GATE Online Mock Exam Quiz!

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GATE Online Mock Exam Quiz! - Quiz

Questions and Answers
  • 1. 

    A Carrier is a frequency modulated with a sinusoidal signal of 2 kHz, resulting in a maximum frequency deviation of 5 kHz, the Bandwidth of the modulated signal.

    • A.

      32 KHz

    • B.

      14 KHz

    • C.

      15 KHz

    • D.

      7 Khz

    • E.

      None Of these

    Correct Answer
    B. 14 KHz
    Explanation
    When a carrier signal is frequency modulated with a sinusoidal signal, the bandwidth of the modulated signal can be calculated using Carson's rule. According to Carson's rule, the bandwidth is equal to twice the sum of the maximum frequency deviation and the highest frequency component of the modulating signal. In this case, the maximum frequency deviation is 5 kHz and the highest frequency component of the modulating signal is 2 kHz. Therefore, the bandwidth of the modulated signal is 2 * (5 kHz + 2 kHz) = 14 kHz.

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  • 2. 

    A Certain telephone line bandwidth is 3.5 kHz, the data rate can be transmitted if we use binary signaling with the raised cosine pulses and a roll-off factor α = 0.25

    • A.

      1400 b/s

    • B.

      2800 b/s

    • C.

      5600 b/s

    • D.

      3600 b/s

    • E.

      None Of These

    Correct Answer
    C. 5600 b/s
  • 3. 

    Consider a system with the transfer function G(s) = . Its damping ratio will be 0.5 when the value of K is  

    • A.

      1/7

    • B.

      2/7

    • C.

      3

    • D.

      7

    • E.

      None Of these

    Correct Answer
    A. 1/7
  • 4. 

    The root locus of the system G(s) H(s) =  has the break-away point located at

    • A.

      (–0.680, 0)

    • B.

      (–3.786, 0)

    • C.

      (–0.5, 0)

    • D.

      (–0.880, 0)

    • E.

      (–0.450, 0

    Correct Answer
    D. (–0.880, 0)
  • 5. 

    Two identical and parallel dipole antenna are kept apart by a distance of λ/4 in the H-plane. They are fed with equal currents but the right most antenna has a phase shift of +90º.

    • A.
    • B.
    • C.
    • D.
    • E.

      None Of These

    Correct Answer
    A.
    Explanation
    There will no pattern E Plane Only in H Plane

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  • 6. 

      The system with the open loop transfer function G(s) H(s) = has a gain margin & cross over frequency of

    • A.

      0 dB, 1 rad/sec

    • B.

      3.5 dB, 2 rad/sec

    • C.

      5 dB, 5 rad/sec

    • D.

      7 dB, 1 rad/sec

    • E.

      7 dB, 2 rad/sec

    Correct Answer
    A. 0 dB, 1 rad/sec
  • 7. 

    The signal x(t) shown in figure can be expressed as      

    • A.

      U (t + 1) – 2u(t – 1) + 2u(t – 2)

    • B.

      U(t – 1) – 2u(t + 1) + 2 u(t + 2)

    • C.

      U(t – 1) – 2u(t + 1) + 2 u(t + 2)

    • D.

      U(t – 1) + 2u(t + 1) – 2u(t + 2)

    • E.

      None Of These

    Correct Answer
    A. U (t + 1) – 2u(t – 1) + 2u(t – 2)
    Explanation
    The given signal x(t) can be expressed as u (t + 1) – 2u(t – 1) + 2u(t – 2).

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  • 8. 

    An air filled rectangular waveguide has inner dimension of 3 cm × 2 cm. The wave impedance of the TE20 mode of propagation in the waveguide at a frequency of 20 GHz is (free space impedance  η0 = 377Ω)

    • A.

      461 Ω

    • B.

      400 Ω

    • C.

      308 Ω

    • D.

      435 Ω

    • E.

      445 Ω

    Correct Answer
    A. 461 Ω
    Explanation
    The wave impedance of the TE20 mode of propagation in a rectangular waveguide can be calculated using the formula Z = (2π/λ) * sqrt(1 - (λ/λc)^2), where λ is the wavelength and λc is the cutoff wavelength. The cutoff wavelength for the TE20 mode can be calculated using the formula λc = 2a/sqrt(4 - m^2), where a is the width of the waveguide and m is the mode number. Substituting the given values into the formulas, we can calculate the wave impedance to be approximately 461 Ω.

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  • 9. 

    The circuit in the figure has two CMOS-NOR gates. This circuit functions as a  

    • A.

      Flip-flop

    • B.

      Schmitt Trigger

    • C.

      Monosatable Multivibrator

    • D.

      Bistable Multivibrator

    • E.

      None Of These

    Correct Answer
    A. Flip-flop
    Explanation
    The circuit in the figure consists of two CMOS-NOR gates. A flip-flop is a circuit that can store one bit of information and has two stable states. The inputs of the CMOS-NOR gates are connected in such a way that they can function as a flip-flop. Therefore, the correct answer is flip-flop.

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  • Current Version
  • Mar 22, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Jan 01, 2014
    Quiz Created by
    Appliedjobz
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