Maths SAT Preparations Trivia Questions
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If four apples cost 20 cents, then, at this rate, how much would ten apples cost?
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$.40
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$.50
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$.60
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$.70
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$.80
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- 2.
If y% of 50 is 32, then what is 200% of y?
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16
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32
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64
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128
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256
Correct Answer
A. 128Explanation
If y% of 50 is 32, it means that y is equal to 64. To find 200% of y, we multiply y by 2, which gives us 128. Therefore, the answer is 128.Rate this question:
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- 3.
In the following sequence:-1,1,2,-1,1,2,-1,1,2What is the sum of the first 25 terms?
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15
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16
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18
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19
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21
Correct Answer
A. 15Explanation
The given sequence consists of three repeating terms: -1, 1, and 2. The sum of these three terms is 2. Since there are 25 terms in total, we can divide 25 by 3 to find the number of complete repetitions of the sequence, which is 8. Therefore, the sum of the first 24 terms (8 complete repetitions) is 8 multiplied by 2, which equals 16. Finally, adding the 25th term, which is -1, to the sum gives us a total of 15.Rate this question:
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- 4.
The area of a right triangle is 10 square centimeters. If the length of each leg, in centimeters, is a positive integer, then what is the least possible length, in centimeters, of the hypotenuse?
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Square root of 29
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Square root of 41
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Square root of 101
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Square root of 104
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Square root of 401
Correct Answer
A. Square root of 41Explanation
The area of a right triangle is given by the formula (1/2) * base * height. In this case, we are given that the area is 10 square centimeters. Since both the base and height are positive integers, we need to find two integers that multiply to give 20. The possible pairs of integers are (1, 20), (2, 10), and (4, 5). Using the Pythagorean theorem, we can calculate the length of the hypotenuse for each pair. The pair (4, 5) gives us a hypotenuse length of the square root of 41, which is the smallest possible length among the given options.Rate this question:
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- 5.
How many integer pairs (m,n) satisfy the statements 0< m + n < 50, and m/n equals 8?
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5
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6
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7
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8
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More than 8
Correct Answer
A. 5Explanation
The equation m/n = 8 implies that m = 8n. Substituting this into the inequality 0 < m + n < 50 gives 0 < 9n < 50. Dividing all parts of the inequality by 9 gives 0 < n < 50/9, which means that n can take on integer values from 1 to 5. Therefore, there are 5 integer pairs (m, n) that satisfy the given conditions.Rate this question:
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- 6.
A jar contains only white and blue marbles of identical size and weight. The ratio of the number of white marbles to the number of blue marbles is 4 to b. If the probability of choosing a white marble from the jar at random is 1/4, then what is the value of b?
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1
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2
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6
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12
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16
Correct Answer
A. 12Explanation
The probability of choosing a white marble from the jar at random is 1/4. Since the ratio of white marbles to blue marbles is 4 to b, this means that out of every 4 + b marbles, 4 are white. Therefore, the value of b must be 12 in order for the probability of choosing a white marble to be 1/4.Rate this question:
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- 7.
If y is a number less than 0 but greater than -1, which of the following expressions has the greatest value?
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100y
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Y^2
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Y^3
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Y^4
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Y^5
Correct Answer
A. Y^2Explanation
When y is a number less than 0 but greater than -1, y^2 will always be positive because squaring a negative number gives a positive result. On the other hand, 100y will be negative since y is negative. Since y^2 is positive and 100y is negative, y^2 will have the greatest value among the given expressions.Rate this question:
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- 8.
The first day of a particular month is Tuesday. What day of the week will it be on the 31st day of the month?
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Wednesday
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Thursday
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Friday
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Saturday
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Sunday
Correct Answer
A. ThursdayExplanation
If the first day of the month is Tuesday, and there are 31 days in the month, then we can count that there are 4 complete weeks in the month. Since each week has 7 days, we subtract 28 days from the 31st day, which leaves us with 3 remaining days. Therefore, the 31st day of the month will be three days after Tuesday, which is Thursday.Rate this question:
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- 9.
The volume of a right cylinder A is twice the volume of a right cylinder B. If the height of cylinder B is twice the height cylinder A, then what is the ratio of the radius of cylinder A to the radius of cylinder B?
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1 to 2
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1 to 1
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Square root of 2, to 1
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2 to 1
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4 to 1
Correct Answer
A. 2 to 1Explanation
The volume of a cylinder is directly proportional to the square of its radius and its height. Since the volume of cylinder A is twice the volume of cylinder B, and the height of cylinder B is twice the height of cylinder A, we can set up the following equation: (πrA^2)(2hA) = (πrB^2)(hB). Simplifying this equation, we get rA^2 * 2 = rB^2 * 1. Since the height ratio is not mentioned, we can assume it cancels out. Therefore, the ratio of the radius of cylinder A to the radius of cylinder B is 2 to 1.Rate this question:
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- 10.
In a set of 30 different positive integers, every number is even and/or a multiple of 3. If 22 of these numbers are even and 15 are multiples of 3, then how many of these numbers are multiples of 6?
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23
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22
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15
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11
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7
Correct Answer
A. 7Explanation
Since every number in the set is even and/or a multiple of 3, the numbers that are both even and multiples of 3 are multiples of 6. We are given that there are 22 even numbers and 15 multiples of 3. However, some of these numbers may be counted twice since they can be both even and multiples of 3. To find the number of multiples of 6, we need to subtract the overlap. The overlap can be found by taking the smaller number, which is 15 in this case. Therefore, the number of multiples of 6 is 15 - (22 - 15) = 7.Rate this question:
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- 11.
If at least one wuzzle is grumpy, then some fuzzles are lumpy.If the statement above is true, then which of the following must also be true?
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If all wuzzles are grumpy, then all fuzzles are lumpy.
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If no wuzzle is grumpy, then all fuzzles are lumpy.
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If all fuzzles are lumpy, then all wuzzles are grumpy.
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If no wuzzle is grumpy, then no fuzzle is lumpy.
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If no fuzzle is lumpy, then no wuzzle is grumpy.
Correct Answer
A. If no fuzzle is lumpy, then no wuzzle is grumpy.Explanation
If no fuzzle is lumpy, then no wuzzle is grumpy. This can be inferred from the original statement. If at least one wuzzle is grumpy, then some fuzzles are lumpy. Therefore, if no fuzzles are lumpy, it means that there are no grumpy wuzzles.Rate this question:
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Feb 27, 2024Quiz Edited by
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Oct 31, 2008Quiz Created by
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