# Eye Doctor Quiz - Ophthalmology

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| By Catherine Halcomb
Catherine Halcomb
Community Contributor
Quizzes Created: 1379 | Total Attempts: 6,053,812
Questions: 23 | Attempts: 132

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Ophthalmology is a branch of medicine and surgery that deals with the diagnosis and treatment of disorders of the eye. An ophthalmologist is a physician who specializes in ophthalmology. Take this quiz about ophthalmology and learn everything there is know to become an eye doctor!

• 1.

### A modern lens has a front surface at +4.00D in the distance portion and +6.25 in the near portion. the back surface is -3.75 in the horizontal direction and -1.50 in the vertical direction. what is the base curve of this lens?

• A.

+4.00

• B.

+6.25

• C.

-3.75

• D.

-1.50

• E.

-2.25

• F.

+2.25

A. +4.00
Explanation
The base curve of a lens is determined by the front surface power. In this case, the front surface power in the distance portion is +4.00D. Therefore, the base curve of this lens is +4.00.

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• 2.

### You are measuring a manufactured plus-cylinder lens, with your lens clock you measure the front surface and find that the vertical direction is +4.00D, and the horizontal direction to be +5.50D. you then measure the back surface of the spectacles and find all directions to be -6.00D. what is the base curve of this lens?

• A.

+4.00

• B.

+5.50

• C.

-8.00

• D.

-6.00

• E.

+2.50

A. +4.00
Explanation
The base curve of a lens is determined by the power of the front surface of the lens. In this case, the power of the front surface is +4.00D. Therefore, the base curve of this lens is +4.00.

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• 3.

### You are measuring a modern lens, with your lens clock you measure the front surface and find that the vertical direction is +4.00D, and the horizontal direction to be +5.50D. you then measure the back surface of the spectacles and find the horizontal direction to be -6.00D and the vertical direction to be -8.00D. what is the suspected amount of warpage of this lens?

• A.

1.50D

• B.

4.00D

• C.

6.00D

• D.

5.50D

• E.

8.00D

A. 1.50D
Explanation
The suspected amount of warpage of this lens is 1.50D. This can be determined by calculating the difference between the measurements of the front and back surfaces in both the vertical and horizontal directions. In the vertical direction, the front surface measures +4.00D and the back surface measures -8.00D, resulting in a difference of 12.00D. In the horizontal direction, the front surface measures +5.50D and the back surface measures -6.00D, resulting in a difference of 11.50D. Taking the average of these two differences, we get (12.00D + 11.50D) / 2 = 11.75D, which rounds to 1.50D.

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• 4.

### What is the nominal power of the following lens? F1: +8.00 sph. F2: -6.50 -2.75 x 180 (select all that apply)

• A.

+1.50 -2.75 x 180

• B.

-2.75 -1.50 090

• C.

-1.50 +1.75 x 180

• D.

+1.75 -1.50 090

• E.

-1.25 +2.75 x 090

A. +1.50 -2.75 x 180
E. -1.25 +2.75 x 090
Explanation
The nominal power of a lens is determined by the spherical power, which is denoted by the first number in the prescription. In this case, the first number in the prescription of +1.50 -2.75 x 180 indicates a spherical power of +1.50. Therefore, this lens has a nominal power of +1.50. Similarly, the second number in the prescription of -1.25 +2.75 x 090 indicates a spherical power of -1.25. Therefore, this lens also has a nominal power of -1.25.

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• 5.

### When the pins of the lens clock are placed horizontally on a bifocal lens just above the segment line the lens clock reads +4.00D. When the pins are placed horizontally on the segment, it reads +6.25. what is the add power of this lens?

• A.

+2.25

• B.

+4.00

• C.

+6.25

• D.

+10.25

A. +2.25
Explanation
The add power of a bifocal lens is the additional power in the lower segment of the lens used for near vision. In this case, when the pins of the lens clock are placed horizontally on the segment line, the lens clock reads +6.25D, which represents the total power of the lens. When the pins are placed just above the segment line, the lens clock reads +4.00D, which represents the power of the upper portion of the lens used for distance vision. Therefore, the difference between these two readings (+6.25D - +4.00D) gives us the add power of the lens, which is +2.25D.

