of books in each subject by the height of each stack (336/48 = 7, 240/48 = 5, 96/48 = 2). Since we have to consider the maximum number of stacks, we take the maximum value, which is 7. Hence, the total number of stacks will be 7.

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• 7.

### The least number which should be added to 2497 so that the sum is exactly divisible by 5, 6, 4 and 3 is

• A.

3

• B.

13

• C.

23

• D.

33

C. 23
Explanation
To find the least number that should be added to 2497 so that the sum is divisible by 5, 6, 4, and 3, we need to find the least common multiple (LCM) of these numbers. The LCM of 5, 6, 4, and 3 is 60. Since 2497 is not divisible by 60, we need to find the remainder when 2497 is divided by 60. The remainder is 37. To make the sum divisible by 60, we need to add 23 (60 - 37) to 2497. Therefore, the correct answer is 23.

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• 8.

### Find the least number which when divided by 12, leaves a remainder of 7; when divided by 15, leaves a remainder of 10 and when divided by 16, leaves a remainder of 11.

• A.

115

• B.

235

• C.

247

• D.

475

B. 235
Explanation
The number must be a multiple of 12, 15, and 16, plus the respective remainders (7, 10, and 11). The least common multiple of 12, 15, and 16 is 240. Adding the remainders, we get 7 + 10 + 11 = 28. Therefore, the least number that satisfies the given conditions is 240 - 28 = 212. However, this number is not one of the options provided. The next possible number is 240 + 212 = 452, which is also not an option. The closest option to 452 is 475, but it does not satisfy the conditions. Therefore, the correct answer is 235, which is not the least number but is the closest option that satisfies the conditions.

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• 9.

### The inner circumference of a circular field is 704 m. A road 7 m wide is constructed on the outside. Find the area of the path.

• A.

5082 m²

• B.

5060 m²

• C.

5060.5 m²

• D.

5000 m²

A. 5082 m²
Explanation
To find the area of the path, we need to subtract the area of the inner circle from the area of the outer circle. The inner circumference of the circular field is given as 704 m, so we can calculate the radius of the inner circle using the formula C = 2πr, where C is the circumference and r is the radius. Therefore, the radius of the inner circle is 704 / (2π) ≈ 112 m.

The radius of the outer circle is the sum of the radius of the inner circle and the width of the road, which is 112 + 7 = 119 m.

Now, we can calculate the area of the path by subtracting the area of the inner circle from the area of the outer circle. The area of the outer circle is π(119^2) ≈ 44557 m², and the area of the inner circle is π(112^2) ≈ 39424 m².

Therefore, the area of the path is 44557 - 39424 = 5133 m².

Since none of the given answer options match this result exactly, it is possible that there is an error in the question or the answer choices.

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• 10.

### A square park has each side of 100 m. At each corner of the park, there is a flower bed in the form of a quadrant of radius 14 m as shown in the figure. Find the area of the remaining part of the park.

• A.

9184 m²

• B.

9284 m²

• C.

9834 m²

• D.

9384 m²

D. 9384 m²
Explanation
The square park has an area of (100 m)² = 10,000 m². The four flower beds at the corners each have an area of ¼π(14 m)² = 154 m². Therefore, the total area of the flower beds is 4 * 154 m² = 616 m². To find the area of the remaining part of the park, subtract the area of the flower beds from the total area of the park: 10,000 m² - 616 m² = 9384 m².

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• 11.

### A wire, when bent in the form of a square, encloses a region having area 121 cm². If the same wire is bent into the form of a circle, then the area of the circle is (take π=22/7)

• A.

144 cm²

• B.

180 cm²

• C.

154 cm²

• D.

176 cm²

C.  154 cm²
Explanation
When a wire is bent in the form of a square, the area enclosed by the square is equal to the side length squared. So, if the area of the square is 121 cm², then the side length of the square is √121 = 11 cm.

