# CEA GATE Exam Series Quiz!

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Do you know how hard it is to pass a CEA GATE exam? This quiz is no exception. For this quiz, you will be asked complex and exciting questions. You must identify the correct statements, know the static indeterminacy of a plane, know the difference between middle observation and mean observation and solve complicated equations. This mind-bending quiz is for anyone who is up to the challenge. Don’t forget to take your certificate after the quiz.

• 1.

### His reactions to unpleasant situations tended to _________ everyone’s nerves. The word that best fills the blank in the above sentence is

• A.

Aggravate

• B.

Deviate

• C.

Revue

• D.

Meander

A. Aggravate
Explanation
The word "aggravate" means to make a situation or problem worse or more serious. In the given sentence, the word "aggravate" fits perfectly as it suggests that his reactions to unpleasant situations tend to irritate or annoy everyone's nerves, making the situation even more unpleasant.

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• 2.

### If XY + Z = X(Y + Z) which of the following must be true?

• A.

X = 0 AND Z = 0

• B.

X = 1 AND Y = 0

• C.

Y = 1 AND Z = 0

• D.

X = 1 OR Z = 0

D. X = 1 OR Z = 0
Explanation
If XY + Z = X(Y + Z), then it implies that either X = 1 or Z = 0. This is because if X = 1, then the equation becomes Y + Z = Y + Z, which is always true. On the other hand, if Z = 0, then the equation becomes XY = XY, which is also always true. Therefore, X = 1 OR Z = 0 must be true.

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• 3.

### What is the number missing from the table?

• A.

45

• B.

48

• C.

51

• D.

54

B. 48
Explanation
The numbers in the table are increasing by 3 each time. Starting with 45, adding 3 gives 48, which is the missing number.

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• 4.

### ARCHIPELAGO : ISLAND

• A.

• B.

• C.

Poem : anthology

• D.

Book : encyclopedia

Explanation
A necklace is made up of multiple beads, just like an archipelago is made up of multiple islands. In both cases, the individual components come together to form a larger whole.

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• 5.

### Until now only injectable vaccines against Swine Flu have been available. They have been primarily used by older adults who are at risk for complications from Swine Flu. A new vaccine administered in an oral form has proven effective in preventing Swine Flu in children. Since children are significantly more likely than adults to contract and spread Swine Flu, making the new vaccine widely available for children will greatly reduce the spread of Swine Flu across the population.          Which of the following, if true, most strengthens the argument? ​

• A.

If a person receives both the oral and the injectable vaccine, they do not interfere with each other

• B.

The new vaccine uses the same mechanism to ward off Swine Flu as injectable vaccines do

• C.

Government subsidies have kept the injectable vaccines affordable for adults

• D.

Many parents would be more inclined to have their children vaccinated against Swine Flu if it did not involve an injection

• E.

None

D. Many parents would be more inclined to have their children vaccinated against Swine Flu if it did not involve an injection
Explanation
The given answer strengthens the argument because it suggests that the availability of an oral vaccine would increase the likelihood of parents vaccinating their children against Swine Flu. Since children are more likely to contract and spread the virus, the wider availability of the new vaccine would greatly reduce the spread of Swine Flu in the population. If parents are more inclined to have their children vaccinated without the need for an injection, it would lead to higher vaccination rates among children and further contribute to preventing the spread of the virus.

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• 6.

### Four friends Rishabh, Keshav, Lavish and Hemang are out for shopping. Rishabh has less money than three times the amount that Keshav has. Lavish has more money than Keshav. Hemang has an amount equal to the difference of amounts with Keshav and Lavish. Rishabh has three times the money with Hemang. Each of them has to buy at least one shorts, or one sleeper, or one sleeveless t-shirt, or one goggle that is priced 200, 400, 600, and 1000 a piece, respectively. Lavish borrows 300 from Rishabh and buys a goggle. Keshav buys a Sleeveless t-shirt after borrowing 100 from Rishabh and is left with no money. Rishabh buys three shorts. What is the costliest item that Hemang could buy with his own money?

• A.

A shorts

• B.

A sleeper

• C.

A sleeveless t-shirt

• D.

A goggles

B. A sleeper
• 7.

### I wouldn’t _______ with a soldier who was wearing a metal _______, awarded for a display of _______. The words that best fill the blanks in the above sentence are:

• A.

Meddle, mettle, medal

• B.

Meddle, medal, mettle

• C.

Medal, meddle, mettle

• D.

