Biology Quiz - 2019 Batch
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What’s the function of the proteins in chromosomes
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Maintain structure of chromosomes
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Fusing DNA molecules to chromosomes
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Help control the activity of the genes
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Two Answers are correct
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This Biology Quiz for the 2019 batch explores critical aspects of cell biology, specifically focusing on mitosis. It assesses understanding of chromosome structure, phases of the cell cycle, and key events during mitosis, which are essential for students specializing in biological sciences.
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- 2.
Sister Chromatids are attached to each other by ?
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Chemical bonds
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Microtubules
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Cohesion
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None of the above
Correct Answer
A. CohesionExplanation
Sister chromatids are attached to each other by cohesion. Cohesion is a protein complex that holds the two identical DNA strands of sister chromatids together during cell division. This attachment ensures that the genetic material is properly distributed to the daughter cells. Chemical bonds and microtubules are not involved in the attachment of sister chromatids.Rate this question:
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- 3.
Which is the correct arrangement of phases in cell cycle ?
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G1 > S > G2 > Interphase
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G1 > G2 > mitosis > cytokinesis
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G2 > prophase > Telophase >metaphase
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Anaphase > Telophase > cytokinesis > G1
Correct Answer
A. Anaphase > Telophase > cytokinesis > G1 -
- 4.
In which of these stages nuclear envelope suddenly fragments ?
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Prophase
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Prometaphase
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Telophase
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Anaphase
Correct Answer
A. PrometaphaseExplanation
During prometaphase, the nuclear envelope suddenly fragments. This is because the nuclear envelope disassembles to allow the microtubules of the mitotic spindle to interact with the chromosomes. The breakdown of the nuclear envelope is a crucial step in preparing the chromosomes for their separation during anaphase. Therefore, prometaphase is the stage where the nuclear envelope undergoes fragmentation.Rate this question:
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- 5.
Shortest stage of M phase is
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Anaphase
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Telophase
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cytokinesis
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Non of the above
Correct Answer
A. AnaphaseExplanation
Anaphase is the correct answer because it is the shortest stage of the M phase. During anaphase, the sister chromatids are separated and pulled towards opposite ends of the cell. This process is facilitated by the spindle fibers. Once the sister chromatids are separated, the cell proceeds to telophase, where the nuclear envelope reforms around each set of chromosomes. Cytokinesis, on the other hand, is the final stage of the cell cycle where the cytoplasm divides to form two daughter cells. Therefore, anaphase is the correct answer as it is the shortest stage of the M phase.Rate this question:
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- 6.
The process mitosis ends in ?
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Anaphase
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Telophase
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Cytokinesis
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Two answers are correct
Correct Answer
A. TelophaseExplanation
Telophase is the correct answer because it is the final stage of mitosis. During telophase, the duplicated chromosomes reach the opposite poles of the cell and begin to unwind. Nuclear envelopes start to form around each set of chromosomes, and the nucleoli reappear. Cytokinesis, which is the division of the cytoplasm, typically occurs simultaneously or shortly after telophase. Therefore, telophase marks the end of mitosis and the beginning of two new daughter cells.Rate this question:
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- 7.
The protein and enzyme which are related to sister cromatids are ?
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Cohesion + protease
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Tubulin + separase
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Cohesion + separase
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Tubulin + protease
Correct Answer
A. Cohesion + separaseExplanation
The proteins cohesion and separase are related to sister chromatids. Cohesion is responsible for holding sister chromatids together during cell division, ensuring that they are properly segregated to daughter cells. Separase, on the other hand, is an enzyme that cleaves the cohesion protein, allowing the separation of sister chromatids. Therefore, cohesion and separase play crucial roles in the proper distribution of genetic material during cell division.Rate this question:
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- 8.
which of the following explains the movement of chromosomes along microtubules ?