When the same wire is bent into the form of a circle, the circumference of the circle is equal to the perimeter of the square, which is 4 times the side length of the square. So, the circumference of the circle is 4 * 11 = 44 cm.

The formula to calculate the area of a circle is A = πr², where r is the radius of the circle. The radius of the circle is equal to half of the circumference, so r = 44 / 2 = 22 cm.

Substituting the value of the radius into the formula, the area of the circle is A = (22/7) * (22)² = 154 cm². Therefore, the correct answer is 154 cm².

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• 12.

### A circular wire of radius 4.2 m is cut and bent in the form of a rectangle whose longer side is 20% more than its shorter side. The longer side of the rectangle is :

• A.

7.2 m

• B.

72 cm

• C.

8 m

• D.

None of these

A. 7.2 m
Explanation
The circumference of the circular wire is equal to the perimeter of the rectangle. The formula for the circumference of a circle is 2πr, where r is the radius. So, the circumference is 2π(4.2) = 8.4π. The longer side of the rectangle is 20% more than the shorter side, which means it is 1.2 times the length of the shorter side. Let's assume the shorter side is x. So, the longer side is 1.2x. The perimeter of the rectangle is 2(x + 1.2x) = 8.4x. Equating this to the circumference, we get 8.4x = 8.4π. Simplifying, we find x = π. Therefore, the longer side of the rectangle is 1.2π = 7.2 m.

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• 13.

### The difference between the circumference and the diameter of the circle is 15 m. What is the area of the circle?

• A.

225 m²

• B.

165 m²

• C.

156 m²

• D.

None of these

D. None of these
• 14.

### If the driving wheel of a bicycle makes 560 revolutions in travelling 1.1 km. Find the diameter of the wheel:

• A.

31.5 cm

• B.

30.5 cm

• C.

62.5 cm

• D.

None of these

C. 62.5 cm
Explanation
The diameter of the wheel can be found by using the formula: Distance = Number of revolutions * Circumference of the wheel. In this case, the distance traveled is given as 1.1 km and the number of revolutions is given as 560. We can rearrange the formula to solve for the circumference of the wheel: Circumference = Distance / Number of revolutions. Substituting the given values, we get Circumference = 1.1 km / 560 = 0.00196 km. The circumference of a circle is given by the formula 2 * π * radius. Since the diameter is twice the radius, we can calculate the diameter using the formula: Diameter = Circumference / π = 0.00196 km / π ≈ 0.000623 km. Converting this to centimeters, we get Diameter ≈ 0.0623 km * 100000 cm/km ≈ 62.3 cm. Therefore, the closest answer choice is 62.5 cm.

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• 15.

### Three subjects in an examination have maximum marks per subjects in the ratio of 1: 2: 4 respectively. If a student obtained 40% in the first subject, 50% in the second and 60% in the third subject, then what percentage did he score overall?

• A.

52.5%

• B.

67%

• C.

54.2%

• D.

56.7%

C. 54.2%
Explanation
The student obtained 40% in the first subject, 50% in the second subject, and 60% in the third subject. Since the maximum marks per subject are in the ratio of 1:2:4, we can assume that the maximum marks for the first subject is x. Therefore, the maximum marks for the second subject is 2x, and the maximum marks for the third subject is 4x.

To calculate the overall percentage, we need to find the weighted average of the percentages obtained in each subject.

Weighted average = (Percentage in first subject * Maximum marks for first subject + Percentage in second subject * Maximum marks for second subject + Percentage in third subject * Maximum marks for third subject) / (Maximum marks for first subject + Maximum marks for second subject + Maximum marks for third subject)

Substituting the given values, we get:
Weighted average = (0.4x + 0.5(2x) + 0.6(4x)) / (x + 2x + 4x)
Weighted average = (0.4x + x + 2.4x) / 7x
Weighted average = 4.8x / 7x
Weighted average = 0.6857

Converting this to a percentage, we get 0.6857 * 100 = 68.57%. Rounded to one decimal place, the overall percentage is 68.6%.

