Online Aptitude Test For Developer

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| By Deadwin85
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Deadwin85
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Quizzes Created: 1 | Total Attempts: 279
| Attempts: 279
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  • 1/15 Questions

    If in code of alphabet AT = 20, BAT = 40 then CAT = ?

    • A.34
    • B.56
    • C.40
    • D.60
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About This Quiz

The 'Online Aptitude Test for Developer' assesses critical thinking, problem-solving, and logical reasoning skills through a variety of coded and scenario-based questions. It's designed to challenge and enhance the analytical abilities of prospective developers.

Aptitude Quizzes & Trivia

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  • 2. 

    Read the following information carefully and answer the questions given below it: (A)Gopal is shorter than Ashok but taller than Kunal. (B)Navin is shorter than Kunal. (C)Jayesh is taller than Navin. (D)Ashok is taller than Jayesh. Who among them is the tallest?

    • Gopal

    • Ashok

    • Kunal

    • Navin

    Correct Answer
    A. Ashok
    Explanation
    Based on the given information, we can determine the following height order: Navin < Kunal < Gopal < Ashok < Jayesh. Therefore, Ashok is the tallest among them.

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  • 3. 

    Compare the knowledge of persons X, Y, Z, A, B and C in relation to each other 1.X knows more than A. 2.Y knows as much as B. 3.Z knows less than C. 4.A knows more than Y The best knowledge person amongst all is:

    • X

    • Y

    • A

    • C

    Correct Answer
    A. X
  • 4. 

    In a certain code language K is written as 11 and KEEP is written as 37. How will the word DRAFT be written in that code language?

    • 45

    • 49

    • 46

    • 48

    Correct Answer
    A. 49
    Explanation
    In the given code language, each letter is assigned a numerical value. The value assigned to K is 11 and the value assigned to KEEP is 37. Therefore, we can conclude that each letter in the word is assigned a value that is the sum of the numerical values of its individual letters. Applying this logic to the word DRAFT, we add the values of each letter (4 + 18 + 1 + 6 + 20) which equals 49. Hence, the word DRAFT will be written as 49 in that code language.

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  • 5. 

    Arrange the words given below in a meaningful sequence. 1. Protect&nbsp; 2. Pressure 3. Relief 4. Rain 5. Flood

    • 2, 4, 3, 1, 5

    • 2, 4, 5, 1, 3

    • 2, 5, 4, 1, 3

    • 3, 2, 4, 5, 1

    Correct Answer
    A. 2, 4, 5, 1, 3
    Explanation
    The correct sequence is 2, 4, 5, 1, 3. First, pressure builds up due to heavy rain. Then, the rain causes a flood. After the flood, relief is needed to help those affected. Finally, measures are taken to protect against future floods.

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  • 6. 

    Select the pair of words which has the same relationship. ARMY:LOGISTICS

    • Business:Strategy

    • Soldier:Students

    • War:Logic

    • Team:Individual

    Correct Answer
    A. Business:Strategy
    Explanation
    The correct answer is Business:Strategy. In both pairs of words, the first word represents a larger entity or concept, while the second word represents a specific aspect or component of that larger entity. In the given pair, "business" is a broader term that encompasses various activities and operations, while "strategy" is a specific approach or plan used within the context of business. Similarly, "army" is a larger organization that involves various aspects, including logistics, while "logistics" is a specific component of the army's operations.

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  • 7. 

    The square of a two digit number is divided by half the number. After 36 is added to the quotient, this sum is then divided by 2. The digits of the resulting number are the same as those in the original number, but they are in reverse order. The ten`s place of the original number is equal to twice the difference between its digits. What is the number?