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Pac Man theory
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Reeled in theory
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Centrosomes pull microtubule easily
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Two of the answers are correct
Correct Answer
A. Two of the answers are correctExplanation
The movement of chromosomes along microtubules can be explained by both the Pac Man theory and the centrosomes pull microtubule easily theory. The Pac Man theory suggests that the microtubules act like "Pac Man" and directly attach to the chromosomes, pulling them along. On the other hand, the centrosomes pull microtubule easily theory suggests that the centrosomes, which are located at the opposite ends of the cell, exert force on the microtubules, causing them to move and pull the chromosomes along with them. Both of these explanations contribute to the understanding of how chromosomes move along microtubules.Rate this question:
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- 9.
Which of the following related to reproduction of bacteria ?
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Meiosis
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Mitosis
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Binary fission
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Non of the above
Correct Answer
A. Binary fissionExplanation
Binary fission is the correct answer because it is the primary method of reproduction in bacteria. During binary fission, a single bacterial cell divides into two identical daughter cells. This process allows bacteria to rapidly reproduce and increase their population. Meiosis and mitosis are not related to bacterial reproduction as they are specific to eukaryotic cells.Rate this question:
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- 10.
Which of the following unicellular eukaryotes divides similarly to normal multicellular eukaryotes ?
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Yeasts
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Dinoflagellates
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diatoms
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Two answers are correct
Correct Answer
A. Two answers are correctExplanation
The correct answer is yeasts and dinoflagellates. Yeasts are unicellular fungi that reproduce through a process called budding, which is similar to how cells divide in multicellular eukaryotes. Dinoflagellates are unicellular protists that undergo a process called binary fission, which is also similar to cell division in multicellular eukaryotes. Both yeasts and dinoflagellates exhibit division mechanisms that resemble those of multicellular eukaryotes.Rate this question:
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- 11.
The regulatory Molecules in cell cycle are mainly made of ?
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Protein kinase
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Cyclins
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CDKs
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Two answers are correct
Correct Answer
A. Two answers are correctExplanation
The regulatory molecules in the cell cycle are mainly made of cyclins and CDKs. Cyclins are proteins that regulate the progression of the cell cycle by binding to and activating cyclin-dependent kinases (CDKs). CDKs are enzymes that control the cell cycle by phosphorylating target proteins, thus regulating their activity. These two types of molecules work together to ensure the proper progression and regulation of the cell cycle.Rate this question:
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- 12.
The most important check point at the cell cycle is
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G1
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M Phase
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G2
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G0
Correct Answer
A. G1Explanation
The G1 phase is the most important checkpoint in the cell cycle. During this phase, the cell undergoes growth and prepares for DNA replication. At the G1 checkpoint, the cell checks for any DNA damage or errors in the replicated DNA. If any issues are found, the cell can either repair the damage or undergo programmed cell death (apoptosis) to prevent the propagation of damaged DNA. This checkpoint ensures that the cell is ready to proceed to the next phase of the cell cycle and helps maintain genomic stability.Rate this question:
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- 13.
As electrons travel down the electrons transport chain and become closer to the oxygen in the aerobic respiration :
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Free energy increases
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Electronegativity increases
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Free energy decreases
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Two answers are correct
Correct Answer
A. Two answers are correctExplanation
As electrons travel down the electron transport chain and become closer to the oxygen in aerobic respiration, both free energy and electronegativity increase. Free energy increases because the electrons release energy as they move down the chain, which is used to generate ATP. Electronegativity increases because oxygen has a higher electronegativity than the previous molecules in the chain, causing the electrons to be more strongly attracted to it. Therefore, both options stating that free energy increases and electronegativity increases are correct.Rate this question:
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- 14.
For 5 moles of glucose oxidized by cellular respiration ,what is the net amount of moles of ATP released from glycolysis?
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5 ATP
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10 ATP
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15 ATP
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20 ATP
Correct Answer
A. 10 ATPExplanation
During glycolysis, which is the first step of cellular respiration, one molecule of glucose is converted into two molecules of pyruvate. In this process, a net of two molecules of ATP are produced per molecule of glucose. Since there are 5 moles of glucose being oxidized, the net amount of moles of ATP released from glycolysis would be 5 moles of glucose multiplied by 2 moles of ATP per glucose, which equals 10 moles of ATP.Rate this question:
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- 15.
