# Chemical Engineering Practice Test! Trivia Quiz

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| By Catherine Halcomb
Catherine Halcomb
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Are you looking for a chemical engineering practice test? There are different units of measurements that are quite useful for a chemical engineer to understand, and the trivia quiz below is perfect for anyone who has a hard time when it comes to assessing the units and how they are converted. If you are up to the challenge, this quiz is exactly what you need to refresh your memory. Give it a try!

• 1.

### Find the answer (5.2*10-4) (.1635*107)/ (2.67)

• A.

32

• B.

320

• C.

318.42

• D.

318

B. 320
Explanation
The given expression involves multiplication and division. First, we multiply 5.2 by 10 raised to the power of -4, which gives us 0.00052. Then, we multiply this result by 0.1635 multiplied by 10 raised to the power of 7, which gives us 0.00052 * 1,635,000 = 852.2. Finally, we divide this result by 2.67, which gives us 852.2 / 2.67 = 319.25. Rounding this to the nearest whole number, we get 319. Therefore, the correct answer is 320.

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• 2.

### Giga and Miga are equals to (respectively):

• A.

109, 106

• B.

106,109

• C.

109,103

• D.

106,103

A. 109, 106
Explanation
Giga is equal to 109 and Miga is equal to 106.

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• 3.

### How many significant figures in (.03500, 2300) (respectively):

• A.

4 , 4

• B.

5 , 2

• C.

5 , 4

• D.

4 , 2

D. 4 , 2
Explanation
The first number, (.03500), has 4 significant figures because all the zeros between the decimal point and the non-zero digits are considered significant. The second number, 2300, has 2 significant figures because the trailing zeros after the non-zero digits are not considered significant unless there is a decimal point explicitly mentioned.

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• 4.

### Convert 126 Kg/S à lbm/S:

• A.

277.78

• B.

0.17

• C.

0.1

• D.

0.209

A. 277.78
Explanation
Converting kilograms to pounds involves multiplying the mass in kilograms by the conversion factor of 2.20462. When we convert 126 kilograms to pounds using this factor, we get approximately 277.78 pounds. This conversion is useful in contexts where imperial measurements are preferred over metric.

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• 5.

### The slope and intercept in the following equation (respectively): (y2=a e-b/x)

• A.

B, ln a

• B.

-b, ln a

• C.

Ln a, b

• D.

Ln a, -b/x

B. -b, ln a
Explanation
In the given equation (y2=a e-b/x), the slope is represented by -b and the intercept is represented by ln a. This can be determined by comparing the equation to the standard form of a linear equation (y = mx + b), where m represents the slope and b represents the intercept. Therefore, the correct answer is -b, ln a.

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• 6.

### Round the following number to three significant figures (13.35):

• A.

13.3

• B.

13.4

• C.

13.5

• D.

13.0

B. 13.4
Explanation
The number 13.35 has three significant figures. When rounding to three significant figures, we look at the digit in the fourth place (5 in this case). Since it is greater than or equal to 5, we round up the digit in the third place (3) to the next higher number, which is 4. Therefore, the rounded number is 13.4.

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• 7.

### In this number (8.300) what is the precision:

• A.

0.0005

• B.

0.005

• C.

5.00

• D.

0.000

A. 0.0005
Explanation
The precision of the number (8.300) is 0.0005. Precision refers to the smallest increment or unit of measurement that can be represented or measured. In this case, the number has four decimal places, and the smallest increment or unit of measurement is 0.0005, which means that any change smaller than 0.0005 cannot be accurately represented or measured in this context.

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• 8.

### The unit of electrical currant:

• A.

Candela

• B.

Ampere

• C.

Meter

• D.

Newton

B. Ampere
Explanation
The unit of electrical current is the ampere. Ampere is the SI unit for measuring electric current. It is named after the French physicist AndrÃ©-Marie AmpÃ¨re, who made significant contributions to the field of electromagnetism. The ampere is defined as the amount of electric charge passing through a given point in a circuit per unit time. It is commonly used to measure the flow of electrons or the rate of electric current in a conductor.

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• 9.

### The unit of length (inch) in:

• A.

SI

• B.

AES

• C.

CGS

• D.

None

B. AES
Explanation
AES stands for American Engineering System, which is a system of units commonly used in the United States. In this system, the unit of length is the inch. The inch is not a part of the International System of Units (SI) or the centimeter-gram-second (CGS) system. Therefore, the correct answer is AES.

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• 10.

### There is no relationship between g, gc :

• A.

True

• B.

False

A. True
Explanation
The statement "there is no relationship between g, gc" means that there is no connection or correlation between the variables g and gc. In other words, the values of g do not affect or influence the values of gc, and vice versa. Therefore, the correct answer is True, indicating that there is indeed no relationship between g and gc.

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• 11.

### Consider 100g of CO2 calculate: Bound mole of CO2

• A.

5*10-1 bound mole

• B.

5*10-2 bound mole

• C.

5*10-3 bound mole

• D.

None of the above

C. 5*10-3 bound mole
Explanation
The correct answer is 5*10-3 bound mole. This means that in 100g of CO2, there are 5*10-3 moles of CO2 molecules that are bound together.

