Grade 5 Math Mayhem: The Ultimate Quiz Challenge!

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Janaisa Harris, BA-Mathematics |
Mathematics Expert
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Ms. Janaisa Harris, an experienced educator, has devoted 4 years to teaching high school math and 6 years to tutoring. She is now broadening her educational impact by engaging in curriculum mapping for her county. This endeavor enriches her understanding of educational strategies and their implementation.
, BA-Mathematics
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• 1.

Which of these numbers if divided by 7 will have a remainder?

• A.

35

• B.

63

• C.

69

• D.

84

C. 69
Explanation
To determine our answer, we need to check which number is divisible by 7 without a remainder. Thus, 35 divided by 7 equals 5, 63 divided by 7 equals 9, and 84 divided by 7 equals 12. Therefore, the only number that cannot be divided by 7 without a remainder is 69.

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• 2.

Ï€r2 is the formula for

• A.

The area of a circle

• B.

The area of a cube

• C.

The area of a triangle

• D.

None of these

A. The area of a circle
Explanation
The formula πr2 represents the area of a circle. The symbol π represents the mathematical constant pi, which is approximately equal to 3.14159. The radius of the circle is denoted by r, and squaring it (r2) gives the area of the circle. Therefore, the correct answer is "The area of a circle."

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• 3.

• A.

3243

• B.

3300

• C.

6821

• D.

4638

A. 3243
• 4.

What is 152/4?

• A.

38

• B.

40

• C.

42

• D.

44

A. 38
Explanation
The correct answer is 38 because when we divide 152 by 4, we get 38.

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• 5.

What is a prime number?

• A.

A number with more than 2 factors

• B.

A whole number

• C.

A number with only factors 1 and itself

• D.

A number in decimals

C. A number with only factors 1 and itself
Explanation
A prime number is a number that can only be divided by 1 and itself without leaving a remainder. It does not have any other factors. For example, 2, 3, 5, 7, and 11 are prime numbers because they can only be divided by 1 and themselves. Any number with more than 2 factors, such as 4 (1, 2, and 4), is not a prime number.

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• 6.

One-fifth of something is equal to 20 percent of it.

• A.

True

• B.

False

A. True
Explanation
The statement is true because one-fifth is equal to 20 percent. This can be understood by converting the fraction one-fifth to a percentage, which is done by multiplying it by 100. One-fifth multiplied by 100 equals 20, therefore it is equal to 20 percent.

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• 7.

The formula for the volume of a sphere is V = (4/3)πr^3. The formula for the surface area of a sphere is A = 4πr^2.

• A.

True

• B.

False

A. True
Explanation
The given answer is true because the formulas provided for the volume and surface area of a sphere are correct. The volume formula is V = (4/3)πr^3, where r is the radius of the sphere, and the surface area formula is A = 4πr^2. These formulas are widely accepted and used in mathematics to calculate the volume and surface area of a sphere. Therefore, the answer is true.

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• 8.

What is the percent of 3/5?

• A.

60%

• B.

85%

• C.

80%

• D.

92%

A. 60%
Explanation
The percent of 3/5 can be found by dividing 3 by 5 and then multiplying the result by 100. This gives us (3/5) * 100 = 300/5 = 60. Therefore, the correct answer is 60%

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• 9.

Solve: 35 - 12 x 5 =

• A.

-15

• B.

-20

• C.

-25

• D.

25

C. -25
Explanation
To solve this equation, we need to follow the order of operations (PEMDAS/BODMAS). First, we multiply 12 by 5 which equals 60. Then, we subtract 35 from 60, resulting in -25. Therefore, the correct answer is -25.

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• 10.

Solve: 42 + 12/4 =

• A.

34

• B.

45

• C.

51

• D.

74

B. 45
Explanation
42 + 12/4
First, perform the division:
12/4 = 3
Now, substitute this result back into the expression:
42 + 3
42 + 3 = 45
So, the solution is 45.

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Janaisa Harris |BA-Mathematics |
Mathematics Expert
Ms. Janaisa Harris, an experienced educator, has devoted 4 years to teaching high school math and 6 years to tutoring. She is now broadening her educational impact by engaging in curriculum mapping for her county. This endeavor enriches her understanding of educational strategies and their implementation.

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