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2.

Which of the following will be the kinetically favored product from the depicted reaction ?

B
D
A
C

Correct Answer

A. D

3.

A C₈H₁₄ hydrocarbon (X) is reduced by sodium in liquid ammonia to a single C₈H₁₆ product (Y). Both of these compounds undergo hydrogenation (Pt catalyst) to give 2,5-dimethylhexane. Ozonolysis of Y with an oxidative workup produces a single C₄H₈O₂ carboxylic acid. Reaction of Y with perbenzoic acid (C₆H₅CO₃H) gives a chiral C₈H₁₄O product, but reaction with bromine gives an achiral C₈H₁₄Br₂ product What are X and Y?

X is 2,5-dimethyl-2,4-hexadiene ; Y is cis-2,5-dimethyl-3-hexene.
X is 2.5-dimethyl-1,5-hexadiene ; Y is 2,5-dimethyl-3-hexyne.
X is 2,5-dimethyl-3-hexyne ; Y is trans-2,5-dimethyl-3-hexene.
X is 2,5-dimethyl-3-hexyne ; Y is cis-2,5-dimethyl-3-hexene.

Correct Answer

A. X is 2,5-dimethyl-3-hexyne ; Y is trans-2,5-dimethyl-3-hexene.

Explanation

The given information suggests that X is a C8H14 hydrocarbon that undergoes reduction to form Y, a C8H16 hydrocarbon. Y is then subjected to ozonolysis, which produces a single C4H8O2 carboxylic acid. This implies that Y must contain a double bond, which is cleaved during ozonolysis to form the carboxylic acid. Additionally, Y reacts with perbenzoic acid to form a chiral product, indicating the presence of a stereocenter. However, Y reacts with bromine to form an achiral product, suggesting that the bromine addition occurs in a way that does not generate a stereocenter. The only option that satisfies all of these conditions is X being 2,5-dimethyl-3-hexyne and Y being trans-2,5-dimethyl-3-hexene.

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4.

A C8H12 chiral hydrocarbon, X, is reduced by catalytic hydrogenation to an achiral C8H14 compound.
Ozonolysis of X (H2O2 workup) gave a chiral C8H12O4 dicarboxylic acid.
Which of the following could be X ? - ProProfs

A C₈H₁₂ chiral hydrocarbon, X, is reduced by catalytic hydrogenation to an achiral C₈H₁₄ compound. Ozonolysis of X (H₂O₂ workup) gave a chiral C₈H₁₂O₄ dicarboxylic acid. Which of the following could be X ?

A
D
B
C

Correct Answer

A. A

5.

Addition of HBr to 2,3-dimethyl-1,3-cyclohexadiene may occur in the absence or presence of peroxides.
In each case two isomeric C8H13Br products are obtained.
Which of the following is a common product from both reactions? - ProProfs

Addition of HBr to 2,3-dimethyl-1,3-cyclohexadiene may occur in the absence or presence of peroxides. In each case two isomeric C₈H₁₃Br products are obtained. Which of the following is a common product from both reactions?

B
D
A
C

Correct Answer

A. B

Explanation

The common product obtained from both reactions is B.

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6.

Cyclooctatetraene, C8H8, appears to be a conjugated annulene.
In addition to the planar configuration, three non-planar structures may be considered, all of which are shown below.
Which of these is most likely to be the favored conformation? note that D is planar. - ProProfs

Cyclooctatetraene, C₈H₈, appears to be a conjugated annulene. In addition to the planar configuration, three non-planar structures may be considered, all of which are shown below. Which of these is most likely to be the favored conformation? note that D is planar.

A
B
D
C

Correct Answer

A. C

Explanation

The most likely favored conformation is C. This is because in order to have conjugation in a molecule, it is favorable for the p-orbitals to overlap and align in a planar configuration. The other structures shown are non-planar, which would disrupt the conjugation and make it less stable. Therefore, C, which is also planar, is the most likely favored conformation for cyclooctatetraene.

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1

7.

The S_N2 reaction of 1-chloro-3-methylbutane with sodium methoxide is relatively slow, but can be accelerated by the addition of a small amount of NaI. How is this catalysis best explained?

The NaI changes the mechanism to SN1
SN2 reaction of iodide ion converts the alkyl chloride to the more reactive alkyl iodide
The iodide anion activates the methoxide nucleophile
The sodium cation helps pull off the chloride anion

Correct Answer

A. SN2 reaction of iodide ion converts the alkyl chloride to the more reactive alkyl iodide

Explanation

The addition of NaI in the reaction converts the alkyl chloride to a more reactive alkyl iodide. This is because the iodide ion is a better leaving group than the chloride ion, making the alkyl iodide more susceptible to nucleophilic attack. Therefore, the SN2 reaction is accelerated by the presence of NaI.

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8.

Which reagent(s) would best accomplish the following transformation?

