Online Aptitude Test 1 - Freshers Venture - Quiz, Flashcards & Trivia

1. 14 students in a class failed in both QT and Accounts. 20 failed in QT, but 32 failed in Accounts. How many students were there in total ?

38

42

40

39

20+32 – 14 = 38 students

Explanation

20+32 – 14 = 38 students

2. A thief steals a car at 2.30pm and drives it at 60kmph. The theft is discovered at 3pm and the owner sets off in another car at 75kmph when will he overtake the thief ?

7 pm

8 pm

5 pm

12 pm

Let the thief is overtaken x hrs after 2.30pm distance covered by the thief in x hrs = distance covered by the owner in x-1/2 hr 60x = 75 ( x- ½) x= 5/2 hr thief is overtaken at 2.30 pm + 2 ½ hr = 5 pm

Explanation

Let the thief is overtaken x hrs after 2.30pm distance covered by the thief in x hrs = distance covered by the owner in x-1/2 hr 60x = 75 ( x- ½) x= 5/2 hr thief is overtaken at 2.30 pm + 2 ½ hr = 5 pm

3. A train covers a distance in 50 min ,if it runs at a speed of 48kmph on an average.The speed at which the train must run to reduce the time of journey to 40min will be?

40kmph

30kmph

80kmph

60kmph

Time=50/60 hr=5/6hr Speed=48mph distance=S*T=48*5/6=40km time=40/60hr=2/3hr New speed = 40* 3/2 kmph= 60kmph

Explanation

Time=50/60 hr=5/6hr Speed=48mph distance=S*T=48*5/6=40km time=40/60hr=2/3hr New speed = 40* 3/2 kmph= 60kmph

4. The least multiple of 7 which leaves a remainder 4 when divided by 6,9,15 and 18 is ?

365

364

366

367

Let x be the least multiple of 7, which when divided by 90 leaves the remainder 4. Then x is of the form 90k + 4. Now, minimum value of k for which 90k + 4 is divisible by 4. : . x = 4 * 90 + 4 = 364

Explanation

Let x be the least multiple of 7, which when divided by 90 leaves the remainder 4. Then x is of the form 90k + 4. Now, minimum value of k for which 90k + 4 is divisible by 4. : . x = 4 * 90 + 4 = 364

5. A certain number of men can finish a piece of work in 10 days. If however there were 10 men less it will take 10days more for the work to be finished. How many men were there originally?

19

21

20

22

Number of men =x
total work =10X
10X = (X-10)(20)
10X=20X-200
X=20

Explanation

Number of men =x
total work =10X
10X = (X-10)(20)
10X=20X-200
X=20

6. How many terms are there in 2,4,6,8..........,1024?

256

600

512

1024

It is a question on AP (Arithmetic progression).
Basic formula is :
Tn = a + (n-1)*d
a = first term, n= number of terms, d = difference between two terms
1024 = 2 + (n-1)2
2n= 1024 or n =512

Explanation

It is a question on AP (Arithmetic progression).
Basic formula is :
Tn = a + (n-1)*d
a = first term, n= number of terms, d = difference between two terms
1024 = 2 + (n-1)2
2n= 1024 or n =512

7. Simple interest on a sum of money is 1/9th of sum and the number of years and the rate % per annum are equal. What is rate?

3.33

3.5

3.4

3.2

Formula : ( P*R*T)/100 = interest
p=principal, r=rate, t=time, here r=t
let us assume principal = 9, interest = 1
9 * R^2 / 100 =1
R^2= 100/9
R=10/3 = 3.33

Explanation

Formula : ( P*R*T)/100 = interest
p=principal, r=rate, t=time, here r=t
let us assume principal = 9, interest = 1
9 * R^2 / 100 =1
R^2= 100/9
R=10/3 = 3.33

8. A batsman in his 18th innings makes a score of 150 runs and there by increasing his Average by 6. Find his average after 18th innings ?

