# Robocon Aptitude Test 2

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Quizzes Created: 1 | Total Attempts: 140
Questions: 30 | Attempts: 140

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• 1.

### A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:

• A.

45 km/hr

• B.

50 km/hr

• C.

54 km/hr

• D.

55 km/hr

B. 50 km/hr
Explanation
The man is running in the same direction as the train, so his speed needs to be subtracted from the relative speed between the train and the man. The length of the train is 125 m and it takes 10 seconds to pass the man. Therefore, the relative speed between the train and the man is 125 m/10 s = 12.5 m/s. Converting this to km/hr, we get 12.5 m/s * 3.6 km/hr = 45 km/hr. Adding the man's speed of 5 km/hr, the speed of the train is 45 km/hr + 5 km/hr = 50 km/hr.

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• 2.

### Look at this series: 53, 53, 40, 40, 27, 27, ... What number should come next?

• A.

12

• B.

14

• C.

27

• D.

53

B. 14
Explanation
The given series alternates between two patterns. The first pattern is a repetition of the number 53, followed by the number 40, then the number 27, and so on. The second pattern is the same as the first pattern, but with each number decreased by 13. Following this pattern, the next number in the series should be 14.

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• 3.

### (1) Tanya is older than Eric. (2) Cliff is older than Tanya. (3) Eric is older than Cliff. If the first two statements are true, the third statement is

• A.

True

• B.

False

• C.

Uncertain

• D.

None

B. False
Explanation
Based on the given information, Tanya is older than Eric (statement 1) and Cliff is older than Tanya (statement 2). Therefore, it is not possible for Eric to be older than Cliff (statement 3). Hence, the third statement is false.

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• 4.

### A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?

• A.

3.6

• B.

7.2

• C.

8.4

• D.

10

B. 7.2
Explanation
To find the speed in km per hour, we need to convert the distance from meters to kilometers and the time from minutes to hours. Since 1 kilometer is equal to 1000 meters, the person crossed 0.6 kilometers (600 meters / 1000 meters per kilometer). Similarly, since 1 hour is equal to 60 minutes, the person took 1/12 hours to cross the street (5 minutes / 60 minutes per hour). Dividing the distance (0.6 km) by the time (1/12 hours) gives us a speed of 7.2 km per hour.

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• 5.

### ELFA, GLHA, ILJA, _____, MLNA

• A.

OLPA

• B.

KLMA

• C.

LLMA

• D.

KLLA

D. KLLA
Explanation
The pattern in the given sequence is that each letter in the first half of the sequence is incremented by one, while each letter in the second half is decremented by one. Starting with "ELFA," the first half letters increase by one (E to F, L to M, A to B), while the second half letters decrease by one (A to L, G to F, H to G). Applying this pattern to the missing term, the first half letter should be "K" (J + 1), and the second half letter should be "L" (M - 1), resulting in "KLLA."

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• 6.

### The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is:

• A.

40.00%

• B.

42.00%

• C.

44.00%

• D.

46.00%

C. 44.00%
Explanation
When each side of a rectangle is increased by 20%, the new length and width will be 120% of the original length and width. The area of a rectangle is calculated by multiplying the length and width, so the new area will be (120% * 120%) = 144% of the original area. To find the percentage increase, we subtract 100% (the original area) from 144% and get 44%. Therefore, the correct answer is 44.00%.

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• 7.

### (112 x 54) = ?

• A.

67000

• B.

70000

• C.

76500

• D.

77200

B. 70000
Explanation
The given expression (112 x 54) can be calculated as 6048. However, none of the answer options match this result. Therefore, the correct answer is not available.

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• 8.

### Which one of the following is not a prime number?

• A.

31

• B.

61

• C.

71

• D.

91

D. 91
Explanation
A prime number is a number that is only divisible by 1 and itself. In this case, 91 is not a prime number because it is divisible by 7 and 13 in addition to 1 and 91.

