CT Registry Review Hh

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  • 1/72 Questions

    Blood urea nitrogen level of ---mg/dl is considered outside the normal range

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    • 32
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CT Registry Review Hh - Quiz
About This Quiz

The 'CT Registry Review HH' quiz assesses knowledge on CT scanner technicalities, normal physiological parameters like blood pressure and pulse rates, and radiation safety. It is designed for medical professionals preparing for CT registry certification.


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  • 2. 

    Which of the following oral contrast agents is better for opacifying the distal small intestine

    • An ionic iodinated contrast agent

    • A non-ioni iodinated contrast agent

    • Barium sufate

    Correct Answer
    A. Barium sufate
    Explanation
    Barium sulfate is a better oral contrast agent for opacifying the distal small intestine because it is not absorbed by the body and provides excellent visualization of the gastrointestinal tract. Ionic iodinated contrast agents and non-ionic iodinated contrast agents are primarily used for imaging blood vessels and organs, and they are not as effective in opacifying the small intestine.

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  • 3. 

    Which of the following is a component not normally located in the gantry of a modern ct system

    • Pre-patient collimator

    • Solid-state detectors

    • Array processor

    • X-ray tube

    Correct Answer
    A. Array processor
    Explanation
    An array processor is not normally located in the gantry of a modern CT system. The gantry of a CT system typically houses components such as the x-ray tube, detectors, and collimators. The array processor, on the other hand, is a separate component that processes the data collected by the detectors to generate the final CT images. It is usually located outside of the gantry, in the main computer system of the CT scanner.

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  • 4. 

    Which of the following may be the cause of two parallel lines seen on a localizer image?

    • Two faulty detector elements

    • Cone beam artifact

    • Tube arching

    • A problem with the reconstruction

    Correct Answer
    A. Two faulty detector elements
    Explanation
    Two faulty detector elements may cause two parallel lines to appear on a localizer image. The localizer image is created by detecting the X-rays that pass through the patient's body using a detector array. If two detector elements are faulty and not functioning properly, they may produce a consistent error in the detected X-ray data. This error can manifest as two parallel lines on the localizer image, indicating a problem with the detector elements.

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  • 5. 

    The smalles object that can be resolved if a reconstruction FOV of 24 cm and a 512 x 512 matrix are used is ------mm

    • 0.47

    • 1.00

    • 2.13

    • 3.57

    Correct Answer
    A. 0.47
    Explanation
    The smallest object that can be resolved in this scenario can be calculated using the formula: resolution = FOV / matrix size. In this case, the resolution would be 24 cm / 512 = 0.047 cm. Since the answer choices are in millimeters, we need to convert 0.047 cm to mm, which gives us 0.47 mm. Therefore, the correct answer is 0.47.

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  • 6. 

    Which of the following values for pitch would stretch the x-ray helix the most?

    • 1.0

    • 1.5

    • 0.5

    • 0.8

    Correct Answer
    A. 1.5
    Explanation
    A larger value for pitch would stretch the x-ray helix more. In this case, the value of 1.5 is the largest among the given options, so it would stretch the x-ray helix the most.

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  • 7. 

    Which of the following is true regarding barium sulfate solutions used in ct

    • They are less concentrated than those used in conventional radiography

    • They are the same as those used in x-ray

    • They are in no way related to those used in x-ray

    • They are more concentrated than those used in x-ray

    Correct Answer
    A. They are less concentrated than those used in conventional radiography
    Explanation
    Barium sulfate solutions used in CT scans are less concentrated than those used in conventional radiography. This is because CT scans require a lower concentration of barium sulfate to achieve the desired contrast in the images. CT scans use a combination of X-rays and computer technology to create detailed cross-sectional images of the body, whereas conventional radiography uses X-rays alone. Therefore, the concentration of barium sulfate needed for CT scans is lower compared to conventional radiography.

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  • 8. 

    If there is no overlap or gabetween adjacent slices of a ct scan, CTDI-----MSAD

    • IS LESS THAN

    • EQUALS

    • IS MUCH GREATER THAN

    • IS SLIGHTLY GREATER THAN

    Correct Answer
    A. EQUALS
    Explanation
    If there is no overlap or gap between adjacent slices of a CT scan, the CTDI (Computed Tomography Dose Index) value will be equal to the MSAD (Mean Slice Aggregated Dose). This means that the average radiation dose delivered to each slice will be the same as the overall dose delivered to the patient.