    • 45

    • 46

    • 47

    • 48

    Correct Answer
    A. 46
    Explanation
    Let the two-digit number be represented as AB, where A is the tens digit and B is the units digit. The square of this number is (10A + B)^2 = 100A^2 + 20AB + B^2. Half of the number is (10A + B)/2 = 5A + B/2. Dividing the square by half the number gives (100A^2 + 20AB + B^2) / (5A + B/2). Adding 36 to this quotient gives (100A^2 + 20AB + B^2 + 36) / (5A + B/2). Dividing this sum by 2 gives (100A^2 + 20AB + B^2 + 36) / (10A + B). Since the digits of the resulting number are the same as those in the original number but in reverse order, we can set up the equation 10B + A = (100A^2 + 20AB + B^2 + 36) / (10A + B). Simplifying this equation gives B = 2A. The only two-digit number that satisfies this condition is 46, making it the correct answer.

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  • 8. 

    If Sand is coded as Brick, Brick as House, House as Temple, Temple as Palace then where do you worship?

    • Palace

    • Temple

    • Brick

    • House

    Correct Answer
    A. Palace
    Explanation
    The given question is a substitution code puzzle, where each word is replaced with another word. According to the code, "Sand" is coded as "Brick", "Brick" as "House", "House" as "Temple", and "Temple" as "Palace". Therefore, if "Temple" is the code for "House", then "Palace" would be the code for "Temple". Hence, the answer is "Palace" as that is where you would worship according to the given code.

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  • 9. 

    If Sn denotes the sum of the first n terms in an Arithmetic Progression and S1: S4 = 1: 10 Then the ratio of first term to fourth term is:

    • 1: 3

    • 2: 3

    • 1: 4

    • 1: 5

    Correct Answer
    A. 1: 4
    Explanation
    The ratio of the sum of the first term to the sum of the fourth term in an arithmetic progression is equal to the ratio of the first term to the fourth term. In this case, the ratio of S1 to S4 is 1:10. Therefore, the ratio of the first term to the fourth term is also 1:10.

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  • 10. 

    Two merchants, M and N, enter into partnership. M puts in Rs. 20,000 in the first month and at the end of four months adds Rs.5,000 to his capital. While N withdraws Rs.20, 000 at the end of 8 months. At the end of the year, M and N received equal profit. Find the amount invested by N ?

    • Rs.20,000

    • Rs.30,000

    • Rs.40,000

    • Rs.50,000

    Correct Answer
    A. Rs.30,000
    Explanation
    Since M and N received equal profit at the end of the year, we can assume that their investments are equal.
    M initially invested Rs. 20,000 and added Rs. 5,000 after 4 months, so his total investment is Rs. 25,000.
    N withdrew Rs. 20,000 at the end of 8 months, so his total investment is also Rs. 25,000.
    Therefore, the amount invested by N is Rs. 25,000.

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  • 11. 

    The total capital investment in setting up a production unit is Rs.15 lakhs and the production unit produces 3 million kg of product annually. Selling price of product is 9 per kg. Manufacturing cost include raw material at the rate Rs.0.8 per kg, labour at the rate 1.2 per kg, packing at the rate of 0.6 per kg and utilities at the rate of 0.8 per kg. General expenses comes out to be 15% of manufacturing cost. If taxes are considered as 33% of gross annual earnings, determine the net profit of the production unit per year?

    • 0.5 crores

    • 1.02 crores

    • 1.5 crores

    • 2 crores

    Correct Answer
    A. 1.02 crores
    Explanation
    The net profit of the production unit per year is 1.02 crores. This can be calculated by subtracting the total expenses from the gross annual earnings. The total expenses include the manufacturing cost, which is calculated by adding the cost of raw material, labor, packing, and utilities. The general expenses, which are 15% of the manufacturing cost, are also included. Finally, the taxes, which are 33% of the gross annual earnings, are deducted from the gross annual earnings to determine the net profit.

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  • 12. 