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• 9.

### Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:

• A.

2:5

• B.

3:5

• C.

4:5

• D.

6:7

C. 4:5
Explanation
If two numbers are respectively 20% and 50% more than a third number, it means that the first number is 20% greater than the third number and the second number is 50% greater than the third number. To find the ratio of the two numbers, we can assume the third number to be 100. The first number would then be 120 (20% more than 100) and the second number would be 150 (50% more than 100). Simplifying the ratio of the two numbers, we get 4:5.

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• 10.

### An accurate clock shows 8 o'clock in the morning. Through how may degrees will the hour hand rotate when the clock shows 2 o'clock in the afternoon?

• A.

144º

• B.

150º

• C.

168º

• D.

180º

D. 180º
Explanation
The hour hand of a clock completes a full rotation of 360 degrees in 12 hours. From 8 o'clock in the morning to 2 o'clock in the afternoon, a total of 6 hours have passed. Therefore, the hour hand will rotate 6/12 or 1/2 of a full rotation, which is equal to 180 degrees.

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• 11.

• A.

39, 30

• B.

41, 32

• C.

42, 33

• D.

43, 34

C. 42, 33
• 12.

### If one-third of one-fourth of a number is 15, then three-tenth of that number is:

• A.

35

• B.

36

• C.

45

• D.

54

D. 54
Explanation
If one-third of one-fourth of a number is 15, it means that one-fourth of the number is 15 multiplied by 3, which equals 45. To find three-tenths of the number, we can multiply 45 by 3 and divide the result by 10. This calculation gives us 54, which is the correct answer.

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• 13.

### A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?A man has Rs. 480 in the denominations of one-rupee notes, five-rupee notes and ten-rupee notes. The number of notes of each denomination is equal. What is the total number of notes that he has ?

• A.

45

• B.

60

• C.

75

• D.

90

D. 90
Explanation
Since the number of notes of each denomination is equal, let's assume that the number of notes of each denomination is x. Therefore, the total value of one-rupee notes is x, the total value of five-rupee notes is 5x, and the total value of ten-rupee notes is 10x. Since the total value of all the notes is Rs. 480, we can write the equation x + 5x + 10x = 480. Solving this equation, we get x = 24. Since x represents the number of notes of each denomination, the total number of notes that he has is 24 + 24 + 24 = 72.

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• 14.

### If a - b = 3 and a2 + b2 = 29, find the value of ab.If a - b = 3 and a2 + b2 = 29, find the value of ab.

• A.

10

• B.

12

• C.

15

• D.

18

A. 10
Explanation
To find the value of ab, we can use the given equations. We know that a - b = 3, so we can rewrite it as a = b + 3. Substituting this into the equation a^2 + b^2 = 29, we get (b + 3)^2 + b^2 = 29. Expanding and simplifying this equation, we get b^2 + 6b + 9 + b^2 = 29. Combining like terms, we have 2b^2 + 6b + 9 = 29. Rearranging this equation, we get 2b^2 + 6b - 20 = 0. Factoring this quadratic equation, we get (b - 2)(2b + 10) = 0. Solving for b, we find b = 2. Substituting this back into the equation a = b + 3, we get a = 5. Therefore, ab = 2 * 5 = 10.

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• 15.

### Isometric drawings are often used by ________ to help illustrate complex designs.

• A.

Mechanical engineers

• B.

Piping drafters

• C.

Aerospace engineers

• D.

All of the above

D. All of the above
Explanation
Isometric drawings are a type of 3D representation that show an object from multiple angles, allowing for a better understanding of its design. These drawings are commonly used by mechanical engineers, piping drafters, and aerospace engineers to visually communicate complex designs. Therefore, the correct answer is "all of the above" as all of these professionals can benefit from using isometric drawings in their work.

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• 16.

### The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:The average weight of A, B and C is 45 kg. If the average weight of A and B be 40 kg and that of B and C be 43 kg, then the weight of B is:

• A.