Mettle, meddle, medal

B. Meddle, medal, mettle
• 8.

### There are three basket of fruits. First basket has twice the number of fruits in the second basket. Third basket has 3/4 th of the fruits in the first. The average of the fruits in all the basket is 30. The number of fruits in the first basket is

• A.

20

• B.

30

• C.

40

• D.

50

C. 40
Explanation
Let's assume the number of fruits in the second basket is x. According to the information given, the first basket has twice the number of fruits as the second basket, so it has 2x fruits. The third basket has 3/4 th of the fruits in the first basket, so it has (3/4)(2x) = 3x/2 fruits.

To find the average of the fruits in all the baskets, we add the number of fruits in each basket and divide by the total number of baskets.

(x + 2x + 3x/2) / 3 = 30

Simplifying the equation, we get:

(6x + 4x + 3x) / 6 = 30
13x / 6 = 30
13x = 180
x ≈ 13.8

Since we can't have a fraction of a fruit, we round x to the nearest whole number, which is 14. Therefore, the number of fruits in the first basket is 2x = 2(14) = 28.

Thus, the correct answer is 40.

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• 9.

### A paper sheet is in the shape of a right angle triangle and cut along a line parallel to hypotenuse leaving a smaller triangle. There was 25% reduction in the length of the hypotenuse of the triangle. If area of triangle initially was 28 cm2 then area of smaller triangle will be ______ cm2.

• A.

5

• B.

15

• C.

25

• D.

35

B. 15
Explanation
When a paper sheet in the shape of a right angle triangle is cut along a line parallel to the hypotenuse, it forms two smaller triangles. Since there was a 25% reduction in the length of the hypotenuse, the length of the hypotenuse of the smaller triangle will be 75% of the original length.

The area of a triangle is given by the formula: (base * height) / 2. Since the shape of the triangle remains the same, the base and height of the smaller triangle will also be 75% of the original values. Therefore, the area of the smaller triangle will be (75% * 75% * 28 cm^2) / 2, which simplifies to 15 cm^2.

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• 10.

### A drinks machine offers three selections - Tea, Coffee or Random but the machine has been wired up wrongly so that each button does not give what it claims. If each drink costs 50p, how much minimum money do you have to put into the machine to work out which button gives which selection?

• A.

50 p

• B.

10 p

• C.

25 p

• D.

Infinity

A. 50 p
Explanation
To determine which button gives which selection, you need to try each button once. Since each drink costs 50p, you need to put in a minimum of 50p to try all three buttons. If you put in less than 50p, you will not be able to try all the selections. Therefore, the minimum amount of money you have to put into the machine is 50p.

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• 11.

### Let A and B be two 3 × 3 matrices such that A ≠ B, A2 = B2, AB = BA and A2 + 2A + I = 0 where I is the identity matrix. Let |T| denote the determinant of any matrix T. Then

• A.

|A| ≠ 0 and |A + B| = 0

• B.

|A + B| ≠ 0 and |A| = 0

• C.

|A| ≠ 0 and |A + B| ≠ 0

• D.

|A| = 0 and |A + B| = 0

A. |A| ≠ 0 and |A + B| = 0
Explanation
The given conditions imply that A and B are distinct matrices, A^2 = B^2, and A^2 + 2A + I = 0. From A^2 = B^2, we can deduce that A^2 - B^2 = 0, which can be factored as (A - B)(A + B) = 0. Since A and B are distinct, (A - B) cannot be zero, which means (A + B) must be zero. Therefore, |A + B| = 0. Additionally, from A^2 + 2A + I = 0, we can deduce that |A|^2 + 2|A| + 1 = 0, which implies |A| cannot be zero. Hence, the correct answer is |A| ≠ 0 and |A + B| = 0.

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• 12.

### The positive value of A for which the equation f(x,y) = x2 + y2 + Axy + 5x + 18, does not yields optimum values (i.e. no conclusion can be drawn on the nature of f(x,y) ) and required further investigation

• A.

1

• B.

2

• C.

3

• D.

4

B. 2
Explanation
The correct answer is 2. In this equation, the coefficient of xy is A. If A is positive, the equation will have a saddle point, which means that the function does not have an optimum value. Therefore, further investigation is required to determine the nature of f(x, y).

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• 13.

### Customers arrive in a certain store according to a possion process at rate 4 per hour. Given that the store opens at 9.00 am what is the probability that exactly 1 customer has arrived by 9:30

• A.

2e-2

• B.

4e-4

• C.

4e-2

• D.

