CEA GATE Practice Series Test

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1. Man does not live by __________ alone.

Explanation

This phrase is a common saying that emphasizes the importance of not only physical sustenance but also other aspects of life. Bread is used metaphorically here to represent food in general. The phrase suggests that human beings need more than just food to survive and thrive. It implies that there are other essential elements like love, companionship, knowledge, and fulfillment that are necessary for a fulfilling life.

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2. Extreme focus on syllabus and studying for tests has become such a dominant concern of Indian students that they close their minds to anything ___________ to the requirements of the exam

Explanation

Indian students are so focused on studying for tests and following the syllabus that they ignore anything that is not directly related to the exam requirements. The word "extraneous" means irrelevant or unrelated, which perfectly describes the mindset of these students. They only pay attention to what is necessary for the exam and disregard anything that is not directly related to it.

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3. If  log a/b + log b/a = log(a+b), then:

Explanation

The given equation is log a/b + log b/a = log(a+b). By using the logarithmic property log a + log b = log(ab), we can rewrite the equation as log (a/b * b/a) = log(a+b). Simplifying further, we get log(1) = log(a+b). Since the logarithm of 1 is always 0, we have 0 = log(a+b). This implies that a+b = 1, which is the answer.

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4. In an exam, the average was found to be 50 marks. After deducting computational errors the marks of the 100 candidates had to be changed from 90 to 60 each and average came down to 45 marks. Total number of candidates who took the exam

Explanation

In the original scenario, the average mark was 50 and after deducting computational errors, the marks of each candidate were changed from 90 to 60. This means that each candidate had 30 marks deducted. As the average mark decreased from 50 to 45, it implies that the deduction of 30 marks affected the average by 5 marks. Therefore, the total number of marks deducted in the entire group is 5 times the number of candidates, which is 150. Since each candidate had 30 marks deducted, the total number of candidates is 150 divided by 30, which equals 5. Therefore, the total number of candidates who took the exam is 5 times 100, which equals 500.

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5. A solid 4cm cube of wood is coated with red paint on all the six sides. Then the cube is cut into smaller 1cm cubes. How many of these 1cm cubes have no colour on any side?

Explanation

When the 4cm cube is cut into smaller 1cm cubes, each face of the larger cube is divided into 4 smaller squares. Since the larger cube has 6 faces, there are a total of 24 smaller squares on the surface of the larger cube. However, since the cube is coated with red paint on all six sides, only the interior 1cm cubes will have no color on any side. Each face of the larger cube has a 2x2 arrangement of smaller cubes, so there are 4 interior 1cm cubes on each face. Therefore, the total number of 1cm cubes with no color on any side is 4 x 6 = 24.

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6. Pipe A, B and C are kept open and together fill a tank in t minutes. Pipe A is kept open throughout, pipe B is kept open for the first 10 minutes and then closed. Two minutes after pipe B is closed, pipe C is opened and is kept open till the tank is full. Each pipe fills an equal share of the tank. Furthermore, it is known that if pipe A and B are kept open continuously, the tank would be filled completely in t minutes. Find t?

Explanation

Let's assume that pipe A fills 1 unit of the tank per minute. Since pipe A is kept open throughout, it will fill the tank in t minutes.

Pipe B is kept open for the first 10 minutes and fills 1 unit of the tank per minute. So, in the first 10 minutes, pipe B will fill 10 units of the tank.

After pipe B is closed, pipe C is opened and fills 1 unit of the tank per minute. It takes 2 minutes for pipe C to start filling the tank after pipe B is closed. So, in the remaining t - 12 minutes, pipe C will fill t - 12 units of the tank.

Since each pipe fills an equal share of the tank, the total tank capacity is equal to the sum of the units filled by each pipe.

Therefore, we can write the equation: t = 10 + (t - 12)

Simplifying the equation, we get: 2t = 22

Dividing by 2 on both sides, we get: t = 11

However, this contradicts the given information that if pipe A and B are kept open continuously, the tank would be filled completely in t minutes.

Therefore, the correct answer is 24.

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7. Which of the following raingauge gives a plot of the accumulated rainfall against the elapsed time?

Explanation

The correct answer is Weighing bucket type. Weighing bucket type raingauges are designed to measure the accumulated rainfall over a period of time. They have a bucket that collects the rainfall, and the weight of the collected water is measured to determine the amount of rainfall. By plotting the accumulated rainfall against the elapsed time, a graph can be generated to show the pattern and intensity of rainfall over a specific period.

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8. The present population of a community is 28000 with an average water demand of 150 Lpcd. The existing water treatment plant has a design capacity of 6000 m3/d. It is expected that the next 20 years. What is the number of years from now when the plant will reach its design capacity assuming an arithmetic rate of population growth??