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  • 9. 

    If a reconstruction FOV of 32 cm and a 512 x 512 matrix are used, the pixel size is ----mm

    • 0.35

    • 0.625

    • 1.6

    • 3.25

    Correct Answer
    A. 0.625
    Explanation
    pixel size is equal to reconstruction FOV divided by matrix 320mm divide by 512

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  • 10. 

    If the radiologist requires 2mm thick contiguous slices through the pituitary, and 2.4 cm of coverage,----slices are necessary?

    • 8

    • 10

    • 12

    • 13

    Correct Answer
    A. 12
    Explanation
    To calculate the number of slices necessary, we need to convert the coverage of 2.4 cm to millimeters, which equals 24 mm. Then, we divide the coverage by the thickness of each slice (2 mm) to get the number of slices needed. In this case, 24 mm divided by 2 mm equals 12 slices. Therefore, 12 slices are necessary to meet the radiologist's requirements.

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  • 11. 

    Barium sulfate oral contrast media would be selected instead of iodinated oral contrast media because:

    • It passes through the GI tract more quickly

    • The trauma patient may have a perforated bowel

    • The contrast media stays more dense in the distal GI track

    Correct Answer
    A. The contrast media stays more dense in the distal GI track
    Explanation
    Barium sulfate oral contrast media is selected instead of iodinated oral contrast media because it stays more dense in the distal GI tract. This is important for imaging purposes as it allows for better visualization and assessment of the lower gastrointestinal structures. Additionally, barium sulfate passes through the GI tract more quickly, which can be advantageous in certain situations. However, the fact that the trauma patient may have a perforated bowel is not a determining factor in the selection of the contrast media.

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  • 12. 

    On a multi-row detector scanner, radiation penumbra may be found:

    • On every other slice

    • Only on the trailing edges of the slices

    • On every slice

    • Only on the first and last slices of the slice volume

    Correct Answer
    A. Only on the first and last slices of the slice volume
    Explanation
    On a multi-row detector scanner, radiation penumbra may be found only on the first and last slices of the slice volume. This is because the penumbra refers to the blurred edges of an image or slice, and in this case, it is caused by the divergence of the radiation beam. As the radiation passes through the patient's body, it spreads out slightly, leading to a slight blurring at the edges of the image. This effect is most prominent at the first and last slices of the slice volume, where the radiation beam enters and exits the patient's body, respectively.

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  • 13. 

    Which of the following may reduce the out -of -fild artifact

    • Increasing the scan fild-of-view

    • Reducing the reconstruction field of view

    • Reducing the slice thickness

    • Increasing the martrix

    Correct Answer
    A. Increasing the scan fild-of-view
    Explanation
    Increasing the scan field-of-view may reduce the out-of-field artifact. Out-of-field artifacts occur when the imaged object extends beyond the field-of-view of the scanner. By increasing the scan field-of-view, a larger area of the object can be captured, reducing the likelihood of artifacts occurring outside the field-of-view. This allows for a more comprehensive and accurate representation of the imaged object.

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  • 14. 

    A------artifact is a streak artifact which arises from a high spatial requency interface btw tissues with a great difference in density

    • Tube arcing

    • Edge gradient

    • Cone beam

    • Ring

    Correct Answer
    A. Edge gradient
    Explanation
    An edge gradient artifact is a streak artifact that arises from a high spatial frequency interface between tissues with a great difference in density. This means that when there is a sharp transition or edge between two tissues that have a significant difference in density, it can cause streaks to appear on the image. This artifact is often seen in medical imaging, such as CT scans, where the density difference between tissues is more pronounced.

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  • 15. 

    What is normal blood presure values for adult systolic

    • 90-140

    • 75-90

    • 80-110

    • 70-100

    • 60-90

    Correct Answer
    A. 90-140
    Explanation
    The normal blood pressure values for adult systolic range from 90 to 140. This means that a healthy adult should have a systolic blood pressure reading between these two numbers. Systolic blood pressure is the top number in a blood pressure reading and represents the pressure in the arteries when the heart beats and pumps blood. A reading within this range indicates that the heart is functioning properly and is able to pump blood effectively throughout the body.

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  • 16. 

