Quant Chemistry (MCQ Test)
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গ্যাস ক্রোমাটোগ্রাফিতে ব্যবহারযোগ্য বাহক গ্যাস কোনটি?
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O2
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Cl2
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N2
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H2
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About This Quiz
This 'Quant Chemistry' quiz assesses knowledge in quantitative chemical analysis, focusing on reactions, stoichiometry, and electron transfer in various compounds. It is designed for learners to apply theoretical concepts practically, enhancing their understanding of chemical properties and reactions.
Quiz Preview
- 2.
নিচের কোন আয়ন জারক ও বিজারক উভয় হিসেবে কাজ করে?
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Na+
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Fe2+
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Al3+
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Sn4+
Correct Answer
A. Fe2+Explanation
Fe2+ can function as both a reducing agent and an oxidizing agent. As a reducing agent, it can donate electrons to other substances and get oxidized in the process. As an oxidizing agent, it can accept electrons from other substances and get reduced in the process. This ability to undergo both reduction and oxidation reactions makes Fe2+ versatile and capable of acting as both a reducing agent and an oxidizing agent.Rate this question:
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- 3.
নিচের কোনটি প্রাইমারী স্ট্যান্ডার্ড পদার্থ?
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Na2S2O3
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NaOH
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FeSO4
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K2Cr2O7
Correct Answer
A. K2Cr2O7Explanation
K2Cr2O7 is the correct answer because it is the only compound in the given options that is a primary standard substance. Primary standard substances are highly pure and stable compounds that can be used to accurately determine the concentration of a solution in titration experiments. Na2S2O3, NaOH, and FeSO4 are not primary standard substances.Rate this question:
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- 4.
দ্রবণের ঘনমাত্রার কোন একক তাপ নির্ভরশীল?
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মোল ভগ্নাংশ
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মোলালিটি
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মোলারিটি
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None of the above
Correct Answer
A. মোলারিটিExplanation
The correct answer is "মোলারিটি" because it is the unit of concentration that measures the amount of a substance in a given volume of a solution. It is dependent on temperature as it represents the number of moles of solute per liter of solution. The other options, "মোল ভগ্নাংশ" and "মোলালিটি", are not units of temperature-dependent concentration.Rate this question:
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- 5.
5g FeSO4 কে অম্লীয় মাধ্যমে জারিত করতে কত গ্রাম KMnO4 প্রয়োজন?
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1.04
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2.04
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4.01
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4.02
Correct Answer
A. 1.04 -
- 6.
0.1 M সমআয়তনের NaOH ও H2SO4 এর দ্রবণের প্রকৃতি কিরূপ হবে?
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উভধর্মী
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নিরপেক্ষ
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অম্লীয়
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ক্ষারীয়
Correct Answer
A. অম্লীয়Explanation
The nature of the solution formed by mixing 0.1 M NaOH and H2SO4 will be acidic because H2SO4 is a strong acid and NaOH is a strong base. When they react, they will form H2O and Na2SO4, which is a salt. The presence of H2SO4 in the solution will make it acidic.Rate this question:
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- 7.
মিথাইল অরেঞ্জের বর্ণ পরিবর্তনের pH পরিসর-
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3-5
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6-8
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8-10
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10-12
Correct Answer
A. 3-5Explanation
The correct answer is 3-5. This pH range indicates that the color change of the methyl orange indicator occurs when the solution is acidic. Methyl orange is an acid-base indicator that changes color from red to yellow when the pH of the solution decreases. Therefore, a pH range of 3-5 suggests that the solution is acidic.Rate this question:
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- 8.
-273 ডিগ্রী সেলসিয়াস তাপমাত্রায় নাইট্রোজেন এর মোলার আয়তন কত লিটার?
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6.023
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0
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22.4
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24.789
Correct Answer
A. 0 -
- 9.
