What Do You Know About Population Genetics? Trivia Quiz

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| By Dajatsu
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Dajatsu
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Quizzes Created: 10 | Total Attempts: 8,613
| Attempts: 1,521
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  • 1/5 Questions

    Hardy-Weinberg equilibrium assumes that in the population.

    • No selection is occurring.
    • No mutation is occurring
    • No migration is occurring
    • Mating is random
    • The mating population is very large
    • All of the above
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About This Quiz

What do you know about population genetics? Genetics is a wonderful study that lets us know more about our genetic makeup than the naked eye could ever allow us to. It makes us understand how likely we are to suffer from a life-threatening illness or have certain features that our parents have. Just how different is one person’s genetic makeup different from another, and why the change? Take the quiz to see how knowledgeable you are.

What Do You Know About Population Genetics? Trivia Quiz - Quiz

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  • 2. 

    If the frequency of the a allele is 0.1, then, if the population is at Hardy-Weinberg equilibrium, the percentage of individuals that are AA should be ______%

    Explanation
    In a population at Hardy-Weinberg equilibrium, the frequency of the homozygous genotype AA can be calculated by squaring the frequency of the A allele. In this case, the frequency of the A allele is 0.1, so squaring it gives 0.01. To convert this to a percentage, we multiply by 100, resulting in 1%. Therefore, the correct answer is 1%, not 81,81%.

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  • 3. 

    If the frequency of the a allele is 0.1, then, if the population is at Hardy-Weinberg equilibrium, the percentage of individuals that are Aa should be ______%

    Explanation
    If the frequency of the "a" allele is 0.1, then in a population at Hardy-Weinberg equilibrium, the percentage of individuals that are heterozygous (Aa) can be calculated using the equation 2pq, where p is the frequency of the dominant allele (A) and q is the frequency of the recessive allele (a). In this case, p = 0.9 (1 - 0.1) and q = 0.1. Plugging these values into the equation, we get 2 * 0.9 * 0.1 = 0.18 or 18%. So, the percentage of individuals that are Aa is 18%.

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  • 4. 

    If the frequency of the a allele is 0.1, then, if the population is at Hardy-Weinberg equilibrium, the percentage of individuals that are aa should be ______%

    Explanation
    If the frequency of the a allele is 0.1, then in a population at Hardy-Weinberg equilibrium, the percentage of individuals that are aa can be calculated using the equation p^2, where p is the frequency of the a allele. In this case, p = 0.1. Therefore, the percentage of individuals that are aa would be 0.1^2 = 0.01, which is equivalent to 1%.

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  • 5. 

    If, in a population at Hardy-Weinberg equilibrium, 4% of the individuals are aa, then the percentage of AA individual should be ______%

    Explanation
    In a population at Hardy-Weinberg equilibrium, the percentage of AA individuals can be determined by subtracting the percentage of aa individuals from 100%. Since 4% of the individuals are aa, the remaining percentage of individuals must be made up of AA and Aa genotypes. Therefore, the percentage of AA individuals is 100% - 4% = 96%.

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  • Current Version
  • Mar 22, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Dec 05, 2010
    Quiz Created by
    Dajatsu
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