Physics Gce O Level, Topical - Mass, Weight, Density

Reviewed by Editorial Team
The ProProfs editorial team is comprised of experienced subject matter experts. They've collectively created over 10,000 quizzes and lessons, serving over 100 million users. Our team includes in-house content moderators and subject matter experts, as well as a global network of rigorously trained contributors. All adhere to our comprehensive editorial guidelines, ensuring the delivery of high-quality content.
Learn about Our Editorial Process
| By Aliextrawork
A
Aliextrawork
Community Contributor
Quizzes Created: 1 | Total Attempts: 960
| Attempts: 960
Quiz Flashcard
SettingsSettings
Please wait...
  • 1/15 Questions

    An object that has a mass of 15kg on the Earth is taken to the Moon.The gravitational field strength on the Earth is 10N/ kg and on the Moon is 1.6N/ kg. What are the mass and the weight of the object on the Moon?  mass/kg  weight/N A  15  24 B  15  150 C  24  15 D  150  24Q6, Winter 2005 

    • Option 1
    • Option 2
    • Option 3
    • Option 4
Please wait...
Physics Gce O Level, Topical - Mass, Weight, Density - Quiz
About This Quiz

This quiz assesses key concepts of mass, weight, and density at GCE O Level Physics. It includes practical questions on gravitational field strength and material density, enhancing understanding and application skills relevant for students.

Quiz Preview

  • 2. 

    A student does an experiment to estimate the density of an irregularly-shaped stone.Which items of equipment are needed?  A) a balance and a measuring cylinder containing water B) a balance and a ruler C) a ruler and a measuring cylinder containing water D) only a measuring cylinder containing waterQ6, Summer 2007 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 1
    Explanation
    To estimate the density of an irregularly-shaped stone, a balance is needed to measure the mass of the stone. A measuring cylinder containing water is also needed to measure the volume of the stone. By dividing the mass of the stone by its volume, the density can be calculated. Therefore, option A, which includes both a balance and a measuring cylinder containing water, is the correct answer.

    Rate this question:

  • 3. 

    A person of weight 600 N at the bottom of a mountain climbs to the top. The gravitational field strength changes from 10.00 N / kg at the bottom to 9.97 N / kg at the top. His mass is unchanged as he climbs.What are his mass and his weight at the top of the mountain?  mass at top of mountain/ kg  weight at top of mountain/N A  60.0  598 B  60.0  600 C  60.1  598 D  60.1  600Q7, Winter 2010, Variant 1 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 1
    Explanation
    As the person's mass is unchanged, his mass at the top of the mountain will also be 60.0 kg. The weight of an object is given by the equation weight = mass x gravitational field strength. Since the gravitational field strength decreases from 10.00 N/kg at the bottom to 9.97 N/kg at the top, the person's weight at the top of the mountain will be slightly less than 600 N. Therefore, the correct answer is option 1, with a mass of 60.0 kg and a weight of 598 N at the top of the mountain.

    Rate this question:

  • 4. 
    Three objects are cut from the same sheet of steel. They are different shapes but they all have the same mass  Which object has the greatest density?  A) the disc B) the L-shape C) the square D) they all have the same densityQ6, Winter 2006  - ProProfs

    Three objects are cut from the same sheet of steel. They are different shapes but they all have the same mass  Which object has the greatest density?  A) the disc B) the L-shape C) the square D) they all have the same densityQ6, Winter 2006 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 4
    Explanation
    The three objects are cut from the same sheet of steel and have the same mass. Density is defined as mass divided by volume. Since the objects have the same mass, the object with the greatest density would be the one with the smallest volume. Since the question does not provide any information about the dimensions or volumes of the objects, we can conclude that all three objects have the same density.

    Rate this question:

  • 5. 

    A room measures 4.0m × 3.0m × 2.0m. The density of the air in the room is 1.3kg/m^3.What is the mass of air in the room?  A) 0.054kg B) 18kg C) 24kg D) 31kgQ7, Winter 2009 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 4
    Explanation
    The mass of air in the room can be calculated using the formula mass = density × volume. The volume of the room is given as 4.0m × 3.0m × 2.0m, which is equal to 24.0m^3. The density of the air is given as 1.3kg/m^3. Therefore, the mass of air in the room is 1.3kg/m^3 × 24.0m^3 = 31.2kg.

