Chemistry: All The Gas Laws

Explanation
Boyle's law: P1V1 = P2V2 Temperature is constant.
(Where 1 indicates the first set of conditions and a 2 indicates the second set of conditions.
{Charle's law is V1/T1 = V2/T2 with pressure constant;
Ideal is PV = nRT and
combined is PV/T = PV/T}

Explanation
If the variables are only Pressure and Volume, (with constant temperature), this indicates Boyle's Law:
P1V1 = P2 V2 (Where 1 indicates the first set of conditions and 2 indicates the second set of conditions).
(1.2 atm) (12L) = (P2) (9L)
Math: 1.2 times 12 divided by 9.

Explanation
Since the temperature is a constant (it started at 100C and ended at 100C) and Pressure and volume are the variables, this is Boyle's Law. P1V1 = P2V2. (Where 1 indicates the initial set of conditions and 2 indicates the final set of conditions).
(103.2kPa) (4L) = (80 kPa) (V2)
Math: 103.2 x 4 divided by 80

Explanation
(3L)/(353K) = V2/(373K)
Math: 3 x 373 divided by 353.

Explanation
This problem uses Charles' law. (V1/T1 = V2/T2)
MAKE SURE YOU CHANGE YOUR TEMPERATURE TO KELVIN (add 273)!!
(6.3L)/307K = (8L)/T2
Math: 8 x 307 divided by 6.3

Explanation
The combined gas law states that the product of pressure and volume is directly proportional to the temperature. In this case, we have the initial pressure of 1.1 atmospheres and volume of 2.2 L at a temperature of 32 degrees Celsius. The new pressure is 1.4 atmospheres and volume is 1.8 L. To find the new temperature, we can set up the equation (P1 * V1) / T1 = (P2 * V2) / T2, where P1, V1, and T1 are the initial values and P2, V2, and T2 are the new values. Rearranging the equation, we get T2 = (P2 * V2 * T1) / (P1 * V1). Plugging in the values, we get T2 = (1.4 * 1.8 * 305.15) / (1.1 * 2.2) = 317.6 K.

Explanation
The ideal gas law states that the product of pressure and volume is directly proportional to the product of temperature and the number of moles of gas. In this case, the initial pressure, volume, and temperature are given as 0.9 atm, 3.6 L, and 34 degrees Celsius respectively. The final pressure and temperature are given as 1.4 atm and 38 degrees Celsius. To find the new volume, we can use the formula P1V1/T1 = P2V2/T2, where P1, V1, and T1 are the initial pressure, volume, and temperature respectively, and P2, V2, and T2 are the final pressure, volume, and temperature respectively. Plugging in the given values, we can solve for V2, which comes out to be approximately 2.34 L.

Explanation
(1.1 atm) (V) = (2 moles) (0.08321 L atm/molK) (305K)

Explanation
(1.1 atm) (3.7 L) = (3.4 moles) (0.08321 Latm/mol K) (T)

Explanation
There is only 1 set of conditions and you are solving for moles, therefore use the ideal gas law:
PV = nRT.
Since Pressure is given in kPa, you must use R = 8.314 kPa L/mol K.
Make sure to change to Kelvin for temperature.
(105 kPa) (79.9L) = n (8.314 kPa L/mol K) (297K)