During cellular respiration, acetyl CoA accumulates in which location ?
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Cytosol
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Mitochondrial matrix
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Mitochondrial outer membrane
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Mitochondrial inner membrane
Correct Answer
A. Mitochondrial matrixExplanation
During cellular respiration, acetyl CoA accumulates in the mitochondrial matrix. This is because acetyl CoA is produced in the cytosol during the breakdown of glucose, and it then enters the mitochondria to undergo further reactions in the citric acid cycle. The citric acid cycle takes place in the mitochondrial matrix, where acetyl CoA combines with oxaloacetate to form citrate. Therefore, the accumulation of acetyl CoA occurs in the mitochondrial matrix during cellular respiration.Rate this question:
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- 16.
What is the final electron acceptor of the electron transport chain in aerobic respiration?
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Pyruvate
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Acetaldehyde
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Inorganic compounds like sulfate ion
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Oxygen
Correct Answer
A. OxygenExplanation
The final electron acceptor of the electron transport chain in aerobic respiration is oxygen. Oxygen acts as the final electron acceptor in the process of oxidative phosphorylation, where it combines with electrons and protons to form water. This reaction allows for the production of ATP, the energy currency of the cell. Without oxygen, the electron transport chain cannot function properly, leading to a decrease in ATP production and ultimately, cell death.Rate this question:
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- 17.
What of the following accounts for almost 10% of the ATP generated by cellular respiration?
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Oxidative phosphorylation
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Pyruvate oxidation +Glycolysis
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Glycolysis
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Citric acid cycle
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Glycolysis + Citric acid cycle
Correct Answer
A. Glycolysis + Citric acid cycleExplanation
Glycolysis and the citric acid cycle together account for almost 10% of the ATP generated by cellular respiration. Glycolysis is the initial step in glucose metabolism, where glucose is broken down into pyruvate, generating a small amount of ATP. The citric acid cycle, also known as the Krebs cycle, further breaks down pyruvate into carbon dioxide, producing more ATP in the process. Together, these two processes contribute to the majority of ATP production in cellular respiration.Rate this question:
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- 18.
The location of the respiratory chain in prokaryotes and eukaryotes respectively?
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Cytoplasm , Plasma membrane
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Mitochondrial inner membrane , Mitochondrial outer membrane
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Plasma membrane , Mitochondrial inner membrane
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Plasma membrane , Cytoplasm
Correct Answer
A. Plasma membrane , Mitochondrial inner membraneExplanation
In prokaryotes, the respiratory chain is located in the plasma membrane. This is because prokaryotes lack mitochondria, so their plasma membrane serves as the site for cellular respiration. On the other hand, in eukaryotes, the respiratory chain is located in the mitochondrial inner membrane. This is because eukaryotic cells have mitochondria, which are specialized organelles responsible for cellular respiration. The inner membrane of the mitochondria provides a highly folded surface area for the respiratory chain enzymes to carry out the electron transport chain and generate ATP.Rate this question:
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- 19.
What is proton-motive force ?
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The force required to remove an electron from hydrogen
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The force the moves hydrogen to NAD+
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The force that moves hydrogen into the mitochondrion
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The force exerted on a proton by a transmembrane proton concentration gradient
Correct Answer
A. The force exerted on a proton by a transmembrane proton concentration gradientExplanation
Proton-motive force refers to the force exerted on a proton by a transmembrane proton concentration gradient. This force is generated during cellular respiration when protons are pumped across the inner mitochondrial membrane, creating a concentration gradient. The protons then flow back into the mitochondrion through ATP synthase, driving the synthesis of ATP. The proton-motive force is essential for the production of ATP, the energy currency of the cell.Rate this question:
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- 20.