43

42

45

44

Let the average for 17 innings is x runs Total runs in 17 innings = 17x Total runs in 18 innings = 17x + 150

Average of 18 innings = 17x + 150/18

therefore 17x + 150/18 = x + 6 -- > x = 42 Thus, average after 18 innings = 42

Explanation

Let the average for 17 innings is x runs Total runs in 17 innings = 17x Total runs in 18 innings = 17x + 150

Average of 18 innings = 17x + 150/18

therefore 17x + 150/18 = x + 6 -- > x = 42 Thus, average after 18 innings = 42

9. A's salary is 20% more than B's salary. By what % is B's salary less than that of A?

16.66%

16.%

15.6%

14.8%

Let us assume B’s salary = 100
A’s salary is : 100 + 20 = 120
B’s salary is 20 less than 120
20/120 * 100 = 16.66%

Explanation

Let us assume B’s salary = 100
A’s salary is : 100 + 20 = 120
B’s salary is 20 less than 120
20/120 * 100 = 16.66%

10. There is a merry-go-round race going on.One person says,"1/3 of those in front of me and 3/4 of those behind me, give the total number of children in the race". Then the number of children took part in the race?

13

15

17

21

Assume there are x participants in the race.In a round race,no: of participants in front of a person wil be x-1 an that behind him wil b x-1. i.e, 1/3(x-1) + 3/4(x-1) = x ; solving x = 13

Explanation

Assume there are x participants in the race.In a round race,no: of participants in front of a person wil be x-1 an that behind him wil b x-1. i.e, 1/3(x-1) + 3/4(x-1) = x ; solving x = 13

11. The Value of √24 + 3√64 + 4√28 is?

12

14

15

13

24*1/2 + 43*1/3 + 28*1/4

-- > 4 + 4 + 4 -- > 12

Explanation

24*1/2 + 43*1/3 + 28*1/4

-- > 4 + 4 + 4 -- > 12

12. The average age of a family of 8 persons is 20. The age of the youngest person is 5 years. What was the average age of the family just before the birth of the youngest person ?

12

14

16

17.14

The total now = 20 * 8 = 160
Total just after birth : (20-5) * 8 = 120
Average just before birth: 120/7 = 17.14

Explanation

The total now = 20 * 8 = 160
Total just after birth : (20-5) * 8 = 120
Average just before birth: 120/7 = 17.14

13. 13 sheeps and 9 pigs were bought for Rs. 1291.85.If the average price of a sheep be Rs. 74. What is the average price of a pig?

Rs. 970

Rs. 968

Rs. 964

Rs. 962

Average price of a sheep = Rs. 74 : . Total price of 13 sheeps = (74*13) = Rs. 962

Explanation

Average price of a sheep = Rs. 74 : . Total price of 13 sheeps = (74*13) = Rs. 962

14. 3 ¼ - 4/5 of 5/6 / 4 1/3 / 1/5 – ( 3/10 + 21 1/5 ) is equal to?

16 1/2

15 1/2

17 1/2

13 1/2

13/4 – 4/5 * 5/6 / 13/3 / 1/5 – ( 3/10 + 106/5 ) (use BODMASRULE)

-- > 13/4 – 4/6 / 13/3 / 1/5 – 215/10 -- > 31/12 / 13/3 * 5 – 215/10

-- > 31/12 / 65/3 – 43/2 -- > 31/12 / 130 – 129/6 -- > 31/12/1/6 = 31/12 * 6/1 -- > 31/2 = 15 1/2

Explanation

13/4 – 4/5 * 5/6 / 13/3 / 1/5 – ( 3/10 + 106/5 ) (use BODMASRULE)

-- > 13/4 – 4/6 / 13/3 / 1/5 – 215/10 -- > 31/12 / 13/3 * 5 – 215/10

-- > 31/12 / 65/3 – 43/2 -- > 31/12 / 130 – 129/6 -- > 31/12/1/6 = 31/12 * 6/1 -- > 31/2 = 15 1/2

15. A person invested Rs. 5000 at some rate (simple interest) and 4000 at 1% higher rate of interest. If the interest in both the cases is equal after 4 years. What is the rate of interest in former case?

4

5

3

2

(5000*R*4)/100=(4000*(r+1)*4)/100
5r=4r+4
r=4

Explanation

(5000*R*4)/100=(4000*(r+1)*4)/100
5r=4r+4
r=4