Amines and Nitrogen Compounds Chemistry

  • Grade 12th
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1. Alkylamine dissolves in hydrochloric acid to form alkylammonium chloride. The nitrogen in the latter salt is:

Explanation

In alkylammonium chloride, the nitrogen atom is bonded to four substituents: three hydrogen atoms and one alkyl group, making it quadricovalent. Additionally, it carries a positive charge due to protonation by hydrochloric acid, which means it can also be considered unielectrovalent as it has a single positive charge. Thus, nitrogen in this context exhibits both quadricovalent and unielectrovalent characteristics.

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About This Quiz
Amines and Nitrogen Compounds Chemistry - Quiz

This assessment focuses on the chemistry of amines and nitrogen compounds. It evaluates your understanding of reactions, properties, and classifications of various amines. By engaging with this content, you will reinforce key concepts essential for mastering organic chemistry related to nitrogen compounds.

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2. The nitrogen in alkylammonium chloride (formed when alkylamine reacts with HCl) is:

Explanation

In alkylammonium chloride, the nitrogen atom is bonded to three alkyl groups and carries a positive charge due to the protonation by hydrochloric acid (HCl). This gives nitrogen a tetravalent character, as it forms four bonds (three with carbon atoms and one with the proton). However, the positive charge indicates that it can also be considered electrovalent, as it is associated with an ionic bond in the chloride salt. Thus, nitrogen exhibits both tetravalent and electrovalent properties in this compound.

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3. Which of the following is produced when aniline reacts with bromine water?

Explanation

When aniline reacts with bromine water, the amino group (-NH2) activates the aromatic ring, making it more reactive towards electrophilic substitution. Bromine, being an electrophile, adds to the benzene ring at the ortho (2-) and para (4-) positions relative to the amino group. Due to the presence of multiple reactive sites, bromination occurs at all three positions (2-, 4-, and 6-) of the benzene ring, resulting in the formation of 2,4,6-tribromoaniline. This product is favored because the amino group strongly directs electrophilic substitution to these positions.

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4. The carbylamine reaction is a test for:

Explanation

The carbylamine reaction specifically tests for primary amines because these compounds react with chloroform and a strong base (like potassium hydroxide) to form a characteristic isocyanide or carbylamine, which has a distinct foul odor. Secondary and tertiary amines do not yield this reaction, making it a selective test for primary amines only. This specificity is crucial in distinguishing between different types of amines in organic chemistry.

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5. Which reagent is known as Hinsberg reagent?

Explanation

Hinsberg reagent, or benzene sulfonyl chloride, is used in organic chemistry to differentiate between primary, secondary, and tertiary amines. It reacts with amines to form sulfonamides, which can be further analyzed. Primary amines form a soluble sulfonamide, while secondary amines yield a sulfonamide that is insoluble in water, and tertiary amines do not react. This property makes benzene sulfonyl chloride a valuable tool for identifying and characterizing amines in various chemical reactions.

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6. Aniline (C₆H₅NH₂) belongs to which class of amines?

Explanation

Aniline is classified as an aromatic primary amine because it contains a phenyl group (C₆H₅) attached to a primary amine functional group (NH₂). In primary amines, the nitrogen atom is bonded to one alkyl or aryl group and two hydrogen atoms. Since aniline's amine group is directly connected to an aromatic ring, it is categorized as aromatic. This distinguishes it from aliphatic amines, which lack aromatic rings. Thus, aniline fits the definition of an aromatic primary amine.

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7. LiAlH₄ reduction of an amide (R–CO–NR₂) gives:

Explanation

LiAlH₄ (lithium aluminum hydride) is a strong reducing agent that can effectively reduce amides. When an amide (R–CO–NR₂) is treated with LiAlH₄, the carbonyl group (C=O) is reduced to a primary amine, while the nitrogen remains bonded to the alkyl groups. This reduction process involves the addition of hydride ions, which facilitate the conversion of the carbonyl carbon to a saturated carbon, ultimately yielding an amine as the final product.

