Spongebob Genetics Worksheets II

The genotype presented, [yb], is a heterozygous genotype (He). This is because it contains two different alleles for the given gene, represented by the letters y and b. In a homozygous genotype, both alleles would be the same.

The genotype [TT] consists of two identical alleles, which means it is homozygous (Ho).

The genotype presented, [Pp], indicates that there are two different alleles present for the gene in question. This means that the genotype is heterozygous (He), as it contains both a dominant allele (P) and a recessive allele (p).

The genotype presented is "dd". In genetics, homozygous refers to having two identical alleles for a particular gene. Since both alleles in "dd" are the same, it is homozygous.

The correct answer is "Homozygous: Same". Homozygous refers to having two identical alleles for a specific trait. In this context, SpongeBob and Squidward are bragging about being "purebred," which means they have two identical alleles for the selected trait they are discussing. This is why the term "Homozygous" fits as the correct answer.

When a homozygous red shell snail (rr) is crossed with a homozygous white shell snail (ww), the resulting offspring will have the genotype of (rw), which represents a pink shell. This is because the gene for red shell (r) is incompletely dominant over the gene for white shell (w), resulting in a blend of the two colors. Therefore, the children of this cross would have a pink shell phenotype.

The phenotype for the genotype (Yy) is yellow body color.

Wilma's genotype is [Rr]. This means that she has one dominant allele for round eye shape (R) and one recessive allele for non-round eye shape (r).

If Sherry, who has a genotype of [rr], wants to have kids with red shells, her husband snail must also have a genotype of [rr]. This is because the genotype [rr] is homozygous for the red shell trait. When both parents have the same genotype for the desired trait, there is a higher chance of passing on that trait to their children. In this case, having a genotype of [rr] for both parents would result in a 50% chance of having children with red shells.

The genotype [rr] would not be found in their children because both SpongeWilma and SpongeWilbur have at least one dominant allele for round eyes ([Rr] and [RR] respectively). In order for a child to have the genotype [rr], they would need to inherit a recessive allele from both parents, which is not possible in this case.

The statement is true because a phenotype refers to the observable characteristics or traits of an organism, which can include physical attributes like color. In this case, "green goobers" is being referred to as a phenotype, indicating that the observable characteristic being discussed is the color green.

A purebred squarepants would have a genotype of [SS] because the squarepants gene is represented by the letter S, and a purebred individual would have two copies of the squarepants gene, denoted by SS.

Wilbur's genotype is [RR]. This means that both of his alleles for the eye shape gene are dominant, resulting in round eyes. Since Wilbur's family claims to have a pure line, it suggests that both of his parents also had the genotype [RR].

The symbol used to denote "genotype" is [ ]. This symbol is commonly used in genetics to represent the genetic makeup of an organism. It is used to enclose the combination of alleles or genes that an individual possesses for a particular trait or set of traits. The square brackets indicate that the information inside represents the genotype of an organism, distinguishing it from other symbols or notations used in genetics.

Based on the given information, SpongeBetty's father is a heterozygous squarepants. This means that he has one dominant allele (S) and one recessive allele (s) for the squarepants trait. The genotype [Ss] represents this combination of alleles, where S stands for the dominant allele and s stands for the recessive allele.

The phenotype for the genotype (ll) is "stubby nose style". This means that an individual with this genotype will have a nose that is short and stubby in appearance.

The correct genotype for a red poofkin is [rr]. This is because the question states that the red gene is represented by the lowercase letter "r". Since red is the desired color for the poofkin, it means that both alleles in the genotype must be lowercase "r". Therefore, the correct answer is [rr].

SpongeBetty's father is heterozygous for squarepants (Ss) and her mother is roundpants (ss). Since SpongeBetty inherits one allele from each parent, her genotype would be Ss.

The genotype for purebred oval eye shapes is [rr]. This is because the lowercase letter "r" represents the recessive allele for oval eye shape. Since the genotype is purebred, it means that both alleles are the same and there are no dominant alleles present. Therefore, the genotype for purebred oval eye shapes is [rr].

The correct genotype for a blue poofkin is [bb]. This is because the blue color is represented by the recessive blue gene, and since there is no mention of a dominant gene for blue color, it can be inferred that the genotype for blue poofkin would be homozygous recessive, represented by [bb].

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If SpongeBob and Patrick crossed a blue jellyfish with a goober, the resulting colors would be green and blue. This is because some jellyfish end up green as a result of incomplete dominance, meaning that the traits of both parents are expressed in the offspring. In this case, the blue jellyfish would contribute the blue color trait, while the goober would contribute the yellow color trait. When these traits combine, the offspring would have both green and blue colors.

When SpongeBob crosses a Poofkin with a red flower (rr) with a Poofkin with blue flowers (bb), the offspring will have a genotype of [rb]. This is because the red gene (r) is incompletely dominant over the blue gene (b), resulting in a blend of the two colors. Therefore, the phenotype of the offspring will be a blend of red and blue, which is represented by [rb].

If SpongeBob crossed two Poofkins with purple flowers, the resulting cross would yield 500 offspring with purple flowers. This is because the question states that Poofkins have incomplete dominance, meaning that when two different alleles (in this case, red and blue) are present, they blend together to create a third phenotype (purple). Therefore, when two Poofkins with purple flowers are crossed, their offspring will also have purple flowers. Since the question states that there were 1,000 seeds in total, and all of them will be purple, the number of purple offspring will be 500.

When SpongeBob crosses two Poofkins with purple flowers, the offspring will inherit one purple gene (p) from each parent. Since purple is a result of incomplete dominance, the offspring will also be purple. Therefore, 100% of the offspring will have purple flowers.

If SpongeBob and Patrick crossed two heterozygous green "goobers," the offspring would have a 25% chance of being yellow. This is because green color in the jellyfish is a result of incomplete dominance, where neither the yellow nor blue allele is completely dominant over the other. When two heterozygous green "goobers" are crossed, the possible genotypes of the offspring are YY (yellow), Yb (green), and bb (blue). Therefore, only 25% of the offspring would have the genotype for yellow color.

If SpongeBob crossed two Poofkins with purple flowers, the offspring would inherit one purple gene from each parent. Since purple is a result of incomplete dominance between red and blue genes, the offspring will have a 25% chance of inheriting a blue gene from both parents and therefore having blue flowers.

In incomplete dominance, when two different alleles are crossed, the resulting offspring will exhibit a phenotype that is intermediate between the two parental phenotypes. In this case, crossing a poofkin with red flowers (rr) with a poofkin with blue flowers (bb) would result in offspring with the genotype rb. Since rb represents a purple flower, all of the offspring would have purple flowers. Therefore, the correct answer is 100%.

If SpongeBob and Patrick crossed two "goobers", the offspring would have a 50% chance of being green. This is because the jellyfish exhibit incomplete dominance, meaning that neither the yellow nor the blue allele is completely dominant over the other. When two goobers are crossed, there is a 25% chance of getting yellow offspring (yy), a 25% chance of getting blue offspring (bb), and a 50% chance of getting green offspring (yb or by). Therefore, 50% of the offspring would be green.