B2/B3 - 1.3 Homework
- 1.
A runner's position is 40 m at time t = 0 s. If he runs at a constant pace of 1.5 m/s, what will his position be at t = 45s? (Hint: Draw a graph to help!)
- A.
67.5 meters
- B.
107.5 meters
- C.
40 meters
- D.
106.5 meters
Correct Answer
B. 107.5 metersExplanation
The runner's position is initially 40 meters at t = 0s. Since the runner is running at a constant pace of 1.5 m/s, we can calculate his position at t = 45s by multiplying the constant pace by the time elapsed. 1.5 m/s * 45s = 67.5 meters. However, this only gives us the distance covered in 45s. To find the runner's position, we need to add this distance to his initial position of 40 meters. 40 meters + 67.5 meters = 107.5 meters. Therefore, the runner's position at t = 45s will be 107.5 meters.Rate this question:
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- 2.
A runner's position is 20 m at time t = 0 s. If he runs at a constant pace of 0.5 m/s, what will his position be at t = 45s? (Hint: Draw a graph to help!)
- A.
20 meters
- B.
40.5 meters
- C.
42.5 meters
- D.
22.5 meters
Correct Answer
C. 42.5 metersExplanation
The runner's position is given as 20 meters at time t = 0s. Since the runner is running at a constant pace of 0.5 m/s, we can calculate his position at t = 45s by multiplying the pace by the time elapsed. Therefore, the runner will have covered a distance of 0.5 m/s * 45s = 22.5 meters. Adding this distance to his initial position of 20 meters, we get a final position of 20 meters + 22.5 meters = 42.5 meters.Rate this question:
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- 3.
Use the data below to answer the following question: Is the velocity of the object constant? If so, what is the object's velocity? Time (s) Position (m) 0.0 30 1.0 40 2.0 50 3.0 60 4.0 70 5.0 80
- A.
Yes; +50 m/sec
- B.
Yes; +30 m/sec
- C.
Yes; + 10 m/sec
- D.
Yes; +16 m/sec
- E.
No
Correct Answer
C. Yes; + 10 m/secExplanation
The object's velocity is constant because the position values increase by a consistent amount of 10 meters every second. Therefore, the object's velocity is +10 m/sec.Rate this question:
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- 4.
Use the data below to answer the following question: What is the starting position of the object? Time (s) Position (m) 0.0 30 1.0 40 2.0 50 3.0 60 4.0 70 5.0 80
- A.
0 meters
- B.
+30 meters
- C.
+15 meters
- D.
-30 meters
- E.
+80 meters
Correct Answer
B. +30 metersExplanation
Based on the given data, the object starts at a position of 30 meters. This is evident from the position at time 0.0 seconds, which is given as 30 meters.Rate this question:
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- 5.
Use the data below to answer the following question: Write an equation for the objects position over time. Time (s) Position (m) 0.0 30 1.0 40 2.0 50 3.0 60 4.0 70 5.0 80
- A.
X = (-10 m/sec) (t) + 30 m
- B.
X = (+10 m/sec) (t) - 30 m
- C.
X = (-10 m/sec) (t) - 30 m
- D.
X = (+10 m/sec) (t) + 30 m
- E.
X = (10 m/sec) (t) + 30 m
Correct Answer
D. X = (+10 m/sec) (t) + 30 mExplanation
The equation X = (+10 m/sec) (t) + 30 m represents the object's position over time. The constant term of 30 m indicates that the object's initial position is 30 m. The coefficient of t is +10 m/sec, which means that the object's position is increasing by 10 m for every second that passes. Therefore, the equation accurately represents the given data and describes the object's position as it moves forward in time.Rate this question:
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- 6.
Use the data below to answer the following question: Use your equation to solve for the objects position at time 15.0 s Time (s) Position (m) 0.0 30 1.0 40 2.0 50 3.0 60 4.0 70 5.0 80
- A.
+150 m
- B.
+180 m
- C.
-150 m
- D.
- 180 m
- E.
0 m
Correct Answer
B. +180 mExplanation
The given data represents the position of an object at different points in time. To find the position at time 15.0 s, we can use interpolation. By observing the given data, we can see that the position increases by 10 m every 1 s. Therefore, in 15.0 s, the position would have increased by 10 m * 15 = 150 m from the initial position of 30 m. Adding this to the initial position gives us a final position of 30 m + 150 m = 180 m.Rate this question:
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- 7.
Use the graph below to answer questions 7-11 #7: What interval had the greatest velocity?
- A.
2-5 sec
- B.
5-7 sec
- C.
7-12 sec
- D.