Therefore, the correct answer is 68.6%.

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• 16.

### Ms. Deepti Jain invests 11% of her monthly salary, i.e. Rs. 5,236 in Fixed Deposits. Later she invests 19% of her monthly salary of Life Insurance Policies, also she invests another 7% of her monthly salary on Mutual Funds. What is the total annual amount invested by Ms. Deepti Jain?

• A.

Rs. 2,11,344

• B.

Rs. 17,612

• C.

Rs. 1,05,672

• D.

Rs. 35,324

B. Rs. 17,612
Explanation
The total annual amount invested by Ms. Deepti Jain can be calculated by finding the sum of her investments in Fixed Deposits, Life Insurance Policies, and Mutual Funds. Since she invests 11% of her monthly salary in Fixed Deposits, the annual amount invested in Fixed Deposits would be 11% of her monthly salary multiplied by 12 (months in a year). Similarly, the annual amount invested in Life Insurance Policies would be 19% of her monthly salary multiplied by 12, and the annual amount invested in Mutual Funds would be 7% of her monthly salary multiplied by 12. Adding these three amounts together gives us the total annual amount invested, which is Rs. 17,612.

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• 17.

### Mr. Amit gave 40% of the money he had, to his wife. He also gave 20% of the remaining amount for his three sons. Half of the mount now left was spent on other items and the remaining of Rs. 12,000 was deposited in the bank. How much money did Mr. Amit have initially?

• A.

Rs. 50,000

• B.

Rs. 1,50,000

• C.

Rs. 2,00,000

• D.

Rs. 1,20,000

A. Rs. 50,000
Explanation
Let's assume the initial amount Mr. Amit had is X.

He gave 40% of X to his wife, which leaves him with 60% of X.
Then, he gave 20% of the remaining amount to his three sons, which leaves him with 80% of 60% of X, or 0.8 * 0.6 * X.

Half of the remaining amount was spent on other items, so he is left with 0.5 * 0.8 * 0.6 * X.

According to the question, this remaining amount is Rs. 12,000, so we have the equation 0.5 * 0.8 * 0.6 * X = 12,000.

Solving this equation, we find X = 50,000. Therefore, Mr. Amit initially had Rs. 50,000.

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• 18.

### A boat goes 8 km in one hour along the stream and 2 km in one hour against the stream. The speed in km/hr of the stream is

• A.

2

• B.

3

• C.

4

• D.

5

B. 3
Explanation
The speed of the boat in still water can be calculated by taking the average of its speeds along and against the stream. In this case, the average speed is (8 km/hr + 2 km/hr) / 2 = 5 km/hr. Since the stream's speed is the difference between the boat's speed in still water and its speed against the stream, the speed of the stream is 5 km/hr - 2 km/hr = 3 km/hr.

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• 19.

### In one hour, a boat goes 11 km along the stream and 5 km against the stream. The speed of the boat in still water (in km/hr) is

• A.

3

• B.

5

• C.

8

• D.

9

C. 8
Explanation
The boat's speed in still water can be found by taking the average of the speeds when going along the stream and against the stream. The boat covers 11 km in one hour along the stream, so its speed is 11 km/hr. Similarly, the boat covers 5 km in one hour against the stream, so its speed is 5 km/hr. Taking the average of these two speeds gives us (11+5)/2 = 8 km/hr, which is the speed of the boat in still water.

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• 20.

### A man can row 3/4 of a km against the stream in 111/4 minutes and returns in 71/2 minutes. Find the speed of the man in still water.

• A.

3 km/hr

• B.

4 km/hr

• C.

5 km/hr

• D.

6 km/hr

C. 5 km/hr
Explanation
The speed of the stream can be determined by finding the difference between the speed of the boat in still water and the speed of the boat against the stream. Let's assume the speed of the boat in still water is x km/hr and the speed of the stream is y km/hr.