17 kg

• B.

20 kg

• C.

26 kg

• D.

31 kg

D. 31 kg
Explanation
Let the weight of A, B, and C be a, b, and c respectively. We are given that the average weight of A and B is 40 kg, so (a + b)/2 = 40. Similarly, the average weight of B and C is 43 kg, so (b + c)/2 = 43. From these two equations, we can find that a + b = 80 and b + c = 86. Subtracting these two equations, we get a - c = -6. Now, the average weight of A, B, and C is 45 kg, so (a + b + c)/3 = 45. Substituting the values of a + b = 80 and a - c = -6, we can solve for b and find that b = 31 kg. Therefore, the weight of B is 31 kg.

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• 17.

### What smallest number should be added to 4456 so that the sum is completely divisible by 6 ?What smallest number should be added to 4456 so that the sum is completely divisible by 6 ?

• A.

4

• B.

3

• C.

2

• D.

1

C. 2
Explanation
To make the sum of 4456 completely divisible by 6, we need to find the smallest number that, when added to 4456, results in a multiple of 6. Since 6 is divisible by 2, we can infer that the sum needs to be an even number. Adding 1, 3, or 4 to 4456 would result in an odd number, which is not divisible by 6. However, adding 2 to 4456 would give us 4458, which is divisible by 6. Therefore, the smallest number that should be added to 4456 is 2.

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• 18.

### The sum of two number is 25 and their difference is 13. Find their product.

• A.

104

• B.

114

• C.

315

• D.

325

B. 114
Explanation
Let's assume the two numbers are x and y. From the given information, we can set up two equations: x + y = 25 and x - y = 13. Solving these equations simultaneously, we find that x = 19 and y = 6. The product of these two numbers is 19 * 6 = 114.

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• 19.

### 397 x 397 + 104 x 104 + 2 x 397 x 104 = ?

• A.

250001

• B.

251001

• C.

260101

• D.

261001

B. 251001
Explanation
To solve this problem, we can use the formula (a + b)^2 = a^2 + b^2 + 2ab. In this case, a = 397 and b = 104. Plugging in these values, we get (397 + 104)^2 = 397^2 + 104^2 + 2(397)(104). Simplifying this equation, we get 501^2 = 157609 + 10816 + 82688. Adding all the numbers together, we get 251001. Therefore, the correct answer is 251001.

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• 20.

### If in a certain language, POPULAR is coded as QPQVMBS, which word would be coded as GBNPVT?

• A.

FASOUM

• B.

FAMSUO

• C.

FOSAUM

• D.

FAMOUS

D. FAMOUS
Explanation
The given question is a coding question where each letter in the word is shifted one position backward in the English alphabet. Applying the same logic, the word "GBNPVT" will be coded as "FAMOUS".

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• 21.

### The sum of even numbers between 1 and 31 is:

• A.

6

• B.

28

• C.

240

• D.

512

C. 240
Explanation
The sum of even numbers between 1 and 31 can be calculated by adding all the even numbers within this range. The even numbers between 1 and 31 are 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, and 30. Adding these numbers together gives a sum of 240.

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• 22.

### In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?

• A.

6.25

• B.

6.5

• C.

6.75

• D.

7

A. 6.25
Explanation
To find the required run rate, we need to consider the total number of runs needed to reach the target. Since the first 10 overs had a run rate of 3.2, the total runs scored in those overs would be 3.2 x 10 = 32 runs. To reach the target of 282 runs, the remaining 40 overs need to score 282 - 32 = 250 runs. Therefore, the required run rate for the remaining overs would be 250 runs / 40 overs = 6.25 runs per over.

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• 23.

### Find the odd one out

• A.

Echo

• B.

Resonance

• C.

Tone

• D.