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8. Which compound among the following is a secondary amine?

Explanation

A secondary amine is characterized by having two alkyl or aryl groups attached to the nitrogen atom, along with one hydrogen atom. In the given options, (CH₃)₂NH has two methyl groups (CH₃) and one hydrogen attached to the nitrogen, fitting the definition of a secondary amine. In contrast, CH₃NH₂ is a primary amine, (CH₃)₃N is a tertiary amine, and C₆H₅NH₂ is also a primary amine, as they do not possess the necessary two organic substituents on the nitrogen.

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9. Which of the following amines does NOT respond to carbylamine reaction?

Explanation

The carbylamine reaction, used to identify primary amines, involves their reaction with chloroform and a strong base to produce a characteristic isocyanide. Secondary and tertiary amines do not participate in this reaction because they lack the necessary hydrogen atom on the nitrogen to form the isocyanide. Therefore, only primary amines can yield a positive result, while secondary and tertiary amines do not respond, making them the correct answer in this context.

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10. Reactants of reaction-I are CH₃CONH₂, KOH, Br₂ and reactants of reaction-II are CH₃NH₂, CHCl₃, KOH. The products of reaction-I and reaction-II are respectively:

Explanation

In reaction-I, CH₃CONH₂ (acetamide) reacts with KOH and Br₂ to form an alkyl isocyanate through a dehydrohalogenation process. In reaction-II, CH₃NH₂ (methylamine) with CHCl₃ and KOH leads to the generation of a carbene, a reactive intermediate characterized by a divalent carbon atom. The distinct nature of the reactants and conditions in both reactions results in the formation of these specific products: alkyl isocyanate from the first and carbene from the second.

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11. Which of the following amines does NOT respond to carbylamine reaction?

Explanation

The carbylamine reaction involves the reaction of primary amines with chloroform and a strong base to form isocyanides, which have a characteristic foul odor. In this case, (CH₃)₂NH, or dimethylamine, is a secondary amine and does not undergo the carbylamine reaction because it lacks the necessary primary amine structure. Primary amines like ethylamine, methylamine, and phenylamine can participate in this reaction, producing the distinct isocyanides, while secondary amines do not.

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12. Which of the following diazonium salts is relatively stable at 0–5°C?

Explanation

Diazonium salts are generally stabilized by resonance, particularly when they can delocalize their positive charge. The phenyl diazonium salt, [C₆H₅–N≡N]⁺Cl⁻, benefits from resonance stabilization through the aromatic ring, allowing for greater stability compared to aliphatic diazonium salts. At low temperatures (0–5°C), this stability is crucial, as it prevents decomposition. In contrast, the other options, which lack such effective resonance stabilization, are less stable under similar conditions, making the phenyl diazonium salt the most stable choice in this context.

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13. The intermediate species of reaction-I (CH₃CONH₂, KOH, Br₂) and reaction-II (CH₃NH₂, CHCl₃, KOH) are respectively:

Explanation

In reaction-I, the combination of acetamide (CH₃CONH₂) with KOH and Br₂ leads to the formation of an alkyl isocyanate intermediate. This occurs through the formation of an isocyanate from the deprotonation and subsequent reaction with bromine. In reaction-II, the use of methylamine (CH₃NH₂) with KOH and chloroform (CHCl₃) generates a carbene intermediate via the dehydrohalogenation process. The presence of strong bases facilitates these transformations, resulting in the specified intermediates of alkyl isocyanate and carbene.

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14. In the reaction: C₆H₅–CO–N(CH₃)₂ reacted with LiAlH₄ → [X]. What is [X]?

Explanation

In this reaction, lithium aluminum hydride (LiAlH₄) acts as a strong reducing agent. It reduces the ketone functional group (C₆H₅–CO–) in the compound C₆H₅–CO–N(CH₃)₂ to a primary alcohol, leading to the formation of C₆H₅–CH₂–N(CH₃)₂. The nitrogen atom remains attached to the dimethyl group, while the carbonyl carbon is reduced to a methylene group (–CH₂–), resulting in the product that retains the amine functionality.