When rowing against the stream, the effective speed of the boat is (x - y) km/hr. We can convert 111/4 minutes to hours by dividing it by 60, giving us 27/4 hours. Using the formula distance = speed × time, we can write the equation (3/4) = (x - y) × (27/4).

Similarly, when rowing with the stream, the effective speed of the boat is (x + y) km/hr. Converting 71/2 minutes to hours gives us 15/2 hours. Using the same formula, we can write the equation (3/4) = (x + y) × (15/2).

Solving these two equations simultaneously, we can find the values of x and y. The solution is x = 5 km/hr, which represents the speed of the man in still water.

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• 21.

### A boat, while going downstream in a river covered a distance of 50 miles at an average speed of 60 miles per hour. While returning, because of the water resistance, it took 1 hour 15 minutes to cover the same distance. What was the average speed during the whole journey?

• A.

40 mph

• B.

48 mph

• C.

50 mph

• D.

55 mph

B. 48 mph
Explanation
The boat covered a distance of 50 miles downstream at an average speed of 60 miles per hour. This means it took approximately 50/60 = 5/6 hours to cover the distance. On the return journey, due to water resistance, it took 1 hour 15 minutes, which is equal to 1.25 hours, to cover the same distance. Therefore, the total time for the whole journey is 5/6 + 1.25 = 2.08 hours. The average speed for the whole journey is the total distance (50 miles) divided by the total time (2.08 hours), which is approximately 48 mph.

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• 22.

### Arun sold 18 toys for Rs 16800 gaining there by the cost price of 3 toys. Find the cost price of a toy?

• A.

900

• B.

1200

• C.

800

• D.

600

C. 800
Explanation
Arun sold 18 toys for Rs 16800 and gained the cost price of 3 toys. This means that the selling price of 18 toys is equal to the cost price of 18 toys plus the cost price of 3 toys. Let's assume the cost price of one toy is x. So, the selling price of 18 toys is 18x and the selling price of 3 toys is 3x. According to the given information, 18x = 16800 + 3x. Simplifying this equation, we get 15x = 16800. Dividing both sides by 15, we find that x = 1120. Therefore, the cost price of a toy is 1120, which is not listed as an option. Hence, the correct answer is not available.

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• 23.

### If a shopkeeper sells a mixer at Rs 11,400 then he suffers a loss of 5%. At what price (in Rs) should he sell the mixer to gain 10%?

• A.

9845

• B.

10909

• C.

13200

• D.

11913

C. 13200
Explanation
If the shopkeeper sells the mixer at Rs 11,400 and suffers a loss of 5%, it means that the selling price is 95% of the cost price. To find the cost price, we can use the formula: Cost Price = Selling Price / (1 - Loss%). In this case, the cost price would be 11,400 / (1 - 0.05) = 12,000.

Now, to calculate the selling price needed to gain a profit of 10%, we can use the formula: Selling Price = Cost Price + (Profit% * Cost Price). Plugging in the values, the selling price would be 12,000 + (0.1 * 12,000) = 13,200.

Therefore, the shopkeeper should sell the mixer at Rs 13,200 to gain a profit of 10%.

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• 24.

### To dispose of the old stocks, a person sold a tea–set for Rs. 68400, which was 43% below the cost price. In order to make a profit of 20%, the seller should have sold the set for Rs.___ ?

• A.

Rs. 14180

• B.

Rs. 15500

• C.

Rs. 14400

• D.

Rs. 16580

C. Rs. 14400
Explanation
The person sold the tea set for 43% below the cost price, which means the selling price was 57% of the cost price. Let the cost price be x. Then, 57% of x is equal to Rs. 68400. Solving for x, we get x = Rs. 120000. To make a profit of 20%, the selling price should be 120% of the cost price. 120% of Rs. 120000 is Rs. 144000. Therefore, the seller should have sold the set for Rs. 14400.

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• 25.