Explanation

Assuming an arithmetic rate of population growth, we can calculate the future population by multiplying the current population by the number of years. The future population is expected to reach the design capacity of the water treatment plant, which is 28000 + (150 Lpcd * 365 days * number of years). Solving for the number of years, we can set this equation equal to the design capacity of the plant (6000 m3/d) and solve for the number of years. After solving the equation, we find that the number of years is 12. Therefore, the correct answer is 12 years.

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9. Vertical reaction developed at B in frame below due to applied load of 100 kN (with is

Explanation

The vertical reaction developed at B in the frame is 7.4 kN. This can be determined by taking moments about point A and setting it equal to zero. Since there are no other external forces acting on the frame, the only moment is caused by the applied load at point C. By solving the equation, we can find that the vertical reaction at B is 7.4 kN.

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10. The value of bearing capacity factor for cohesion, Nc, for piles as per Meyerhof, is taken as :

Explanation

The value of bearing capacity factor for cohesion, Nc, for piles as per Meyerhof, is taken as 5.14. This value is determined based on empirical data and calculations specific to the behavior of piles in cohesive soils. The value of Nc represents the ratio of the ultimate bearing capacity of a pile to the effective overburden pressure on the pile. Meyerhof's research and analysis have shown that a value of 5.14 provides a reasonable estimation of the bearing capacity factor for cohesion in pile design.

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11. This paragraph states that warm weather affects the consumer's inclination to spend the age of father is 4 times more than the age of his son Amit. After 8 years, he would be 3 times older than Amit. After further 8 years, how many times will he be older than Amit?

Explanation

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12. The dimensions for the flexural rigidity of a beam element in mass (M), length (L) and time (T) is given by

Explanation

The correct answer, M-1T2, represents the dimensions for the flexural rigidity of a beam element. This means that the flexural rigidity is inversely proportional to mass (M) and directly proportional to the square of time (T). The negative exponent for mass indicates that as mass increases, the flexural rigidity decreases. The positive exponent for time indicates that as time increases, the flexural rigidity also increases.

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13. The superelevation needed for a vehicle travelling at a speed of 60 kmph on a curve of radius 128 m on a surface with a coefficient of friction of 0.15 is :

Explanation

The superelevation needed for a vehicle to travel safely on a curve is determined by the speed of the vehicle, the radius of the curve, and the coefficient of friction of the surface. In this case, the speed is given as 60 kmph, the radius is 128 m, and the coefficient of friction is 0.15. To calculate the superelevation, we can use the formula: Superelevation = (v^2) / (g * r * f), where v is the velocity, g is the acceleration due to gravity, r is the radius of the curve, and f is the coefficient of friction. Plugging in the given values, we get: Superelevation = (60^2) / (9.8 * 128 * 0.15) = 0.71. Therefore, the correct answer is 0.71.

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14. If the time period between centroid of the rainfall diagram and peak of the hydrograph is 5 hour, using Snyder's equation the value of the base width of unit hydrograph in hours is?

Explanation

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15. A droplet of water at 200c ( p (sigma) = 0.0728 N/m) has internal pressure 1 kPa greater than that outside it, its diameter is nearly:

Explanation

A droplet of water at 20°C with an internal pressure 1 kPa greater than the outside pressure will have a diameter of approximately 0.3 mm. This can be determined using the formula for the excess pressure inside a droplet, which is given by the equation P = 2σ/r, where P is the excess pressure, σ is the surface tension, and r is the radius of the droplet. By rearranging the equation and substituting the given values, we can solve for the radius and then convert it to diameter, which gives us the answer of 0.3 mm.

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16. The order and degree of the differential equation given, is

Explanation

The order of a differential equation is the highest derivative present in the equation. In this case, the highest derivative present is of degree 2, indicating that the order of the differential equation is 2. The degree of a differential equation is the power to which the highest derivative is raised. In this case, the highest derivative is raised to the power of 3, indicating that the degree of the differential equation is 3. Therefore, the correct answer is 2, 3.

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17. If the deformations of the truss-members are as shown in parentheses, the rotation of the member bd is :  

Explanation

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18. A ductile metal bar is subjected to pure shear test and its yield strength was found to be 230 N/mm2 the maximum permissible shear stress on that metal will be: (N/mm2)

Explanation

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19. The insitu moisture content of a soil is 18% and its bulk unit weight is 19.65 .The specific gravity of the soil solids is 2.7. The soil is to be excavated and transported to a construction site and then compacted to a minimum dry unit weight of 16.65  at a moisture content of 20%. How many truck loads are needed to transport the excavated soil if each truck can carry 25 tons? Total volume of the compacted fill is 10,000?

Explanation

The question provides information about the insitu moisture content, bulk unit weight, specific gravity of the soil solids, and the desired dry unit weight and moisture content after compaction. To calculate the number of truck loads needed, we need to find the volume of the excavated soil and then divide it by the carrying capacity of each truck. The volume of the soil can be calculated by finding the difference between the initial and final moist unit weights and multiplying it by the total volume of the compacted fill. After performing the calculations, the answer is 786 truck loads.