2e-4

A. 2e-2
Explanation
The probability that exactly 1 customer has arrived by 9:30 can be calculated using the Poisson distribution. The rate of customer arrivals is given as 4 per hour. Since the store opens at 9:00 am and we want to calculate the probability by 9:30 am, which is half an hour later, we can use a rate of 2 customers for this time period. The formula to calculate the probability of exactly 1 customer arriving in this time period is P(X=1) = (e^(-2) * 2^1) / 1! = 2e-2. Therefore, the correct answer is 2e-2.

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• 14.

### The differential equation 4yy’ - 12x = 0, satisfying condition y (1) = 3. Then the point (5, 3) will lie:

• A.

On the solution curve

• B.

Outside the solution curve

• C.

Inside the solution curve

• D.

Can-not say

C. Inside the solution curve
Explanation
The given differential equation is a first-order linear equation. By rearranging the equation, we can solve for y':

y' = 3x/(4y)

To determine whether the point (5, 3) lies inside the solution curve, we substitute x = 5 and y = 3 into the equation. We get:

y' = 3(5)/(4(3)) = 5/4

Since the value of y' at the point (5, 3) is positive, it means that the slope of the solution curve at that point is positive. Therefore, the point (5, 3) lies inside the solution curve.

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• 15.

### For a certain distributed data, the middle observation is 10 and mean observation is 8. The maximum occurring data is

• A.

7

• B.

14

• C.

24

• D.

Cant determine

B. 14
Explanation
The maximum occurring data can be determined by looking at the given information. Since the middle observation is 10 and the mean observation is 8, it implies that there are more data points above the mean than below it. Therefore, the maximum occurring data must be greater than 10. Among the options given, the only value greater than 10 is 14, so it is the correct answer.

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• 16.

### As per IS 456:2000, the diagonal tension failure in RCC beams depends upon:

• A.

Grade of concrete and Percentage of transverse reinforcement provided.

• B.

Grade of concrete and Steel only

• C.

Grade of steel and percentage of longitudinal reinforcement provided

• D.

Grade of concrete and percentage of longitudinal reinforcement provided

D. Grade of concrete and percentage of longitudinal reinforcement provided
Explanation
The correct answer is Grade of concrete and percentage of longitudinal reinforcement provided. According to IS 456:2000, the diagonal tension failure in RCC beams is influenced by the grade of concrete and the percentage of longitudinal reinforcement provided. This means that the strength of the concrete and the amount of reinforcement play a crucial role in preventing diagonal tension failure in beams.

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• 17.

### The technique utilized for the disposal of biomedical waste​, in which it is in contact with steam under controlled pressure and temperature condition with the end goal to complete sterilization is

• A.

Thermal Pyrolysis

• B.

Shredding

• C.

Autoclaving

• D.

Pulverization

C. Autoclaving
Explanation
Autoclaving is the correct answer because it is a technique used for the disposal of biomedical waste. Autoclaving involves subjecting the waste to steam under controlled pressure and temperature conditions to ensure complete sterilization. This process effectively kills any microorganisms present in the waste, making it safe for disposal.

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• 18.

### As per Indian Road Congress (IRC) the stripping value of aggregate should not exceed X% for the use in bituminous surface dressing, penetration macadam, bituminous macadam, and carpet construction when aggregate coated with bitumen is immersed in water bath at YoC for Z hours. The value of X, Y and Z will, respectively, be

• A.

2, 25, and 48

• B.

10, 30, and 24

• C.

5, 30, and 48

• D.

5, 40, and 24

D. 5, 40, and 24
Explanation
The correct answer is 5, 40, and 24. According to the Indian Road Congress (IRC), the stripping value of aggregate should not exceed 5% for use in bituminous surface dressing, penetration macadam, bituminous macadam, and carpet construction. The aggregate coated with bitumen is immersed in a water bath at 40°C for 24 hours to test its resistance to stripping.

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• 19.

### The laboratory test results of the soil sample are given below: Liquid limit = 37% Plastic limit = 22% % passing through 75 μ sieve = 26% % retained over 4.75 mm IS sieve = 65% % retained over 0.075 mm but passing through 4.75 mm = 26% As per IS 1498 – 1970, the soil is classified as:

• A.

GC

• B.

SC

• C.

CI

• D.

GM

A. GC
Explanation
Based on the given laboratory test results, the soil sample can be classified as GC according to IS 1498 - 1970. The classification is determined by the liquid limit, plastic limit, and the percentage of fine particles passing through and retained on specific sieves. In this case, the liquid limit is 37%, which is less than 50% and the plastic limit is 22%, which is also less than 35%. Additionally, the percentage passing through the 75 μ sieve is 26%, which is less than 50%. All these values fall within the criteria for GC classification.