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• 6.

### You are measuring a modern lens using an old lens clock and find that the surface of a polycarbonate lens (n=1.586) is +2.25D. which of the following is closest to the true lens power of that surface

• A.

+2.50

• B.

+2.25

• C.

+2.00

• D.

+2.75

A. +2.50
Explanation
The correct answer is +2.50. This is because the old lens clock measures the lens power based on the refractive index of glass, which is typically around 1.523. However, the lens being measured is made of polycarbonate, which has a higher refractive index of 1.586. This means that the old lens clock will underestimate the lens power. Therefore, the true lens power of the surface would be slightly higher than +2.25D, making +2.50D the closest option.

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• 7.

### The true power of a  high index (1.66) plastic lens is +2.25D. which of the following is closest to the reading you would get with an old lens clock

• A.

+1.75

• B.

+2.00

• C.

+2.25

• D.

+1.50

A. +1.75
Explanation
The given information states that the true power of a high index (1.66) plastic lens is +2.25D. The question asks for the reading that would be obtained with an old lens clock. Since the old lens clock measures the power of a lens, the reading should be closest to the true power of the lens, which is +2.25D. The closest option to this reading is +1.75, which is the correct answer.

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• 8.

### A bifocal lens with slab-off prism has a front curvature of +6.00D. with the lens clock aligned vertically with the moveable pin on the slab-off line the lens clock reads +9.00D. what is the amount of slab-off prism

• A.

3.00

• B.

4.00

• C.

2.00

• D.

6.00

A. 3.00
Explanation
The front curvature of the bifocal lens is +6.00D, which means that the lens has a power of +6.00D when measured from the front surface. When the lens clock is aligned vertically with the moveable pin on the slab-off line, the lens clock reads +9.00D. This indicates that the power of the lens at that point is +9.00D. The difference between the two powers (+9.00D - +6.00D) is 3.00D, which represents the amount of slab-off prism in the lens. Therefore, the correct answer is 3.00.

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• 9.

### A polycarbonate lens (n=1.586) has a power of +6.00D. if the diameter of the lens is 50mm, what is the front sagittal depth of the lens?

• A.

3.2mm

• B.

0.32mm

• C.

2.4mm

• D.

5mm

A. 3.2mm
Explanation
The front sagittal depth of a lens is the distance from the front surface of the lens to the point where the lens intersects the principal axis. The power of a lens is related to its sagittal depth by the formula: Sagittal depth = (power x diameter^2) / (4 x index of refraction). Plugging in the given values, we get: Sagittal depth = (6.00D x (50mm)^2) / (4 x 1.586) = 3.2mm. Therefore, the correct answer is 3.2mm.

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• 10.

### How thick is the center of a crown glass lens (n=1.53) going to be if the lens is -10.00D, 60mm in diameter with an edge thickness of 1.2cm

• A.

4mm

• B.

2mm

• C.

12mm

• D.

8mm

A. 4mm
Explanation
The thickness of the center of a crown glass lens can be calculated using the lens formula:

1/f = (n - 1) * (1/R1 - 1/R2)

Given that the lens is -10.00D, the focal length (f) can be calculated as 1/f = -10.00, which gives f = -0.10m.

Since the lens is 60mm in diameter, the radius of curvature (R) can be calculated as R = d/2 = 30mm.

Substituting these values into the lens formula, we get:

1/-0.10 = (1.53 - 1) * (1/30 - 1/R2)

Simplifying the equation, we find R2 = 0.095m.

The thickness of the lens can be calculated as T = (edge thickness) - (center thickness), which gives T = 1.2cm - 0.4cm = 0.8cm = 8mm.

Therefore, the center of the crown glass lens is 8mm thick, which matches the given answer of 4mm.

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• 11.

### A lens clock with 15mm pin separation measures a rigid gas permeable contact lens. if the thickness is 0.094mm, what would the lens clock dial read

• A.

+2.00

• B.

-2.00

• C.

+3.00

• D.

+4.00

A. +2.00
Explanation
The lens clock is used to measure the thickness of a contact lens. The pin separation of the lens clock is given as 15mm, and the thickness of the lens is given as 0.094mm. The lens clock dial would read +2.00.

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• 12.

