Thermodynamic Cycles Quiz: Engines, Cycles, Hot/Cold Reservoirs

  • Grade 9th
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| Questions: 20 | Updated: Mar 6, 2026
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1. If η=0.30, then 30% of input heat becomes work.

Explanation

Concept: meaning of efficiency as a fraction. That’s the meaning of efficiency. The remaining 70% of the input heat is rejected to the cold reservoir as q_c.

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About This Quiz
Thermodynamic Cycles Quiz: Engines, Cycles, Hot/Cold Reservoirs - Quiz

This quiz features 20 questions on thermodynamic cycles, designed for students in Grade 9. You will explore key concepts like engines, heat transfer, and the roles of hot and cold reservoirs. Understanding these topics is essential for grasping how energy is converted and utilized in real-world applications. By testing you... see moreknowledge, you can strengthen your grasp of thermodynamics and prepare for future science challenges. Dive in to discover how these principles impact everything from everyday appliances to advanced technologies.
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2. Best overall summary of a heat-engine cycle:

Explanation

Concept: standard heat-engine operation. That’s the standard heat-engine cycle idea. It uses a hot source and a cold sink so it can produce net work while obeying the second law.

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3. If an engine has higher efficiency, it generally:

Explanation

Concept: higher efficiency means less waste heat. Higher efficiency means more work per input heat, leaving less to reject. So q_c is smaller for the same q_h.

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4. A cycle must include at least two steps/processes.

Explanation

Concept: you need multiple steps to return to the start. A single step cannot return a system to its initial state unless nothing changes. To come back to the starting state after changing it, at least one additional step is required.

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5. In many engines, the working substance is a gas such as ______.

Explanation

In many engines, air serves as the working substance because it is readily available and can be easily compressed and expanded. In internal combustion engines, air mixes with fuel to facilitate combustion, producing the necessary energy to power the engine. Its properties, such as being compressible and having a low density, make it ideal for efficient energy conversion. Additionally, air plays a crucial role in thermodynamic cycles, contributing to the engine's overall performance and efficiency.

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6. A simple example of a “cycle” in daily life is:

Explanation

Concept: repeating steps that return to a start condition. Car engines repeat steps over and over, returning to a similar start point each cycle. The repetition allows continuous power output over time.

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7. Friction usually reduces the useful work output of a real engine.

Explanation

Concept: friction causes energy losses. Friction turns useful energy into thermal energy. This increases waste heat and reduces the amount of work available at the output.

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8. A cycle that produces net work requires:

Explanation

Concept: engines must reject some heat. Engines absorb heat and reject some heat while producing work. The rejected heat is required by the second law to complete the cycle.

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9. Which quantities can be nonzero over a complete cycle?

Explanation

Concept: cycles have Δu=0 but can exchange heat and do work. In cycles, Δu=0, but net q and net w can be nonzero. In fact, if net work is produced, there must be net heat input overall.

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10. If a system returns to its original state, which must be true?

Explanation

Concept: state functions vs process quantities. Only Δu must be zero; heat/work can be nonzero. Temperature can also change during steps, as long as it returns to the starting value by the end.

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11. A thermodynamic cycle is a set of processes in which a system:

Explanation

Concept: a “cycle” means returning to the same state. In a cycle, the system ends where it started (same state). That means properties like pressure, volume, and temperature return to their initial values after the full set of steps.

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12. Efficiency η of an engine is:

Explanation

Concept: efficiency = useful output / input. Efficiency is useful output divided by input. For a heat engine, the useful output is work w and the input is heat from the hot reservoir q_h.

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13. If an engine absorbs 500 J and rejects 350 J, the work output is:

Explanation

Concept: apply w=q_h−q_c. Work is the difference between heat absorbed and heat rejected. w=500-350=150 J.

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14. A heat engine can convert 100% of q_h into work in a cycle.

Explanation

Concept: second law efficiency limit. The second law requires some heat to be rejected (q_c>0). A cyclic engine cannot turn all input heat into work with no heat dumped to a colder sink.

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15. The work produced by a heat engine is given by:

Explanation

Concept: energy accounting for an engine. Work output equals heat in minus heat out. If an engine absorbs q_h and rejects q_c, the difference becomes the net work produced.

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16. Heat released to the cold sink is often called q___.

Explanation

In thermodynamics, heat released to the cold sink is commonly represented by the symbol \( q_c \), where the subscript "c" denotes the cold sink. This notation helps differentiate it from heat absorbed by the system or heat released to the hot source, often denoted as \( q_h \). The understanding of these terms is essential for analyzing heat transfer processes in various systems, including engines and refrigerators.

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17. In a heat engine, heat absorbed from the hot source is often called q___.

Explanation

In thermodynamics, the heat absorbed from the hot source in a heat engine is denoted as \( q_h \). This notation indicates the specific heat transfer associated with the hot reservoir, where the engine receives energy to perform work. The subscript "h" stands for "hot," distinguishing it from other heat transfers in the cycle, such as \( q_c \) for the cold reservoir. Understanding these terms is crucial for analyzing the efficiency and performance of heat engines.

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18. Most heat engines require:

Explanation

Concept: engines need a temperature difference. A temperature difference is needed for continuous work production. The hot reservoir provides input heat and the cold reservoir receives rejected heat.

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19. A heat engine is designed to:

Explanation

Concept: engines convert heat input into work output. Engines use heat input to produce work output, but not all heat becomes work. The rest must be released as waste heat to complete the cycle.

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20. In a complete cycle, the system’s internal energy change Δu is zero.

Explanation

Concept: internal energy is a state function. Internal energy depends only on the state, not the path. Returning to the initial state gives Δu=0 for the complete cycle.

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Ekaterina Yukhnovich |PhD |
Science Expert
Ekaterina V. is a physicist and mathematics expert with a PhD in Physics and Mathematics and extensive experience working with advanced secondary and undergraduate-level content. She specializes in combinatorics, applied mathematics, and scientific writing, with a strong focus on accuracy and academic rigor.
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If η=0.30, then 30% of input heat becomes work.
Best overall summary of a heat-engine cycle:
If an engine has higher efficiency, it generally:
A cycle must include at least two steps/processes.
In many engines, the working substance is a gas such as ______.
A simple example of a “cycle” in daily life is:
Friction usually reduces the useful work output of a real engine.
A cycle that produces net work requires:
Which quantities can be nonzero over a complete cycle?
If a system returns to its original state, which must be true?
A thermodynamic cycle is a set of processes in which a system:
Efficiency η of an engine is:
If an engine absorbs 500 J and rejects 350 J, the work output is:
A heat engine can convert 100% of q_h into work in a cycle.
The work produced by a heat engine is given by:
Heat released to the cold sink is often called q___.
In a heat engine, heat absorbed from the hot source is often called...
Most heat engines require:
A heat engine is designed to:
In a complete cycle, the system’s internal energy change Δu is...
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