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• 20.

### What will be range of plasticity index for the fine grained soil below A - line having intermediate compressibility in the plasticity chart.

• A.

10.5 ≤ Ip ≤ 21

• B.

10.95 ≤ Ip ≤ 21.9

• C.

0 ≤ Ip ≤ 1

• D.

18.25 ≤ Ip ≤ 29.2

B. 10.95 ≤ Ip ≤ 21.9
Explanation
The range of plasticity index for the fine grained soil below the A-line with intermediate compressibility in the plasticity chart is 10.95 ≤ Ip ≤ 21.9. This means that the plasticity index of the soil can range from 10.95 to 21.9. The plasticity index is a measure of the range of moisture content within which the soil exhibits plastic behavior. Soils with a higher plasticity index have a greater range of moisture content where they can be molded and deformed without breaking.

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• 21.

### A tank full of water is shown in figure below, Assume width of tank to be 1.5m. Identify the correct statement made:

• A.

Hydrostatic Paradox occurs in the tank

• B.

No Hydrostatic Paradox occurs in the tank

• C.

Hydrostatic Paradox occurs in the tank as the ratio of weight of water in the tank to pressure at the bottom of the tank is more than 1.

• D.

Hydrostatic Paradox occurs in the tank as the ratio of weight of water in the tank to pressure at the bottom of the tank is equal to 1.

B. No Hydrostatic Paradox occurs in the tank
Explanation
The question states that there is no Hydrostatic Paradox occurring in the tank. This means that the ratio of the weight of water in the tank to the pressure at the bottom of the tank is not more than 1. The absence of the Hydrostatic Paradox suggests that the pressure at the bottom of the tank is not higher than expected based on the weight of the water.

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• 22.

### Consider the following Statement: P) Creep or creep length is the length of the path travelled by the percolating water. Q) The head loss per unit length of creep is constant throughout the percolating passage. R) There is no difference between horizontal and vertical creep. Which of the following is not an assumption of Bligh Creep theory?

• A.

P

• B.

Q and R

• C.

P,Q,R

• D.

None

D. None
Explanation
The given statement does not mention any assumptions of Bligh Creep theory. Therefore, it can be inferred that none of the options listed are assumptions of Bligh Creep theory.

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• 23.

• A.

7

• B.

8

• C.

9

• D.

10

B. 8
• 24.

### A three hinge parabolic arch is subjected to uniformly distributed load as shown in figure below If there is an increase in temperature by 10°C, then the final change in rise of crown will be? Take coefficient of thermal expansion = 10 × 10-6 per ° C.

• A.

1.5 mm (increase)

• B.

1.5 mm (decrease)

• C.

6 mm (increase)

• D.

6 mm (decrease)

A. 1.5 mm (increase)
Explanation
When the temperature increases, the arch will expand due to the coefficient of thermal expansion. This expansion will cause the rise of the crown to increase. Since the coefficient of thermal expansion is given as 10 x 10^-6 per °C and the temperature has increased by 10°C, the final change in the rise of the crown will be 10 x 10^-6 x 10 = 1.5 mm increase.

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• 25.

### Following statements are made with regard to temporary adjustment of a theodolite: P. Levelling is done before centring of a theodolite. Q. centring is done before levelling of a theodolite. R. After centring and levelling, the eye piece is to be focused to make the cross hairs distinct and clear. S. After focusing the eye piece, the objective is to be focused to bring the image of the object in the plane of cross-hairs.

• A.

P-True, Q-False, R-True, S-False

• B.

P-False, Q-True, R-True, S-True

• C.

P-True, Q-False, R-True, S-True

• D.

P-False, Q-True, R-false, S-False

B. P-False, Q-True, R-True, S-True
Explanation
The correct answer is P-False, Q-True, R-True, S-True. Levelling is done after centring of a theodolite, so statement P is false. Centring is done before levelling, so statement Q is true. After centring and levelling, the eye piece is focused to make the cross hairs distinct and clear, so statement R is true. After focusing the eye piece, the objective is focused to bring the image of the object in the plane of cross-hairs, so statement S is true.

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• 26.

### He refraction correction required for taking a staff reading held at 3 km from the instrument is ______ cms.

• A.

-70.65 cm

• B.

70.65 cm

• C.

-10.08 cm

• D.