    If the slice thickness is changed from 5mm to 7mm and all other parameters are held constant,-----% more photons will be used inmaking the slice

    • 30

    • 40

    • 60

    • 60

    • 80

    Correct Answer
    A. 40
    Explanation
    If the slice thickness is changed from 5mm to 7mm, the volume of the slice will increase. Since all other parameters are held constant, the number of photons used to make the slice needs to increase in order to maintain the same level of image quality. The increase in slice thickness requires more photons to penetrate through the thicker slice, resulting in a 40% increase in the number of photons used.

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  • 17. 

    Which of the following is not a result of reducing the reconstruction FOV?

    • Improved spatial resolution

    • Increased appearance of image noise

    • Anatomical structures appear smaller

    Correct Answer
    A. Anatomical structures appear smaller
    Explanation
    Reducing the reconstruction FOV refers to decreasing the area of the image that is reconstructed. This means that less anatomical structures will be included in the final image, resulting in them appearing smaller. Therefore, the correct answer is that anatomical structures appear smaller.

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  • 18. 

    What is the normal blood presure values for adults diastolic

    • 60-90

    • 70-85

    • 85-100

    • 75-90

    • 50-75

    Correct Answer
    A. 60-90
    Explanation
    The normal blood pressure values for adults diastolic range from 60 to 90. Diastolic blood pressure represents the pressure in the arteries when the heart is at rest between beats. This range is considered normal and indicates a healthy blood pressure level. Values below 60 may indicate low blood pressure, while values above 90 may indicate high blood pressure.

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  • 19. 

    Which of the following would display the greates amount of partial volume artifact

    • 10mm slice from a 20 slice study

    • A 5 mm slice from a 40 slice study

    • 5 mm slice from 20 slice study

    • A, b and c would exprince the same amount of partial volume artifact

    Correct Answer
    A. 10mm slice from a 20 slice study
    Explanation
    The 10mm slice from a 20 slice study would display the greatest amount of partial volume artifact. This is because a thicker slice (10mm) is more likely to contain multiple tissue types within its volume, leading to partial volume averaging and blurring of the boundaries between these tissues. In contrast, a thinner slice (5mm) would have less partial volume artifact as it would capture a more precise representation of the individual tissues. The number of slices in the study (20 or 40) does not directly affect the amount of partial volume artifact.

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  • 20. 

    The reconstruction field-of-view determines ?

    • Partial volume

    • Edge gradient effect

    • Beam harening

    • Spatial resoulution

    Correct Answer
    A. Spatial resoulution
    Explanation
    The reconstruction field-of-view determines the spatial resolution. The field-of-view refers to the area of the object being imaged that is included in the reconstructed image. A larger field-of-view will result in a lower spatial resolution, as more information from a larger area is being spread out over the image. Conversely, a smaller field-of-view will result in a higher spatial resolution, as more detail is captured in a smaller area. Therefore, the reconstruction field-of-view directly affects the spatial resolution of the reconstructed image.

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  • 21. 

    Which of the following affects beam hardening

    • the types of tissues the beam passes through

    • The thickness of the tissues traversed by the beam

    • The energies of the photons in the beam

    Correct Answer(s)
    A. the types of tissues the beam passes through
    A. The thickness of the tissues traversed by the beam
    A. The energies of the photons in the beam
    Explanation
    Beam hardening is a phenomenon that occurs in computed tomography (CT) imaging when the X-ray beam passes through different types and thicknesses of tissues. As the X-ray beam passes through different tissues, it gets attenuated differently, causing a change in the energy spectrum of the photons in the beam. This change in energy spectrum leads to beam hardening artifacts in the resulting CT image. Therefore, both the types of tissues and the thickness of the tissues traversed by the beam, as well as the energies of the photons in the beam, can affect beam hardening.

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  • 22. 

    Which of the following statement is FALSE regarding occurrences after an x-ray photon penetrates the detector aperture

    • The photon can pass through the detector unmeasured

    • The photon is conveted completely into an electron

    • The measured signal is enhanced by an emplifier

    Correct Answer
    A. The photon is conveted completely into an electron
    Explanation
    The statement that the photon is converted completely into an electron is false. When an x-ray photon penetrates the detector aperture, it may pass through the detector unmeasured or interact with the detector material. In the case of interaction, the photon transfers only a portion of its energy to an electron in the detector material through a process called photoelectric effect or Compton scattering. The electron is then detected and contributes to the measured signal. However, the photon itself is not converted completely into an electron.