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15. Which of the following compounds will dissolve in an alkali solution after it has undergone reaction with Hinsberg reagent?

Explanation

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16. How many isomeric amines with formula C₇H₉N contain a benzene ring?

Explanation

The formula C₇H₉N indicates a compound with seven carbon atoms, nine hydrogen atoms, and one nitrogen atom. When considering isomeric amines that include a benzene ring, variations arise from different placements of the amine group and the carbon chain. The benzene ring can be attached to the carbon chain in several ways, and the remaining carbon atoms can be arranged to form various structural isomers. This leads to five distinct isomeric amines that satisfy the given formula while containing a benzene ring.

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17. Which one of the following compounds gives carboxylic acid with HNO₂?

Explanation

When an amide, such as C₆H₅CONH₂ (benzamide), reacts with nitrous acid (HNO₂), it undergoes a process called hydrolysis, resulting in the formation of a carboxylic acid (benzoic acid) and nitrogen gas. This reaction occurs because the amide bond is susceptible to cleavage by nitrous acid, leading to the release of the carboxylic acid functional group. In contrast, the other compounds listed do not undergo this specific reaction with HNO₂ to yield a carboxylic acid.

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18. N-Ethyl pthalimide on hydrolysis gives:

Explanation

N-Ethyl pthalimide undergoes hydrolysis, which involves the cleavage of the pthalimide structure, leading to the formation of ethyl amine. During this process, the ethyl group is released as an amine, while the pthalimide ring is opened and converted into the corresponding amine. The hydrolysis reaction specifically yields ethyl amine rather than other amines or alcohols due to the nature of the substituents and the reaction conditions. Thus, ethyl amine is the primary product formed from the hydrolysis of N-ethyl pthalimide.

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19. The bromination of aniline in water produces which compound?

Explanation

Aniline, when brominated in water, undergoes electrophilic aromatic substitution. The amino group (-NH2) is a strong activating group that directs bromination to the ortho and para positions relative to itself. In the presence of excess bromine, multiple bromine atoms can add to the aromatic ring. Consequently, bromination occurs at the 2, 4, and 6 positions, leading to the formation of 2,4,6-tribromoaniline as the major product. The presence of water facilitates the reaction and stabilizes the intermediates, promoting further bromination.

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20. Which gas is evolved when acetamide is treated with sodium nitrite and HCl?

Explanation

When acetamide reacts with sodium nitrite in the presence of hydrochloric acid, a process known as diazotization occurs. During this reaction, acetamide is converted into a diazonium salt, which is unstable and decomposes to release nitrogen gas (N₂) as a byproduct. The nitrogen gas is evolved due to the breakdown of the diazonium compound, making nitrogen the primary gas produced in this chemical reaction.

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Alkylamine dissolves in hydrochloric acid to form alkylammonium...
The nitrogen in alkylammonium chloride (formed when alkylamine reacts...
Which of the following is produced when aniline reacts with bromine...
The carbylamine reaction is a test for:
Which reagent is known as Hinsberg reagent?
Aniline (C₆H₅NH₂) belongs to which class of amines?
LiAlH₄ reduction of an amide (R–CO–NR₂) gives:
Which compound among the following is a secondary amine?
Which of the following amines does NOT respond to carbylamine...
Reactants of reaction-I are CH₃CONH₂, KOH, Br₂ and reactants of...
Which of the following amines does NOT respond to carbylamine...
Which of the following diazonium salts is relatively stable at...
The intermediate species of reaction-I (CH₃CONH₂, KOH, Br₂) and...
In the reaction: C₆H₅–CO–N(CH₃)₂ reacted with LiAlH₄ →...
Which of the following compounds will dissolve in an alkali solution...
How many isomeric amines with formula C₇H₉N contain a benzene...
Which one of the following compounds gives carboxylic acid with...
N-Ethyl pthalimide on hydrolysis gives:
The bromination of aniline in water produces which compound?
Which gas is evolved when acetamide is treated with sodium nitrite and...
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