    Rate this question:

  • 6. 
    The mass of a measuring cylinder is measured before and after pouring a liquid into it.  What is the density of the liquid?  A) 0.79g/ cm^3 B) 1.3g/ cm^3 C) 1.4g/ cm^3 D) 2.2g/ cm^3Q6, Winter 2008  - ProProfs

    The mass of a measuring cylinder is measured before and after pouring a liquid into it.  What is the density of the liquid?  A) 0.79g/ cm^3 B) 1.3g/ cm^3 C) 1.4g/ cm^3 D) 2.2g/ cm^3Q6, Winter 2008 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 1
    Explanation
    The density of a substance is defined as its mass divided by its volume. In this question, the mass of the measuring cylinder is measured before and after pouring the liquid into it. By subtracting the mass of the empty measuring cylinder from the mass of the cylinder with the liquid, we can determine the mass of the liquid. To calculate the density, we need to divide this mass by the volume of the liquid. However, the volume of the liquid is not provided in the question. Therefore, it is not possible to determine the density of the liquid based on the information given.

    Rate this question:

  • 7. 
    Some students measure the masses and the volumes of different sized samples of a type of wood. Which graph shows their results?   A  B  C  D Q5, Summer 2005  - ProProfs

    Some students measure the masses and the volumes of different sized samples of a type of wood. Which graph shows their results?   A  B  C  D Q5, Summer 2005 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 2
    Explanation
    Option 2 shows a graph with the mass on the y-axis and the volume on the x-axis. This is the most appropriate representation for the students' results as they are measuring the masses and volumes of different sized samples of wood. The graph allows for a clear comparison between the mass and volume of each sample, showing any possible patterns or relationships between the two variables.

    Rate this question:

  • 8. 

    The weight of a stone is found using a newton meter, and its mass is found using a pan balance. The experiment is carried out on the Earth and on the Moon.For each meter, is its reading the same or different on the Earth and on the Moon?  reading on newton meter  reading on pan balance A  different  different B  different  same C  same  different D  same  sameQ7, Winter 2011, Variant 1 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 2
    Explanation
    The weight of an object is the force exerted on it due to gravity, while the mass of an object is the amount of matter it contains. The reading on a newton meter measures the weight of the stone, which would be different on the Earth and on the Moon due to the difference in gravitational pull. The reading on a pan balance measures the mass of the stone, which would remain the same regardless of the location. Therefore, the correct answer is Option 2 - the reading on the newton meter is different on the Earth and on the Moon, but the reading on the pan balance is the same.

    Rate this question:

  • 9. 
    A measuring cylinder contains 118 cm^3 of water. When a small object is fully immersed in the water, the reading goes up to 132cm^3. The object has a mass of 42g.What is the density of the object?   A B C DQ7, Summer 2009 - ProProfs

    A measuring cylinder contains 118 cm^3 of water. When a small object is fully immersed in the water, the reading goes up to 132cm^3. The object has a mass of 42g.What is the density of the object?   A B C DQ7, Summer 2009

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 2
    Explanation
    The density of an object is defined as its mass divided by its volume. In this case, the mass of the object is given as 42g. The change in volume of the water in the measuring cylinder when the object is immersed is 132cm^3 - 118cm^3 = 14cm^3. Therefore, the volume of the object is 14cm^3. To find the density, we divide the mass (42g) by the volume (14cm^3), which gives us a density of 3g/cm^3.

    Rate this question:

  • 10. 
    A box has an internal volume of 1000 cm^3. When a solid object is placed in the closed box, the volume of air in the box is 520cm^3.The density of the object is 8.00g/ cm^3.  What is the mass of the object?  A) 60.0g B) 3840g C) 4160g D) 8000gQ8, Winter 2010, Variant 1  - ProProfs

    A box has an internal volume of 1000 cm^3. When a solid object is placed in the closed box, the volume of air in the box is 520cm^3.The density of the object is 8.00g/ cm^3.  What is the mass of the object?  A) 60.0g B) 3840g C) 4160g D) 8000gQ8, Winter 2010, Variant 1 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 2
    Explanation
    The volume of the object can be calculated by subtracting the volume of air in the box from the internal volume of the box: 1000 cm^3 - 520 cm^3 = 480 cm^3.
    The mass of the object can be calculated using the formula: mass = density x volume.
    Plugging in the given density of 8.00 g/cm^3 and the volume of 480 cm^3, we get: mass = 8.00 g/cm^3 x 480 cm^3 = 3840 g.
    Therefore, the correct answer is option 2, 3840g.

    Rate this question:

  • 11. 
    An object of mass 100g is immersed in water as shown in the diagram.  What is the density of the material from which the object is made?  A) 0.4g/cm^3 B) 0.9g/cm^3 C) 1.1g/cm D) 2.5g/cmQ7, Summer 2006  - ProProfs

    An object of mass 100g is immersed in water as shown in the diagram.  What is the density of the material from which the object is made?  A) 0.4g/cm^3 B) 0.9g/cm^3 C) 1.1g/cm D) 2.5g/cmQ7, Summer 2006 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 4
    Explanation
    The density of a material is equal to its mass divided by its volume. In this question, the object is immersed in water, which means it displaces a certain volume of water equal to its own volume. Since the object has a mass of 100g and it displaces 40cm^3 of water, its density is 100g/40cm^3 = 2.5g/cm^3. Therefore, the correct answer is option D) 2.5g/cm^3.

