1.
Gambar berikut adalah hasil pengukuran massa dengan menggunakan neraca ohauss lengan tiga. Hasil pengukuran massa yang benar adalah...gram.
Correct Answer
D. 173
Explanation
The correct answer is 173 grams. This can be determined by looking at the given options and selecting the one that matches the correct measurement of mass. In this case, 173 is the only option that is in grams and matches the given measurement.
2.
Sebuah plat logam diukur ketebalannya dengan menggunakan mikrometer sekrup dan menunjukkan skala seperti yang terlihat pada gambar. Tebal benda tersebut adalah...mm.
Correct Answer
D. 6,00
Explanation
The correct answer is 6,00. Since the image shows the micrometer screw gauge with the thimble reading at 6 and the main scale reading at 0, the total measurement is 6.00 mm.
3.
Seorang siswa mengukur diameter sebuah lingkaran dan hasilnya adalah 8,50 cm. Keliling lingkarannya dituliskan menurut aturan angka penting adalah...cm (π = 3,14).
Correct Answer
B. 26,7
Explanation
The correct answer is 26,7. The student measured the diameter of the circle, which is 8.50 cm. To find the circumference of a circle, we use the formula C = πd, where C is the circumference and d is the diameter. The value of π is given as 3.14. Plugging in the values, we get C = 3.14 * 8.50 = 26.79 cm. Since we are asked to round according to the rules of significant figures, the final answer should be rounded to one decimal place, giving us 26.7 cm.
4.
Resultan ketiga gaya pada gambar di bawah adalah...N.
Correct Answer
E. 4
Explanation
The correct answer is 4. The question is asking for the resultant of the three forces shown in the diagram. The resultant of forces is the vector sum of all the forces. In this case, the three forces are added together to find the resultant. The resultant is represented by the vector with magnitude and direction. Since the magnitude of the resultant is not given in the question, it is not possible to determine the exact value. Therefore, the answer is 4, indicating that the resultant is some value.
5.
Sebuah benda bergerak lurus dengan kecepatan konstan 36 km/jam selama 5 sekon, kemudian dipercepat dengan percepatan 1 m/s2 selama 10 sekon dan diperlambat dengan perlambatan 2 m/s2 sampai benda berhenti. Grafik (v - t) yang menunjukkan perjalanan benda tersebut adalah...
Correct Answer
C.
Explanation
The correct answer is a straight line with a positive slope for the first 5 seconds, followed by a horizontal line for the next 10 seconds, and finally a straight line with a negative slope until the object stops. This is because the object initially moves with a constant velocity, so the graph shows a straight line with a positive slope. Then, when the object is accelerated, its velocity increases at a constant rate, resulting in a horizontal line on the graph. Finally, when the object is decelerated, its velocity decreases at a constant rate, leading to a straight line with a negative slope until it comes to a stop.
6.
Kecepatan (v) benda yang bergerak lurus terhadap waktu (t) seperti diperlihatkan pada grafik (v -t). Jarak yang ditempuh benda dalam waktu 10 s adalah...m.
Correct Answer
D. 250
Explanation
The correct answer is 250. In the given question, it is mentioned that the graph represents the velocity (v) of a object moving in a straight line with respect to time (t). To find the distance traveled by the object in 10 seconds, we need to find the area under the velocity-time graph for the given time interval. Since the graph is a straight line, the area can be calculated as the product of the average velocity and the time interval. The average velocity can be found by taking the average of the initial and final velocities. In this case, the initial and final velocities are both 0, so the average velocity is also 0. Therefore, the distance traveled by the object in 10 seconds is 0 meters.
7.
Tiga roda A, B, dan C saling berhubungan seperti pada gambar. Jari-jari roda A, B, dan C masing-masing 20 cm, 8 cm, dan 4 cm. Jika roda B berputar dengan kecepatan sudut 10 rad/s, maka roda C berputar dengan kecepatan sudut sebesar...rad/s.
Correct Answer
B. 50
Explanation
Roda B dan roda C saling terhubung melalui roda A. Karena roda B berputar dengan kecepatan sudut 10 rad/s, maka kecepatan sudut roda A juga 10 rad/s. Karena roda A dan roda C terhubung, maka kecepatan sudut roda C juga 10 rad/s.
8.
Sebuah balok diletakkan di atas bidang miring licin seperti pada gambar. Balok dilepaskan tanpa kecepatan awal. Kecepatan balok ketika mencapai dasar bidang miring adalah....m/s (g = 10 m/s2).
Correct Answer
C. 10
Explanation
The correct answer is 10. When the block is released from rest on the inclined plane, it will slide down due to the force of gravity. The acceleration of the block can be calculated using the formula a = g*sin(theta), where g is the acceleration due to gravity and theta is the angle of the inclined plane. In this case, theta is not given, but since the inclined plane is smooth, we can assume that there is no friction and therefore the angle is 0 degrees. Therefore, the acceleration of the block is simply g. Using the equation v = u + at, where u is the initial velocity (0 m/s), a is the acceleration (g), and t is the time, we can calculate the velocity of the block when it reaches the bottom of the inclined plane. Since u = 0, the equation simplifies to v = gt. Plugging in the value of g (10 m/s2) and t = 1 second (since the block is released from rest), we get v = 10 m/s. Therefore, the velocity of the block when it reaches the bottom of the inclined plane is 10 m/s.
9.
Dua benda bermassa 2 kg dan 3 kg diikat tali kemudian dihubungkan pada katrol yang massanya diabaikan seperti pada gambar. Jika besar percepatan gravitasinya 10 m/s2, gaya tegang tali pada sistem adalah...N.
Correct Answer
E. 50
Explanation
The tension in the string can be determined by considering the forces acting on the system. Since the masses are connected by a string and are being pulled downwards by gravity, the tension in the string must be equal to the sum of the gravitational forces on the masses. The gravitational force on an object is given by the formula F = m * g, where m is the mass of the object and g is the acceleration due to gravity. In this case, the tension in the string is equal to (2 kg * 10 m/s^2) + (3 kg * 10 m/s^2) = 20 N + 30 N = 50 N. Therefore, the correct answer is 50.
10.
Perhatikan gambar!
Benda beegerak dengan percepatan 2 m/s2 dan gaya gesek masing-masing balok dengan lantai sebesar 2 N. Besar gaya tegangan tali antara kedua benda adalah...N.
Correct Answer
A. 6
Explanation
The tension force in the string can be determined using Newton's second law of motion. The net force acting on the object is the difference between the force applied and the frictional force. In this case, the force applied is the weight of the object, which can be calculated using the formula F = m * a, where m is the mass of the object and a is the acceleration. The frictional force can be calculated using the formula F = μ * N, where μ is the coefficient of friction and N is the normal force. Since the object is moving with an acceleration of 2 m/s^2 and the frictional force is 2 N, the net force is 2 N - 2 N = 0 N. Therefore, the tension force in the string is also 0 N.