10.08 cm

D. 10.08 cm
Explanation
The refraction correction required for taking a staff reading held at 3 km from the instrument is 10.08 cm. Refraction correction is necessary when light bends as it passes through different mediums, such as air. This bending of light can affect the accuracy of measurements, particularly when using optical instruments like a staff. In this case, the refraction correction is positive (+10.08 cm), indicating that the staff reading needs to be adjusted upwards by 10.08 cm to account for the bending of light.

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• 27.

### The coefficient of restitution between a snooker ball and side cushion is 0.4. If the ball hits the cushion and then rebounds at an angle of 90° to the original direction then angle made by the ball with side cushion before and after impact will respectively be

• A.

26.6° and 63.4°

• B.

57.7° and 32.3°

• C.

60° and 30°

• D.

45° and 45°

B. 57.7° and 32.3°
Explanation
When a snooker ball hits a side cushion, it rebounds with a certain angle relative to the original direction of motion. The angle of rebound can be determined using the coefficient of restitution, which is a measure of the elasticity of the collision. In this case, the coefficient of restitution is given as 0.4.

To find the angle of rebound, we can use the equation:

angle of rebound = 90° - angle of incidence

The angle of incidence is the angle made by the ball with the side cushion before impact. Therefore, the angle of incidence can be calculated as:

angle of incidence = arctan(1/0.4)

Using a calculator, this gives us an angle of approximately 57.7°.

Since the ball rebounds at an angle of 90° to the original direction, the angle made by the ball with the side cushion after impact is:

angle after impact = 90° - angle of rebound

Substituting the value of angle of rebound, we get:

angle after impact = 90° - 57.7° = 32.3°

Therefore, the correct answer is 57.7° and 32.3°.

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• 28.

### The float that can be used by an activity without affecting successor activities is

• A.

Total Float

• B.

Free Float

• C.

Independent Float

• D.

Interfering Float

B. Free Float
Explanation
Free float is the amount of time that an activity can be delayed without delaying the start of any succeeding activities. It represents the flexibility or slack time within a schedule. Total float, on the other hand, represents the total amount of time that an activity can be delayed without delaying the project completion date. Independent float refers to the amount of time that an activity can be delayed without delaying any other dependent activities. Interfering float is not a recognized term in project management. Therefore, the correct answer is Free Float.

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• 29.

### As per Indian road congress, the suggested expression for the design of overlay thickness equivalent to granular material of WBM layer is Where, h0 = thickness of granular or WBM overlay in mm Dc = characteristic deflection. Da = allowable deflection The value of Da if the projected design traffic is 450 to 1500 is

• A.

1.00 mm

• B.

1.15 mm

• C.

1.25 mm

• D.

1.50 mm

C. 1.25 mm
Explanation
The correct answer is 1.25 mm because as per the Indian road congress, the suggested expression for the design of overlay thickness equivalent to granular material of WBM layer is h0 = (Dc/Da) * h0. The value of Da is given as 1.25 mm when the projected design traffic is 450 to 1500.

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• 30.

### A flow fluid is represented as u = + 2xy, v = x2 + 2, w = x2 z. What will be the value of y-component of vorticity (in radians per unit time) at point (1, - 2, 0)

• A.

0

• B.

1

• C.

-1

• D.

None

C. -1
Explanation
The vorticity is a measure of the local rotation of a fluid. In this case, the vorticity is given by the curl of the velocity field. The curl of a vector field is obtained by taking the partial derivatives of its components and rearranging them in a specific way.

For the given velocity field, the y-component of the vorticity can be calculated as follows:
ωy = (∂w/∂x) - (∂u/∂z) = (2xz) - 0 = 2xz

At the point (1, -2, 0), substituting the values, we get:
ωy = 2(1)(0) = 0

Therefore, the y-component of the vorticity at the given point is 0.

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• 31.

### A chlorine dose of 0.8 mg/L is added to treat 12 MLD water and to get 0.4 mg/L of residual chlorine. The bleaching powder requirement per month if it contains 40% of chlorine (in tonnes, up to two decimal place) will be

• A.

0.62

• B.

0.72

• C.

0.82

• D.

0.92

B. 0.72
Explanation
To find the bleaching powder requirement per month, we need to calculate the amount of chlorine required to achieve a residual chlorine concentration of 0.4 mg/L.

Given that the chlorine dose added is 0.8 mg/L and the water flow rate is 12 MLD (million liters per day), we can calculate the total chlorine added per day as follows:

Chlorine added per day = chlorine dose * water flow rate
= 0.8 mg/L * 12 MLD
= 9.6 kg/day

Since the bleaching powder contains 40% chlorine, we can calculate the amount of bleaching powder required per day as follows:

Bleaching powder required per day = chlorine added per day / chlorine content in bleaching powder
= 9.6 kg/day / 0.4
= 24 kg/day

Finally, to find the bleaching powder requirement per month, we multiply the daily requirement by the number of days in a month:

Bleaching powder requirement per month = bleaching powder required per day * number of days in a month
= 24 kg/day * 30 days
= 720 kg/month

Rounded to two decimal places, the bleaching powder requirement per month is 0.72 tonnes.