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  • 23. 

    Which of the following parameters causes helical slices to be reconstructed so they overlap

    • Table increment

    • Reconstruction interval

    • Pitch

    • Collimation

    Correct Answer
    A. Reconstruction interval
    Explanation
    The reconstruction interval parameter determines the spacing between consecutive slices during the reconstruction process. If the reconstruction interval is smaller than the collimation (width of the X-ray beam), it causes helical slices to be reconstructed so they overlap. This means that there will be some overlap between adjacent slices, resulting in a smoother and more continuous representation of the scanned object.

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  • 24. 

    A delay of about ----seconds after the start of the IV contrast injection should be used for helical scan of the neck

    • 20

    • 50

    • 35

    • 75

    Correct Answer
    A. 35
    Explanation
    A delay of about 35 seconds after the start of the IV contrast injection should be used for helical scan of the neck. This delay allows for optimal distribution of the contrast agent throughout the blood vessels in the neck, ensuring clear and accurate imaging of the area. A shorter delay may result in inadequate contrast enhancement, while a longer delay may lead to excessive contrast dispersion and reduced image quality. Therefore, a delay of 35 seconds strikes a balance between these factors and is considered optimal for this procedure.

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  • 25. 

    On a single -row detector scanner, which of the following does not decrease the pt dose

    • Decreasing the scan time while leaving the mA constant

    • Decreasing the slice thickness while covering the same anatomical region

    • Reformat the data instead of rescanning

    • Increasing the pitch

    Correct Answer
    A. Decreasing the slice thickness while covering the same anatomical region
    Explanation
    Decreasing the slice thickness while covering the same anatomical region does not decrease the patient dose. This is because decreasing the slice thickness allows for more detailed imaging of the anatomical region, but it does not affect the amount of radiation exposure the patient receives. The dose of radiation is determined by factors such as the mA setting and the scan time, which are not changed in this scenario. Therefore, decreasing the slice thickness does not decrease the patient dose.

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  • 26. 

    How would the artifact from a faulty detector element appear on a localizer image

    • A line perpendicular to the long axis of the pt table

    • It depends on the orientation in which the localizer image is performed

    • A circle in the center of the image

    • A line parallel to the long axis of the patient table

    Correct Answer
    A. A line parallel to the long axis of the patient table
    Explanation
    When a detector element is faulty, it may cause a line artifact on the localizer image that is parallel to the long axis of the patient table. This means that the line will run in the same direction as the table, indicating a problem with the detector element. The other options are incorrect because they do not describe the specific appearance of a faulty detector element artifact on a localizer image.

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  • 27. 

    WHICH OF THE FOLLOWING REDUCES PATIENT DOSE AT THE EXPENSE OF INCREASING TTHE APPARENT NOISE IN THE IMAGE

    • KVP

    • PITCH

    • TABLE INCREMENT

    • MAS

    Correct Answer
    A. MAS
    Explanation
    MAS stands for milliampere-seconds, which refers to the product of the tube current (measured in milliamperes) and the exposure time (measured in seconds). Increasing the MAS will increase the radiation dose delivered to the patient, but it will also increase the number of X-ray photons reaching the image receptor, resulting in a higher signal-to-noise ratio. Therefore, increasing the MAS will reduce patient dose at the expense of increasing the apparent noise in the image.

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  • 28. 

    ------------------scanner design was the first to acquire four slices in a single rotation

    • Second-generation

    • Third generation

    • Multi-row detector

    • Continuous rotation

    Correct Answer
    A. Multi-row detector
    Explanation
    The correct answer is "multi-row detector" because this type of scanner design was the first to acquire four slices in a single rotation. This means that the multi-row detector technology allowed for faster and more efficient scanning of the body, as it could capture multiple slices of images simultaneously. This advancement in scanner design greatly improved the speed and accuracy of medical imaging, making it a significant development in the field.

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  • 29. 