12-14
Correct Answer
B. 5-7 secExplanation
The interval from 5-7 seconds had the greatest velocity. This can be determined by looking at the graph and observing that the slope of the line during this interval is steeper compared to the other intervals. A steeper slope indicates a higher velocity, so the 5-7 second interval had the greatest velocity.Rate this question:
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- 8.
Use the graph below to answer questions 7-11 #8: What interval had the most negative velocity?
- A.
2-5 sec
- B.
5-7 sec
- C.
7-12 sec
- D.
12-14
Correct Answer
A. 2-5 secExplanation
The interval from 2-5 seconds had the most negative velocity. This can be determined by looking at the graph and observing that the slope of the line during this interval is the steepest and has a negative value. This indicates that the object was moving in the negative direction at a faster rate during this time period compared to the other intervals.Rate this question:
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- 9.
Use the graph below to answer questions 7-11 #9: Describe the motion of the vehicle at 10 seconds?
- A.
The vehicle is at a constant positive velocity and moving.
- B.
The vehicle is at a constant negative velocity and moving.
- C.
The vehicle is at a constant velocity and not moving.
- D.
The vehicle is continually increasing in velocity.
Correct Answer
C. The vehicle is at a constant velocity and not moving.Explanation
At 10 seconds, the graph shows that the position of the vehicle remains constant. This means that the vehicle is not moving, as its displacement does not change over time. Additionally, since the graph does not show any change in velocity, it can be concluded that the vehicle is at a constant velocity. Therefore, the correct answer is that the vehicle is at a constant velocity and not moving.Rate this question:
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- 10.
Use the graph below to answer questions 7-11 #10: Describe the motion of the vehicle at 10 seconds?
- A.
The vehicle is at a constant positive velocity and moving.
- B.
The vehicle is at a constant negative velocity and moving.
- C.
The vehicle is at a constant velocity and not moving.
- D.
The vehicle is continually increasing in velocity.
Correct Answer
C. The vehicle is at a constant velocity and not moving. -
- 11.
Use the graph below to answer questions 7-11 #11: Describe the motion of the vehicle at 2-5 seconds
- A.
Velocity = +1 m/sec, traveling in the positive direction
- B.
Velocity = -1 m/sec, traveling in the positive direction
- C.
Velocity = +1 m/sec, traveling in the negative direction
- D.
Velocity = -1 m/sec, traveling in the negative direction
Correct Answer
D. Velocity = -1 m/sec, traveling in the negative directionExplanation
At 2-5 seconds, the motion of the vehicle is described as having a velocity of -1 m/sec and traveling in the negative direction. This means that the vehicle is moving backwards at a speed of 1 m/sec.Rate this question:
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- 12.
Is this graph possible? Can it describe the motion for one vehicle in a single trial? Choose the best answer below.
- A.
No, a vehicle can't be in the same position at the same value.
- B.
No, a vehicle can't have different positions attached to different time values.
- C.
Yes, a vehicle is able to have two positions at one time value
- D.
Yes, a vehicle can have multiple positions (one or more) at one time value.
Correct Answer
A. No, a vehicle can't be in the same position at the same value.Explanation
The answer is stating that a vehicle cannot be in the same position at the same time value. This is because in physics, an object can only occupy one position at a specific time. Therefore, it is not possible for a vehicle to have multiple positions at the same time value.Rate this question:
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- 13.
Use the following for questions 13-15 What happens when the lines above cross?
- A.
CMV1 and CMV2 crash
- B.
CMV1 and CMV2 have the same velocity
- C.
CMV1 and CMV2 are at the same position from the origin
- D.
CMV1 and CMV2 have moved the same total position
Correct Answer
A. CMV1 and CMV2 crashExplanation
When the lines above cross, it means that CMV1 and CMV2 collide or crash into each other.Rate this question:
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- 14.
Use the following for questions 13-15 Which CMV has moved more position overall from 0-15 seconds?
- A.
CMV1
- B.
CMV2
- C.
CMV1 and CMV2 are same
Correct Answer
B. CMV2Explanation
CMV2 has moved more positions overall from 0-15 seconds compared to CMV1.Rate this question:
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- 15.
Use the following for questions 13-15 Which answer best supports your response in #14
- A.
CMV1 has changed more position over this time period than CMV2
- B.
CMV2 is moving in the negative direction, and CMV1 is moving positive, so it has traveled further.
- C.
CMV2 has changed more position over this time period than CMV1
- D.
CMV1 and CMV2 change the same amount of position
Correct Answer
C. CMV2 has changed more position over this time period than CMV1 -
.png "Use the following for questions 13-15
What happens when the lines above cross?")
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Mar 22, 2023Quiz Edited by
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Sep 23, 2013Quiz Created by
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