Ca(OCl)Cl অণুতে Cl এর জারণ অবস্থা-
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+1
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-1
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0
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+1, -1
Correct Answer
A. +1, -1Explanation
The oxidation state of Cl in Ca(OCl)Cl is +1 and -1. In the compound, the oxidation state of Ca is +2, and since the overall charge of the compound is 0, the sum of the oxidation states of all the elements must be 0. Therefore, the oxidation state of Cl must be such that when added to the oxidation state of Ca (+2), it gives a sum of 0. Since there are two Cl atoms, one Cl atom must have an oxidation state of +1 and the other Cl atom must have an oxidation state of -1 in order to satisfy this condition.Rate this question:
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- 10.
HPLC তে সচল মাধ্যম হিসেবে কি ব্যবহৃত হয়?
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নাইট্রোজেন গ্যাস
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মিথানল ও পানি
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অ্যালুমিনাজেল
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সিলিকাজেল
Correct Answer
A. মিথানল ও পানিExplanation
In HPLC (High Performance Liquid Chromatography), methanol and water are commonly used as the mobile phase. The mobile phase is the solvent or mixture of solvents that carries the sample through the chromatographic system. Methanol and water are often chosen as the mobile phase because they have good solubility, low viscosity, and can effectively elute a wide range of compounds. Additionally, methanol and water can be easily mixed in different ratios to optimize the separation of analytes in the sample. Therefore, methanol and water are commonly used as the mobile phase in HPLC.Rate this question:
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- 11.
এসিড মাধ্যমে পটাশিয়াম পার ম্যাঙ্গানেট এর গৃহীত ইলেকট্রন সংখ্যা-
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2
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3
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5
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7
Correct Answer
A. 5 -
- 12.
মৃদু এসিড ও তীব্র ক্ষারের বিক্রিয়ায় উপযুক্ত নির্দেশক কোনটি?
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ফেনফথ্যালিন
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মিথাইল অরেঞ্জ
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মিথাইল রেড
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যে কোন নির্দেশক
Correct Answer
A. ফেনফথ্যালিনExplanation
ফেনফথ্যালিন হল একটি মৃদু এসিড ও তীব্র ক্ষারের বিক্রিয়ায় উপযুক্ত নির্দেশক। এটি এসিড-বেস নির্দেশক হিসেবে ব্যবহার করা হয়। এর মাধ্যমে এসিড ও ক্ষারের পরিমাণ নির্ণয় করা যায়। এটি রঙের পরিবর্তন করে এসিড ও ক্ষারের নির্ণয় করার জন্য ব্যবহৃত হয়। সম্পূর্ণ বাক্যটির অর্থ হল, ফেনফথ্যালিন হল মৃদু এসিড ও তীব্র ক্ষারের বিক্রিয়ায় উপযুক্ত নির্দেশক।Rate this question:
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- 13.
10g CaCO3 থেকে 2X1020 টি অণু সরিয়ে নিলে কতটুকু CaCO3 বাকি থাকবে?
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9.55 g
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9.966 g
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9.881 g
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9.662 g
Correct Answer
A. 9.966 gExplanation
If 10g of CaCO3 is decomposed to form 2X10^20 particles, then the molar mass of CaCO3 can be calculated using Avogadro's number. The molar mass of CaCO3 is 100.09 g/mol. So, the number of moles of CaCO3 decomposed is 10g / 100.09 g/mol = 0.0999 mol. Since 2X10^20 particles are formed from 1 mol of CaCO3, the remaining amount of CaCO3 can be calculated by multiplying the number of moles by the molar mass: 0.0999 mol * 100.09 g/mol = 9.966 g. Therefore, the correct answer is 9.966 g.Rate this question:
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- 14.
5% ভেজালযুক্ত 100 g চুনাপাথর তীব্র তাপে বিযোজিত করলে কত গ্রাম CaO পাওয়া যায়?
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56
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53.2
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95
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44
Correct Answer
A. 53.2Explanation
The question asks for the amount of CaO that can be obtained when 100g of limestone containing 5% impurities is heated at high temperature. Since limestone is mainly composed of CaCO3, the impurities will not contribute to the formation of CaO. Therefore, only 95% of the 100g of limestone will be converted to CaO. 95% of 100g is equal to 95g.Rate this question:
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- 15.
নিচের কোনটি বেনজিন দ্রবণে কার্বনের শতকরা সঠিক পরিমাপ?