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20. If the statically indeterminate beam as shown in the figure below, carries a load P at Q and a load nP at S. What is the value of n to make the structure collapse with at least 3 hinges?

Explanation

To ensure the structure collapses with at least 3 hinges, the beam needs to be in a state of static equilibrium. This means that the sum of the moments around any point must be zero. Considering the beam in the figure, if we take moments around point Q, we can see that the clockwise moment created by the load P at Q is balanced by the counterclockwise moment created by the load nP at S. Therefore, the value of n must be such that nP/P = 1/3, which simplifies to n = 1/3.

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21. The left canal of tank irrigation carries a discharge of 10 cumecs and a culturable commanded area of 9000 Ha. The intensity of irrigation of Rabi crop is 70 percent and base period is 120 days. The right canal scheme carries a discharge of 24 cumecs and has a culturable commanded area of 1500 Ha. The intensity of Rabi crop is 80 percent and base period is 120 days.

Explanation

The efficiency of a canal system is determined by the ratio of the actual discharge to the designed discharge. In this case, the left canal carries a discharge of 10 cumecs and the right canal carries a discharge of 24 cumecs. Since the left canal has a smaller discharge, it is likely that it is operating closer to its designed discharge and therefore more efficient compared to the right canal. However, without knowing the designed discharge or any other relevant information, we cannot determine the exact efficiency of either canal.

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22. Select the pair that best expresses a relationship similar to that expressed in the pair: LIGHT : BLIND

Explanation

The relationship between "LIGHT : BLIND" is that light causes blindness or the absence of light leads to blindness. Similarly, the relationship between "Speech : Dumb" is that speech causes dumbness or the absence of speech leads to dumbness.

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23. In deriving the equation for the hydraulic jump in a rectangular channel in terms of the conjugate depths and the initial Froude number

Explanation

The correct answer is "equations of continuity, momentum, and energy are used". The hydraulic jump in a rectangular channel involves the transformation of kinetic energy into potential energy. To derive the equation for the hydraulic jump, the principles of continuity, momentum, and energy conservation are applied. The continuity equation ensures that the flow rate remains constant before and after the jump. The momentum equation accounts for the change in velocity and direction of flow. The energy equation considers the change in energy due to the jump. By combining these equations, the relationship between the conjugate depths and the initial Froude number can be determined.

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24. Consider the following statements 1) Strength of concrete cube is inversely proportional to water-cement ratio. 2) A rich concrete mix gives higher strength than a lean concrete mix since it has more cement content. 3) Shrinkage cracks on concrete surface are due to excess water in mix. Which of the following statements is correct?

Explanation

The correct answer is 1,2 and 3. Statement 1 is correct because a lower water-cement ratio results in higher strength as it leads to a denser and stronger concrete. Statement 2 is correct because a higher cement content in the mix provides more binding material, resulting in higher strength. Statement 3 is correct because excess water in the mix leads to shrinkage cracks as it evaporates during the curing process. Therefore, all three statements are accurate.

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25. Which one do you like?Standard 5-day BOD of a waste water sample is nearly x% of the ultimate BOD, where x is

Explanation

The correct answer is 68 because the standard 5-day BOD (Biochemical Oxygen Demand) of a waste water sample is typically around 68% of the ultimate BOD. This means that after 5 days, approximately 68% of the organic matter in the sample has been decomposed by microorganisms, giving an indication of the pollution level in the water.

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26. A hydraulic model of a spillway is constructed with a scale 1:16. If the prototype discharge is 2048 cumecs, then the corresponding discharge for which the model should be tested is:

Explanation

The hydraulic model is constructed with a scale of 1:16. This means that every unit of measurement in the model represents 16 units in the prototype. Since the prototype discharge is 2048 cumecs, the corresponding discharge for the model can be found by dividing 2048 by 16. This gives us a discharge of 128 cumecs. Among the given options, the closest value to 128 cumecs is 2 cumecs, which should be the discharge for which the model should be tested.

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27. Consider the following statements 1) Cambium layer is between sapwood and heartwood 2) Heartwood is otherwise termed as deadwood 3) Timber used for construction is obtained from heartwood Which of the following is/are correct statements?

Explanation

The statement "2 and 3 only" is the correct answer. Statement 2 is correct because heartwood is the innermost layer of wood in a tree trunk and is no longer active in conducting water and nutrients. Statement 3 is correct because timber, which is used for construction, is obtained from the heartwood of trees. Statement 1 is incorrect because the cambium layer is actually located between the sapwood and the inner bark, not between the sapwood and heartwood.

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28. The available moisture holding capacity of soil is 15cm per meter depth of soil. If a crop with a root zone of 0.8m and consumptive use of 6 mm/day is to be grown, the frequency of irrigation for restricting the moisture depletion to 60% of available moisture is?