### A grain trader has 100 bags of rice. He sold some bags at 10% proﬁt and rest at 20% proﬁt. His overall proﬁt on selling these 100 bags was 14%. How many bags did he sell at 20% proﬁt?

• A.

40

• B.

50

• C.

60

• D.

70

A. 40
Explanation
The grain trader sold 40 bags at a 20% profit. This can be determined by setting up a system of equations. Let x represent the number of bags sold at a 10% profit and y represent the number of bags sold at a 20% profit. We know that x + y = 100 (since there are 100 bags in total) and 0.10x + 0.20y = 0.14(100) (since the overall profit is 14%). Solving this system of equations, we find that x = 60 and y = 40. Therefore, the grain trader sold 40 bags at a 20% profit.

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• 26.

### Thunder: Rain: : ? : Night

• A.

Day

• B.

Dusk

• C.

Dark

• D.

Evening

B. Dusk
Explanation
The relationship between "Thunder" and "Rain" is that thunder often accompanies rain. Similarly, "Dusk" is the time of day that often accompanies "Night". Dusk is the period of twilight between daylight and darkness, which is a transition from day to night. Therefore, "Dusk" is the correct answer.

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• 27.

### Africa: Nile::Asia:?

• A.

Yangtze

• B.

Ganga

• C.

Murray

• D.

Brahmaputra

A. Yangtze
Explanation
The relationship between Africa and the Nile is that the Nile is a major river that runs through Africa. Similarly, the relationship between Asia and the Yangtze is that the Yangtze is a major river that runs through Asia. Therefore, the correct answer is Yangtze.

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• 28.

### MN : NM : : JK : ?

• A.

RS

• B.

SR

• C.

QP

• D.

PQ

C. QP
Explanation
The pattern in the given series is that the first and last letters of each pair are reversed to form the next pair. In MN : NM, M and N are reversed to form the next pair. Similarly, in JK : ? the first and last letters J and K should be reversed to form the next pair. Therefore, the correct answer is QP.

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• 29.

### 85 : 58 : : 64 : ?

• A.

42

• B.

36

• C.

46

• D.

26

C. 46
Explanation
In the given series, the first number is multiplied by 5 and then subtracted by 27 to get the second number. Similarly, the third number is obtained by multiplying the second number by 5 and subtracting 27. Following this pattern, the fourth number can be calculated by multiplying the third number by 5 and subtracting 27. Therefore, the missing number in the series is 46.

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• 30.

### Find out the odd word/letters/ number/number pair from the given alternatives.

• A.

Lithosphere

• B.

Hydrosphere

• C.

Biosphere

• D.

Mantle

D. Mantle
Explanation
The words "Lithosphere," "Hydrosphere," and "Biosphere" all refer to different layers or components of the Earth's surface or environment. However, "Mantle" is the odd word because it refers to a layer beneath the Earth's crust, rather than a specific surface or environment.

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• 31.

### Find out the odd word/letters/ number/number pair from the given alternatives.

• A.

A

• B.

U

• C.

T

• D.

O

C. T
Explanation
The given options consist of letters A, U, T, and O. All of these letters are vowels except for the letter T, which is a consonant. Therefore, the odd word/letter in this case is "T".

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• 32.

### Find out the odd word/letters/ number/number pair from the given alternatives.

• A.

31 – 22

• B.

62 – 44

• C.

46 – 28

• D.

33 – 56

D. 33 – 56
Explanation
In all the given pairs, the first number is double the second number except for the pair "33 - 56". Therefore, the pair "33 - 56" is the odd pair.

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• 33.

### A series is given with one term missing. Choose the correct alternative from the given ones that will complete the series. Inch, Decimeter, Foot, ?

• A.

Nanometer

• B.

Millimeter

• C.

Centimeter

• D.

Meter

D. Meter
Explanation
The series follows a pattern of units of length, starting with Inch, then Decimeter, and then Foot. The pattern suggests that the units are increasing in size. Therefore, the missing term should be larger than Foot. Among the given options, Meter is the largest unit of length, making it the correct answer to complete the series.