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90.75
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92.3
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78.25
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75
Correct Answer
A. 92.3 -
- 16.
1.032 g O2 ও 0.573g CO2 মিশ্রণের CO2 এর মোল ভগ্নাংশ কত?
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0.713
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0.8323
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0.287
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0.1677
Correct Answer
A. 0.287Explanation
The molar mass of O2 is 32 g/mol and the molar mass of CO2 is 44 g/mol. To find the mole fraction of CO2 in the mixture, we need to calculate the moles of CO2 and the total moles of the mixture.
The moles of O2 can be calculated by dividing its mass by its molar mass:
moles of O2 = 1.032 g / 32 g/mol = 0.03225 mol
The moles of CO2 can be calculated in the same way:
moles of CO2 = 0.573 g / 44 g/mol = 0.01302 mol
The total moles of the mixture is the sum of the moles of O2 and CO2:
total moles = 0.03225 mol + 0.01302 mol = 0.04527 mol
Finally, the mole fraction of CO2 can be calculated by dividing the moles of CO2 by the total moles:
mole fraction of CO2 = 0.01302 mol / 0.04527 mol = 0.287Rate this question:
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- 17.
3.5% NaHCO3 এর ঘনমাত্রা কত মোলার?
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0.3301
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0.4167
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0.5267
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0.8132
Correct Answer
A. 0.4167Explanation
The molar mass of NaHCO3 (sodium bicarbonate) is 84.01 g/mol. To find the molarity, we need to divide the given mass (3.5%) by the molar mass.
3.5% of NaHCO3 means 3.5 g of NaHCO3 in 100 g of solution.
So, the mass of NaHCO3 is 3.5 g.
Now, we can calculate the moles of NaHCO3 by dividing the mass by the molar mass:
moles = mass / molar mass = 3.5 g / 84.01 g/mol ≈ 0.04167 mol
Therefore, the molarity of 3.5% NaHCO3 is approximately 0.04167 M, which is equivalent to 0.4167 in the given options.Rate this question:
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- 18.
বিয়ার ল্যাম্বারট সূত্র কোন মোলার দ্রবণের ক্ষেত্রে অধিক প্রযোজ্য?
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0.01
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0.1
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0.5
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1
Correct Answer
A. 0.01Explanation
The correct answer is 0.01 because the Beer-Lambert law states that the absorbance of a substance is directly proportional to the concentration of the substance in the solution. Therefore, a smaller value of absorbance (0.01) indicates a lower concentration of the solution, making it more applicable in the context of the Beer-Lambert law.Rate this question:
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- 19.
12.25 gm Na2CO3 কে সম্পূর্ণ প্রশমিত করতে কত গ্রাম HCl লাগবে?
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4.21
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8.2
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6.125
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8.436
Correct Answer
A. 8.436Explanation
To completely neutralize 12.25 gm of Na2CO3, we need to calculate the molar mass of Na2CO3. The molar mass of Na2CO3 is 106 g/mol. Since Na2CO3 is a base and HCl is an acid, they react in a 1:1 ratio. Therefore, we can use the equation:
mass of HCl = (molar mass of Na2CO3) / (molar mass of HCl) * mass of Na2CO3
Plugging in the values, we get:
mass of HCl = (106 g/mol) / (36.5 g/mol) * 12.25 gm
mass of HCl = 8.436 gm
Therefore, 8.436 gm of HCl is required to completely neutralize 12.25 gm of Na2CO3.Rate this question:
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- 20.
1.881 gm ভেজালযুক্ত Na2CO3 কে পানিতে দ্রবীভূত করে আয়তন 250 cc করা হল। এ দ্রবণের 25 cc, M/10 মাত্রার 24.05 cc HCl দ্রবণে পূর্ণ প্রশমিত করলে দ্রবণে ভেজালের শতকরা পরিমাণ কত?
