Physics Unit 1 Quiz 5

When a volleyball player taps a volleyball well above the net, the ball will follow a projectile motion trajectory. The ball's speed is least at the highest point of its path because at that point, its vertical velocity component is zero. As the ball moves upwards, its speed decreases due to the opposing force of gravity, until it reaches its maximum height where its speed is at its minimum. After reaching the highest point, the ball starts to descend, and its speed gradually increases again until it reaches the ground. Therefore, the correct answer is at the highest point of its path.

When an object is launched at an angle and lands at the same horizontal level, the final velocity will be equal and opposite to the initial velocity. This is because the vertical component of the initial velocity will be equal in magnitude but opposite in direction to the vertical component of the final velocity. The horizontal component of the velocity remains unchanged throughout the motion. Therefore, the final velocity will have the same magnitude as the initial velocity, but in the opposite direction.

At the highest point of the ball's flight, the y-velocity is zero because the ball has reached its maximum height and is momentarily stationary before starting to descend. However, the x-velocity is non-zero because the ball is still moving horizontally along the fairway. The velocity is a vector quantity that includes both the magnitude and direction of motion, and in this case, the magnitude is non-zero in the x-direction. The acceleration, on the other hand, is zero at the highest point because there is no change in velocity at that instant.

The acceleration in the x-direction for a projectile is 0 m/s2. This is because there is no force acting on the projectile in the horizontal direction once it is in motion. The only force acting on the projectile is gravity, which only affects the projectile's motion in the vertical direction. Therefore, the acceleration in the x-direction is zero.

The range of a projectile is the horizontal distance it travels before hitting the ground. When the launch angle is increased from 0° to 90°, the range initially increases because a higher launch angle allows the projectile to stay in the air for a longer time. However, as the launch angle approaches 90°, the projectile starts to go more vertically than horizontally, causing the range to decrease. Therefore, the range of a projectile will first increase and then decrease as the launch angle is increased from 0° to 90°.

The direction of acceleration during the flight of the bullet is downward. This is because gravity acts vertically downward and causes the bullet to accelerate in that direction. The angle at which the bullet is fired does not affect the direction of acceleration, as gravity always acts vertically downward regardless of the initial velocity or angle of projection.

The time the athlete spends in the air can be calculated using the projectile motion equations. The horizontal and vertical components of the motion are independent of each other. Given that the angle of the jump is 35o with respect to the horizontal, we can use the vertical component of the motion to calculate the time of flight. The time of flight can be determined using the equation t = 2 * (V * sinθ) / g, where V is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity. Since the initial velocity is not given, we can assume it to be 1 m/s for simplicity. Plugging in the values, we get t = 2 * (1 * sin(35)) / 9.8 ≈ 0.93 s.

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