Stages And Functions Of Meiosis Trivia Questions! Quiz

During meiosis, two rounds of nuclear division occur. This is because meiosis involves two stages: meiosis I and meiosis II. In meiosis I, the homologous chromosomes separate, resulting in two haploid cells. Then, in meiosis II, the sister chromatids separate, resulting in four haploid cells. Therefore, a total of two rounds of nuclear division occur during meiosis.

Metaphase I is the correct answer because during this stage of meiosis, tetrads (homologous pairs of chromosomes) align at the equator of the cell. This alignment is important for the subsequent separation of the homologous chromosomes during anaphase I. Prophase I is the stage where crossing over occurs, prophase II is the stage where chromosomes condense again after the first division, and anaphase II is the stage where sister chromatids separate.

During prophase I of meiosis, homologous chromosomes pair up and exchange genetic material through a process called crossing over. This results in significant gene shuffling, as sections of DNA are swapped between the paired chromosomes. This genetic recombination increases genetic diversity and ensures that each gamete produced will have a unique combination of genes. Therefore, prophase I is the stage in which there is significant gene shuffling.

Anaphase II is the stage in meiosis where sister chromatids separate and move towards opposite poles of the cell. This occurs after the chromosomes have already undergone crossing over and independent assortment in meiosis I. During anaphase II, the centromeres divide and the sister chromatids are pulled apart by the spindle fibers, ensuring that each daughter cell receives a complete set of chromosomes. Therefore, anaphase II is the correct answer for the stage in which sister chromatids split and move to poles.

During metaphase I of meiosis, homologous chromosomes align at the equator of the cell. This stage occurs after prophase I, where homologous chromosomes pair up and undergo crossing over, and before anaphase I, where homologous chromosomes separate and move to opposite poles of the cell. In metaphase I, the alignment of homologous chromosomes at the equator ensures that each daughter cell will receive one chromosome from each homologous pair, contributing to genetic diversity in offspring. Therefore, metaphase I is the correct stage where homologous chromosomes move to the equator.

Prophase II is the stage of meiosis that follows the first division of meiosis. During prophase II, the nuclear envelope breaks down, the spindle fibers reassemble, and the chromosomes condense. The sister chromatids, which were formed during the first division, become visible. Therefore, it is likely that the stage that starts with 2 cells is prophase II, as it is the beginning of the second division of meiosis.

During anaphase I of meiosis, homologous chromosomes separate and move towards opposite poles of the cell. This is possible due to the contraction of the spindle fibers attached to the chromosomes, pulling them apart. This stage is crucial as it ensures that each daughter cell receives one complete set of chromosomes, consisting of one homolog from each pair. Therefore, anaphase I is the correct answer as it accurately describes the stage in which homologous chromosomes move to poles.

During telophase II of meiosis, the cytoplasm divides to form four cells. This is the final stage of meiosis, where the chromosomes have already separated into two sets in the previous stages. In telophase II, the nuclear envelope reforms around each set of chromosomes, and the cytoplasm divides through cytokinesis to create four individual cells. These cells are haploid, meaning they contain half the number of chromosomes compared to the parent cell. Therefore, the given answer is correct.

During prophase I of meiosis, homologous chromosomes pair up and form tetrads. This stage is characterized by the crossing over of genetic material between the homologous chromosomes, which leads to genetic variation. Anaphase II and telophase II occur during the second round of cell division in meiosis and do not involve the formation of tetrads. Prophase II also does not involve the pairing of homologous chromosomes. Therefore, the correct answer is prophase I.

Anaphase II is the stage of meiosis where the tetrads, which are pairs of homologous chromosomes, separate and move towards opposite poles of the cell. This is the final step before the formation of four haploid daughter cells. In anaphase II, the sister chromatids of each chromosome separate and are pulled apart by the spindle fibers, ensuring that each daughter cell receives one copy of each chromosome.