In addition to ATP , what are the end products(for one mole of glucose )of citric acid cycle ?
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3NADH , 1FADH2, 2CO2
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3NADH , 1FADH2, H2O
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2NADH , 4CO2 , 2 Acetyl CoA
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6 NADH , 2 FADH2 ,4 CO2
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None of the above
Correct Answer
A. 6 NADH , 2 FADH2 ,4 CO2Explanation
The correct answer is 6 NADH, 2 FADH2, 4 CO2. This is because during the citric acid cycle, one mole of glucose is completely oxidized and produces 6 molecules of NADH, 2 molecules of FADH2, and 4 molecules of CO2. NADH and FADH2 are electron carriers that play a crucial role in oxidative phosphorylation, which generates ATP. CO2 is a waste product of cellular respiration.Rate this question:
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- 21.
Which of the following is used as electron carrier during glycolysis?
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NADH and FADH2
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FAD
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NAD+
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NAD+ and FAD
Correct Answer
A. NAD+Explanation
NAD+ is used as an electron carrier during glycolysis. It accepts electrons and hydrogen ions from glucose and transfers them to other molecules in the process. NAD+ is reduced to NADH during this process, and it plays a crucial role in the production of ATP during glycolysis. FAD and FADH2 are involved in other metabolic pathways, but they are not directly used as electron carriers in glycolysis.Rate this question:
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- 22.
Which of the following types of molecules are the major structural components of the cell membrane?
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Phospholipids and cellulose
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Nucleic acids and proteins
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Phospholipids and proteins
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Proteins and cellulose
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Glycoproteins and cholesterol
Correct Answer
A. Phospholipids and proteinsExplanation
Phospholipids and proteins are the major structural components of the cell membrane. Phospholipids form a bilayer that makes up the basic structure of the membrane, with their hydrophilic heads facing outward and their hydrophobic tails facing inward. This arrangement provides a barrier that separates the inside and outside of the cell. Proteins are embedded within the phospholipid bilayer and have various functions, such as transporting molecules across the membrane and acting as receptors for cell signaling. Together, phospholipids and proteins give the cell membrane its structure and functionality.Rate this question:
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- 23.
The presence of cholesterol in the plasma membranes of some animals:
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Enables the membrane to stay fluid more easily when cell temperature drops.
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Enables the animal to remove hydrogen atoms from saturated phospholipids.
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Enables the animal to add hydrogen atoms to unsaturated phospholipids.
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Makes the membrane less flexible, allowing it to sustain greater pressure from within the cell.
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Makes the animal more susceptible to circulatory disorders.
Correct Answer
A. Enables the membrane to stay fluid more easily when cell temperature drops.Explanation
Cholesterol is a lipid molecule that is present in the plasma membranes of some animals. It plays a crucial role in maintaining the fluidity of the membrane. When the temperature drops, the phospholipids in the membrane tend to pack together, making the membrane less fluid. However, the presence of cholesterol prevents this packing by inserting itself between the phospholipids, preventing them from becoming too closely packed. This helps to maintain the fluidity of the membrane even at lower temperatures, ensuring that the membrane functions properly and allowing the cells to continue their normal activities.Rate this question:
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- 24.
Why are lipids and proteins free to move laterally in membranes?
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The interior of the membrane is filled with liquid water.
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Lipids and proteins repulse each other in the membrane.
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Hydrophilic portions of the lipids are in the interior of the membrane.
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There are only weak hydrophobic interactions in the interior of the membrane.
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Molecules such as cellulose can pull them in various directions.
Correct Answer
A. There are only weak hydrophobic interactions in the interior of the membrane.Explanation
The correct answer is that there are only weak hydrophobic interactions in the interior of the membrane. This allows lipids and proteins to move laterally because the weak interactions make it easier for them to slide past each other. If there were strong interactions, it would restrict the movement of lipids and proteins in the membrane.Rate this question:
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- 25.
Which of the following is a characteristic feature of a carrier protein in a plasma membrane?