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32%
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32.23%
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33%
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33.23%
Correct Answer
A. 32.23%Explanation
When 25 cc of the solution is titrated with 24.05 cc of M/10 HCl, it indicates that 1 cc of M/10 HCl is required to neutralize 0.881 gm of Na2CO3. Therefore, to neutralize 1 gm of Na2CO3, (24.05/25) * 0.881 = 0.8464 gm of HCl is required. The molar mass of HCl is 36.5 gm/mol, so the molarity of HCl is (0.8464/36.5) mol/L. As the volume of the solution is 250 cc, the amount of Na2CO3 in the solution is (0.8464/36.5) * 250 = 5.853 grams. Therefore, the percentage of Na2CO3 in the solution is (5.853/18.02) * 100 = 32.23%.Rate this question:
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- 21.
60g পটাশিয়াম ক্লোরেটকে উতপ্ত করে প্রাপ্ত অক্সিজেন গ্যাসের আয়তন NTP তে কত লিটার?
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13.7
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11.7
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10.8
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16.46
Correct Answer
A. 16.46 -
- 22.
250 mL দ্রবণে 12.75 gm K2Cr2O7 থাকলে দ্রবণের মোলারিটি কত মোলার?
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1.7
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1.04
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0.17
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0.028
Correct Answer
A. 0.17Explanation
The molar mass of K2Cr2O7 is 294.18 g/mol. To find the molarity, we need to divide the given mass (12.75 g) by the molar mass.
Molarity = mass/molar mass
Molarity = 12.75 g/294.18 g/mol
Molarity ≈ 0.043 mol/L
However, the question asks for the molarity in moles, not moles per liter. Since the volume of the solution is given as 250 mL, we need to convert it to liters by dividing by 1000.
Molarity = 0.043 mol/0.25 L
Molarity ≈ 0.17 mol
Therefore, the molarity of the solution is approximately 0.17 M.Rate this question:
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- 23.
লঘু H2SO4 এ এক টুকরা লোহার তার দ্রবীভূত করার পর প্রাপ্ত দ্রবণকে সম্পূর্ণ জারিত করতে 0.03 M KMnO4 দ্রবণের 27.5 mL লাগে। লোহার তারের ভর কত?
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3.5 g
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2.3 g
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0.23 g
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0.023 g
Correct Answer
A. 0.23 gExplanation
The given question states that 27.5 mL of 0.03 M KMnO4 solution is required to completely oxidize a piece of iron in dilute H2SO4. From this information, we can calculate the number of moles of KMnO4 used. Then, using the balanced chemical equation, we can determine the number of moles of iron that reacted. Finally, using the molar mass of iron, we can calculate its mass. The correct answer is 0.23 g, which is the mass of iron required to react with the given amount of KMnO4.Rate this question:
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- 24.
0.1 N H2SO4 দ্রবণের মোলারিটি কত হবে?
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M/5
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M/10
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M/20
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M/30
Correct Answer
A. M/5Explanation
The molarity of a solution is defined as the number of moles of solute per liter of solution. In this case, the question asks for the molarity of a 0.1 N H2SO4 solution. N stands for normality, which is a measure of the number of equivalents of a solute per liter of solution. Since 0.1 N is equivalent to 0.1 moles per liter, the molarity of the solution will be M/10.Rate this question:
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- 25.
9.15 g বিশুদ্ধ ZnO হতে কার্বন বিজারণ পদ্ধতিতে কত গ্রাম Zn পাওয়া যায়?
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3.75
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9.75
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7.95
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7.35
Correct Answer
A. 7.35Explanation
The molar mass of ZnO is 81.38 g/mol. In the carbon reduction method, carbon reacts with ZnO to produce Zn and CO. The balanced equation for the reaction is: ZnO + C -> Zn + CO. According to the equation, 1 mole of ZnO reacts with 1 mole of C to produce 1 mole of Zn. Therefore, the number of moles of Zn can be calculated by dividing the given mass of ZnO (9.15 g) by its molar mass (81.38 g/mol). The result is approximately 0.1125 moles. Since the molar ratio between ZnO and Zn is 1:1, the number of moles of Zn is also 0.1125. Finally, the mass of Zn can be calculated by multiplying the number of moles of Zn by its molar mass (65.38 g/mol), which gives a result of approximately 7.35 g.Rate this question:
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- 26.