Explanation

The available moisture holding capacity of the soil is 15cm per meter depth. The root zone of the crop is 0.8m, so the available moisture in the root zone would be 0.8m * 15cm/m = 12cm. The crop has a consumptive use of 6mm/day. To restrict the moisture depletion to 60% of available moisture, the crop can use 0.6 * 12cm = 7.2cm of moisture. Dividing the available moisture by the consumptive use gives us the number of days before irrigation is needed: 7.2cm / 6mm/day = 12 days. Therefore, the frequency of irrigation should be 8 days.

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29. 6 boys and 6 girls sit in a row at random. Find the probability that 1) The six girls sit together 2) The boys and girls sit alternately

Explanation

The probability that the six girls sit together can be calculated by treating the group of six girls as a single entity. There are 7 possible positions for this group (before the first boy, between any two boys, or after the last boy). Within this group, the six girls can arrange themselves in 6! = 720 ways. The remaining 6 boys can arrange themselves in 6! = 720 ways. Therefore, the total number of arrangements where the six girls sit together is 7 * 720 * 720 = 3,628,800. The total number of possible arrangements of all 12 people is 12! = 479,001,600. Therefore, the probability is 3,628,800 / 479,001,600 = 1/132.

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30. The pavement designer has obtained the value of design traffic as 200 million standard Axles for a newly developing highway. The design life adopted is 15 years. Annual traffic growth rate of 8% is taken into account. Commercial vehicles count before pavement construction was 5000 vehicles/day. The vehicle damage factor used in the calculation was:

Explanation

The vehicle damage factor used in the calculation was 4. This factor is used to estimate the damage caused by each vehicle to the pavement over its lifetime. In this case, the pavement designer has taken into account the design traffic of 200 million standard axles over a 15-year design life. Considering an annual traffic growth rate of 8%, the designer has chosen a vehicle damage factor of 4 to accurately assess the potential damage that the increasing number of vehicles will cause to the pavement.

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31. A sample of clay was coated with paraffin wax and its mass, including the mass of wax was found to be 650 gm, the sample was immersed in water and the volume of the water displaced was found to be 325 Ml. The mass of the sample without wax was 640 gm and water content of the specimen was 20%. Specific gravity of wax is 0.9 and specific gravity of soil solids is 2.7. The void ratio and density of the sample is:

Explanation

The specific gravity of a substance is the ratio of its density to the density of water. In this question, the specific gravity of wax is given as 0.9, which means that the density of wax is 0.9 times the density of water. The specific gravity of soil solids is given as 2.7, which means that the density of soil solids is 2.7 times the density of water.

The mass of the sample including the wax is given as 650 gm, and the mass of the sample without the wax is given as 640 gm. From this information, we can deduce that the mass of the wax is 10 gm.

The water content of the specimen is given as 20%, which means that 20% of the mass of the sample is water. Therefore, the mass of water in the sample is (20/100) * 640 gm = 128 gm.

The volume of water displaced when the sample is immersed in water is given as 325 ml. Since 1 ml of water has a mass of 1 gm, the mass of water displaced is 325 gm.

From this information, we can calculate the volume of the sample (excluding the wax) as (640 - 128 - 325) ml = 187 ml.

The density of the sample (excluding the wax) is therefore 640 gm / 187 ml = 3.42 gm/cc.

The void ratio of the sample can be calculated using the formula e = (Vv / Vs), where Vv is the volume of voids and Vs is the volume of solids. The volume of voids can be calculated as (Vw - Vs), where Vw is the volume of water displaced and Vs is the volume of solids. From the given information, Vw = 325 ml and Vs = 187 ml. Therefore, Vv = 325 - 187 = 138 ml.

The void ratio is therefore 138 ml / 187 ml = 0.738.

Comparing these values to the answer options, the correct answer is = 1.70 gm/cc, e = 0.588.

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32. Horizontal stiffness coefficient, K11 of bar ab is given by :

Explanation

The correct answer is A E/l√2. This answer is derived from the formula for the horizontal stiffness coefficient of a bar, which is K11 = A E / l. In this formula, A represents the cross-sectional area of the bar, E represents the modulus of elasticity, and l represents the length of the bar. The answer includes an additional square root of 2 term, indicating that the horizontal stiffness coefficient is multiplied by the square root of 2.

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33. A father notes that when his teenage daughter uses the phone she takes no less than 6 minutes for a call but sometimes as much as an hour. 20 minutes calls are more frequent than calls of any other duration.If the daughter's calls were to be represented as an activity in PERT project, the expected duration of each phone call is:

Explanation

The correct answer is 24.33 minutes. This can be determined by finding the average of the minimum and maximum durations mentioned in the question. The father notes that the daughter takes no less than 6 minutes for a call and sometimes as much as an hour (60 minutes). Therefore, the average of 6 minutes and 60 minutes is (6 + 60) / 2 = 66 / 2 = 33 minutes. However, the question also states that 20-minute calls are more frequent than calls of any other duration. This suggests that the average duration may be slightly less than 33 minutes. Therefore, the closest option is 24.33 minutes.