Ear

D. Ear
Explanation
The odd one out in this list is "Ear" because it is the only item that is a body part, while the others are related to sound. "Echo," "Resonance," and "Tone" all refer to different aspects of sound, while "Ear" is the only item that does not fit into this category.

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• 24.

### 39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?

• A.

10

• B.

13

• C.

14

• D.

15

B. 13
Explanation
If 39 persons can repair a road in 12 days, working 5 hours a day, it means that the total work requires 39 * 12 * 5 = 2340 person-hours. Now, if 30 persons work 6 hours a day, they will work a total of 30 * 6 = 180 person-hours per day. To complete the work, they will need 2340 / 180 = 13 days. Therefore, the correct answer is 13.

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• 25.

### A told B that C is his father's nephew. D is A's cousin but not the brother of C. What relationship is there between D and C ?

• A.

Father

• B.

Sisters

• C.

Aunt

• D.

Mother

B. Sisters
Explanation
D and C are sisters because A told B that C is his father's nephew. This means that C is the child of A's father's sibling. Since D is A's cousin but not the brother of C, it can be inferred that D and C share the same parents, making them sisters.

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• 26.

### (1) A fruit basket contains more apples than lemons. (2) There are more lemons in the basket than there are oranges. (3) The basket contains more apples than oranges. If the first two statements are true, the third statement is

• A.

True

• B.

False

• C.

Uncertain

• D.

None

A. True
Explanation
The first statement states that there are more apples than lemons in the fruit basket. The second statement states that there are more lemons in the basket than there are oranges. Since the first statement already establishes that there are more apples than lemons, and the second statement further establishes that there are more lemons than oranges, it can be concluded that there are definitely more apples than oranges in the basket. Therefore, the third statement is true.

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• 27.

### B2CD, _____, BCD4, B5CD, BC6D

• A.

B2C2D

• B.

BC3D

• C.

B2C3D

• D.

BCD7

B. BC3D
Explanation
The pattern in the given sequence is that the letter "B" remains constant, the letter "C" increases by one each time, and the letter "D" remains constant. Therefore, the missing term in the sequence would be "BC3D" where "C" is increased by one.

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• 28.

### Two bus tickets from city A to B and three tickets from city A to C cost Rs. 77 but three tickets from city A to B and two tickets from city A to C cost Rs. 73. What are the fares for cities B and C from A ?

• A.

Rs. 4, Rs. 23

• B.

Rs. 13, Rs. 17

• C.

Rs. 15, Rs 14

• D.

Rs. 17, Rs. 13

B. Rs. 13, Rs. 17
Explanation
Let's assume the fare for city B from A is x and the fare for city C from A is y. From the given information, we can form the following equations:

2x + 3y = 77 (equation 1)
3x + 2y = 73 (equation 2)

To find the values of x and y, we can solve these equations simultaneously. By solving the equations, we get x = 13 and y = 17. Therefore, the fares for cities B and C from A are Rs. 13 and Rs. 17 respectively.

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• 29.

### A man walks 6km to the east and then turns to the south 2km. Again he turns to east and walks 2km. Next he turns north and walks 8km. How far is he now from his starting point?

• A.

18km

• B.

10km

• C.

16km

• D.

12km

B. 10km
Explanation
The man initially walks 6km to the east, then 2km to the south, and then 2km to the east again. This means he has moved 6km east and 2km south, resulting in a net displacement of 4km east. Next, he turns north and walks 8km, which cancels out his previous eastward displacement. Therefore, he is now back at his starting point, which means he is 0km away from his starting point. However, the options provided do not include this answer, so the closest option is 10km, which is incorrect.

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• 30.

### The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?

• A.

1

• B.

10

• C.

19

C. 19
Explanation
Since the average of 20 numbers is zero, it means that the sum of all the numbers is also zero. In order for the sum to be zero, there must be some positive numbers to balance out the negative numbers. Therefore, at most, 19 numbers can be greater than zero, while the remaining number must be negative to ensure that the sum is zero.

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