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It is a peripheral membrane protein.
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It exhibits a specificity for a particular type of molecule.
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It requires the expenditure of cellular energy to function.
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It works against diffusion.
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It has few, if any, hydrophobic amino acids.
Correct Answer
A. It exhibits a specificity for a particular type of molecule.Explanation
A characteristic feature of a carrier protein in a plasma membrane is that it exhibits a specificity for a particular type of molecule. This means that carrier proteins are selective in the molecules they transport across the membrane. They have binding sites that only recognize and transport specific molecules, ensuring that only the required substances are transported across the membrane. This specificity allows carrier proteins to regulate the movement of molecules in and out of the cell, maintaining homeostasis and controlling cellular processes.Rate this question:
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- 26.
Which of the following would likely move through the lipid bilayer of a plasma membrane most rapidly?
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K+
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An amino acid
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Starch
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Glucose
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CO2
Correct Answer
A. CO2Explanation
CO2 would likely move through the lipid bilayer of a plasma membrane most rapidly because it is a small, nonpolar molecule. The lipid bilayer is composed of hydrophobic tails that repel polar molecules, making it difficult for them to pass through. CO2, being nonpolar, can easily dissolve in the lipid bilayer and diffuse across it. On the other hand, amino acids, glucose, K+, and starch are larger and/or polar molecules that would have a harder time crossing the lipid bilayer.Rate this question:
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- 27.
Mammalian blood contains the equivalent of 0.15 M NaCl. Seawater contains the equivalent of 0.45 M NaCl. What will happen if red blood cells are transferred to seawater?
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NaCl will be exported from the red blood cells by facilitated diffusion.
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Water will leave the cells, causing them to shrivel and collapse.
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The blood cells will take up water, swell, and eventually burst.
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NaCl will passively diffuse into the red blood cells.
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All answers are correct
Correct Answer
A. Water will leave the cells, causing them to shrivel and collapse.Explanation
When red blood cells are transferred to seawater, which has a higher concentration of NaCl than mammalian blood, osmosis will occur. Osmosis is the movement of water from an area of lower solute concentration to an area of higher solute concentration through a semipermeable membrane. In this case, water will leave the red blood cells in an attempt to equalize the concentration of NaCl inside and outside the cells. As a result, the cells will lose water, shrink, and eventually shrivel and collapse.Rate this question:
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- 28.
12) In most cells, there are electrochemical gradients of many ions across the plasma membrane even though there are usually only one or two electrogenic pumps present in the membrane. The gradients of the other ions can be used by:
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Ion channels.
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Carrier proteins.
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Cotransport proteins.
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Cellular metabolic reactions that create or destroy ions.
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Passive diffusion across the plasma membrane.
Correct Answer
A. Cotransport proteins.Explanation
Cotransport proteins are able to use the electrochemical gradients of ions across the plasma membrane to transport other molecules or ions against their concentration gradient. This is achieved by coupling the movement of the desired molecule or ion with the movement of the ions that are already moving down their electrochemical gradient. Therefore, cotransport proteins can utilize the existing ion gradients to transport molecules or ions into or out of the cell.Rate this question:
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- 29.
An organism with a cell wall would most likely be unable to take in materials through
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Phagocytosis.
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Diffusion.
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Osmosis.
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Active transport.
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Facilitated diffusion.
Correct Answer
A. Phagocytosis.Explanation
An organism with a cell wall would most likely be unable to take in materials through phagocytosis. Phagocytosis is a process by which cells engulf and ingest solid particles or other cells. However, organisms with a cell wall have a rigid structure surrounding their cells, which prevents them from engulfing and ingesting particles in this way. Diffusion, osmosis, active transport, and facilitated diffusion are all passive processes that do not require the organism to engulf particles, making them more likely to occur in organisms with a cell wall.Rate this question:
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- 30.
Which of the following processes includes all others?