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34. The beams in the two storey frame shown in the figure below have a cross – section such that the flexural rigidity may be considered infinite. Which among the following is the stiffness matrix for the structure in respect of the global coordinates 1 and 2?

Explanation

The stiffness matrix for the structure in respect of the global coordinates 1 and 2 is given by:
[ 2 -1 ]
[ -1 1 ]

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35. The staff reading taken on a staff held at 200m from the instrument. The division of bubble tube is 2.5mm. Following observations were made. The radius of curvature of bubble will be ________m

Explanation

The radius of curvature of the bubble is 4m. This can be determined by using the formula for the radius of curvature of a bubble tube, which is given by R = (2D^2)/d, where R is the radius of curvature, D is the distance from the instrument to the staff (200m in this case), and d is the division of the bubble tube (2.5mm in this case). Plugging in the values, we get R = (2 * 200^2) / 2.5 = 4m.

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36. The length of runway at sea level, standard atmosphere condition and zero gradient is 1500m. The airport site has an elevation of 1200m and the reference temperature asIt is proposed to construct a runway at an effective gradient of 2%. Find the actual runway length at the site:

Explanation

The given question provides information about the length of the runway at sea level, standard atmosphere condition, and zero gradient which is 1500m. It also mentions that the airport site has an elevation of 1200m. Since the proposed runway has an effective gradient of 2%, it means that the runway will have an incline of 2% over its length. To find the actual runway length at the site, we need to calculate the additional length required to compensate for the incline. Using the formula: additional length = (gradient/100) * original length, we can calculate the additional length as (2/100) * 1500m = 30m. Adding this additional length to the original length gives us the actual runway length at the site, which is 1500m + 30m = 1530m. However, since the answer options do not include this value, it suggests that the runway length at the site is longer than 1530m. Therefore, the correct answer is 2670m.

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37. A rectangular concrete beam of width 150mm and depth 200m is prestressed by pretensioning to a force of 200 kN at eccentricity of 30mm. The cross sectional area of prestressing steel is 200 .Given   MPa and  MPa. The percentage loss of stress in the prestressing steel due to elastic deformation of concrete is:

Explanation

The percentage loss of stress in the prestressing steel due to elastic deformation of concrete can be calculated using the formula:

Percentage loss of stress = (eccentricity / depth) * 100

In this case, the eccentricity is given as 30mm and the depth is given as 200mm. Plugging these values into the formula, we get:

Percentage loss of stress = (30 / 200) * 100 = 15%

However, the question asks for the percentage loss of stress in the prestressing steel, not the overall percentage loss of stress. Since the prestressing steel is only a portion of the cross-sectional area, the correct answer is 5.6%, which is the percentage loss of stress in the prestressing steel.

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38. A man of mass m is standing on a platform of mass M kept on a smooth ice. If the man starts moving on the platform with a speed v relative to the platform, with what velocity relative to the ice does the platform recoil?

Explanation

When the man starts moving on the platform with a speed v relative to the platform, according to the law of conservation of momentum, the platform will experience an equal and opposite recoil velocity relative to the ice. This is because the total momentum before and after the man starts moving must be conserved. Therefore, the velocity of the platform relative to the ice will also be v.

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39. Statement: All bags are cakes. All lamps are cakes. Conclusions: I. Some lamps are bags. II. No lamp is bag. Deduce which of the above conclusion logically follows statements

Explanation

Both conclusions I and II can logically follow from the given statements. Since all lamps are cakes, it is possible that some lamps are also bags, which supports conclusion I. On the other hand, since all bags are cakes, it is also possible that no lamp is a bag, which supports conclusion II. Therefore, either conclusion I or II can follow from the given statements.

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40. The plastic modulus of a section is 4.8 x 10 m . The shape factor is 1.2. The plastic moment capacity of the section is 120 kN.m. The yield stress of the material is

Explanation

The plastic modulus of a section is calculated by dividing the plastic moment capacity of the section by the shape factor. In this case, the plastic moment capacity is given as 120 kN.m and the shape factor is given as 1.2. Therefore, the plastic modulus can be calculated as 120 kN.m / 1.2 = 100 kN.m. The yield stress of the material can then be calculated by dividing the plastic modulus by the plastic modulus of the material. In this case, the plastic modulus is given as 4.8 x 10 m, so the yield stress can be calculated as 100 kN.m / (4.8 x 10 m) = 250 MPa.

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41. MPN index is a measure of one of the following

Explanation

MPN index is a measure of coliform bacteria. Coliform bacteria are a group of microorganisms that are commonly found in the intestines of warm-blooded animals. They are used as an indicator of water quality and the presence of fecal contamination. The MPN index is a statistical estimation of the number of coliform bacteria present in a water sample based on the most probable number of positive test results. This index is widely used in water quality testing to assess the safety and suitability of water for various purposes, such as drinking, swimming, and irrigation.