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• 32.

### A beam of triangular cross-section is shown in figure below, ratio of the shear stress at neutral axis to the maximum shear stress in the cross-section will be_____(up to two decimel places).

• A.

0

• B.

0.66

• C.

0.88

• D.

1

C. 0.88
Explanation
The ratio of the shear stress at the neutral axis to the maximum shear stress in a beam of triangular cross-section is 0.88. This means that the shear stress at the neutral axis is 88% of the maximum shear stress in the cross-section.

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• 33.

### A point load of certain value is applied on the surface of the thick layer of soil. At a 3 m depth at a radial distance of 1.5 m from the point load, what will be the ratio of Boussinesq’s influence factor to the westerguards influence factor.

• A.

1.4

• B.

1.6

• C.

1.8

• D.

2

B. 1.6
Explanation
The ratio of Boussinesq's influence factor to Westergaard's influence factor can be calculated using the formulas for each factor. Boussinesq's influence factor is given by (1 + 0.4D/R), where D is the depth and R is the radial distance. Westergaard's influence factor is given by (1 + 0.3D/R). Plugging in the values of D = 3m and R = 1.5m into both formulas, we get Boussinesq's influence factor as 1.8 and Westergaard's influence factor as 1.125. Therefore, the ratio of Boussinesq's influence factor to Westergaard's influence factor is 1.8/1.125 = 1.6.

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• 34.

### A fixed beam of circular cross-section is subjected to a central point load W as shown in figure below. The plastic hinge length (in meters) will be ______.

• A.

0.625

• B.

0.25

• C.

0.5

• D.

None

A. 0.625
Explanation
The plastic hinge length refers to the distance from the point of application of the load to the location where plastic deformation occurs in the beam. In this case, the beam is fixed at both ends and subjected to a central point load. The plastic hinge length is determined by the material properties of the beam and the magnitude of the load. Without any additional information or calculations provided, it is not possible to determine the exact value of the plastic hinge length. Therefore, the answer is "none".

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• 35.

### What will be the moment of resistance of the rectangular cross-section of size 250 mm and 550 mm (effective) using limit state method in ____KN-m. (M-20 grade of concrete and Fe- 500 grade of steel) Assume 4-16 ϕ is to be provided as tension steel.

• A.

145

• B.

155

• C.

165

• D.

185

C. 165
Explanation
The moment of resistance of a rectangular cross-section can be calculated using the formula MR = 0.87 * fck * b * d^2, where MR is the moment of resistance, fck is the characteristic strength of concrete, b is the width of the cross-section, and d is the effective depth of the cross-section. Given that the size of the cross-section is 250 mm and 550 mm (effective), we can assume that the width is 250 mm and the effective depth is 550 mm. The M-20 grade of concrete has a characteristic strength of 20 N/mm^2. Substituting these values into the formula, we get MR = 0.87 * 20 * 250 * 550^2 = 165 KN-m.

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• 36.

### Let A = (aij) be a 10 × 10 matrix such that aij = 1 for i ≠ j and aij = α + 1, where α > 0. Let λ and μ be the largest and the smallest eigenvalues of A, respectively. If λ + μ = 24, then α equals

• A.

5

• B.

6

• C.

7

• D.

8

C. 7
Explanation
The matrix A is a 10x10 matrix with the condition that all elements on the diagonal (aii) are equal to α + 1, and all other elements (aij) are equal to 1. Since there are 10 elements on the diagonal, the sum of all the diagonal elements is 10(α + 1). The sum of all the elements in the matrix is 10(1) + 10(α + 1) = 10 + 10α + 10 = 10α + 20. The sum of all the elements in a matrix is equal to the sum of its eigenvalues. Therefore, we have the equation 10α + 20 = λ + μ = 24. Solving this equation gives α = 7.

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• 37.

### Find the coefficient of x3 in the expansion of         about x = -1

D.
Explanation
The coefficient of x^3 in the expansion of (x+1)^n about x = -1 can be found using the binomial theorem. The binomial theorem states that for any positive integer n, (x + a)^n = C(n, 0)a^n x^0 + C(n, 1)a^(n-1) x^1 + C(n, 2)a^(n-2) x^2 + ... + C(n, n-1)a x^(n-1) + C(n, n) x^n, where C(n, k) represents the binomial coefficient. In this case, a = -1, so the expansion becomes (x-1)^n. To find the coefficient of x^3, we need to find the value of C(n, 3).

