Carbohydrates Nomenclature and Stereochemistry

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Quizzes Created: 2064 | Total Attempts: 1,167,242
| Questions: 8 | Updated: Aug 14, 2026
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1. What percentage of the dry matter of plants do carbohydrates comprise?

Explanation

Carbohydrates are the primary products of photosynthesis in plants, serving as a major source of energy and structural components. They include sugars, starches, and cellulose, which collectively account for a significant portion of a plant's dry mass. Research indicates that in many plant species, carbohydrates can constitute over 90% of the total dry matter, especially in the leaves and stems, where they play crucial roles in growth and development. This high percentage reflects the importance of carbohydrates in plant biology and their central role in energy storage and metabolism.

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Carbohydrates Nomenclature and Stereochemistry - Quiz

This assessment focuses on carbohydrates nomenclature and stereochemistry. It evaluates key concepts such as the building blocks of carbohydrates, the classification of carbohydrates, and the significance of stereoisomers. Understanding these principles is essential for students and professionals in biochemistry and related fields, enhancing their grasp of molecular structures and functions.

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2. Which of the following is the building block of carbohydrates, also known as the glycosyl unit?

Explanation

Glucose is a simple sugar and a primary building block of carbohydrates, often referred to as a glycosyl unit. It is a monosaccharide that serves as a fundamental energy source for cells. Carbohydrates are formed by linking glucose molecules together in various configurations, leading to the creation of disaccharides and polysaccharides. Other options like fructose and galactose are also monosaccharides but are not the primary building block; sucrose is a disaccharide composed of glucose and fructose. Thus, glucose is essential in carbohydrate structure and metabolism.

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3. Which class of carbohydrates cannot be hydrolysed into simpler compounds?

Explanation

Monosaccharides are the simplest form of carbohydrates and consist of single sugar units, such as glucose and fructose. Unlike polysaccharides, oligosaccharides, and disaccharides, which can be broken down into smaller sugar units through hydrolysis, monosaccharides cannot be further hydrolyzed. They are already in their most basic form, making them the building blocks for more complex carbohydrates. Thus, they cannot undergo hydrolysis to yield simpler compounds.

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4. Glucose is systematically named 'Aldohexose' because it has an aldehyde group and _____ carbon atoms.

Explanation

Glucose is classified as an aldohexose due to its chemical structure, which includes an aldehyde functional group and a total of six carbon atoms. The term "aldo" indicates the presence of the aldehyde group, while "hexose" refers to the six carbon atoms in the molecule. This classification is crucial for understanding glucose's role in metabolism and its function as a primary energy source in living organisms.

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5. In the name 'α-D-glucopyranose', what does the prefix 'D' indicate?

Explanation

In carbohydrate chemistry, the prefix 'D' in 'α-D-glucopyranose' indicates the configuration of the hydroxyl (OH) group on the second last carbon (C5) in the Fischer projection. For D-isomers, this OH group is positioned on the right side when the molecule is depicted in its straight-chain form. This configuration helps distinguish D-glucopyranose from its L-isomer, which has the OH group on the left. The 'α' designation further specifies the orientation of the OH group on the anomeric carbon (C1) in the cyclic form.

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6. Stereoisomers that are not mirror images of each other are called Enantiomers.

Explanation

Stereoisomers that are not mirror images of each other are known as diastereomers, not enantiomers. Enantiomers are a specific type of stereoisomer that are non-superimposable mirror images of each other, possessing chiral centers. Diastereomers, on the other hand, differ in configuration at one or more chiral centers but are not mirror images. Therefore, the statement is false as it incorrectly defines the relationship between these two categories of stereoisomers.

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7. Match each term with its correct definition.

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8. A molecule with 4 chiral centres will have how many possible stereoisomers?

Explanation

A molecule with chiral centers can exhibit stereoisomerism due to the different spatial arrangements of its atoms. For each chiral center, there are two possible configurations (R or S). Therefore, the total number of stereoisomers can be calculated using the formula 2^n, where n is the number of chiral centers. In this case, with 4 chiral centers, the calculation is 2^4, which equals 16. This means there are 16 unique stereoisomers possible for a molecule with 4 chiral centers.

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What percentage of the dry matter of plants do carbohydrates comprise?
Which of the following is the building block of carbohydrates, also...
Which class of carbohydrates cannot be hydrolysed into simpler...
Glucose is systematically named 'Aldohexose' because it has an...
In the name 'α-D-glucopyranose', what does the prefix 'D' indicate?
Stereoisomers that are not mirror images of each other are called...
Match each term with its correct definition.
A molecule with 4 chiral centres will have how many possible...
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