Practice Paper For SBI Clerk 2014

If the average of two numbers is 52 and the difference between them is 12, we can solve for the numbers using a system of equations. Let's assume the two numbers are x and y. We know that (x + y)/2 = 52, which simplifies to x + y = 104. We also know that x - y = 12. By solving these two equations simultaneously, we can find that x = 58 and y = 46. Therefore, the numbers are 58 and 46.

To solve the equation, we need to combine like terms on both sides. On the left side, we have 11x - 7x, which simplifies to 4x. On the right side, we have x + 67. Now we can isolate the variable x by subtracting x from both sides of the equation. This gives us 4x - x = 67. Simplifying further, we have 3x = 67. To solve for x, we divide both sides by 3, giving us x = 67/3. However, this is not one of the answer choices provided. Therefore, the correct answer is not available.

Given that the ratio of the ages of A, B, and C is 7:5:4, we can let the common ratio be x. Therefore, A's age is 7x, B's age is 5x, and C's age is 4x. We are given that C's age is 32 years, so 4x = 32. Solving for x, we get x = 8. Therefore, A's age is 7x = 7 * 8 = 56 years, and B's age is 5x = 5 * 8 = 40 years. The sum of the ages of A, B, and C is 56 + 40 + 32 = 128 years.

Based on the given information, in twenty years from now, Sagar will be six times as old as he was twenty years ago. This means that his age twenty years ago was one-sixth of his age in the future. Therefore, if we let x represent Sagar's present age, we can set up the equation: x - 20 = (1/6)(x + 20). Solving this equation, we find that x = 28 years. Thus, the present age of Sagar is 28 years.

The age of the father is six times the age of his son, so let's assume the son's age is x. Therefore, the father's age is 6x.
Twenty years from now, the father's age will be twice as old as the son's age, so we can set up the equation 6x + 20 = 2(x + 20).
Simplifying the equation, we get 6x + 20 = 2x + 40.
Combining like terms, we have 4x = 20.
Dividing both sides by 4, we find x = 5.
Therefore, the father's present age is 6x = 6(5) = 30.

The correct answer is 3,2. By solving the given pair of equations, we can find the values of x and y that satisfy both equations. By using the method of substitution or elimination, we can find that x=3 and y=2 satisfy both equations. Therefore, the correct answer is 3,2.

Let the three consecutive odd numbers be x, x+2, and x+4. The sum of the three numbers is x + (x+2) + (x+4) = 3x + 6. Given that the sum is 33, we can set up the equation 3x + 6 = 33 and solve for x. Solving this equation gives x = 9. Therefore, the three numbers are 9, 11, and 13. The sum of the squares of these numbers is 9^2 + 11^2 + 13^2 = 81 + 121 + 169 = 371.

The total profit earned by the firm can be calculated by adding up the individual profits of each partner. Since Ben earned a profit of Rs.10,800, the total profit earned by the firm would be the sum of the investments of all partners multiplied by the profit earned by Ben divided by his investment. This can be calculated as (Rs.80,000 + Rs.64,000 + Rs.48,000) * Rs.10,800 / Rs.48,000 = Rs.43,200.

The ratio of ages of A and B is 7:9. This means that for every 7 years A ages, B ages 9 years.
Given that B is twelve years older than A, we can set up the equation 7x + 12 = 9x, where x represents A's age.
Solving the equation, we find that x = 6.
Therefore, A is 6 years old and B is 9(6) + 12 = 54 years old.

The profit percentage in selling the article is 10.4%. This can be calculated by first finding the selling price after applying the 8% discount on the marked price. Then, the profit percentage is calculated by finding the difference between the selling price and the cost price (which is 20% over the cost), and expressing it as a percentage of the cost price.

The correct answer is Rs.24,200. Compound interest is calculated using the formula A = P(1 + r/n)^(nt), where A is the final amount, P is the principal amount, r is the annual interest rate, n is the number of times interest is compounded per year, and t is the number of years. In this case, the principal amount is Rs.20,000, the annual interest rate is 10%, the interest is compounded annually, and the time period is 2 years. Plugging these values into the formula, we get A = 20000(1 + 0.10/1)^(1*2) = 20000(1.10)^2 = Rs.24,200.

The given problem involves a series of ratios. To find the ratio f:a, we need to find the individual ratios of f:e, e:d, d:c, c:b, and b:a and multiply them together. Given that f:e = 15:14, e:d = 7:10, c:d = 8:5, b:c = 3:4, and a:b = 2:3, we can calculate f:a as follows: f:e * e:d * d:c * c:b * b:a = 15:14 * 7:10 * 8:5 * 3:4 * 2:3 = 15:16. Therefore, the correct answer is 15:16.