    Rate this question:

  • 12. 
     A lump of metal has a mass of 210 g. It is lowered into a measuring cylinder containing water. The level of the water rises from 35cm^3 to 140cm^3.  What is the density of the metal?  A) 0.67g/ cm^3 B) 1.5g/ cm^3 C) 2.0g/ cm^3 D) 6.0g/ cm^3Q6, Summer 2008  - ProProfs

     A lump of metal has a mass of 210 g. It is lowered into a measuring cylinder containing water. The level of the water rises from 35cm^3 to 140cm^3.  What is the density of the metal?  A) 0.67g/ cm^3 B) 1.5g/ cm^3 C) 2.0g/ cm^3 D) 6.0g/ cm^3Q6, Summer 2008 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 3
    Explanation
    The density of an object is calculated by dividing its mass by its volume. In this question, the mass of the metal is given as 210 g and the change in volume of the water in the measuring cylinder is given as 140 cm^3 - 35 cm^3 = 105 cm^3. Therefore, the volume of the metal is 105 cm^3. Dividing the mass by the volume, we get 210 g / 105 cm^3 = 2.0 g/cm^3. Therefore, the density of the metal is 2.0 g/cm^3.

    Rate this question:

  • 13. 
    A student is trying to find the density of a stone, but he has mixed up the instruction cards.  What order should the cards be in?  A) 5 → 3 → 6 → 2 → 1 → 4 → 7 B) 1 → 5 → 3 → 6 → 2 → 7 → 4 C) 5 → 6 → 3 → 2 → 1 → 7 → 4 D) 1 → 4 → 5 → 3 → 6 → 2 → 7Q7, Winter 2005  - ProProfs

    A student is trying to find the density of a stone, but he has mixed up the instruction cards.  What order should the cards be in?  A) 5 → 3 → 6 → 2 → 1 → 4 → 7 B) 1 → 5 → 3 → 6 → 2 → 7 → 4 C) 5 → 6 → 3 → 2 → 1 → 7 → 4 D) 1 → 4 → 5 → 3 → 6 → 2 → 7Q7, Winter 2005 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 2
    Explanation
    The correct order of the instruction cards should be 1 -> 5 -> 3 -> 6 -> 2 -> 7 -> 4. This is because the student needs to follow a specific sequence of steps to find the density of the stone. Option 2 is the only answer choice that has this correct sequence of cards.

    Rate this question:

  • 14. 

    At a point on the surface of the Earth, the gravitational field strength is 9.8N/ kg.Which pair of values for mass and weight are correct for an object placed at this point?  mass/kg  weight/N A  9.8  10 B  10  9.8 C  10  98 D  98  10Q4, Summer 2005 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 3
    Explanation
    The gravitational field strength at a point on the surface of the Earth is 9.8 N/kg. The weight of an object is given by the formula weight = mass x gravitational field strength. So, for an object placed at this point, if the mass is 10 kg, the weight would be 10 kg x 9.8 N/kg = 98 N. Therefore, Option 3 is correct.

    Rate this question:

  • 15. 
    The diagram shows two objects on a beam balance in equilibrium.  Which need not be the same?  A) the masses of the two objects B) the moments about the pivot of the two objects C) the volumes of the two objects D) the weights of the two objectsQ5, Winter 2008  - ProProfs

    The diagram shows two objects on a beam balance in equilibrium.  Which need not be the same?  A) the masses of the two objects B) the moments about the pivot of the two objects C) the volumes of the two objects D) the weights of the two objectsQ5, Winter 2008 

    • Option 1

    • Option 2

    • Option 3

    • Option 4

    Correct Answer
    A. Option 3
    Explanation
    The diagram shows two objects on a beam balance in equilibrium. The question asks which need not be the same. Option 3 states "the volumes of the two objects." This means that the volumes of the two objects can be different and still maintain equilibrium on the beam balance. The masses, moments about the pivot, and weights of the two objects must be equal in order for the beam balance to be in equilibrium.

    Rate this question:

Quiz Review Timeline (Updated): Mar 22, 2023 +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Mar 22, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Jul 20, 2016
    Quiz Created by
    Aliextrawork
Back to Top Back to top
Advertisement
×

Wait!
Here's an interesting quiz for you.

We have other quizzes matching your interest.