Physics Quiz On Thermodynamics For B.Sc. Students

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  • 1/10 Questions

    The different types of energies associated with a molecule are __________

    • Electronic energy
    • Vibrational energy
    • Rotational energy
    • All of the mentioned
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About This Quiz

Science Forum
Govt. First Grade College,
T. Narasipura, Mysuru 571124
Organized by
The Department of Physics
in Association with
IQAC

Physics Quiz On Thermodynamics For B.Sc. Students - Quiz

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  • 2. 

    Luminescence is because of

    • Photons emitted while excited electrons drops down

    • Knocking out of electrons by photons

    • Photons stimulated by photons

    • All

    Correct Answer
    A. Photons emitted while excited electrons drops down
    Explanation
    When an electron is excited to a higher energy level, it can drop back down to its original energy level. During this process, it releases energy in the form of photons, which are particles of light. This phenomenon is known as luminescence. Therefore, the correct answer is "Photons emitted while excited electrons drops down."

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  • 3. 

    The K.E. of the electron in an orbit of radius r in hydrogen atom is proportional to

    • E^(2)/r

    • E^(4)/r

    • 2e^(2)/r

    • E^(2)/2r

    Correct Answer
    A. E^(2)/r
    Explanation
    The correct answer is e^(2)/r. The kinetic energy (K.E.) of an electron in an orbit of radius r in a hydrogen atom is proportional to e^(2)/r. This is because the kinetic energy of a particle is directly proportional to its charge (e) squared and inversely proportional to its distance (r) from the center of the orbit. Therefore, as the radius decreases, the kinetic energy increases.

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  • 4. 

    In Bohr’s model of an atom which of the following is an integral multiple of h/2π?

    • Angular momentum

    • Potential energy

    • Radius of an atom

    • Kinetic energy

    Correct Answer
    A. Angular momentum
    Explanation
    In Bohr's model of an atom, the angular momentum of an electron is quantized and can only take on certain specific values. These values are given by an integral multiple of h/2Ï€, where h is Planck's constant. Therefore, the angular momentum is the only option among the given choices that can be an integral multiple of h/2Ï€.

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  • 5. 

    Solar cell works based on

    • Laser technology

    •  Tyndall effect

    • Photo-conduction

    • Thermal emission

    Correct Answer
    A. Photo-conduction
    Explanation
    Solar cells work based on the principle of photo-conduction. Photo-conduction refers to the process where the absorption of light by a material generates electric charges, leading to the flow of current. In solar cells, photons from sunlight are absorbed by a semiconductor material, such as silicon, creating electron-hole pairs. These charges then separate at the junction of different materials within the solar cell, creating a voltage difference and generating an electric current. Therefore, photo-conduction is the correct explanation for how solar cells convert sunlight into electricity.

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  • 6. 

    The transition zone for Raman spectra is __________

    • Between magnetic levels of unpaired electrons

    • Between magnetic levels of nuclei

    • Between electronic levels

    • Between vibrational and rotational levels

    Correct Answer
    A. Between vibrational and rotational levels
    Explanation
    The transition zone for Raman spectra is between vibrational and rotational levels. Raman spectroscopy is a technique that involves the interaction of light with molecules, causing a shift in energy levels. The energy levels of molecules can be categorized into electronic, vibrational, and rotational levels. In Raman spectroscopy, the transition zone refers to the energy range where transitions occur between the vibrational and rotational levels of the molecule. This transition zone is important in Raman spectroscopy as it provides information about the molecular structure and dynamics.

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  • 7. 

    The correct order of different types of energies is __________

    • Eel >> Evib >> Erot >> E tr

    • Eel >> Erot >> Evib >> E tr

    • Eel >> Evib >> Etr >> E rot

    • E<sub style="font-variant-ligatures:normal; font-variant-caps:normal; orphans:2; widows:2; -webkit-text-stroke-width:0px; text-decoration-style:initial; text-decoration-color:initial; word-spacing:0px">tr >> E<sub style="font-variant-ligatures:normal; font-variant-caps:normal; orphans:2; widows:2; -webkit-text-stroke-width:0px; text-decoration-style:initial; text-decoration-color:initial; word-spacing:0px">vib >> E<sub style="font-variant-ligatures:normal; font-variant-caps:normal; orphans:2; widows:2; -webkit-text-stroke-width:0px; text-decoration-style:initial; text-decoration-color:initial; word-spacing:0px">rot >> E <sub style="font-variant-ligatures:normal; font-variant-caps:normal; orphans:2; widows:2; -webkit-text-stroke-width:0px; text-decoration-style:initial; text-decoration-color:initial; word-spacing:0px">el

    Correct Answer
    A. Eel >> Evib >> Erot >> E tr
    Explanation
    The correct order of different types of energies is Eel (electrical energy) >> Evib (vibrational energy) >> Erot (rotational energy) >> E tr (translational energy). This order represents the hierarchy of energy types, with electrical energy being the highest in the hierarchy, followed by vibrational energy, rotational energy, and finally translational energy.

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  • 8. 

    Proton has the charge

    • 1637 times of an electron

    • 1737 times of an electron

    • 1837 times of an electron

    • 1937 times of an electron

    Correct Answer
    A. 1837 times of an electron
    Explanation
    The charge of a proton is 1837 times greater than the charge of an electron.

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  • 9. 

    If 13.6 eV energy is required to ionise the hydrogen atom, then energy required to remove an electron from n = 2 is

    • 3.4 eV

    • 0 eV

    • .4 eV

    • 6.8 eV.

    Correct Answer
    A. 3.4 eV
    Explanation
    The energy required to remove an electron from the n = 2 energy level in the hydrogen atom can be calculated using the formula E = 13.6/n^2, where E is the energy in eV and n is the principal quantum number. Plugging in n = 2, we get E = 13.6/2^2 = 13.6/4 = 3.4 eV. Therefore, the energy required to remove an electron from n = 2 is 3.4 eV.

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  • 10. 

    Visible light’s wavelength range ______________

    • 0.39 – 0.77 mm

    • 0.39 – 0.77 µm

    • 0.39 – 0.77 nm

    • 0.39 – 0.77 cm

    • Option 5

    Correct Answer
    A. 0.39 – 0.77 mm
    Explanation
    Visible light's wavelength range is typically measured in nanometers, not millimeters. The correct answer is 0.39 – 0.77 μm, which represents the range of wavelengths for visible light.

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  • Current Version
  • Mar 20, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • May 08, 2020
    Quiz Created by
    Pramodh B
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