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Osmosis
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Diffusion of a solute across a membrane
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Facilitated diffusion
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Passive transport
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Transport of an ion down its electrochemical gradient
Correct Answer
A. Passive transportExplanation
Passive transport is the correct answer because it is a broad term that includes all the other processes mentioned. Osmosis is a type of passive transport where water molecules move across a membrane from an area of lower solute concentration to an area of higher solute concentration. Diffusion of a solute across a membrane and facilitated diffusion are also types of passive transport, where solute molecules move from an area of higher concentration to an area of lower concentration without the need for energy. Transport of an ion down its electrochemical gradient is a specific type of passive transport.Rate this question:
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- 31.
Which part of Cytoskeleton does this photo indicate?
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Actin filament
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Microtubules
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Intermediate filaments
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All of the above are true
Correct Answer
A. Intermediate filamentsExplanation
The photo in question indicates the presence of intermediate filaments in the cytoskeleton. Intermediate filaments are a type of structural protein that provide mechanical support and stability to the cell. They are composed of various proteins, such as keratins, vimentins, and neurofilaments, and are typically found in the cytoplasm of cells. This photo may show the characteristic appearance of intermediate filaments, such as their rope-like or filamentous structure, which distinguishes them from other components of the cytoskeleton, such as actin filaments and microtubules.Rate this question:
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- 32.
The letter X represents:
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Stoma
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Cristea
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Stroma
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Thylakoid
Correct Answer
A. StromaExplanation
The letter X represents "Stroma." Stroma is a term used in biology to refer to the fluid-filled space inside the chloroplasts of plant cells. It is where the light-independent reactions of photosynthesis take place. The stroma contains enzymes and other molecules necessary for the synthesis of glucose from carbon dioxide and water. It also surrounds the thylakoid membrane, which is responsible for the light-dependent reactions of photosynthesis. Therefore, the letter X represents the stroma, which is an essential component of the chloroplasts and plays a crucial role in photosynthesis.Rate this question:
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- 33.
The letters B & C represent respectively:
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Dyneins, Central Microtubule
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Outer microtubule doublet, Redial spoke
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Outer microtubule doublet, Central Microtubule
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Dyneins, Redial spoke
Correct Answer
A. Dyneins, Redial spokeExplanation
The correct answer is Dyneins, Redial spoke. Dyneins are motor proteins that move along microtubules and are involved in the movement of cilia and flagella. Radial spokes, on the other hand, are protein complexes that connect the central microtubules to the outer microtubule doublets in cilia and flagella. Therefore, the letters B and C in the answer choice represent dyneins and radial spokes, respectively.Rate this question:
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- 34.
The letter A represents:
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Cisternae of Golgi
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Lumen of ER
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Lumen of Golgi
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Cisternae of ER
Correct Answer
A. Lumen of ERExplanation
The correct answer is "Lumen of ER." The letter A represents the lumen of the endoplasmic reticulum (ER). The ER is a network of membranous tubules and sacs within the cell that is involved in the synthesis, folding, and transport of proteins. The lumen of the ER refers to the inner space or cavity within these tubules and sacs.Rate this question:
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- 35.
One of the following is incorrect relating to microfilaments
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Cytoplasmic streaming
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They support cell's shape
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They are called Actin filaments
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None of the above
Correct Answer
A. None of the aboveExplanation
The given question asks for the incorrect statement relating to microfilaments. The options provided are: Cytoplasmic streaming, They support cell's shape, They are called Actin filaments, and None of the above. The correct answer is "None of the above" because all the statements mentioned are correct. Cytoplasmic streaming is a process where cytoplasm moves within the cell, microfilaments do support cell's shape, and microfilaments are indeed called Actin filaments. Therefore, there is no incorrect statement among the given options.Rate this question:
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- 36.
Cristae is analogous to
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Thylakoid
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Grana
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Granum
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All of them are correct
Correct Answer
A. All of them are correctExplanation
Cristae is a term used to describe the folded inner membrane structures found in mitochondria. Thylakoids are the flattened membrane sacs found in chloroplasts, specifically involved in the light-dependent reactions of photosynthesis. Grana refers to the stacks of thylakoids found in chloroplasts. Granum is the singular form of grana. All of these structures are similar in the sense that they are membrane-bound compartments involved in energy-related processes within cells.Rate this question:
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- 37.