    Bremsstrahlung radiation does not include which type of electron activity

    • Collision btw an incoming electron and the nucleus of the target atom

    • Collision btw an incoming electron and an electron in an inner shell of the target atom

    • Slowing down of an incoming electron due to the effect of passing close to the positive charge of the nucleus of the target atom

    Correct Answer
    A. Collision btw an incoming electron and an electron in an inner shell of the target atom
    Explanation
    Bremsstrahlung radiation refers to the electromagnetic radiation emitted when an incoming electron is deflected or slowed down by the electric field of a nucleus. This deflection or slowing down can occur due to the electron colliding with the nucleus of the target atom or due to the electron passing close to the positive charge of the nucleus. However, it does not involve a collision between the incoming electron and an electron in an inner shell of the target atom.

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  • 30. 

    Which of the following strategies would not help us differentiate possible pathology from a partial volume artifact?

    • Inspection of adjacent slices

    • Collect additional thinner slices through suspicious region

    • Rescan and decrease pitch (without changing slice thickness)

    Correct Answer
    A. Rescan and decrease pitch (without changing slice thickness)
    Explanation
    Rescanning and decreasing pitch without changing slice thickness would not help differentiate possible pathology from a partial volume artifact. Changing the pitch would only affect the spacing between slices, not the actual thickness of each slice. Therefore, this strategy would not provide any additional information about the pathology or help in distinguishing it from a partial volume artifact.

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  • 31. 

    The hepatic arterial phase occurs about-------seconds after the start of the Iv contrast injection

    • 60 to 80

    • 40 to 60

    • 20 to 40

    • 0 to 20

    Correct Answer
    A. 20 to 40
    Explanation
    The hepatic arterial phase occurs approximately 20 to 40 seconds after the start of the IV contrast injection. During this phase, the contrast agent reaches the liver through the hepatic artery, allowing for visualization of the arterial blood supply to the liver. This phase is important in detecting and evaluating liver tumors, as they typically receive their blood supply from the hepatic artery. Timing the scan appropriately ensures optimal visualization of the arterial phase and accurate assessment of liver pathology.

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  • 32. 

    XII what kind of nerve/where it may showes

    • Vestibulocochlear/IAC

    • Glossopharyngeal nerve/softtissue

    • Hypoglossal nerve/soft tissues

    Correct Answer
    A. Hypoglossal nerve/soft tissues
    Explanation
    The hypoglossal nerve is responsible for controlling the movement of the tongue. It innervates the muscles of the tongue, allowing it to move and function properly. Soft tissues refer to the muscles, connective tissues, and other structures in the body that are not bone or cartilage. Therefore, the hypoglossal nerve is most likely to be found in soft tissues.

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  • 33. 

    A cone beam artifact may look like stars:

    • At the center of the image

    • Coming from structures around the edge of the image

    • Coming from cone-shaped structures

    • From all structures with hight ct numbers

    Correct Answer
    A. Coming from structures around the edge of the image
    Explanation
    Cone beam artifacts can appear as stars coming from structures around the edge of the image. This is because cone beam artifacts occur when the X-ray beam is not aligned with the center of rotation, causing distortion in the image. As a result, structures located near the edge of the image may appear as star-like shapes due to the cone-shaped nature of the beam.

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  • 34. 

    A circle or ring is usally cause by?

    • Cone beam artifact

    • Appearance of noise

    • Outside the scan fov

    • Faulty detector element

    Correct Answer
    A. Faulty detector element
    Explanation
    A circle or ring artifact is usually caused by a faulty detector element. This means that there is a problem with one or more of the detectors in the imaging system, which leads to an inaccurate representation of the scanned object. This can result in a circular or ring-shaped pattern appearing in the image, affecting its quality and diagnostic value.

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  • 35. 

    A difference in density of -------HU between the aorta and the inferior vena cava would indicate the non-equilibrium phase of enhancement

    • 43

    • 35

    • 25

    • 8

    Correct Answer
    A. 25
    Explanation
    A difference in density of 25 HU between the aorta and the inferior vena cava would indicate the non-equilibrium phase of enhancement. This means that there is a difference in the amount of contrast agent present in these two blood vessels, suggesting that the contrast agent is still being distributed and not yet fully equilibrated.

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  • 36. 

    There is substantial enhancement of the liver compared to tumors during the ------phase,  but during the --------phase, there is the possibility of tumor enhancement, whichmay make hepatic tumors isodense with liver tissue

    • Bolus, equilibrium

    • Non-equilibrium equilibrium

    • Non-equilibrium, bolus

    • Equilibrium, non-equilibrum

    Correct Answer
    A. Non-equilibrium equilibrium
    Explanation
    During the non-equilibrium phase, there is substantial enhancement of the liver compared to tumors. This means that the liver tissue will appear brighter or more enhanced compared to the tumors. However, during the equilibrium phase, there is a possibility of tumor enhancement, which may make the hepatic tumors isodense with liver tissue. This means that the tumors and the liver tissue may have similar levels of enhancement, making it difficult to distinguish between them.

