Gas Laws Quiz: Boyle's And Charles' Law

Reviewed by Matt Balanda
Matt Balanda, BS (Aerospace Engineering) |
Science Teacher
Review Board Member
Matt Balanda, a Calvary Chapel Christian School leader with a Bachelor's in Aerospace Engineering and Mathematics, transitioned from Aerospace Engineering to Education with a Master's from California Baptist University. As the High School Vice-Principal and Physics teacher, he nurtures students' love of learning and faith, creating an enriching and transformational educational experience.
 , BS (Aerospace Engineering)
By Kwchiro
K
Kwchiro
Community Contributor
Quizzes Created: 40 | Total Attempts: 411,083
| Attempts: 9,862
Quiz Lesson
SettingsSettings
Please wait...
  • 1/10 Questions

    What is the final pressure in a balloon when the volume is changed from 1.5  L to a volume of 2.5L at constant temperature? (Initial pressure is 1.1 atm).

    • 0.66 atm
    • 0.66 kPa
    • 4.125 atm
Please wait...
About This Quiz


Welcome to the Gas Laws: Boyle's and Charles' Law Quiz, where you'll delve into the fascinating principles governing the behavior of gasses. Boyle's Law and Charles' Law are foundational concepts in the study of gas physics. As you navigate through this quiz, you'll be challenged to apply these laws in various scenarios and explore their implications on gas behavior. This quiz aims to assess your ability to apply these fundamental gas laws to real-world situations, providing a comprehensive understanding of how gasses respond to changes in pressure, volume, and temperature. Best of luck as you navigate the intricacies of Boyle's and Charles' Laws!

Gas Laws Quiz: Boyles And Charles Law - Quiz

Quiz Preview

  • 2. 

    If the air inside a balloon is heated, the volume will:

    • Increase

    • Decrease

    • Increase a little, then decrease.

    Correct Answer
    A. Increase
    Explanation
    If the air inside a balloon is heated while the pressure remains constant, the volume of the balloon will generally increase. This behavior follows Charles's Law, which states that the volume of a gas is directly proportional to its temperature at constant pressure.

    Rate this question:

  • 3. 

    A balloon occupies 3.2 L at 37oC. How much volume will it occupy at 42oC?

    • 3.25 L

    • 3.65 L

    • 312,480 L

    Correct Answer
    A. 3.25 L
    Explanation
    Using the formula,
    V1/T1=V2/T2 and substituting the values of V1,T1 and T2 and solving the equation we get,
    Given:
    V1​=3.2L at T1​= 37°C =310.15K
    T2=42°C =315.15 K
    3.2L/315.15K=V2/310.15K
    Therefore 
    V2=3.2L x 310.15K/315.15K
    V2​≈3.25L
    Therefore, the balloon will occupy approximately 3.25 L at 42°C.

    Rate this question:

  • 4. 

    What is the final pressure in a vessel when the volume is changed from 1.3  L to a volume of 1.55 L at constant temperature? (Initial pressure is 1.5 atm).

    • 1.26 L

    • 1.65 L

    • 1.49 L

    Correct Answer
    A. 1.26 L
    Explanation
    The formula for Boyle's Law is given by:

    P1 . V1 = P2 . V2
    where:
    - ( P1) is the initial pressure,
    - (V1)  is the initial volume,
    - ( P2) is the final pressure,
    - ( V2) is the final volume.

    Given:
    - (P1 = 1.5 ) atm (initial pressure),
    - ( V1 = 1.3 ) L (initial volume),
    - ( V2= 1.55 ) L (final volume).

    Plug in the values into Boyle's Law:

    [ 1.5. 1.3] L = P2 . 1.55 L

    Now, solve for P2

    P2 = 1.5 atm .  1.3L/ 1.55L
    P2 ≈1.26atm
    Therefore, the final pressure in the vessel when the volume changes from 1.3 L to 1.55 L at constant temperature is approximately 1.26 atm.

    Rate this question:

  • 5. 

    A gas occupies a balloon with a volume 2.0 L at 33oC. How much volume will it occupy at 37oC, if pressure remains constant?

    • 1.97 L

    • 186,000 L

    • 2.026 L

    Correct Answer
    A. 2.026 L
    Explanation
    Using the formula,
    V1/T1=V2/T2 and substituting the values of V1,T1 and T2 and solving the equation we get,
    Given:
    V1​=2.0L at T1​= 33°C =306.15K
    T2=37°C =310.15 K
    2.0L/306.15K=V2/310.15K
    Therefore 
    V2=2.0L x 310.15K/306.15K
    V2​≈2.026L
    Therefore, the balloon will occupy approximately 2.026 L at 37°C.

    Rate this question:

  • 6. 

    A gas expands from a volume 2.0 L at 36oC to a volume of 2.5 L. What is the final temperature (in Kelvin) if the pressure is constant?

