The Certificate Of Numerical Methods Exam Be Carefully
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The Newton Raphson method is also called as ____________
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Tangent method
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Secant method
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Chord method
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Diameter method
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This exam assesses proficiency in Numerical Methods, focusing on skills such as the Newton Raphson method, differentiation, and iterative formulas. It evaluates critical thinking and problem-solving abilities in mathematical engineering contexts.
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- 2.
If f(x) = x2-117 = 0 then the iterative formula for Newton Raphson Method is given by ____________
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X(n+1)=0.25 [x(n)+166x(n)]
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X(n+1)=0.5 [x(n)+166x(n)]
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X(n+1)=0.5 [x(n)-166x(n)]
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X(n+1)=0.25 [x(n)-166x(n)]
Correct Answer
A. X(n+1)=0.5 [x(n)+166x(n)]Explanation
The iterative formula for the Newton Raphson Method is given by x(n+1)=0.5 [x(n)+166x(n)]. This formula is derived from the Newton Raphson Method, which is an iterative method used to find the roots of a given equation. In this case, the equation is f(x) = x^2 - 117 = 0. By applying the Newton Raphson Method, the formula x(n+1)=0.5 [x(n)+166x(n)] is obtained, which represents the next approximation of the root (x(n+1)) based on the current approximation (x(n)).Rate this question:
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- 3.
The convergence of which of the following method depends on initial assumed value?
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False position
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Gauss Seidel method
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Newton Raphson method
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Euler method
Correct Answer
A. Newton Raphson methodExplanation
The Newton Raphson method is an iterative numerical method used to find the root of a function. It relies on an initial assumed value and iteratively improves the approximation until it converges to the actual root. The convergence of the method depends on the initial assumed value chosen.Rate this question:
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- 4.
The points where the Newton Raphson method fails are called?
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Floating
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Continuous
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Non-stationary
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Stationary
Correct Answer
A. StationaryExplanation
The Newton-Raphson method fails at stationary points. In mathematical terms, a stationary point is a point where the derivative of a function is equal to zero. At these points, the Newton-Raphson method is unable to converge and find the root of the function accurately. This is because the method relies on the derivative of the function to update the estimation of the root, and if the derivative is zero, the method cannot progress further. Therefore, the Newton-Raphson method fails at stationary points.Rate this question:
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- 5.
The value of y’/x’ in terms of the angle 0 is given by _____________
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Tanθ
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Secθ
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Cotθ
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Cosecθ
Correct Answer
A. TanθExplanation
The value of y'/x' in terms of the angle 0 is given by tanθ because the tangent of an angle is equal to the ratio of the length of the side opposite the angle to the length of the side adjacent to the angle in a right triangle.Rate this question:
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- 6.
The equation f(x) is given as x2-4=0. Considering the initial approximation at x=6 then the value of x1 is given as ____________
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10/3
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4/3
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7/3
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13/3
Correct Answer
A. 10/3 -
- 7.
The modification of Gauss elimination method is called as ___________
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Gauss Seidal
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Gauss Jordan
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Jacobi’s Method
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Relaxation Method
Correct Answer
A. Gauss JordanExplanation
The modification of Gauss elimination method that is called Gauss Jordan.Rate this question:
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- 8.
In Newton Raphson method f’(x) for a given point is given by the formula ____________
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Y/x’
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Y’/x
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y/x
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y’/x’
Correct Answer
A. y’/x’Explanation
The correct answer is y’/x’ because in the Newton Raphson method, f’(x) represents the derivative of the function f(x) with respect to x. The derivative of a function measures the rate at which the function is changing at a given point. In this case, y’/x’ represents the derivative of y with respect to x, which is the appropriate formula for f’(x) in the Newton Raphson method.Rate this question:
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- 9.
The equation f(x) is given as x3+4x+1=0. Considering the initial approximation at x=1 then the value of x1 is given as _______________
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1.67
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1.87
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1.86
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1.85
Correct Answer
A. 1.86Explanation
To find the value of x1, we can use the Newton-Raphson method. The formula for finding the next approximation is x1 = x0 - f(x0)/f'(x0), where x0 is the initial approximation.
Given that the initial approximation is x=1, we can substitute this value into the equation f(x) = x^3 + 4x + 1 and calculate f(1) and f'(1).
f(1) = 1^3 + 4(1) + 1 = 6
f'(1) = 3(1)^2 + 4 = 7
Substituting these values into the formula, we get:
x1 = 1 - 6/7 = 1 - 0.857 = 0.143
Therefore, the value of x1 is 0.143. However, none of the given answer choices match this value, so it seems that the question may be incomplete or not readable.Rate this question:
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- 10.
For decreasing the number of iterations in Newton Raphson method:
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The value of f’(x) must be increased
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The value of f’’(x) must be decreased
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The value of f’(x) must be decreased
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The value of f’’(x) must be increased
Correct Answer
A. The value of f’(x) must be increasedExplanation
To decrease the number of iterations in the Newton-Raphson method, the value of f'(x) must be increased. This is because f'(x) represents the derivative of the function f(x), which provides information about the slope of the function at a given point. By increasing the value of f'(x), the slope becomes steeper, allowing the Newton-Raphson method to converge more quickly towards the root of the function.Rate this question:
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Current Version
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Mar 18, 2023Quiz Edited by
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May 24, 2020Quiz Created by
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