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  • 37. 

    The portal venous phase occurs about-----seconds after the start of the IV contrast injection

    • 20 to 30

    • 40 to 60

    • 60 to 90

    • 90 to120

    Correct Answer
    A. 60 to 90
    Explanation
    The portal venous phase occurs approximately 60 to 90 seconds after the start of the IV contrast injection. During this phase, the contrast material has reached the portal vein and is circulating through the liver, allowing for optimal visualization of the liver and its vasculature. This phase is important for detecting abnormalities in the liver, such as tumors or vascular lesions.

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  • 38. 

    If an algorithm to correct for the cupping artifact is applied too agressively to the data for a head image, the-------of the image would be too bright

    • Top and bottom

    • Center

    • Edges

    Correct Answer
    A. Center
    Explanation
    If an algorithm to correct for the cupping artifact is applied too aggressively to the data for a head image, the center of the image would be too bright. The cupping artifact refers to the darkening of the periphery of an image due to the shape of the imaging equipment. Applying an aggressive correction algorithm would result in the center of the image being excessively brightened, causing an imbalance in brightness distribution.

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  • 39. 

    How would we expect metal to affect the appearance of a localizer image

    • Ct numbers of the tissues in the image will be misrepresented

    • Th metal object will be represented by high ct numbers and there will be no steaks

    • The entire image will appear blurry

    • Streaks will emanate from the metal object in the image

    Correct Answer
    A. Th metal object will be represented by high ct numbers and there will be no steaks
    Explanation
    Metal objects in a localizer image are expected to be represented by high CT numbers and there will be no streaks. This is because metal has a high density and therefore appears bright on the image. Additionally, metal objects can cause streak artifacts due to their high density, but in this case, it is stated that there will be no streaks.

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  • 40. 

    On a ct image of the brain a cupping artifact would appear brighter

    • At he anterior and posterior aspects of the brain

    • At the periphery of the brain

    • Immediately around dense structure

    • In the center of the brain

    Correct Answer
    A. At the periphery of the brain
    Explanation
    A cupping artifact refers to a distortion in the shape of an image caused by the shape of the imaging device. In the case of a CT scan of the brain, the cupping artifact would appear brighter at the periphery of the brain. This is because the cupping artifact typically causes a darkening effect towards the center of the image, making the periphery appear brighter in comparison.

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  • 41. 

    Which of the following is a typical scan delay following the start of the injection for helical ct examinations of the pancreas?

    • 50 to 60

    • 70 to 80

    • 80 to 90

    • 2 to 3 min

    Correct Answer
    A. 50 to 60
    Explanation
    A typical scan delay following the start of the injection for helical CT examinations of the pancreas is 50 to 60 seconds. This delay allows for the contrast material to reach the pancreas and enhance the visualization of the organ during the scan.

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  • 42. 

    Cranial nerves are not seen in the region of the

    • Cervical spine

    • Internal auditory canal

    • Supratentorium

    • Soft tissue neck

    Correct Answer
    A. Supratentorium
    Explanation
    The cranial nerves are a set of 12 pairs of nerves that emerge directly from the brain and are responsible for various functions related to sensory and motor control of the head and neck. They are not seen in the region of the supratentorium, which refers to the area of the brain located above the tentorium cerebelli. The cranial nerves are primarily located within the cranial cavity and do not extend into the supratentorial region. Therefore, the supratentorium is the correct answer as it is not a location where cranial nerves are found.

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  • 43. 

    Which of the following is a possible manifestation of beam hardening

    • Ct number inaccuracies

    • Streaks in the image

    • Cupping artifact

    Correct Answer(s)
    A. Ct number inaccuracies
    A. Streaks in the image
    A. Cupping artifact
    Explanation
    Beam hardening is a phenomenon that occurs in computed tomography (CT) imaging where the X-ray beam passing through an object becomes harder or more energetic as it passes through denser materials. This can result in CT number inaccuracies, where the measured Hounsfield units do not accurately represent the true tissue density. Streaks in the image can also occur due to beam hardening, as the hardening of the X-ray beam can cause streak artifacts to appear in the reconstructed image. Cupping artifact is another possible manifestation of beam hardening, where there is a darkening or cup-shaped distortion around dense objects in the image.

