# Math Work Trivia Quiz

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| By Derrickmcneill
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Derrickmcneill
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Quizzes Created: 14 | Total Attempts: 36,813
Questions: 10 | Attempts: 139

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In this work-themed maths quiz, you’ll be tasked with working out how much work is being done in each of the given scenarios, using units like newtons, metres and joules in order to help you work it out.

• 1.

### 5,500 J of work is done to move a rock 25 m. How much force was applied?

Explanation
The work done is calculated by multiplying the force applied by the distance moved. In this case, the work done is 5,500 J and the distance moved is 25 m. To find the force applied, we can rearrange the formula to force = work/distance. Therefore, the force applied is 5,500 J / 25 m = 220 N.

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• 2.

### You and 3 friends apply a combined force of 489.5 N to push a piano.  The amount of work done is 1762.2 J.  What displacement  did the piano move?

Explanation
The amount of work done is equal to the force applied multiplied by the displacement. In this case, the work done is 1762.2 J and the force applied is 489.5 N. To find the displacement, we can rearrange the formula to solve for it. The displacement is equal to the work done divided by the force applied. Plugging in the values, the displacement is equal to 1762.2 J divided by 489.5 N, which is approximately 3.60 m or 3.6 m.

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• 3.

### Calculate the amount of work done when moving a 567 N crate a distance of 20 meters.

Explanation
The amount of work done can be calculated using the formula: work = force × distance. In this case, the force applied is 567 N and the distance moved is 20 meters. By multiplying these values together, we get 11340 J. However, since the question asks for the amount of work done, we round this value to the nearest whole number, which is 11300 J.

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• 4.

### A fallen tree branch with a weight of 154 N is lifted 2.75 meters.  How much work is done?

Explanation
The work done can be calculated by multiplying the force applied (weight of the branch) by the distance over which the force is applied (lifting height). In this case, the weight of the branch is given as 154 N and the lifting height is 2.75 meters. Therefore, the work done is 154 N * 2.75 m = 423.5 J.

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• 5.

### If it took a bulldozer 567.6 joules of work to push a mound of dirt 30.5 meters, how much force did the bulldozer have to apply?

Explanation
The force applied by the bulldozer can be calculated using the formula: force = work / distance. In this case, the work done is given as 567.6 joules and the distance is given as 30.5 meters. By substituting these values into the formula, we can find the force applied. The result is 18.6 N, which represents the amount of force the bulldozer had to apply to push the mound of dirt.

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• 6.

### A front end loader needed to apply 137 newtons of force to lift a rock.  A total of 223 joules of work was done.  How far was the rock lifted?

Explanation
The work done on an object is equal to the force applied multiplied by the distance over which the force is applied. In this case, the work done is 223 joules and the force applied is 137 newtons. To find the distance, we can rearrange the equation to distance = work/force. Plugging in the values, we get distance = 223 joules / 137 newtons = 1.63 meters. Therefore, the rock was lifted a distance of 1.63 meters.

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• 7.

### A young boy applied a force of 2,550 newtons on his St. Bernard dog who is sitting on the boy's tennis shoes.  He was unable to move the dog.  How much work did he do trying to push the dog?

Explanation
The work done is calculated by multiplying the force applied by the displacement in the direction of the force. In this case, since the dog did not move, there was no displacement in the direction of the force. Therefore, the work done is zero.

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• 8.

### If it takes 68 joules of work to push a desk chair 22 m across a floor, what force would be needed?

Explanation
The force needed to push the desk chair can be calculated using the formula: Force = Work / Distance. In this case, the work is given as 68 joules and the distance is 22 m. Therefore, the force needed would be 68 joules / 22 m = 3.09 N. The answer 3.09 m is incorrect as it does not represent a force, but rather a distance.

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• 9.

### If a long distance runner with a weight of 596.82 newtons does 35,674.7 joules of work during a portion of a race, what displacement will she cover during that portion?

Explanation
The work done by a runner can be calculated using the formula work = force x displacement. In this case, the work done is given as 35,674.7 joules and the force is the weight of the runner, which is 596.82 newtons. By rearranging the formula, we can solve for the displacement: displacement = work / force. Plugging in the values, we get displacement = 35,674.7 joules / 596.82 newtons = 59.8 meters. Therefore, the runner will cover a displacement of 59.8 meters during that portion of the race.

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• 10.

### Children are sled riding on a hill.  One little girl pulls her sled back up the hill and does 379.5 joules of work while pulling it back up the 17.3 meter hill.  What amount of force did she exert on the sled?

Explanation
The amount of force exerted by the little girl on the sled can be calculated using the formula for work: work = force × distance. In this case, the work done is given as 379.5 joules and the distance is 17.3 meters. Rearranging the formula, we get force = work ÷ distance. Substituting the given values, we find that the force exerted by the girl on the sled is 21.9 N. Therefore, the correct answer is 21.9, 21.9 N, 21.9N.

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