Haloalkanes And Haloarenes: Chemistry Quiz!

The reaction described in the question involves the use of chlorine gas (Cl2) and UV light. UV light is required to initiate the reaction between the chlorine gas and the other reactants. Therefore, the reagent that should be used for this reaction is Cl2/UV light.

The density of a compound is determined by the mass of its molecules and the volume they occupy. In this case, the compound with the highest density is C2H5I. This is because iodine (I) is a heavier element compared to bromine (Br), chlorine (Cl), and fluorine (F). The larger atomic mass of iodine contributes to a higher overall molecular mass for C2H5I, resulting in a higher density.

A primary alkyl halide would prefer to undergo SN2 reaction because SN2 reactions occur in a single step and involve a backside attack by the nucleophile on the carbon center, resulting in inversion of stereochemistry. Primary alkyl halides have less steric hindrance compared to secondary or tertiary alkyl halides, allowing the nucleophile to approach the carbon center more easily. Additionally, primary alkyl halides have a lower energy barrier for the transition state, making SN2 reactions more favorable.

Toluene reacts with a halogen in the presence of Iron (III) chloride, which acts as a catalyst. In electrophilic substitution reactions, a hydrogen atom in the benzene ring is replaced by an electrophile. In this case, the halogen acts as the electrophile, attacking the benzene ring and substituting one of the hydrogen atoms. This reaction is known as electrophilic substitution because an electrophile is involved in the reaction. Therefore, the correct answer is electrophilic substitution reaction.

Chlorobenzene is formed when one molecule of chlorine reacts in the presence of iron with benzene.

The side chain chlorination of toluene takes place in the presence of Cl2/heat and light. Chlorine gas (Cl2) acts as the chlorinating agent, while heat and light provide the necessary energy to initiate the reaction. The heat and light energy breaks the Cl2 molecule into highly reactive chlorine radicals, which then attack the toluene molecule and replace one of the hydrogen atoms in the side chain with a chlorine atom. This reaction is an example of a free radical substitution reaction and is commonly used to introduce chlorine atoms into organic compounds.

not-available-via-ai

The order of boiling points in a group of isomeric alkyl halides is determined by the size and branching of the alkyl groups attached to the halogen atom. The more branching there is in the alkyl groups, the lower the boiling point. This is because branching reduces the surface area available for intermolecular interactions, leading to weaker Van der Waals forces between molecules. Therefore, the correct order is 3o

When 1-chlorobutane is treated with ethanolic KOH, it undergoes an elimination reaction known as dehydrohalogenation. This reaction removes a hydrogen atom from the beta carbon (carbon adjacent to the chlorine) and the chlorine atom, resulting in the formation of an alkene. In this case, 1-butene is formed as the only product because the hydrogen atom is removed from the beta carbon that leads to the formation of a double bond between the first and second carbon atoms. Therefore, the correct answer is 1-butene only.

The correct increasing order of boiling points is 1-Bromoethane

2-Bromobutane is chiral because it contains a chiral carbon atom, which is a carbon atom bonded to four different groups. The presence of this chiral center means that the molecule exists in two non-superimposable mirror image forms, or enantiomers. Therefore, 2-Bromobutane is considered a chiral molecule.

The correct answer is tertiary alcohol. Tertiary alcohols are more reactive towards nucleophilic substitution reactions compared to primary and secondary alcohols. When reacted with concentrated HCl at room temperature, tertiary alcohols undergo an SN1 mechanism, where the alcohol molecule is protonated by HCl to form a carbocation intermediate. The chloride ion then attacks the carbocation, resulting in the formation of the corresponding alkyl chloride. Primary and secondary alcohols, on the other hand, undergo SN2 mechanism, which requires a stronger nucleophile and higher temperatures.

In the reaction between chlorine and benzene in the presence of AlCl3, the species that attacks the benzene ring is Cl+. Chlorine is initially activated by AlCl3 to form Cl+ which is an electrophile. This electrophilic species then attacks the benzene ring, leading to the substitution of one of the hydrogen atoms in benzene with a chlorine atom, resulting in the formation of chlorobenzene.

The correct answer is II

Benzene on reaction with chlorine in the presence of sunlight gives BHC. BHC stands for benzene hexachloride, which is a pesticide commonly used to control insects. The reaction involves the substitution of hydrogen atoms in benzene with chlorine atoms, resulting in the formation of BHC. It is important to note that the other options mentioned (Chlorobenzene, DDT, and p-dichlorobenzene) are not the correct products of this reaction.