Organic Chemistry Trivia: Alcohols, Phenols & Ethers Quiz
-
The structure of iso-butyl alcohol is:
-
Ready to tackle some organic chemistry? Dive into the world of alcohols, phenols, and ethers with our engaging quiz! This comprehensive assessment will challenge your understanding of the structure, properties, and reactions of these fascinating compounds.
In this quiz, you'll encounter a diverse range of questions covering key topics like naming conventions, functional groups, and chemical behavior. Whether you're brushing See moreup on your chemistry knowledge or preparing for an exam, the Alcohols, Phenols & Ethers Quiz is designed to help you identify your strengths and areas needing improvement. Each question provides valuable insights to reinforce your learning and enhance your understanding of these essential compounds.
Take this quiz to see how well you know alcohols, phenols, and ethers, and gain confidence in mastering this crucial segment of organic chemistry!
Quiz Preview
- 2.
Monochlorination of toluene in sunlight followed by hydrolysis with aq. NaOH yields.
-
O- Cresol
-
M- Cresol
-
2, 4- Dihydroxytoulene
-
Benzyl alcohol
Correct Answer
A. Benzyl alcoholExplanation
The monochlorination of toluene in sunlight results in the formation of benzyl chloride. When benzyl chloride is hydrolyzed with aqueous sodium hydroxide (NaOH), it undergoes a nucleophilic substitution reaction to form benzyl alcohol. Therefore, the correct answer is benzyl alcohol.Rate this question:
-
- 3.
The process of converting alkyl halides into alcohols involves:
-
Addition Reaction
-
Substitution Reaction
-
Dehydrohalogenation Reaction
-
Rearrangement Reaction
Correct Answer
A. Substitution ReactionExplanation
The process of converting alkyl halides into alcohols involves substitution reaction. In this reaction, the halogen atom of the alkyl halide is replaced by a hydroxyl group (-OH) to form an alcohol. This substitution reaction occurs through the nucleophilic attack of a hydroxide ion (OH-) on the carbon atom bonded to the halogen. The halogen is displaced and replaced by the hydroxyl group, resulting in the formation of an alcohol.Rate this question:
-
- 4.
The reaction which involves dichlorocarbene as an electrophile is:
-
Reimer-Tiemann Reaction
-
Kolbe’s Reaction
-
Freidel–Craft’s Acylation
-
Kolbe–Schmidt Reaction
Correct Answer
A. Reimer-Tiemann ReactionExplanation
The Reimer-Tiemann Reaction involves the use of dichlorocarbene as an electrophile. In this reaction, a phenol or an enolizable aldehyde or ketone reacts with chloroform in the presence of a base to form a carbonyl compound with a substituted hydroxyl group. The dichlorocarbene acts as an electrophile by attacking the carbon of the carbonyl group, leading to the formation of a new carbon-carbon bond. This reaction is commonly used for the synthesis of salicylaldehydes and salicylic acids.Rate this question:
-
- 5.
Guess the compound A:
Correct Answer
A.Explanation
Bromide ions (Br−) can function as nucleophiles in electrophilic aromatic substitution reactions. In the presence of an oxidizing agent, they can brominate the aromatic ring specifically at positions that are ortho to the hydroxyl group and para to the methyl group. The hydroxyl group (-OH) on the aromatic ring is an activating and ortho/para-directing group. Similarly, the methyl group (-CH33) is also an activating group and directs substitution to the ortho and para positions. As a result, the combination of these substituents leads to preferential bromination at positions that are both ortho to the hydroxyl group and para to the methyl group.Rate this question:
-
- 6.
Anisole reacts with Br2 in ethanoic acid, predominantly give:
-
Only p- bromoanisole
-
2, 4, 6- tribromo anisole
-
Mixture of o- bromoanisole and p- bromoanisole
-
Only o- bromoanisole
Correct Answer
A. Only p- bromoanisoleExplanation
Anisole reacts with Br2 in ethanoic acid to predominantly give only p-bromoanisole. This is because the reaction follows an electrophilic aromatic substitution mechanism, where the bromine molecule acts as the electrophile. The bromine molecule attacks the benzene ring of anisole, and due to the presence of electron-donating methoxy group (-OCH3), the attack occurs at the para position, resulting in the formation of p-bromoanisole as the major product. The ortho position is less favored due to steric hindrance caused by the methoxy group. Therefore, the reaction predominantly produces only p-bromoanisole.Rate this question:
-
- 7.
Order the following compounds from most to least reactive:
-
III > IV > I > II
-
I > IV > III > II
-
II > I > III > IV
-
IV >III > I > II
Correct Answer
A. IV >III > I > IIExplanation
The given answer suggests that compound IV is the most reactive, followed by compound III, compound I, and finally compound II. This order is determined by the reactivity of the compounds, with compound IV being the most reactive and compound II being the least reactive.Rate this question:
-
- 8.
