2a253 Volume 2 CDC

57 Questions | Total Attempts: 128

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This is a study guide to help airman study for there end of course test. Not filling out there bubble sheets. End of disclaimer enjoy your studying. CDC 2A253N SOF/PR Electronic Warfare Systems Journeyman Volume 2. Electronic Warfare Principles and Support Equipment 2A253N 03 1308, Edit Code 01 AFSC 2A253


Questions and Answers
  • 1. 
    2. The serial transmission bit rate for the MIL-1553 data bus is
    • A. 

      A. 2 mega bits per second (Mbps)

    • B. 

      B. 16 Mbps

    • C. 

      C. 32 Mbps

    • D. 

      D. 64 Mbps

  • 2. 
    3. A MIL-STD 1553 data bus message must contain at least one command word with a max of how many data words?
    • A. 

      A. 3

    • B. 

      B. 16

    • C. 

      C. 20

    • D. 

      D. 32

  • 3. 
    6. The basic element in a computer microchip is?
    • A. 

      A. silver.

    • B. 

      B. silicon.

    • C. 

      C. copper.

    • D. 

      D. aluminum.

  • 4. 
    7. (202) Chips with circuits that can do the work of all the different parts of a computer are called
    • A. 

      A. valves.

    • B. 

      B. microchips.

    • C. 

      C. circuit boards.

    • D. 

      D. microprocessors.

  • 5. 
    8. (202) What controls the current passing through a computer circuit?
    • A. 

      A. Gates.

    • B. 

      B. Buffers.

    • C. 

      C. Transistors.

    • D. 

      D. Central processing unit.

  • 6. 
    9. (202) The heart of the entire computer complex data processing system is the
    • A. 

      A. gate.

    • B. 

      B. terminal.

    • C. 

      C. transistor.

    • D. 

      D. central processing unit.

  • 7. 
    10. (202) What controls the speed of a computer’s activities?
    • A. 

      A. Clock.

    • B. 

      B. Timer.

    • C. 

      C. Input equipment.

    • D. 

      D. Output equipment.

  • 8. 
    11. (202) What part of a computer acts like a sophisticated switchboard operator?
    • A. 

      A. Memory.

    • B. 

      B. Logic unit.

    • C. 

      C. Control unit.

    • D. 

      D. Arithmetic unit.

  • 9. 
    12. (202) Where does the arithmetic/logic unit of a computer store the intermediate results of arithmetic operations?
    • A. 

      A. Buffers.

    • B. 

      B. Circuits.

    • C. 

      C. Memory.

    • D. 

      D. Registers.

  • 10. 
    13. (203) The primary computer memory that usually cannot be erased is called
    • A. 

      A. random-access memory (RAM).

    • B. 

      b. read-only memory (ROM).

    • C. 

      C. secondary.

    • D. 

      D. auxiliary.

  • 11. 
    14. (203) Random-access memory is used to
    • A. 

      A. provide secondary memory access.

    • B. 

      B. provide auxiliary storage capabilities.

    • C. 

      C. store computer operating information.

    • D. 

      D. store information being calculated by the computer.

  • 12. 
    15. (203) In a computer the term auxiliary storage refers to
    • A. 

      A. specific storage locations.

    • B. 

      B. the size and capacity of storage area.

    • C. 

      C. memory stored outside the computer.

    • D. 

      D. data processed through the main storage area.

  • 13. 
    1. (201) Which was not a MIL-STD 1553 bus standard requirement?
    • A. 

      A. Information was to have a very low level of data transfer determinism.

    • B. 

      B. Information was to be transferred in a reliable, deterministic, command/response fashion.

    • C. 

      C. Information was to be transferred between bus terminals via a digital serial communications c. Information was to be transferred between bus terminals via a digital serial communications channel.

    • D. 

      D. Electrical interface requirements were to be defined by the standard for all bus terminals and bus terminal connections.

  • 14. 
    4. The MIL-STD 1553 data bus system command that provides a mechanism for a bus terminal (RT) to send data to another RT when the bus controller (BC) does not require the data is called?
    • A. 

      A. BC to RT.

    • B. 

      B. RT to BC.

    • C. 

      C. RT to RT.

    • D. 

      D. BC to BC.

  • 15. 
    5. Which is no a function of the MIL-STD 1553 data bus mode codes?
    • A. 

      A. Resetting terminals.

    • B. 

      B. Synchronizing the subsystem time.

    • C. 

      C. Executing a bus controller (BC) broadcast command.

    • D. 

      D. Commanding at bus terminal (RT) to initiate a system self-test.

  • 16. 
    16. (204) Using a text-based method to display characters and objects on a computer display refers to
    • A. 

      A. using Windows-based programs.

    • B. 

      B. displaying information in the form of individual dots.

    • C. 

      C. displaying information in the form of printed characters.

    • D. 

      D. communicating information from the central processing unit to the screen.

  • 17. 
    17. (205) Internet protocols can best be described as a
    • A. 

      A. way to communicate across interconnected networks.

    • B. 

      B. way to print documents from any work station.

    • C. 

      C. signal that produces radio frequencies.

    • D. 

      D. relay between work stations.

  • 18. 
    18. (205) The switches within a network main function is to
    • A. 

      A. build protocols to send across the network.

    • B. 

      B. forward frames of information over a network.

    • C. 

      c. generates a radio signal to extend range of a network.

    • D. 

      D. enable several users to send information over a network.

  • 19. 
    19. (206) What is the technique where blocks of data can be segmented into numerous blocks so  can be written called?
    • A. 

      A. Data striping.

    • B. 

      B. Mirroring.

    • C. 

      C. Bridging.

    • D. 

      D. Parity.

  • 20. 
    20. (206) What redundant array of independent disks (RAID) level has no redundancy of data?
    • A. 

      A. RAID–0.

    • B. 

      B. RAID–1.

    • C. 

      C. RAID–2.

    • D. 

      D. RAID–3.

  • 21. 
    21. (206) Which redundant array of independent disks (RAID) parity is distributed across all drives and eliminates a bottleneck?
    • A. 

      A. RAID–2.

    • B. 

      B. RAID–3.

    • C. 

      C. RAID–4.

    • D. 

      D. RAID–5.

  • 22. 
    22. (207) Shielded cable consists of a.
    • A. 

      A. metallic braid over the insulation.

    • B. 

      B. a metal conductor covered with a dielectric.

    • C. 

      C. an inner conductor separated by an insulation dielectric.

    • D. 

      D. a compact wire bundle with self-contained wire assemblies.

  • 23. 
    23. (208) Which is not a connector coupling type?
    • A. 

      A. Friction.

    • B. 

      B. Bayonet.

    • C. 

      C. Insertion.

    • D. 

      D. Threaded.

  • 24. 
    24. (208) Which is not a radio frequency (RF) connector precaution?
    • A. 

      A. Never step on the cable.

    • B. 

      B. Ensure a good grip when using pliers.

    • C. 

      C. Ensure you solder double shielded cables together.

    • D. 

      D. Ensure you do not exceed the bend radius of the cable.

  • 25. 
    25. (209) Twisting an optic fiber during installation or maintenance results in
    • A. 

      A. disturbances in lay uniformity

    • B. 

      B. greater elasticity of the glass fibers.

    • C. 

      C. reduced optical power transmission.

    • D. 

      D. good tension control preventing loose or uneven standing.

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