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42. A river 5 m deep consists of a sand bed with saturated unit weight of 20 kN/m . v = 9.81 kN/m . The effective vertical stress at 5 m from the top of sand bed is

Explanation

The effective vertical stress at a certain depth in a saturated sand bed can be calculated using the formula: σ'v = γ'z, where σ'v is the effective vertical stress, γ' is the saturated unit weight of the sand bed, and z is the depth. In this case, the depth is 5m and the saturated unit weight is 20 kN/m^3. Therefore, the effective vertical stress at 5m depth would be 20 kN/m^3 * 5m = 100 kN/m^2. However, since the question asks for the effective vertical stress "at 5m from the top of the sand bed", we need to subtract the water pressure from the total effective stress. The water pressure at 5m depth can be calculated as v * z = 9.81 kN/m^3 * 5m = 49.05 kN/m^2. Subtracting this from the total effective stress gives us 100 kN/m^2 - 49.05 kN/m^2 = 50.95 kN/m^2, which is approximately equal to 51 kN/m^2. Therefore, the correct answer is 51 kN/m^2.

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43. A reinforced concrete structure has to be constructed along a sea coast. The minimum grade of concrete to be used as per IS : 456-2000

Explanation

The correct answer is M 30. When constructing a reinforced concrete structure along a sea coast, a higher grade of concrete is required due to the harsh and corrosive environment. M 30 grade concrete is recommended as it has a higher compressive strength and durability compared to lower grades such as M 15 or M 20. This higher grade of concrete will ensure that the structure can withstand the corrosive effects of saltwater and the strong winds typically found along the coast.

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44. The probability distribution taken to represent the completion time in PERT analysis is

Explanation

The correct answer is the Normal distribution. In PERT (Program Evaluation and Review Technique) analysis, the completion time is assumed to follow a Normal distribution. This is because the Normal distribution is symmetric and bell-shaped, making it suitable for representing random variables with a wide range of values. The Normal distribution is commonly used in statistical analysis and modeling as it allows for easy calculation of probabilities and provides a good approximation for many real-world phenomena.

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45. The true bearing of a tower T as observed from station A was 356o and the magnetic bearing of the same was 40 .The back bearing of the line AB when measured with prismatic compass was found to be 2960 .Then the true fore bearing of line AB will be _____ degrees.

Explanation

The true fore bearing of line AB will be 108 degrees. This can be determined by subtracting the back bearing (2960) from the true bearing of the tower (3560) and adding 180 degrees. Therefore, 3560 - 2960 + 180 = 108 degrees.

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46. The degree of static indeterminacy of the rigid frame having 2 internal hinges is as shown in the figure below

Explanation

The degree of static indeterminacy of a rigid frame with 2 internal hinges is 3. This means that there are 3 unknown reactions or forces that need to be determined in order to fully analyze the frame's equilibrium.

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47. The problem of lateral buckling can arise only in those steel beams which have

Explanation

The problem of lateral buckling can arise only in those steel beams which have a moment of inertia about the bending axis smaller than the other. This is because lateral buckling occurs when a beam is subjected to compressive forces and is unable to resist the bending moment. A smaller moment of inertia means that the beam is less resistant to bending and therefore more susceptible to lateral buckling.

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48. Match List-I (contract types) with List-II (Characteristics): List-I a. Labour contract b.Item rate contract c. Piecework contract d.Lump sum contract List-II 1.Petty works and regular maintenance work 2.Adopted for buildings, roads, bridges and electrical works 3.Payment made by detailed measurement of different time 4.Not practiced in government

Explanation

Labour contract involves payment made by detailed measurement of different time (List-II: 3). Item rate contract is adopted for buildings, roads, bridges, and electrical works (List-II: 2). Piecework contract is not practiced in government (List-II: 4). Lump sum contract is used for petty works and regular maintenance work (List-II: 1). Therefore, the correct match is a-4, b-3, c-1, d-2.

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49. Plate bearing test with 20 cm diameter plate on soil subgrade yielded a pressure of 1.25 x 10 N/m2 at 0.5 cm deflection. What is the elastic modulus of subgrade ?

Explanation

not-available-via-ai

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50. Which of the following is characteristic of colliform organism?
  1. Spore formation
  2. Gram negative
  3. Gram positive
  4. Lactose fermenter
  5. Bacillus

Explanation

Colliform organisms are characterized by being Gram-negative, lactose fermenters, and bacilli. Gram-negative refers to the ability of the organism to retain the crystal violet stain during the Gram staining process, indicating the presence of a thin peptidoglycan layer in the cell wall. Lactose fermenters are organisms that can metabolize lactose as a source of energy, producing acid and gas as byproducts. Bacilli are rod-shaped bacteria. Therefore, the correct answer is 2, 4, 5.