The given expression can be simplified using the properties of logarithms. Using the property log(a) + log(b) = log(ab), we can rewrite the expression as log(25^2) + log(16^8) - log(32^5) + log(5^3). Using the property log(a^b) = b*log(a), we can further simplify it to 2log(25) + 8log(16) - 5log(32) + 3log(5). Evaluating the logarithms using their base 10 values, we get 2*1.39794 + 8*1.20412 - 5*1.50515 + 3*0.69897 = 2.79588 + 9.63296 - 7.52575 + 2.09691 = 6.999. Therefore, the value of the expression is 7.

The average age of the four men in the group is 44 years. This means that the total age of the four men is 4 * 44 = 176 years. The ages are in the ratio 4:5:6:7, which means that the ages can be represented as 4x, 5x, 6x, and 7x. Adding these ages together, we get 4x + 5x + 6x + 7x = 176. Simplifying this equation, we get 22x = 176, which means x = 8. Therefore, the age of the eldest person in the group is 7x = 7 * 8 = 56 years.

The given ratios can be simplified as follows: b:a = 3:1, d:c = 3:2, e:d = 13:12, f:e = 1:1, and b:c = 3:8.
From the ratio b:c = 3:8, we can find the value of b in terms of c as b = (3/8)c.
Substituting this value in the ratio b:a = 3:1, we get (3/8)c:a = 3:1.
Simplifying this further, we find that c:a = 8:3.
Similarly, using the ratio e:d = 13:12, we can find e:d = 13:12 = 1:12/13.
Using the ratio f:e = 1:1, we find f:e = 1:1 = 12/13:12/13.
Finally, combining the ratios a:e:f = 3:12/13:12/13 = 1:4/13:4/13 = 1:13:13.

When an article is marked 35% above the cost, it means the selling price is 135% of the cost price. If a profit of 8% is made, it means the selling price is 108% of the cost price. To find the discount percent, we need to find the difference between the marked price (135%) and the selling price (108%). The difference is 27%. Since the discount is calculated on the marked price, we divide the difference by the marked price (135%) and multiply by 100 to get the discount percent, which is approximately 20%.

A's salary is 30% more than B's salary, which means A's salary is 130% of B's salary. B's salary is 20% less than C's salary, which means B's salary is 80% of C's salary. To find what percentage of C's salary is A's salary, we multiply 130% (A's salary in terms of B's salary) by 80% (B's salary in terms of C's salary). This gives us 104%, which means A's salary is 104% of C's salary.

The correct answer is 4. By applying logarithmic properties, we can simplify the equation to log[(2x-1)/35] = log(x+1). Since the logarithms are equal, we can set the expressions inside the logarithms equal to each other: (2x-1)/35 = x+1. Solving for x, we get 2x - 1 = 35x + 35. Simplifying further, we find that x = 4.

The man borrows Rs.80,000 at 15% p.a. simple interest. At the end of the first year, he repays Rs.48,000. This means that he has already paid off the interest for the first year, which is 15% of Rs.80,000 = Rs.12,000. Therefore, the remaining amount to be repaid at the end of the second year is Rs.80,000 - Rs.48,000 - Rs.12,000 = Rs.20,000. However, this amount is not one of the options given. Therefore, the correct answer cannot be determined from the information provided.

To find the quantity of wheat at Rs.10 per kg that should be mixed, we need to consider the cost and profit percentages. The cost of the mixture is Rs.10 per kg, and the profit percentage is 25%.

Let's assume the quantity of wheat at Rs.10 per kg to be mixed is x kg.

The cost of 48 kg of wheat at Rs.6 per kg is 48 * 6 = Rs.288.
The cost of 30 kg of wheat at Rs.8 per kg is 30 * 8 = Rs.240.

The total cost of the mixture will be (288 + 240 + 10x) Rs.

To earn a profit of 25%, the selling price of the mixture should be 125% of the total cost.

125% of (288 + 240 + 10x) = 10 * (48 + 30 + x)

Simplifying the equation, we get:
(528 + 12.5x) = 480 + 10x
2.5x = 48
x = 48/2.5
x = 19.2

Since the quantity of wheat cannot be in decimal places, the nearest whole number is 19.

Therefore, the quantity of wheat at Rs.10 per kg that should be mixed is 48 kg.