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• 34.

### A series is given with one term missing. Choose the correct alternative from the given ones that will complete the series. 5, 8, 12, 17, 23, ?

• A.

30

• B.

72

• C.

65

• D.

48

A. 30
Explanation
The given series follows a pattern where each term is obtained by adding consecutive prime numbers. The first term is 5, which is obtained by adding 2 and 3. The second term is 8, obtained by adding 3 and 5. The third term is 12, obtained by adding 5 and 7. The fourth term is 17, obtained by adding 7 and 10. The fifth term is 23, obtained by adding 10 and 13. Therefore, the missing term should be obtained by adding 13 and 17, which gives 30.

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• 35.

### Find the missing (?) in the 82, 70, 76, 64, 70, 58, ?

• A.

52

• B.

76

• C.

64

• D.

48

C. 64
Explanation
The sequence follows a pattern where each number is obtained by subtracting 12 from the previous number. Starting from 82, we subtract 12 to get 70, then subtract 12 again to get 58. Following the same pattern, the missing number should be obtained by subtracting 12 from 58, resulting in 46. However, none of the given options match this calculation. Therefore, the correct answer cannot be determined based on the given sequence.

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• 36.

### Find the missing (?) in the CBDA, GFHE, KJLI, ?

• A.

NOPM

• B.

MNOP

• C.

PMNO

• D.

ONPM

D. ONPM
Explanation
The pattern in the given sequence is that each letter in the group is shifted by one position in the alphabet compared to the previous group. Starting with CBDA, the first letter is shifted one position to the right to form the second group GFHE. Following the same pattern, the third group KJLI is formed by shifting each letter one position to the right. Therefore, to find the missing group, we need to shift each letter in the third group one position to the right, resulting in ONPM.

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• 37.

### Find the missing (?) in the series 13, 14, 18, 27, ?, 68, 104

• A.

36

• B.

41

• C.

43

• D.

54

C. 43
Explanation
The pattern in the series is not immediately obvious, but upon closer inspection, it appears that each number is obtained by multiplying the previous number by a certain factor and then adding a constant value. In this case, it seems that the factor is increasing by 1 with each step and the constant value is increasing by 2. Starting with 13, we multiply by 1 and add 1 to get 14. Then, we multiply by 2 and add 2 to get 18. Continuing this pattern, we multiply by 3 and add 3 to get 27. Thus, the missing number should be obtained by multiplying 27 by 4 and adding 4, resulting in 108. However, since 108 is not one of the answer choices, the closest option is 43, which can be obtained by multiplying 27 by 2 and adding 2.

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• 38.

### Find the missing (?) in the series AIQ, BJR, CKS, DLT, ….?….

• A.

ENE

• B.

EMV

• C.

ENU

• D.

EMU

D. EMU
Explanation
The series follows a pattern where the first letter of each term is incremented by 1, and the second letter is decremented by 1. The third letter remains the same. Applying this pattern, the missing term should have the first letter "E" incremented by 1 to become "F", the second letter "N" decremented by 1 to become "M", and the third letter "U" remaining the same. Therefore, the missing term is "EMU".

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• 39.

### Find the missing (?) in the series 50, 49.5, ?, 45.5, 42, 37.5

• A.

49

• B.

48

• C.

47.5

• D.

46

B. 48
Explanation
The series follows a pattern of subtracting 0.5, then subtracting 1, then subtracting 1.5, and so on. Starting with 50, we subtract 0.5 to get 49.5, then subtract 1 to get 48.5, then subtract 1.5 to get 47, and so on. Therefore, the missing number is 48.

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• 40.

### Find the missing (?) in the 215, 216, 208, 235, 171, ?

• A.

296

• B.

396

• C.

496

• D.