    • 386.43 K ( which equals 113.25 Celsius)

    • 247.2 K (which equals -25.8 C)

    • 61.8 K (which equals -211.2 C)

    Correct Answer
    A. 386.43 K ( which equals 113.25 Celsius)
    Explanation
    Using the formula,
    V1/T1=V2/T2 and substituting the values of V1,T1 and V2 and solving the equation we get,
    Given:
    V1​=2.0L at T1​= 36°C =309.15K
    V2=2.5L
    2.0L/309.15K=2.5L/T2
    Therefore 
    T2=2.5L x 309.15K / 2.0 L
    T2​≈ 386.43 K
    Therefore, the final temperature is approximately 386.43 K when the gas expands from a volume of 2.0 L at 36°C to a volume of 2.5 L, assuming the pressure remains constant.

    Rate this question:

  • 7. 

    A balloon occupies a volume of 2.0 L at 40oC. How much volume will it occupy at 30oC?

    • 1.5 L

    • 1.94 L

    • 1.6 L

    Correct Answer
    A. 1.94 L
    Explanation
    Using the formula,
    V1/T1=V2/T2 and substituting the values of V1,T1 and T2 and solving the equation we get,
    Given:
    V1​=2.0L at T1​= 40°C =313.15K
    T2=30°C =303.15 K
    2.0L/313.15K=V2/313.15K
    Therefore 
    V2=2.0L x 303.15K/313.15K
    V2​≈1.94L

    Rate this question:

  • 8. 

    The kinetic theory of gasses, which of the following is important for an ideal gas:

    • There is no attraction or repulsion between the gas molecules, whereas there is attraction between molecules of liquids or solids.

    • The distance between molecules in ideal gasses is closer than in liquids or solids.

    • The gasses are NOT fluid.

    Correct Answer
    A. There is no attraction or repulsion between the gas molecules, whereas there is attraction between molecules of liquids or solids.
    Explanation
    The correct answer is that there is no attraction or repulsion between the gas molecules, whereas there IS attraction between molecules of liquids or solids. This is important for an ideal gas because it assumes that the gas molecules do not interact with each other, except during collisions. This allows for simplifications in the mathematical models used to describe the behavior of ideal gasses. In contrast, liquids and solids have intermolecular forces that result in attractions between their molecules, leading to different behaviors and properties.

    Rate this question:

  • 9. 

    Which of the following describes the relationship between P and V?            

    • Directly proportional

    • Inversely proportional

    • Unrelated

    Correct Answer
    A. Inversely proportional
    Explanation
    The relationship between P and V is described as inversely proportional. This means that as one variable (P) increases, the other variable (V) decreases, and vice versa. In other words, there is a negative correlation between P and V, where an increase in one variable corresponds to a decrease in the other variable.

    Rate this question:

  • 10. 

    Gas in a balloon occupies 3.3  L. What volume will it occupy if the pressure is changed from 100 kPa to 90  kPa (at constant temperature of 310 K (about room temperature)?

    • 29,700 L

    • 2.97 L

    • 3.67 L

    Correct Answer
    A. 3.67 L
    Explanation
    The formula for Boyle's Law is given by:

    P1 . V1 = P2 . V2
    where:
    - ( P1) is the initial pressure,
    - (V1)  is the initial volume,
    - ( P2) is the final pressure,
    - ( V2) is the final volume.

    Given:
    - P1 = 100 kPa (initial pressure),
    - V1 = 3.3 L (initial volume),
    - P2 = 90 kPa (final volume)
    T = 310K (Constant Temperature)

    Plug in the values into Boyle's Law to find V2:
    V2 = P1 . V1 / P2
    Now, solve for V2
    V2 =100 kPa .  3.3L/ 90kPa
    V2 ≈ 3.67L

    Therefore, the volume the gas will occupy when the pressure is changed from 100 kPa to 90 kPa at constant temperature is approximately 3.67 L.

    Rate this question:

Matt Balanda |BS (Aerospace Engineering) |
Science Teacher
Matt Balanda, a Calvary Chapel Christian School leader with a Bachelor's in Aerospace Engineering and Mathematics, transitioned from Aerospace Engineering to Education with a Master's from California Baptist University. As the High School Vice-Principal and Physics teacher, he nurtures students' love of learning and faith, creating an enriching and transformational educational experience.

Quiz Review Timeline (Updated): Sep 17, 2024 +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Sep 17, 2024
    Quiz Edited by
    ProProfs Editorial Team

    Expert Reviewed by
    Matt Balanda
  • Jun 19, 2011
    Quiz Created by
    Kwchiro
Back to Top Back to top
Advertisement
×

Wait!
Here's an interesting quiz for you.

We have other quizzes matching your interest.