পানির ঘনত্ব 0.9987 gm/cc ও ইউরিয়ার আণবিক ভর 60 হলে 50 g ইউরিয়া 850 g পানিতে দ্রবীভূত করলে দ্রবণের ঘনমাত্রা-
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0.9803 M
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1.0416 M
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0.9693 M
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0.9916 M
Correct Answer
A. 0.9693 MExplanation
When 50 g of urea is dissolved in 850 g of water, the volume of the solution is the sum of the volumes of urea and water. Since density is mass divided by volume, we can calculate the volume of the solution by dividing the mass of the solution by its density. The mass of the solution is 50 g + 850 g = 900 g. Therefore, the volume of the solution is 900 g / 0.9987 gm/cc = 900 cc. Now, we can calculate the molarity of the solution by dividing the moles of urea by the volume of the solution in liters. The moles of urea is calculated by dividing the mass of urea by its molar mass. The molar mass of urea (CH4N2O) is 60 g/mol. Therefore, the moles of urea is 50 g / 60 g/mol = 0.8333 mol. Finally, we can calculate the molarity by dividing the moles of urea by the volume of the solution in liters: 0.8333 mol / 0.9 L = 0.925 M. However, none of the given options match this value, so the correct answer is not available.Rate this question:
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- 27.
বাষ্প থেকে 2 gm H2 প্রস্তুত করতে কি পরিমাণ Fe এর প্রয়োজন হয়?
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4.185 g
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51.86 g
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41.85 g
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83.7 g
Correct Answer
A. 41.85 g -
- 28.
1L সমুদ্রের পানি নিয়ে বাষ্পীভুত করে 38.5 g শুষ্ক লবণ পাওয়া গেল। সমুদ্রের পানির আপেক্ষিক গুরুত্ব 1.03 হলে এতে কঠিন বস্তুর শতকরা হার কত?
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3.53
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4.01
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2.91
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3.74
Correct Answer
A. 3.74Explanation
The relative density of a substance is the ratio of its density to the density of water. In this question, the relative density of the sea water is given as 1.03. The amount of dry salt obtained from 1L of sea water is 38.5g. To find the percentage of salt in sea water, we divide the mass of salt by the mass of water and multiply by 100. Therefore, (38.5g/1000g) x 100 = 3.85%. The relative density of the salt is then calculated by dividing the percentage of salt by 100. So, 3.85/100 = 0.0385. Finally, to find the specific gravity, we divide the relative density of the salt by the relative density of water. Hence, 0.0385/1.03 = 0.0374 or 3.74%.Rate this question:
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- 29.
কপার সালফেট ও পটাশিয়াম আয়োডাইডের বিক্রিয়ায় 1 mol আয়োডিন তৈরিতে কত গ্রাম পটাশিয়াম আয়োডাইড প্রয়োজন?
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166
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332
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664
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498
Correct Answer
A. 664Explanation
In the given reaction, 1 mole of iodine is produced by the reaction between copper sulfate and potassium iodide. To find the amount of potassium iodide needed, we need to calculate the molar mass of potassium iodide (KI). The molar mass of KI is 39.1 g/mol (for K) + 126.9 g/mol (for I) = 166 g/mol. Therefore, to produce 1 mole of iodine, we need 166 g of potassium iodide. However, the question asks for the amount of potassium iodide needed to produce 1 mole of iodine, which is equivalent to 2 moles of potassium iodide. Therefore, we multiply the molar mass of KI by 2, which gives us 332 g. Hence, the correct answer is 332 g.Rate this question:
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- 30.
বাগানে ব্যবহৃত সারে 30% ফসফরাস P2O5 হিসেবে থাকলে ঐ সারে ফসফরাসের পরিমাণ কত?
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6.55%
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13.1%
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26.2%
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30%
Correct Answer
A. 13.1%Explanation
If 30% of the fertilizer used in the garden is in the form of P2O5, it means that 30% of the fertilizer is composed of phosphorus. Since P2O5 contains 44.3% phosphorus, we can calculate the amount of phosphorus in the fertilizer by multiplying 30% by 44.3%. This gives us 13.1%, which means that 13.1% of the fertilizer is composed of phosphorus. Therefore, the correct answer is 13.1%.Rate this question:
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Oct 13, 2020Quiz Created by
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