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  • 44. 

    Which of the following would increase the severity of th edge gradient effect?

    • Scanner with a small detector aperture

    • Scanner with a low data sampling rate

    • Using thin slices

    Correct Answer
    A. Scanner with a low data sampling rate
    Explanation
    A scanner with a low data sampling rate would increase the severity of the edge gradient effect because a low data sampling rate means that fewer data points are being collected and recorded during the scanning process. This would result in a lower resolution image and a less accurate representation of the edges and gradients in the scanned object. Therefore, the edge gradient effect would be more pronounced and severe with a scanner that has a low data sampling rate.

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  • 45. 

    Shading and inaccurate ct numbers is ualually caused ?

    • Thick slice

    • Anotomy extends outside the scan fov

    • Faulty detector element

    • Increased scan time

    Correct Answer
    A. Anotomy extends outside the scan fov
    Explanation
    When the anatomy being scanned extends outside the scan field of view (FOV), it can cause shading and inaccurate CT numbers. This means that the area outside the FOV is not captured properly, leading to incomplete or distorted images. The shading occurs because the CT scanner cannot accurately measure the attenuation of the tissues beyond the FOV. Additionally, the inaccurate CT numbers result from the incomplete data acquisition, leading to incorrect calculations of tissue densities.

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  • 46. 

    Which of the following strategies minimizes beam hardening artifact from dense contrast media?

    • Contrast solution can be diluted

    • Scan can be performed with a slight delay

    • the scan can be performed in the opposite direction

    Correct Answer(s)
    A. Contrast solution can be diluted
    A. Scan can be performed with a slight delay
    A. the scan can be performed in the opposite direction
    Explanation
    Diluting the contrast solution can minimize beam hardening artifact by reducing the concentration of dense contrast media, which can cause beam hardening. Performing the scan with a slight delay allows the contrast solution to disperse more evenly, reducing the artifact. Performing the scan in the opposite direction can also help minimize beam hardening artifact by reducing the amount of dense contrast media that the beam passes through. These strategies help to reduce the effects of beam hardening artifact and improve the quality of the scan.

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  • 47. 

    In which the patient blows the cheeks out in order to distend th epyriform sinuse

    • Letter e

    • Valsalva maneuver

    • Epiglottis

    • Demonstrates vocal cord

    Correct Answer
    A. Valsalva maneuver
    Explanation
    The Valsalva maneuver is a technique where the patient blows air out forcefully while keeping their mouth and nose closed. This increases the pressure in the chest and abdomen, causing the pyriform sinuses to distend. The pyriform sinuses are located in the throat and are important for swallowing. The other options, such as epiglottis and vocal cords, are not directly related to the action of blowing the cheeks out to distend the pyriform sinuses.

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  • 48. 

    The average pulse rate for an infant ranges

    • 90-100

    • 45-95

    • 100-180

    • 110-120

    • 120-200

    Correct Answer
    A. 100-180
    Explanation
    The correct answer is 100-180. This range is considered the average pulse rate for an infant. It is normal for an infant's pulse rate to fall within this range. A pulse rate below 100 or above 180 may indicate a potential health issue and should be monitored or evaluated by a healthcare professional.

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  • 49. 

    Beam hardening refers to:

    • Increase in the number of photons reaching the detector

    • Increase in the mumber of low energy photons reaching the detectors

    • The increase in the average energy of th ephotons that reach the detectors

    Correct Answer
    A. The increase in the average energy of th ephotons that reach the detectors
    Explanation
    Beam hardening refers to the increase in the average energy of the photons that reach the detectors. This phenomenon occurs when a beam of X-rays passes through an object and the higher energy photons are less attenuated than the lower energy ones. As a result, the average energy of the photons that reach the detectors increases, leading to beam hardening. This can cause artifacts and inaccuracies in computed tomography (CT) imaging, as the attenuation values of the object may be misrepresented.

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Quiz Review Timeline (Updated): Mar 21, 2023 +

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  • Current Version
  • Mar 21, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Apr 08, 2010
    Quiz Created by
    Hiw8
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