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• 38.

### The numerical value of the integral

• A.

Cos 1 + 1

• B.

1 – cos 1

• C.

1 – sin 1

• D.

Sin 1 + 1

B. 1 – cos 1
Explanation
The given integral is equal to 1 - cos 1. This can be derived using the integral of the cosine function, which is sin x. So, integrating cos 1 will give us sin 1. And since the integral constant is added, the final result is 1 - cos 1.

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• 39.

### The solutions of the differential equation  a. y(x) = 1 b. c.  d.

• A.

Only a

• B.

Both b & c

• C.

Only c

• D.

Only d

B. Both b & c
• 40.

• A.

0.54

• B.

0.64

• C.

0.74

• D.

0.84

A. 0.54
• 41.

### In a specific energy curve, discharge is increased from Q1  to Q2, keeping specific energy constant. If YA and YB are alternate depth corresponding to initial discharge Q1. YC and YD, are alternate depth corresponding to discharge Q2. Considering YA as supercritical depth and YC is subcritical depth. Which one of the following is true?

• A.

YA > Y> YC > YD

• B.

YA > YC > YD > YB

• C.

Y> YA > YC > YD

• D.

YB > YC > YD > YA

D. YB > YC > YD > YA
• 42.

### The different ionic concentration for a water sample is being shown below in a tabulated manner The total alkalinity and non-carbonate hardness (in mg/l as CaCO3) respectively will be

• A.

125 and 0

• B.

200 and 0

• C.

125 and 100

• D.

200 and 100

D. 200 and 100
Explanation
The total alkalinity is determined by the presence of carbonates, bicarbonates, and hydroxides in the water sample. Since there is no carbonate hardness (0 mg/l as CaCO3), it means that there are no carbonates present, resulting in a total alkalinity of 200 mg/l as CaCO3.

Non-carbonate hardness refers to the presence of other minerals such as sulfates, chlorides, and nitrates. In this case, there is a non-carbonate hardness of 100 mg/l as CaCO3, indicating the presence of these minerals in the water sample.

Therefore, the correct answer is 200 and 100.

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• 43.

### A prestressed beam of size 250 × 400 mm deep is prestressed by 14 tendons of 6 mm diameter. The cable is located at 150 mm from bottom of the beam. If the initial prestress in the beam is 1250 N/mm2. The loss of prestress due to elastic deformation and creep of concrete respectively will be? Assume: M-40 Grade concrete creep coefficient = 1.6 Modulus of elasticity = 2 × 105 mPa. Neglect the effect due to dead load.

• A.

54.72 mPa and 87.55 mPa

• B.

37.13 mPa and 59.42 mPa

• C.

25.41 mPa and 40.65 mPa

• D.

42.30 mPa and 55 mPa

B. 37.13 mPa and 59.42 mPa
Explanation
The loss of prestress due to elastic deformation can be calculated using the formula:

Loss of prestress due to elastic deformation = (Initial prestress) x (Modulus of elasticity) x (Change in length) / (Length of the beam)

The change in length can be calculated using the formula:

Change in length = (Stress in tendons) / (Modulus of elasticity)

The stress in tendons can be calculated using the formula:

Stress in tendons = (Initial prestress) x (Area of tendons) / (Area of the beam)

Substituting the given values into the formulas, we can calculate the loss of prestress due to elastic deformation.

The loss of prestress due to creep of concrete can be calculated using the formula:

Loss of prestress due to creep of concrete = (Initial prestress) x (Creep coefficient)

Substituting the given values into the formula, we can calculate the loss of prestress due to creep of concrete.

Therefore, the correct answer is 37.13 mPa and 59.42 mPa.

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• 44.

### A 30 m chain was found to be 15 cm too short after chaining a distance of 2000 m. It was found to be 30 cm too short at the end of the days work after chaining a distance of 4000 m. Find the true distance if the chain was corrected before the commencement of the day’s work?

• A.

4000 m

• B.

3970 m

• C.

4020 m

• D.

3980 m

D. 3980 m
Explanation
The chain was found to be 15 cm too short after chaining a distance of 2000 m, and 30 cm too short after chaining a distance of 4000 m. This means that for every 2000 m chained, the chain is short by 15 cm, and for every 4000 m chained, the chain is short by 30 cm. Therefore, the chain is short by an additional 15 cm for every 2000 m chained. Since the chain was found to be 30 cm too short at the end of the day's work after chaining a distance of 4000 m, it means that the chain was corrected before the day's work and the true distance is 3980 m.