In the fractionation of homogenized cells using centrifugation, the primary factor that determines whether a specific cellular component ends up in the supernatant or the pellet is
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The relative solubility of the component
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The size and weight of the component.
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The percentage of carbohydrates in the component.
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The presence or absence of nucleic acids in the component.
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the presence or absence of lipids in the component.
Correct Answer
A. The size and weight of the component.Explanation
The primary factor that determines whether a specific cellular component ends up in the supernatant or the pellet during the fractionation of homogenized cells using centrifugation is the size and weight of the component. This is because centrifugation separates components based on their sedimentation rate, which is influenced by their size and weight. Larger and heavier components will sediment faster and end up in the pellet, while smaller and lighter components will remain in the supernatant. Solubility, percentage of carbohydrates, presence or absence of nucleic acids, and presence or absence of lipids do not directly determine the distribution of cellular components in the supernatant or pellet during centrifugation.Rate this question:
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- 38.
Which of the following correctly lists the order in which cellular components will be found in the pellet when homogenized cells are treated with increasingly rapid spins in a centrifuge
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A) ribosomes, nucleus, mitochondria
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B) chloroplasts, ribosomes, vacuoles
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C) nucleus, ribosomes, chloroplasts
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D) vacuoles, ribosomes, nucleus
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E) nucleus, mitochondria, ribosomes
Correct Answer
A. E) nucleus, mitochondria, ribosomes -
- 39.
Large numbers of ribosomes are present in cells that specialize in producing which of the following molecules ?
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A) lipids
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B )glycogen
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C) proteins
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D) cellulose
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E) nucleic acids
Correct Answer
A. C) proteinsExplanation
Large numbers of ribosomes are present in cells that specialize in producing proteins. Ribosomes are responsible for protein synthesis, and cells that require a high production of proteins, such as muscle cells or cells in the pancreas that produce digestive enzymes, will have a large number of ribosomes. Lipids, glycogen, cellulose, and nucleic acids are not directly synthesized by ribosomes, so they would not require a high number of ribosomes in specialized cells.Rate this question:
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- 40.
The group of protein that maintains the shape of the nucleus is?
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A) polymer
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B) polypeptide
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C) nuclear lamina
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D) pores
Correct Answer
A. C) nuclear laminaExplanation
The correct answer is C) nuclear lamina. The nuclear lamina is a group of proteins that provides structural support and helps maintain the shape of the nucleus. It forms a mesh-like network on the inner surface of the nuclear envelope and interacts with chromatin and other nuclear components. The nuclear lamina also plays a role in regulating gene expression and DNA replication. Polymers and polypeptides are general terms for large molecules composed of repeating subunits, while pores are openings that allow for the movement of molecules in and out of the nucleus.Rate this question:
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- 41.
The monomers of nucleic acids are :
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A)Nucleotide
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B)Nucleoside
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C)Amino acids
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D)Nucleus
Correct Answer
A. A)NucleotideExplanation
Nucleic acids are composed of monomers called nucleotides. A nucleotide consists of a sugar molecule (ribose or deoxyribose), a phosphate group, and a nitrogenous base (adenine, guanine, cytosine, thymine, or uracil). Nucleotides form the building blocks of DNA and RNA, which are essential for genetic information storage and protein synthesis. Nucleosides, on the other hand, lack the phosphate group and are not considered monomers of nucleic acids. Amino acids are the building blocks of proteins, and the nucleus is an organelle within a cell.Rate this question:
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- 42.