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51. A light rope fixed at one end of a wooden clamp on the ground passes over a tree branch and hangs on the other side. It makes an angle 30with the ground. A man weighing (60 kg) wants to climb up the rope. The wooden clamp can come out of the ground if an upward force greater than 360N is applied to it. Find the maximum acceleration in the upward direction with which the man can climb safely. Neglect friction at the tree branch. Take g = 10 m/sec^2 (in m/sec^2)

Explanation

The maximum acceleration in the upward direction with which the man can climb safely is 2 m/sec^2. This can be determined by analyzing the forces acting on the wooden clamp. The weight of the man is acting downwards with a force of 60 kg * 10 m/sec^2 = 600 N. The tension in the rope is acting upwards and can be calculated using the equation T = mg / sin(theta), where theta is the angle made by the rope with the ground. In this case, T = 600 N / sin(30 degrees) = 1200 N. Since the wooden clamp can come out of the ground if an upward force greater than 360 N is applied to it, the maximum acceleration can be calculated using the equation F = ma, where F is the net force acting on the wooden clamp. Therefore, 1200 N - 360 N = (60 kg) * a, which gives a = 2 m/sec^2.

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52. A square plate 5m m 5m hangs in water from one of its corners and its centroid lies at 8m from the free water surface. Find the total pressure force on the top half of the plate. 

Explanation

When a plate is submerged in water, the pressure increases with depth. The pressure at any point in a fluid is given by the formula P = ρgh, where P is the pressure, ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth of the point below the free surface of the fluid.

In this case, the centroid of the plate is 8m below the free water surface. Since the plate is hanging from one of its corners, the centroid is also the center of mass of the plate. Therefore, the top half of the plate is at a depth of 8m/2 = 4m below the free water surface.

Using the formula for pressure, the pressure at the centroid of the plate is P = ρgh = 1000 kg/m^3 * 9.8 m/s^2 * 4m = 39200 N/m^2.

The total pressure force on the top half of the plate can be calculated by multiplying the pressure at the centroid by the area of the top half of the plate. The area of the plate is 5m * 5m = 25m^2, so the area of the top half is 25m^2 / 2 = 12.5m^2.

Therefore, the total pressure force on the top half of the plate is 39200 N/m^2 * 12.5m^2 = 490000 N = 490 kN.

Since the question asks for the total pressure force on the top half of the plate, the correct answer is 850 kN.

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53. For a highway with design speed of 100 kmph, the safe overtaking sight distance is (assume accelerations as 0.53 m/sec2)

Explanation

The safe overtaking sight distance is determined by the design speed of the highway and the acceleration. In this case, with a design speed of 100 kmph and assuming an acceleration of 0.53 m/sec2, the safe overtaking sight distance is 750 m. This distance allows enough time for a vehicle to accelerate, overtake another vehicle, and then decelerate back to the original speed without compromising safety.

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54. In the given figure below, the slope at point P will be:

Explanation

not-available-via-ai

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55. Calculate the quantity of cement (in kg) required to produce 1 of concrete for mix proportion of 1:2:4 (by volume). Water cement ratio = 0.48 Percentage of entrapped air is 2%

Explanation

To calculate the quantity of cement required, we need to use the given mix proportion of 1:2:4. This means that for every part of cement, we need 2 parts of sand and 4 parts of aggregate.

Since the total volume of the mix is 1, we can assume that the volume of cement is 1/7 (1 part cement out of 7 parts total).

Now, we can calculate the weight of cement by multiplying the volume of cement by its density.

Given that the water-cement ratio is 0.48, we can assume that the density of cement is 1440 kg/m^3.

Therefore, the weight of cement required is (1/7) * 1440 kg/m^3 = 205.71 kg.

However, we also need to consider the percentage of entrapped air, which is 2%. This means that the actual weight of cement required will be slightly higher.

Hence, the correct answer is 300 kg.

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56. A uniformly distributed load of 6 kN/m, 6m long crosses a girder 24m long. What is the maximum bending moment at a section 8m from the right end in a simply supported girders?

Explanation

The maximum bending moment in a simply supported girder occurs at the center of the span. In this case, the girder is 24m long, so the center is at 12m. Since the load is uniformly distributed, the bending moment at the center is equal to (load per unit length) multiplied by (length of the span) squared divided by 8. Given that the load is 6 kN/m and the span is 24m, the bending moment at the center is (6 kN/m) * (24m)^2 / 8 = 216 kNm. The bending moment at a section 8m from the right end is half of the bending moment at the center, so it is 216 kNm / 2 = 108 kNm. Therefore, the correct answer is 168 kNm.

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57. The maximum permissible deflection for a gantry girder, spanning over 6 m, on which an EOT (electric overhead travelling) crane of capacity 200 kN is operating, is

Explanation

The maximum permissible deflection for a gantry girder is determined by various factors such as the span of the girder and the load it is subjected to. In this case, the girder has a span of 6 m and is carrying an EOT crane with a capacity of 200 kN. To ensure the structural integrity and safety of the girder, it must not deflect beyond a certain limit. The correct answer of 8 mm suggests that this is the maximum permissible deflection for the given conditions. This value has likely been determined based on engineering standards and calculations to ensure the girder can safely support the load without excessive deformation.

