10 Questions
| Attempts: 1819

Boyle's, Charles', Ideal Gas Law, Combined gas law.

Questions and Answers

- 1.Which law compares gases at two different sets of conditions, with temperature as a constant and pressure and volume as variables?
- A.
Charle's Law

- B.
Boyle's Law

- C.
Combined Gas Law

- D.
Ideal gas law

- 2.If pressure of a gas is 1.2 atmospheres with a volume of 12 L, how much pressure is exerted by the gas if the volume is changed to 9L? (Assume constant temperature)
- A.
.9 L

- B.
129.6 L

- C.
6.0 L

- D.
1.6 L

- 3.If the pressure of a gas is 103.2 kPa at a temperature of 100 Celsius and a volume of 4L is changed to a lower pressure of 80 kPa and 100 degrees celsius, what will be the new volume? (Hint: kPa is kilo pascals -- a unit of measure for pressure).
- A.
2,064 L

- B.
0.3225 L

- C.
5.16 L

- D.
3.1 L

- 4.A gas at a temperature of 80Celsius and a volume of 3.2 Liters is brought into an area with the temperature of 100 Celsius, what is the new volume if the pressure remains constant? Hint 1: This is Charles law (V1/T1 = V2/T2) Hint 2: ALL GAS PROBLEMS MUST use the KELVIN temperature scale. (To change from Celsius to Kelvin: add 273)
- A.
3.38 L

- B.
2.84 L

- C.
3.75 L

- D.
2.4 L

- 5.A gas at a temperature of 34 Celsius and a volume of 6.3 Liters is brought into a new area where the gas expands to a volume of 8.0 Liters. What is the new temperature? (Assume constant Pressure)
- A.
43.17 K

- B.
389.84 K

- C.
0.164 K

- D.
1.48 K

- 6.A gas in a balloon measures 2.2 L 1.1 atmospheres and 32 degrees Celsius. The environment is changed and the balloon is now 1.8 L and 1.4 atmospheres. What is the new temperature? Hint 1: Always change temperature to Kelvin scale. Hint 2: Pressure volume and temperature are all changed. Use the combined gas law:
- A.
317.6 K

- B.
33.32 K

- C.
384.3 K

- D.
0.02 K

- 7.A gas in a balloon measures 3.6 L, 0.9 atmospheres and 34 degrees Celsius. The environment is changed and the balloon is now 1.4 atmospheres at a temperature of 38 degrees Celsius. What is the new volume?
- A.
2.59 L

- B.
4.6 L

- C.
220,961 L

- D.
2.34 L

- 8.What is the volume of 2 moles of Helium at a temperature of 32 degreees celsius and a pressure of 1.1 atmospheres ? Given R = 0.08321 Latm/molK and 8.314 kPa L/mol K Hint: There is only 1 set of conditions for this gas problem and the moles of the gas are given. This indicates the ideal gas law: PV =
*n*RT. Remember that*n*is equal to the number of moles. P is the pressure, V is the volume and T is the temperature (change to Kelvin). The R MUST match the units in the rest of the problem. IF pressure is given in atmosphere, then use R = 0.08321 Latm/molK . IF pressure was given in kPa, then use 8.314 Kpa L/mol K Note also that volume MUST be in Liters and Temperature (as for all gas problems) must be in Kelvin.- A.
13.96 L

- B.
.45 L

- C.
46.14 L

- D.
4,610 L

- 9.What is the temerature of 3.4 moles of Helium at a pressure of 1.1 atmospheres and a volume of 3.7 Liters. (What is the temperature in Kelvin?) Given R = 0.08321 Latm/molK and 8.314 kPa L/mol K
- A.
14.39 K

- B.
12.15 K

- C.
0.1 K

- D.
142 K

- 10.How many moles is present in a container that is 79.9 Liters with a pressure of 105 kPa and a temperature of 24 degrees Celsius? Given R = 0.08321 Latm/molK and 8.314 kPa L/mol K
- A.
2.7 moles

- B.
271 moles

- C.
3.4 moles

- D.
5.6 moles

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