    SELECTION BASED ON GIVEN CONDITIONS A few essential criteria for selection of group of items are given: From amongst five doctors A,B,C,D and E;four engineers G,H,K and L; six teachers M,N,O,P,Q and R some teams are to be selected.A,B,G,H,O,P and Q are females and the rest are males. Where ever there is a male doctor ,no female teacher. Where ever there is a male engineer, no female doctor. There shall not be more than two male teachers in any team. If the team consists of 2 doctors, 3 female teachers and 2 engineers, the members of the team are:

    • A B O P Q G H

    • C D O P Q G H

    • C D K L O P Q

    • D E G H O P Q

    Correct Answer
    A. A B O P Q G H
    Explanation
    The team consists of 2 doctors, 3 female teachers, and 2 engineers. According to the given conditions, wherever there is a male doctor, there cannot be a female teacher. Therefore, doctors A and B must be selected. Since there should not be more than two male teachers in any team, the team cannot have more than two male teachers. Therefore, the male teachers K and L cannot be selected. The remaining options have either more than two male teachers or do not have the required number of engineers. Therefore, the only valid option is A B O P Q G H.

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  • 13. 

    Six bells commence tolling together and toll at intervals of 2, 4, 6, 8 10 and 12 seconds respectively. In 30 minutes, how many times do they toll together?

    • 4

    • 10

    • 15

    • 16

    Correct Answer
    A. 16
    Explanation
    The bells toll together every 2 seconds. In 30 minutes, there are 30 * 60 = 1800 seconds. Since the bells toll together every 2 seconds, they will toll together 1800 / 2 = 900 times. However, we need to exclude the times when the bells toll together but also coincide with a multiple of 2, 4, 6, 8, 10, or 12 seconds. The least common multiple of these numbers is 120, so we need to subtract 1800 / 120 = 15 from the total. Therefore, the bells toll together 900 - 15 = 885 times.

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  • 14. 

    In an arithmetic series consisting of 51 terms, the sum of the first three terms is 65 and the sum of the middle three terms is 129. What is the first term and the common difference of the series?

    • 64, 9/8

    • 32, 8/9

    • 187/9, 8/9

    • 72, 9/8

    Correct Answer
    A. 187/9, 8/9
    Explanation
    The sum of the first three terms is 65, which means that the average of these three terms is 65/3. Similarly, the sum of the middle three terms is 129, so the average of these three terms is 129/3. Since the series is arithmetic, the average of the first three terms is equal to the average of the middle three terms, which gives us the equation (65/3) = (129/3). Solving this equation gives us the first term of the series as 187/9. The common difference can be found by subtracting the first term from the second term, which gives us (187/9) - (65/3) = 8/9. Therefore, the first term of the series is 187/9 and the common difference is 8/9.

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  • 15. 

    A,B and C enter into a partnership by investing in the ratio of 3:2:4. After one year ,B invests another Rs 2,70,000 and C,at the end of 2 years, also invests Rs 2,70,000.At the end of 3 years ,profit are shared in the ratio of 3:4:5.Find the initial investment of each A?

    • 2,70,000

    • 1,80,000

    • 3,60,000

    • None of these

    Correct Answer
    A. 2,70,000
    Explanation
    The question states that the initial investment ratio of A, B, and C is 3:2:4. After one year, B invests an additional Rs 2,70,000. This means that B's total investment after one year is 2 times his initial investment plus the additional investment, which is 2*2,70,000 = 5,40,000. At the end of 2 years, C also invests Rs 2,70,000. This means that C's total investment after 2 years is 4 times his initial investment plus the additional investment, which is 4*2,70,000 = 10,80,000. The profit at the end of 3 years is shared in the ratio of 3:4:5. Since the question asks for the initial investment of A, we can assume that A's initial investment is x. Therefore, B's initial investment is 2x and C's initial investment is 4x. We can set up the equation 3x : 4x : 5x = 5,40,000 : 10,80,000 : Total Profit. Solving this equation, we find that x = 2,70,000, which is the initial investment of A.

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  • Current Version
  • Mar 20, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • May 22, 2014
    Quiz Created by
    Deadwin85
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