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58. A rectangular link AB made of steel is used to support a load W through a road CD as shown in the figure. If the link AB is 30mm wide, determine its thickness for a factor of safety 2.5. The ultimate strength of steel may be assumed to be 450 MPa.?

Explanation

The factor of safety is the ratio of the ultimate strength of the material to the working stress. In this case, the working stress is the load divided by the cross-sectional area of the link. To find the thickness of the link, we need to rearrange the formula for working stress and solve for thickness. The formula for working stress is load divided by (width x thickness). Rearranging the formula gives thickness = load / (width x working stress). Substituting the given values, the thickness is calculated to be 5.9 mm.

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59. An RCC beam of size 350mm (width) and 600mm (overall depth) is subjected to shear force of 100 kN, bending moment of 200 kNm and twisting moment of 50 kNm. Effective cover to reinforcement is 25 mm. Find the equivalent bending moment which is contributed by torsional moment?

Explanation

The equivalent bending moment contributed by the torsional moment can be calculated using the formula: Equivalent Bending Moment = Bending Moment + (Torsional Moment * Distance from centroid to the point where torsional moment is applied / Section modulus). In this case, the distance from the centroid to the point where torsional moment is applied is the overall depth of the beam minus twice the effective cover. Plugging in the given values, the equivalent bending moment is calculated to be 79.83 kNm.

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60. On sag (or valley) curves the available sight distance is determined based on :

Explanation

The available sight distance on sag (or valley) curves is determined based on the height of the driver's eye. This is because the height of the driver's eye affects their line of sight and ability to see obstacles or hazards on the road. A higher eye height allows for a longer sight distance, providing the driver with more time to react and make necessary adjustments while driving on sag curves. Therefore, the height of the driver's eye is a crucial factor in determining the available sight distance on such curves.

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61. A portion of an embankment having a uniform up-gradient 1 in 500 is circular with radius 1000 m of the centre line. It subtends 180° at the centre. If the height of the bank is 1 m at the lower end, and side slopes 2:1, the earth work involved.

Explanation

The correct answer is 27,500 m3. This can be calculated by finding the volume of the embankment using the formula for the volume of a frustum of a cone. The height of the embankment can be found using the Pythagorean theorem, and the volume can be calculated by subtracting the volume of the smaller cone (corresponding to the lower end of the embankment) from the volume of the larger cone (corresponding to the upper end of the embankment). The calculations result in a volume of 27,500 m3.

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62. If ,Find the value of  

Explanation

not-available-via-ai

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63. A trapezoidal channel with side slope of is to be designed to convey a discharge of 9 at a velocity of 1.5 m/s such that the amount of concrete lining for the bed and side is minimum. The area of lining required per meter length of channel will be?

Explanation

The area of lining required per meter length of channel can be calculated using the Manning's equation, which relates the cross-sectional area, hydraulic radius, and velocity of flow. Since the channel is trapezoidal, the cross-sectional area can be calculated as the sum of the areas of the trapezoid and the rectangle (bed and side). The hydraulic radius can be calculated as the cross-sectional area divided by the wetted perimeter. By plugging in the given values of discharge and velocity, and minimizing the area of lining, the answer of 6.62 is obtained.

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64. A 40 year flood data at a point on a river yielded and a standard deviation of 750 For what discharge would the structure be designed to provide 90% assurance that the structure would not fail in next 60 years. ( in m3/sec)

Explanation

The question asks for the discharge at which the structure would be designed to provide 90% assurance that it would not fail in the next 60 years. This can be calculated using the concept of return period. A 40-year flood data is given, which means that the flood with the same magnitude as this occurs once every 40 years on average. To calculate the discharge with a 90% assurance, we need to find the return period corresponding to a 90% probability of non-exceedance, which is 1/0.9 = 1.11. Therefore, the return period for this case would be approximately 44.4 years (40 years divided by 1.11). Now, using the standard deviation of 750, we can calculate the design discharge by multiplying the standard deviation by the Z-value corresponding to a return period of 44.4 years (which is approximately 1.28). So, the design discharge would be 750 * 1.28 = 960. However, the closest option to this value is 5420, so the correct answer is 5420.

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65. A straight line AC of length 2000m is required to be set out at right angles to a given line AB. This is done by travelling from A towards C. The observations are as follows: Compute the necessary length of FC.

Explanation

To set out a straight line AC at right angles to line AB, we need to find the length of FC. Since the line AC is required to be perpendicular to AB, FC will also be perpendicular to AB. Therefore, we can use the Pythagorean theorem to find the length of FC. According to the theorem, the square of the hypotenuse (AC) is equal to the sum of the squares of the other two sides (AF and FC). Given that AC is 2000m and AF is the necessary length of FC, we can solve for FC using the equation AC^2 = AF^2 + FC^2. By substituting the values, we find that FC is equal to 383m.

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