Chitin is used to build :
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A)cell of plant
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Cell wall of fungi
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B)Phospholipdes
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D)Steroid
Correct Answer
A. Cell wall of fungiExplanation
Chitin is a structural polysaccharide that is found in the cell walls of fungi. It provides strength and rigidity to the cell wall, helping to protect the fungal cells and maintain their shape. Chitin is not found in plant cells, and it is not related to phospholipids or steroids. Therefore, the correct answer is that chitin is used to build the cell wall of fungi.Rate this question:
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- 43.
Which of the following looks like a microfibrils
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A)cellulose
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B)Chitin
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C)Starch
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D)Amylose
Correct Answer
A. A)celluloseExplanation
Cellulose is the correct answer because it is a complex carbohydrate found in the cell walls of plants. It is composed of long chains of glucose molecules that are arranged in a linear and parallel manner, forming microfibrils. These microfibrils provide strength and rigidity to plant cells, making cellulose a key structural component in the plant kingdom. Chitin, starch, and amylose do not exhibit the same microfibril structure as cellulose.Rate this question:
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- 44.
The term "amphipathic” means
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A)Polar -polar
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B)Polar-non polar
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C)Hydrophobic-hydrophobic
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D)Non polar-non polar
Correct Answer
A. B)Polar-non polarExplanation
The term "amphipathic" refers to a molecule or compound that has both polar and non-polar regions. This means that one part of the molecule is attracted to water (hydrophilic) while another part repels water (hydrophobic). This characteristic is commonly found in phospholipids, which make up the cell membrane. The polar region of an amphipathic molecule interacts with water, while the non-polar region avoids water. Therefore, the correct answer is B) Polar-non polar.Rate this question:
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- 45.
All these links are made in the tertiary level except
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A)Van der waol
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B)Hydrophobic
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C) Ionic
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D)Hydrophilic
Correct Answer
A. D)HydrophilicExplanation
The question is asking which of the given options does not belong to the tertiary level of links. In the tertiary level of links, Van der Waals, Hydrophobic, and Ionic interactions play a significant role in stabilizing the three-dimensional structure of a protein. Hydrophilic interactions, on the other hand, are more commonly associated with the secondary level of protein structure. Therefore, the correct answer is D) Hydrophilic.Rate this question:
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- 46.
What is the radius of a nuclear pore ?
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A) 50 nm
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B) 90 m
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C)50 mm
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D) 5 m
Correct Answer
A. A) 50 nmExplanation
The radius of a nuclear pore is 50 nm.Rate this question:
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- 47.
All these diseases are examples of the misfolding disease except
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Cystic fibrosis
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Alzheimers
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Mad cow
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Fever
Correct Answer
A. FeverExplanation
Fever is not a misfolding disease. Cystic fibrosis, Alzheimer's, and mad cow disease are all examples of misfolding diseases, where proteins in the body fold incorrectly and cause various health issues. Fever, on the other hand, is a symptom that occurs as a result of the body's immune response to an infection or illness. It is not caused by misfolded proteins.Rate this question:
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- 48.
The name of the process that occurs between DNA and mRNA in the protein synthesis process is:
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Transcripition
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Translation
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Cloning
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Cleavage
Correct Answer
A. TranscripitionExplanation
The correct answer is Transcription. Transcription is the process where DNA is converted into mRNA. During transcription, an enzyme called RNA polymerase binds to the DNA molecule and synthesizes a complementary mRNA molecule. This mRNA molecule carries the genetic information from the DNA to the ribosomes, where it is used as a template for protein synthesis in the process known as translation. Cloning and cleavage are not directly related to the process that occurs between DNA and mRNA in protein synthesis.Rate this question:
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- 49.
A polymer is made of 55 monomers how many H2O will remove in this reaction ?
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53
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55
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56
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54
Correct Answer
A. 54Explanation
In a polymer made of 55 monomers, each monomer is connected to the adjacent one through a condensation reaction, which releases one water molecule. Since there are 55 monomers, there will be a total of 54 condensation reactions, and thus 54 water molecules will be removed in this reaction.Rate this question:
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Mar 20, 2023Quiz Edited by
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Nov 24, 2019Quiz Created by
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