Dr. Ambedkar Institute Of Technology Mock Test

1. Qn) Write a C Program to find average of N numbers Copy the link ( https://www.onlinegdb.com ) into a new tab and start coding for your above question by deleting the existing content. Kindly note, only if your code is compiled successfully and output is correct you need to choose ''PASS'' Option below and ''FAIL'' Option if you have not compiled or code was error. Contact TCS Personal for Placement officer for any clarification.

PASS

FAIL

The given answer suggests that the code written to find the average of N numbers has been successfully compiled and the output is correct. It indicates that the code is error-free and meets the requirements of the question.

Explanation

The given answer suggests that the code written to find the average of N numbers has been successfully compiled and the output is correct. It indicates that the code is error-free and meets the requirements of the question.

2. On what dates of April, 2001 did Wednesday fall?

1st, 8th, 15th, 22nd, 29th

2nd, 9th, 16th, 23rd, 30th

3rd, 10th, 17th, 24th

4th, 11th, 18th, 25th

In April 2001, Wednesday fell on the 4th, 11th, 18th, and 25th.

Explanation

In April 2001, Wednesday fell on the 4th, 11th, 18th, and 25th.

3.

How many 4-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed?

40

400

5040

2520

The word "LOGARITHMS" has 10 letters. To form a 4-letter word without repetition, we need to select 4 letters out of these 10. This can be done in 10P4 ways, which is equal to 10! / (10-4)! = 10! / 6! = 10 x 9 x 8 x 7 = 5040. Therefore, there are 5040 4-letter words that can be formed.

Explanation

The word "LOGARITHMS" has 10 letters. To form a 4-letter word without repetition, we need to select 4 letters out of these 10. This can be done in 10P4 ways, which is equal to 10! / (10-4)! = 10! / 6! = 10 x 9 x 8 x 7 = 5040. Therefore, there are 5040 4-letter words that can be formed.

4. In the following question choose the word which is the exact OPPOSITE of the given word. QUIESCENT

Active

Dormant

Weak

Unconcerned

The word "quiescent" means being in a state of quietness or inactivity. The word "active" is the exact opposite of "quiescent" as it refers to being engaged in physical or mental activity. Therefore, "active" is the correct answer.

Explanation

The word "quiescent" means being in a state of quietness or inactivity. The word "active" is the exact opposite of "quiescent" as it refers to being engaged in physical or mental activity. Therefore, "active" is the correct answer.

5. A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, the son's age five years back was:

14 years

19 years

33 years

38 years

When the father says "I was as old as you are at the present at the time of your birth," it means that the age difference between the father and the son is the same as the son's current age. Since the father is currently 38 years old, the son's age is 38 - 0 = 38 years. However, the question asks for the son's age five years back, so we subtract 5 from the son's current age to get 38 - 5 = 33 years. Therefore, the son's age five years back was 33 years.

Explanation

When the father says "I was as old as you are at the present at the time of your birth," it means that the age difference between the father and the son is the same as the son's current age. Since the father is currently 38 years old, the son's age is 38 - 0 = 38 years. However, the question asks for the son's age five years back, so we subtract 5 from the son's current age to get 38 - 5 = 33 years. Therefore, the son's age five years back was 33 years.

6. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:

39, 30

41, 32

42, 33

43, 34

The first student secured 42 marks and the second student secured 33 marks. The first student's marks is 9 marks more than the second student's marks. Additionally, the first student's marks is 56% of the sum of their marks. This means that if we add the second student's marks to 56% of the sum of their marks, we would get the first student's marks. Therefore, 33 + 56% of (33 + 42) equals 42, which confirms that the first student secured 42 marks and the second student secured 33 marks.

Explanation

The first student secured 42 marks and the second student secured 33 marks. The first student's marks is 9 marks more than the second student's marks. Additionally, the first student's marks is 56% of the sum of their marks. This means that if we add the second student's marks to 56% of the sum of their marks, we would get the first student's marks. Therefore, 33 + 56% of (33 + 42) equals 42, which confirms that the first student secured 42 marks and the second student secured 33 marks.

7. A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

3.6 sec

18 sec

36 sec

72 sec

The jogger is running at a speed of 9 kmph, which is slower than the train's speed of 45 kmph. The train is 120 meters long and it needs to cover this distance to pass the jogger. The relative speed between the train and the jogger is the difference between their speeds, which is 45 - 9 = 36 kmph. To convert this speed to meters per second, we divide it by 3.6, giving us 10 m/s. The time taken for the train to cover the distance of 120 meters at a speed of 10 m/s is 120/10 = 12 seconds. Therefore, the train will pass the jogger in 12 seconds.

Explanation

The jogger is running at a speed of 9 kmph, which is slower than the train's speed of 45 kmph. The train is 120 meters long and it needs to cover this distance to pass the jogger. The relative speed between the train and the jogger is the difference between their speeds, which is 45 - 9 = 36 kmph. To convert this speed to meters per second, we divide it by 3.6, giving us 10 m/s. The time taken for the train to cover the distance of 120 meters at a speed of 10 m/s is 120/10 = 12 seconds. Therefore, the train will pass the jogger in 12 seconds.

8. Which of the following database activities require a specific knowledge of a DBMS?

Enterprise modeling

Conceptual data modeling

Logical database design

Physical database design and definition

Physical database design and definition require a specific knowledge of a DBMS because it involves the implementation of the logical database design into the physical storage structures and configuration settings of the DBMS. This includes determining the appropriate data types, indexing strategies, partitioning schemes, and other performance optimization techniques specific to the DBMS being used. It also involves defining the physical storage locations and structures for the database files, such as tables, indexes, and views. Without knowledge of the specific DBMS, it would be difficult to effectively design and define the physical aspects of the database.

Explanation

Physical database design and definition require a specific knowledge of a DBMS because it involves the implementation of the logical database design into the physical storage structures and configuration settings of the DBMS. This includes determining the appropriate data types, indexing strategies, partitioning schemes, and other performance optimization techniques specific to the DBMS being used. It also involves defining the physical storage locations and structures for the database files, such as tables, indexes, and views. Without knowledge of the specific DBMS, it would be difficult to effectively design and define the physical aspects of the database.

9. Reena took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If she paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?

3.6

6

18

Cannot be determined

None of these

Reena took a loan of Rs. 1200 with simple interest for 6 years. This is because the interest paid at the end of the loan period is Rs. 432, which is equal to the rate of interest multiplied by the principal amount and the time period. Therefore, the rate of interest is 6.

Explanation

Reena took a loan of Rs. 1200 with simple interest for 6 years. This is because the interest paid at the end of the loan period is Rs. 432, which is equal to the rate of interest multiplied by the principal amount and the time period. Therefore, the rate of interest is 6.

10. A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

2.91 m

3 m

5.82 m

None of these

The area of the park is given by the product of its length and width, which is 60 m * 40 m = 2400 sq. m. Since the area of the lawn is 2109 sq. m, the area covered by the crossroads must be 2400 sq. m - 2109 sq. m = 291 sq. m. Since the crossroads are rectangular, the width of the road is equal to the width of the crossroads. Therefore, the width of the road is 291 sq. m / 60 m = 4.85 m, which is closest to 3 m.

Explanation

The area of the park is given by the product of its length and width, which is 60 m * 40 m = 2400 sq. m. Since the area of the lawn is 2109 sq. m, the area covered by the crossroads must be 2400 sq. m - 2109 sq. m = 291 sq. m. Since the crossroads are rectangular, the width of the road is equal to the width of the crossroads. Therefore, the width of the road is 291 sq. m / 60 m = 4.85 m, which is closest to 3 m.