(i) HOBr (ii) Mg in ether
(i) B2H6 in ether (ii) H2O2 and base
(i) HgSO4 in H2O (ii) NaBH4
H3O+ & heat

Correct Answer

A. (i) B2H6 in ether (ii) H2O2 and base

Explanation

The given transformation involves the addition of a hydroxyl group (-OH) to a double bond. This is a typical reaction of hydroboration-oxidation, where the first step is the addition of borane (B2H6) in ether to the double bond, forming a boron intermediate. In the second step, the boron intermediate is oxidized by H2O2 and base, resulting in the formation of the hydroxyl group. Therefore, the reagents B2H6 in ether and H2O2 with base would best accomplish this transformation.

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9.

Which of the following reagents would not effect the following transformation?

PCl3
SOCl2
HCl & ZnCl2
KCl (5 molar solution)

Correct Answer

A. KCl (5 molar solution)

Explanation

KCl (5 molar solution) would not affect the given transformation because it is a neutral salt and does not possess any reactive or transforming properties. The other reagents, PCl3, SOCl2, and HCl & ZnCl2, are all known to be reactive and can bring about various chemical transformations. However, KCl (5 molar solution) does not possess any such reactivity and would not cause any change in the given transformation.

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10.

The structures of two 3º-bicyclic chlorides (I and II) are shown below.

II is more reactive than I for both substitution and eleimination
I is more reactive than II for both substitution and eleimination
On treatment with KOH in ethanol, I undergoes substitution and II undergoes eleimination.
On treatment with KOH in ethanol, both compounds undergo E2 elimination.

Correct Answer

A. II is more reactive than I for both substitution and eleimination

11.

Identify "AC" product in following chart from following answers ?

A
B
C
D

Correct Answer

A. A

Explanation

The correct answer is A because it is the only option that matches the given "AC" product in the chart.

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Which of the following represents the most stable conformation of all cis-1,2,4-trimethylcyclohexane?

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Which of the following will be the kinetically favored product from the depicted reaction ?

A C₈H₁₂ chiral hydrocarbon, X, is reduced by catalytic hydrogenation to an achiral C₈H₁₄ compound. Ozonolysis of X (H₂O₂ workup) gave a chiral C₈H₁₂O₄ dicarboxylic acid. Which of the following could be X ?

Addition of HBr to 2,3-dimethyl-1,3-cyclohexadiene may occur in the absence or presence of peroxides. In each case two isomeric C₈H₁₃Br products are obtained. Which of the following is a common product from both reactions?

Cyclooctatetraene, C₈H₈, appears to be a conjugated annulene. In addition to the planar configuration, three non-planar structures may be considered, all of which are shown below. Which of these is most likely to be the favored conformation? note that D is planar.

The S_N2 reaction of 1-chloro-3-methylbutane with sodium methoxide is relatively slow, but can be accelerated by the addition of a small amount of NaI. How is this catalysis best explained?

Which reagent(s) would best accomplish the following transformation?

Which of the following reagents would not effect the following transformation?

The structures of two 3º-bicyclic chlorides (I and II) are shown below.

Identify "AC" product in following chart from following answers ?

Learn More About Organic Chemistry Quiz

Which of the following represents the most stable conformation of all cis-1,2,4-trimethylcyclohexane?

Quiz Preview

Which of the following will be the kinetically favored product from the depicted reaction ?

A C8H12 chiral hydrocarbon, X, is reduced by catalytic hydrogenation to an achiral C8H14 compound. Ozonolysis of X (H2O2 workup) gave a chiral C8H12O4 dicarboxylic acid. Which of the following could be X ?

Addition of HBr to 2,3-dimethyl-1,3-cyclohexadiene may occur in the absence or presence of peroxides. In each case two isomeric C8H13Br products are obtained. Which of the following is a common product from both reactions?

Cyclooctatetraene, C8H8, appears to be a conjugated annulene. In addition to the planar configuration, three non-planar structures may be considered, all of which are shown below. Which of these is most likely to be the favored conformation? note that D is planar.

The SN2 reaction of 1-chloro-3-methylbutane with sodium methoxide is relatively slow, but can be accelerated by the addition of a small amount of NaI. How is this catalysis best explained?

Which reagent(s) would best accomplish the following transformation?

Which of the following reagents would not effect the following transformation?

The structures of two 3º-bicyclic chlorides (I and II) are shown below.

Identify "AC" product in following chart from following answers ?

A C₈H₁₂ chiral hydrocarbon, X, is reduced by catalytic hydrogenation to an achiral C₈H₁₄ compound. Ozonolysis of X (H₂O₂ workup) gave a chiral C₈H₁₂O₄ dicarboxylic acid. Which of the following could be X ?

Addition of HBr to 2,3-dimethyl-1,3-cyclohexadiene may occur in the absence or presence of peroxides. In each case two isomeric C₈H₁₃Br products are obtained. Which of the following is a common product from both reactions?

Cyclooctatetraene, C₈H₈, appears to be a conjugated annulene. In addition to the planar configuration, three non-planar structures may be considered, all of which are shown below. Which of these is most likely to be the favored conformation? note that D is planar.

The S_N2 reaction of 1-chloro-3-methylbutane with sodium methoxide is relatively slow, but can be accelerated by the addition of a small amount of NaI. How is this catalysis best explained?