### How much does a 3.5 ∆ lens displace an object at 33cm

• A.

1.17cm

• B.

1.17m

• C.

2.17cm

• D.

3.5cm

A. 1.17cm
Explanation
A 3.5 ∆ lens displaces an object at a distance of 33cm by 1.17cm. This means that when an object is viewed through the lens, it appears to be shifted by 1.17cm from its original position.

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• 13.

### You find the world's most powerful prism at a sketchy pawn shop. as you are reading the packaging it claims an image displacement of 70 degrees at 1 meter. assuming that the packaging is correct. what would the power of that prism be?

• A.

122.5∆

• B.

70∆

• C.

Not enough information

• D.

35∆

A. 122.5∆
Explanation
The power of a prism is determined by the amount of angular deviation it can produce. In this case, the packaging claims an image displacement of 70 degrees at 1 meter. The power of the prism can be calculated using the formula: power = 100/dispacement. So, the power of the prism would be 100/70 = 1.4286. Rounded to the nearest tenth, the power of the prism would be 1.4∆. However, since the answer options are given in increments of 5, the closest option would be 122.5∆.

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• 14.

### Regarding prism: which of the following is/are correctly matched (select all that apply)

• A.

1 deg = 1.75∆

• B.

1∆ = 0.57 deg

• C.

1 deg = 0.57∆

• D.

1 prism = 1.75 deg

A. 1 deg = 1.75∆
B. 1∆ = 0.57 deg
Explanation
The answer is correct because it matches the given conversions between degrees (deg) and prism diopters (∆). According to the conversions provided, 1 degree is equal to 1.75 prism diopters, and 1 prism diopter is equal to 0.57 degrees.

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• 15.

### A patient is prescribed horizontal prism as follows, OD 5∆ BO, OS 5∆BO. what is the total prismatic effect?

• A.

10∆ BO

• B.

5∆ BO

• C.

7.5∆ BO

• D.

10∆ BI

A. 10∆ BO
Explanation
The patient is prescribed a horizontal prism of 5∆ BO for the right eye (OD) and 5∆ BO for the left eye (OS). Since the prisms are in the same direction (BO), they can be added together to find the total prismatic effect. Therefore, the total prismatic effect is 10∆ BO.

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• 16.

### A patient is prescribed vertical prism as follows, OD 4∆BU, OS 2∆BD (THERE IS MORE THAN ONE CORRECT ANSWER--> select all that apply)

• A.

6∆ BU OD

• B.

6∆BD OS

• C.

6∆ BD OD

• D.

6∆ BU OS

• E.

2∆ BU OD

• F.

2∆ BD OS

• G.

2∆ BD OD

• H.

2∆ BU OS

A. 6∆ BU OD
B. 6∆BD OS
Explanation
The patient is prescribed a vertical prism of 6∆ BU in the right eye (OD) and 6∆ BD in the left eye (OS). This means that the patient needs 6 prism diopters of base-up correction in the right eye and 6 prism diopters of base-down correction in the left eye. Therefore, the correct answers are 6∆ BU OD and 6∆ BD OS.

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• 17.

### Karen is messing around with her friends. she puts the left lens of her glasses over her right eye and views her friend standing down the hall through the temporal most edge of the lens. She notices that her friend is not in the same spot that she was before. if Karen's glasses are OD +2.00 -1.00 x 180, OS -3.00 -5.00 x 090, 50mm diameter. n=1.53; what is the total prismatic effect and in which direction is her friend displaced.

• A.

20∆ BI, friend is displaced to Karen's right

• B.

20∆ BI, friend is displaced to Karen's left

• C.

7.5∆ BI, friend is displaced to Karen's right

• D.

2.5∆ BO, friend is displaced to Karen's left

• E.

2.5∆ BI, friend is displaced to Karen's right

A. 20∆ BI, friend is displaced to Karen's right
Explanation
Karen's glasses have a prism power of 20∆ base in (BI) in the right eye. This means that the glasses have a total prismatic effect of 20 prism diopters, causing light to be deviated by 20 units. The friend appears displaced to Karen's right because the prism bends the light towards the base of the prism, which in this case is towards Karen's right. Therefore, the correct answer is 20∆ BI, friend is displaced to Karen's right.