Phenol on nitration with conc. HNO3 form:
-
2-nitrophenol
-
4-nitrophenol
-
3-nitrophenol
-
2,4.6-nitrophenol
Correct Answer
A. 4-nitrophenolExplanation
When phenol undergoes nitration with concentrated nitric acid (HNO3), it results in the formation of 4-nitrophenol. This is a chemical reaction where a nitro group (-NO2) is added to the ortho position of the phenolic ring, producing 4-nitrophenol as the major product.Rate this question:
-
- 9.
The reaction of sodium benzene sulfonate with NaOH followed by acidification gives:
-
Phenol
-
Benzoic Acid
-
Benzene
-
1,2-dihydroxy benzene
Correct Answer
A. PhenolExplanation
When sodium benzene sulfonate reacts with NaOH, it forms sodium phenoxide. This is because the sodium ion from NaOH replaces the hydrogen ion in the sulphonate group, resulting in the formation of sodium phenoxide. When this solution is acidified, the phenoxide ion accepts a proton from the acid, forming phenol. Therefore, the correct answer is Phenol.Rate this question:
-
- 10.
The haloform reaction does not take place with:
-
Acetone
-
2-chloropropane
-
Ethanol
-
Methanol
Correct Answer
A. EthanolExplanation
The haloform reaction, a type of halogenation reaction, does not occur with ethanol because it lacks a methyl ketone group (CH3-CO-), which is essential for the formation of the haloform product. This reaction typically involves methyl ketones like acetone, not alcohols such as ethanol.Rate this question:
-
- 11.
Propene on hydroboration-oxidation produces:
-
CH3CH2CH2OH
-
CH3CHOHCH2OH
-
CH3CH2CHO
-
CH3CHOHCH3
Correct Answer
A. CH3CH2CH2OHExplanation
Propene on hydroboration-oxidation undergoes anti-Markovnikov addition, where the boron atom adds to the less substituted carbon atom, resulting in the formation of an alcohol. In this case, the less substituted carbon atom is the terminal carbon, so the boron atom adds to it. After oxidation, the boron atom is replaced by a hydroxyl group (OH), resulting in the formation of CH3CH2CH2OH, which is the correct answer.Rate this question:
-
- 12.
Among the following compounds, strongest acid is:
-
![Organic Chemistry Trivia: Alcohols, Phenols & Ethers Quiz - Quiz]()
-
C6H6
-
C2H6
-
CH3OH
Correct Answer
A. CH3OHExplanation
The strongest acid among the given compounds is CH3OH (methanol). Methanol is a weak acid but it is stronger than the other two compounds listed. C6H6 (benzene) is a nonpolar compound and does not have any acidic properties. C2H6 (ethane) is also a nonpolar compound and does not exhibit any acidic behavior. Methanol, on the other hand, can donate a proton (H+) and therefore has weak acidic properties.Rate this question:
-
- 13.
Among the following four compounds: (i) Phenol (ii) Methylphenol (iii) meta-nitrophenol (iv) para-nitrophenol The decreasing acidity order is:
-
(iv) > (iii) > (i) > (ii)
-
(iii) > (iv) > (i) > (ii)
-
(i) > (iv) > (iii) > (ii)
-
(ii) > (i) > (iii) > (iv)
Correct Answer
A. (iv) > (iii) > (i) > (ii)Explanation
The correct answer is (iv) > (iii) > (i) > (ii). This is because the acidity of a compound is determined by the stability of its conjugate base. In this case, para-nitrophenol (iv) has the highest acidity because the nitro group stabilizes the negative charge on the phenoxide ion through resonance. Meta-nitrophenol (iii) is next in acidity because the nitro group can still stabilize the negative charge, although to a lesser extent. Phenol (i) is less acidic than the nitrophenols because it lacks any electron-withdrawing groups to stabilize the negative charge. Methylphenol (ii) is the least acidic because the methyl group does not have any electron-withdrawing effect.Rate this question:
-
- 14.
During dehydration of alcohols to alkenes by heating with conc. H2SO4, the initial step is:
-
Formation of an ester
-
Protonation of alcohol molecule
-
Formation of carbocation
-
Elimination of water
Correct Answer
A. Protonation of alcohol moleculeExplanation
In the dehydration of alcohols to alkenes, the initial step is the protonation of the alcohol molecule. This involves the transfer of a proton from the concentrated sulfuric acid (H2SO4) to the alcohol molecule, resulting in the formation of a protonated alcohol. This protonation makes the alcohol a good leaving group, allowing the formation of a carbocation. Therefore, the correct answer is the protonation of the alcohol molecule.Rate this question:
-
- 15.
What are the products of the following reactions?
Correct Answer
A. -
Quiz Review Timeline (Updated): May 10, 2024 +
Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.
-
Current Version
-
May 10, 2024Quiz Edited by
ProProfs Editorial Team
Expert Reviewed by
Zohra Sattar Waxali -
Jan 23, 2014Quiz Created by
Tanmay Shankar
Back to top