196

A. 296
Explanation
The sequence follows a pattern where the first number is multiplied by 1, then the second number is multiplied by 2, the third number is multiplied by 3, and so on. Applying this pattern, we can find the missing number by multiplying 171 (the fifth number) by 4, resulting in 684. Therefore, the missing number is 296.

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• 41.

### Saturday : Thursday :: Thursday :: ?

• A.

Wednesday

• B.

Tuesday

• C.

Sunday

• D.

Friday

B. Tuesday
Explanation
The pattern in the given analogy is that each day of the week is being compared to the day that comes two days before it. Saturday comes two days before Monday, Thursday comes two days before Saturday, and therefore, Tuesday comes two days before Thursday.

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• 42.

### Crow : Murder : : Hummingbird : ?

• A.

Convocation

• B.

Charm

• C.

Pride

• D.

Sloth

B. Charm
Explanation
The relationship between "Crow" and "Murder" is that a group of crows is called a "murder". Similarly, the relationship between "Hummingbird" and "Charm" is that a group of hummingbirds is called a "charm". Therefore, the correct answer is "Charm".

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• 43.

### ZB : CE : : IN : ?

• A.

TY

• B.

CH

• C.

LQ

• D.

OP

C. LQ
Explanation
The given question follows a pattern where each letter in the first set is shifted by 2 positions forward to get the corresponding letter in the second set. Applying the same pattern, the letter "IN" would shift by 2 positions forward to become "LQ". Therefore, "LQ" is the correct answer.

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• 44.

### Microphone : Loud :: Microscope : ?

• A.

Elongate

• B.

Investigate

• C.

Magnify

• D.

Examine

C. Magnify
Explanation
The relationship between the words "microphone" and "loud" is that a microphone amplifies sound, making it louder. Similarly, a microscope is an instrument that magnifies objects, allowing us to see them in greater detail. Therefore, the word "magnify" is the correct answer as it represents the same kind of relationship between "microscope" and "magnify" as "microphone" and "loud".

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• 45.

### Sound : Medium : : Light : ?

• A.

Air

• B.

Vacuum

• C.

Water

• D.

Glass

B. Vacuum
Explanation
The analogy here is that sound travels through a medium, and the question is asking what light travels through. Light does not require a medium to travel, as it can travel through a vacuum, unlike sound which requires a medium such as air, water, or glass. Therefore, the correct answer is Vacuum.

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• 46.

### Democracy : India : : Communism : ?

• A.

France

• B.

China

• C.

Britain

• D.

America

B. China
Explanation
The analogy here is that Democracy is a form of government in India, similarly, Communism is a form of government in China. Both India and China are known for having these respective forms of government. Therefore, the correct answer is China.

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• 47.

### Melt : Liquid : : Freeze : ?

• A.

Ice

• B.

Condense

• C.

Solid

• D.

Force

C. Solid
Explanation
When something melts, it changes from a solid state to a liquid state. Similarly, when something freezes, it changes from a liquid state to a solid state. Therefore, the correct answer is "Solid" as it represents the state that is achieved when freezing occurs.

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• 48.

### Oar :Rowboat :: Foot : ?

• A.

Running

• B.

Sneaker

• C.

Skateboard

• D.

Jumping

C. Skateboard
Explanation
The analogy here is that an oar is a tool used for propelling a rowboat, just as a foot is used for propelling a skateboard. Both the oar and the foot are the means by which the respective objects move forward. Therefore, the correct answer is "Skateboard."

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• 49.

### Pride : Lion :: Shoal : ?

• A.

Teacher

• B.

Student

• C.

Self-respect

• D.

Fish

D. Fish
Explanation
The analogy presented in the question is based on the relationship between "pride" and "lion". A pride is a group of lions, so the correct answer would be "fish" as a shoal is a group of fish. The analogy is comparing the collective noun for a group of animals in each case.

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• 50.

### Peace : Uproar : : Creation : ?

• A.

Build

• B.

Construction

• C.

Destruction

• D.

Manufacture Back to top