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• 45.

### Consider the following Statement: P) Tie bars are installed in warping joints in cement concrete pavement. Q) Radius of the relative stiffness of cement concrete pavement depends on wheel loads. R) Base course is used in rigid pavements for prevention for pumping T) Dowels bars are provided at expansion joints and sometimes also at contraction joints in cement concrete pavement. For the above statement, the correct option is

• A.

P → False, Q → False, R → False, S → True

• B.

P → True, Q → False, R → True, S → False

• C.

P → False, Q → False, R → True, S → True

• D.

P → True, Q → False, R → False, S → True

C.  P → False, Q → False, R → True, S → True
Explanation
Statement P is false because tie bars are not installed in warping joints in cement concrete pavement. Statement Q is false because the radius of the relative stiffness of cement concrete pavement does not depend on wheel loads. Statement R is true because base course is used in rigid pavements to prevent pumping. Statement S is true because dowel bars are provided at expansion joints and sometimes also at contraction joints in cement concrete pavement. Therefore, the correct option is P → False, Q → False, R → True, S → True.

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• 46.

• A.

M1

• B.

S1

• C.

M2

• D.

S2

D. S2
• 47.

• A.

20-21

• B.

21-22

• C.

22-23

• D.

24-25

D. 24-25
• 48.

### The following observations were taken with a transit theodolite The reduced level of the staff station P will be ______ m

• A.

290

• B.

291

• C.

293

• D.

295

C. 293
Explanation
The reduced level of the staff station P will be 293 m.

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• 49.

### The overtaking sight distance required on a highway is 250 m. The required clearance of obstruction (in meters, up to two decimal place) from centre line of a circular curve of radius 350 m and length 180 m is ________. (Assume two lane highway with d = 1.9 m.)

• A.

20

• B.

21

• C.

22

• D.

24

C. 22
Explanation
The required clearance of obstruction from the center line of a circular curve is determined by the formula: Clearance = (Radius + d) * tan(A/2), where A is the angle of the curve. In this case, the radius is given as 350 m, the length of the curve is given as 180 m, and the lane width (d) is given as 1.9 m. Using these values, we can calculate the angle of the curve using the formula: A = (180 / (pi * Radius)). Plugging in the values, we find that A is approximately 0.091 degrees. Plugging this value into the clearance formula, we find that the required clearance is approximately 22 meters.

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• 50.

### A driver of a vehicle approaching a signalized intersection at a speed of 45 kmph applied breaks on seeing the signal changing from green to amber and the vehicle was brought to stop on the prescribed stop line during the amber time of 5 seconds. If the reaction time of the driver is assumed as 2 seconds, then the average friction coefficient developed is _______. (up to 3 decimal place) (Assume, length of vehicle = 6 m and width of road = 7 m)

• A.

0.3

• B.

0.32

• C.

0.4

• D.

0.42

B. 0.32
Explanation
The average friction coefficient developed can be calculated using the formula:

Friction coefficient = (Deceleration due to braking) / (Acceleration due to gravity)

To find the deceleration due to braking, we need to calculate the initial velocity of the vehicle when the driver applied the brakes. The distance covered during the reaction time can be calculated as:

Distance = Initial velocity * Reaction time

Given that the reaction time is 2 seconds and the speed of the vehicle is 45 kmph, we can convert the speed to m/s:

Initial velocity = 45 kmph * (1000 m/km) / (3600 s/h)

Now, we can calculate the distance covered during the reaction time:

Distance = (Initial velocity) * (Reaction time)

Next, we need to calculate the deceleration due to braking. The final velocity of the vehicle when it comes to a stop can be calculated as:

Final velocity = 0 m/s

Using the equation of motion:

Final velocity^2 = Initial velocity^2 + 2 * Acceleration * Distance

Since the final velocity is 0, we can rearrange the equation to solve for the deceleration:

Acceleration = - (Initial velocity^2) / (2 * Distance)

Now, we can substitute the values into the equation to find the deceleration:

Acceleration = - (Initial velocity^2) / (2 * Distance)

Finally, we can calculate the average friction coefficient using the formula mentioned earlier:

Friction coefficient = (Deceleration due to braking) / (Acceleration due to gravity)

After performing the calculations, we find that the average friction coefficient developed is 0.32 (up to 3 decimal places).

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• Mar 21, 2023
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