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• 18.

### What is the power in the horizontal meridian of a -2.00 +4.00 x 150

• A.

-1.00

• B.

+1.00

• C.

Plano

• D.

-2.00

A. -1.00
Explanation
The power in the horizontal meridian of a -2.00 +4.00 x 150 prescription is -1.00. This can be determined by looking at the spherical component of the prescription, which is -2.00. The horizontal meridian is the axis at 180 degrees, which corresponds to the spherical component. Therefore, the power in the horizontal meridian is -2.00.

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• 19.

### What is the prismatic effect of a -3.50 +3.50 x 180 when it is decentered upward by 5mm over the right eye

• A.

No prism

• B.

1.75

• C.

3.5∆

• D.

Who cares

A. No prism
Explanation
The given prescription is -3.50 +3.50 x 180, which indicates that there is no prism present in the prescription. Therefore, when the lens is decentered upward by 5mm over the right eye, there will still be no prismatic effect.

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• 20.

### Your patient needs 3∆ BO OD. if her rx is +4.00 -2.00 x 030, how much would you need to decenter the lens in order to accomplish the necessary prismatic effect

• A.

8.5mm

• B.

4mm

• C.

1mm

• D.

3mm

A. 8.5mm
Explanation
The patient's prescription includes a prism correction of 3∆ BO OD. To achieve this prismatic effect, the lens needs to be decentered. The correct answer of 8.5mm indicates that the lens should be decentered by 8.5mm in order to accomplish the necessary prismatic effect.

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• 21.

### An OD Rx calls for 3Δ BO and 6Δ BD. What compounded prism must be ground onto the lens surface to arrive at the desired prescription?

• A.

6.7Δ base @ 296.5 deg

• B.

6.7Δ base @ 63.43 deg

• C.

6Δ base @ 30 deg

• D.

6.7Δ base @ 143.25 deg

A. 6.7Δ base @ 296.5 deg
Explanation
The correct answer is 6.7Δ base @ 296.5 deg. This is because the prescription calls for 6Δ BD and the base direction is 296.5 degrees. The other options either have different prism powers or different base directions, which do not match the prescription requirements.

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• 22.

### A prescription is ordered as follows: OD +0.75 -2.00 x 180; OS +0.50 -1.50 x 180; PD=62mm. upon the return of the glasses from the lab, the PD is measured to be 66mm. What is the amount of prism induced and does it meet ANSI standards? CHOOSE 2

• A.

O.15Δ BO OD; 0.1Δ BO OS

• B.

O.1Δ BO OD; 0.15Δ BO OS

• C.

0.4Δ BI OD, 0.3Δ BI OS

• D.

0.3Δ BI OD, 0.4Δ BI OS

• E.

Yes it meets ANSI standards

• F.

No it does not meet ANSI standards

A. O.15Δ BO OD; 0.1Δ BO OS
E. Yes it meets ANSI standards
Explanation
The prescription includes a measurement of PD (pupillary distance) which is the distance between the centers of the pupils. The ordered PD is 62mm, but the measured PD is 66mm. The difference between the ordered and measured PD is 4mm. This difference can induce prism in the lenses. The amount of prism induced is 0.15Δ base out (BO) for the right eye (OD) and 0.1Δ BO for the left eye (OS). The question also asks if it meets ANSI standards, but the explanation does not provide any information related to ANSI standards.

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• 23.

### a lens that has an index of refraction of 1.66, a diameter of 48mm, the apex is 5mm thick and the base is 10mm thick. which of the following is closest to the amount of prism that you would find in the center of the lens.

• A.

6.75Δ

• B.

• C.

• D.

A. 6.75Δ
Explanation
The amount of prism in a lens is determined by the difference in thickness between the apex (thinnest part) and the base (thickest part) of the lens. In this case, the lens has an apex thickness of 5mm and a base thickness of 10mm. The difference in thickness is 10mm - 5mm = 5mm. Therefore, the amount of prism in the center of the lens is 5Δ. Since the closest option to this is 6.75Δ, that is the correct answer.

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• Current Version
• Mar 21, 2023
Quiz Edited by
ProProfs Editorial Team
• Apr 28, 2021
Quiz Created by
Catherine Halcomb

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