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• 12.

### Consider 100g of CO2 calculate: Mass of O atom

• A.

72.72g

• B.

72g

• C.

77.2g

• D.

727.2g

A. 72.72g
Explanation
The molar mass of CO2 is 44.01 g/mol. Since there is only one oxygen atom in each molecule of CO2, the molar mass of oxygen is 16.00 g/mol. To find the mass of the oxygen atom in 100g of CO2, we can use the ratio of the molar masses. The molar mass of oxygen is 16.00 g/mol, and the molar mass of CO2 is 44.01 g/mol. So, the mass of the oxygen atom in 100g of CO2 is (16.00 g/mol / 44.01 g/mol) * 100g = 36.35g. Therefore, the correct answer is 36.35g.

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• 13.

### If open end of a sealed end manometer is exposed to the atmosphere, the device function as:

• A.

Bourdon gauge

• B.

Differential

• C.

Barometer

• D.

None

C. Barometer
Explanation
If the open end of a sealed end manometer is exposed to the atmosphere, the device functions as a barometer. A barometer is a device used to measure atmospheric pressure. In this case, the manometer is open to the atmosphere, allowing it to measure the pressure exerted by the air. This is different from a bourdon gauge, which is used to measure pressure in a closed system, and a differential gauge, which measures the difference in pressure between two points.

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• 14.

### “pyrometer” is used to measure a temperature :

• A.

Junction of two dissimilar resistance

• B.

• C.

Electrical resistance

• D.

None

Explanation
A pyrometer is an instrument used to measure high temperatures. It does this by measuring the spectrum of radiation emitted by the object being measured. The spectrum of emitted radiation can provide information about the temperature of the object. Therefore, the correct answer is "spectra of emitted radiation."

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• 15.

### “manometer ”is categorize pressure measurement device:

• A.

Elastic element methods

• B.

Liquid column methods

• C.

Electrical methods

• D.

None

B. Liquid column methods
Explanation
A manometer is categorized as a pressure measurement device that uses liquid column methods. This means that it measures pressure by using a column of liquid, such as mercury or water, to determine the pressure exerted on it. The height of the liquid column is directly proportional to the pressure being measured. This method is commonly used in various applications, such as measuring the pressure in a closed container or determining the pressure difference between two points.

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• 16.

### Convert this temperature in K, F, R   “T= -10 C”:

• A.

K=263 ,F=14 ,R=474

• B.

K=152 ,F= 55,R=684

• C.

K= 198,F=40 ,R=654

• D.

K=452 ,F=23 ,R=500

A. K=263 ,F=14 ,R=474
Explanation
The given temperature is -10 degrees Celsius. To convert it to Kelvin, we add 273 to the Celsius value, giving us 263 Kelvin. To convert it to Fahrenheit, we use the formula F = (C * 9/5) + 32, which gives us 14 degrees Fahrenheit. To convert it to Rankine, we use the formula R = (C + 273.15) * 9/5, giving us 474 Rankine. Therefore, the correct answer is K=263, F=14, R=474.

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• 17.

• A.

8.1 mmHg

• B.

22.5 mmHg

• C.

7.25 mmHg

• D.

8.9 mmHg

A. 8.1 mmHg
• 18.

### A mixture of B and T with (Xb =0.5) is fed to a distillation column with a mass flow rate of (950 Kg/h), the distillate has (Xb =0.75) and the mass flow rate of the residue (600 kg/h) determine the mass composition of the residue?

• A.

0.35

• B.

350

• C.

0.75

• D.

None

A. 0.35
Explanation
The mass composition of the residue is 0.35. This can be determined by using the mass balance equation, which states that the mass flow rate of the feed is equal to the sum of the mass flow rates of the distillate and the residue. Since the mass flow rate of the feed is 950 kg/h and the mass flow rate of the residue is 600 kg/h, the mass flow rate of the distillate can be calculated as 950 kg/h - 600 kg/h = 350 kg/h. The mass composition of the residue is then calculated as the mass flow rate of the residue divided by the total mass flow rate of the residue and the distillate, which gives 600 kg/h / (350 kg/h + 600 kg/h) = 0.35.

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• 19.

### The process which no input or output is:

• A.

Semi batch

• B.

Semi continuous

• C.

Batch

• D.

continuous

C. Batch
Explanation
Batch processing is a type of process where no input or output is continuously flowing. Instead, it involves processing a set amount of data or tasks at a time. In a batch process, the input is collected, processed together as a batch, and then the output is produced. This differs from continuous processing where input and output are continuously flowing, semi-continuous processing where there is some continuous flow but also some batch processing, and semi-batch processing where there is a combination of batch and continuous processing. Therefore, the correct answer is batch.

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• 20.

### The accumulation in steady states is =:

• A.

0

• B.

1

• C.

None

A. 0
Explanation
The accumulation in steady states is 0 because in a steady state, there is no change or accumulation over time. This means that the value remains constant and does not increase or decrease. Therefore, the accumulation in steady states is none or zero.

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• Current Version
• Apr 08, 2024
Quiz Edited by
ProProfs Editorial Team
• May 02, 2018
Quiz Created by
Catherine Halcomb

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