General Quiz 3 First Secondary On Genetics And Classification

During the process of sexual reproduction, two sex cells (gametes) combine to form an offspring. Each sex cell contributes half of the genetic material, including chromosomes, to the offspring. This ensures that the offspring receives a balanced and complete set of chromosomes, with half coming from each parent. Therefore, each sex cell contributes half the normal number of chromosomes.

The figure likely shows the results of a genetic cross between two traits. In case A, the traits are independently assorted, meaning that they segregate independently during gamete formation. In case B, the traits show complete linkage, meaning that they are located close together on the same chromosome and tend to be inherited together.

Both genes and environmental factors can affect a person's height. Genes play a significant role in determining a person's potential height, as certain genes can influence the production of growth hormones and the development of bones. However, environmental factors such as nutrition, exercise, and overall health also play a crucial role in determining how much a person's genes are expressed, ultimately affecting their height. Therefore, it is a combination of both genetic and environmental factors that determine a person's height.

This organism is most likely a member of the kingdom Protists because it is primarily unicellular, has a true nucleus, and organelles. Protists are a diverse group of eukaryotic microorganisms that can be unicellular or multicellular, and they include various types of algae, protozoa, and slime molds.

The genotypes of the husband and wife are AB and AO. The possible genotypes of their children can be AA, AB, AO, and BO. Therefore, there are 4 possible genotypes. However, when it comes to phenotypes, the blood types of the children can be A, B, or O. Since the AB genotype results in the AB blood type, there are only 3 possible phenotypes.

In the given question, it is stated that gene A for a normal character dominates gene a for a certain disease. This means that the presence of gene A will mask the presence of gene a, resulting in a normal phenotype. Member I (2) is genotype Aa, which means that they have one copy of gene A and one copy of gene a. Member II (4) is also genotype Aa, indicating that they also have one copy of gene A and one copy of gene a. This is the only option where both individuals have the same genotype, so it is the correct answer.

A dihybrid refers to an individual that is heterozygous for two different traits. In this case, the genotype WwSs represents a dihybrid because it has two different alleles for each of the two traits being considered (Ww for one trait and Ss for the other).

Based on the given information, the organism does not have feathers or fur and breathes through lungs, which suggests that it is not a bird or a mammal. The key does not provide any specific information about the presence or absence of scales, so it could be a reptile. Additionally, the key does not mention anything about the ability to live on land or in water, so it could also be an amphibian. Therefore, the correct answer is that the organism could be either a reptile or an amphibian.

The probability of having a boy is 50% because the gender of a child is determined by the combination of chromosomes from both parents. Each parent contributes one chromosome, either X or Y, which determines the gender of the child. Since the man has an equal chance of passing on either an X or Y chromosome, and the woman has an equal chance of passing on either an X or Y chromosome, the probability of having a boy is 50%.

A soft-bodied, invertebrate animal could NOT belong to the phylum Arthropoda because Arthropods have a hard exoskeleton made of chitin, which provides support and protection to their body. Soft-bodied animals, on the other hand, lack this exoskeleton and have a more flexible body structure. Therefore, it is not possible for a soft-bodied animal to belong to the phylum Arthropoda.

In this scenario, the color-blindness trait is caused by a defective X gene, which is a recessive trait. Since the father is normal, he must have two normal X genes. The affected son inherited one defective X gene from the mother and one normal X gene from the father. The normal son inherited two normal X genes, one from each parent. Therefore, the only person who can have the defective X gene other than the affected son is the mother.

Organisms that are members of the same order must also be members of the same class. In biological classification, the order is a higher taxonomic rank than the genus, species, and family. It groups together organisms that share similar characteristics and are more closely related to each other. The class, on the other hand, is a higher taxonomic rank than the order, and it includes a broader range of organisms that share common characteristics. Therefore, if organisms belong to the same order, they must also belong to the same class.

A homozygous individual has two identical alleles for a particular gene. Therefore, they can only produce one type of gamete, as both alleles are the same.

Sex-influenced and sex-limited are two genetic cases where two different phenotypes can have the same genotype. In sex-influenced inheritance, the expression of a trait is influenced by the sex of the individual. For example, male pattern baldness is more common in males than females, even though the gene for baldness is present in both sexes. In sex-limited inheritance, the expression of a trait is limited to one sex. For example, milk production in mammals is limited to females. Therefore, both sex-influenced and sex-limited inheritance can result in different phenotypes with the same genotype.

The correct answer is "Family but different species" because although these animals belong to the same genus "Canis" (which is a group of closely related species), they belong to different families. The dog belongs to the family Canidae, the wolf belongs to the family Canidae, and the fox belongs to the family Canidae. Therefore, they are in the same family but different species.

Males tend to inherit more sex-linked conditions because there are no corresponding alleles on the Y-chromosomes. Sex-linked conditions are typically caused by mutations in genes located on the sex chromosomes, with the X chromosome being more commonly associated with these conditions. Since males have one X and one Y chromosome, any mutation on the X chromosome will not have a corresponding allele on the Y chromosome to compensate for it. Therefore, males are more likely to express sex-linked conditions if they inherit the mutated allele on their X chromosome.

The phenotype refers to the physical characteristics or traits that are expressed, while the genotype refers to the genetic makeup of an individual. In this case, the mother is bald, which suggests that she carries the recessive allele for baldness (b). The father is non-bald, indicating that he does not carry the recessive allele. Since baldness is a recessive trait, the daughter will need to inherit two copies of the recessive allele (bb) from both parents in order to express the phenotype. However, since the father does not carry the recessive allele, the daughter will inherit one dominant allele (B) from him, making her genotype Bb. This means that she will not be bald, as the dominant allele masks the expression of the recessive allele.

The correct answer is "Both are placental mammals." This is because while kangaroos are marsupials, which means they give birth to relatively undeveloped young and then carry them in a pouch, deer are placental mammals and give birth to fully developed young.

Protistans are considered to be the connecting link between Monerans (single-celled organisms) and the kingdoms of multicellular organisms (such as plants, animals, and fungi). This is because protistans exhibit characteristics of both single-celled and multicellular organisms. They can be unicellular or multicellular and have features similar to both plants and animals. Therefore, they serve as a transitional group between the simpler Monerans and the more complex kingdoms of multicellular organisms.

In this genetic trait, certain genes are switched on in one sex and switched off in the other sex. This means that the expression of the trait is limited to one sex. For example, only males can have prostate cancer and only females can have ovarian cancer, even though both sexes can carry the genes for these conditions. Therefore, this trait is a sex-limited trait.

The correct answer is "Male with hen feathering, female with hen feathering." This is because cock feathering is an autosomal recessive trait that is only displayed in males. Since both birds are heterozygous, they have one dominant allele and one recessive allele for the cock feathering trait. However, since the trait is recessive, it is not expressed in either bird's phenotype. Therefore, both birds will have the hen feathering pattern.

The presence of chloroplasts is not used to determine the phyla to which a plant belongs. Chloroplasts are present in most plants and are responsible for photosynthesis. However, the presence or absence of chloroplasts does not provide information about the classification of plants into different phyla. Other characteristics such as the absence of a vascular system, presence of seeds, and absence of flowers are commonly used to determine the phyla to which a plant belongs.

A heterozygous individual that has a selective advantage over the homozygous dominant individual indicates that the dominant allele is lethal in homozygous form. This means that individuals who carry two copies of the dominant allele will not survive, while individuals who carry one copy of the dominant allele and one copy of the recessive allele will have a selective advantage and survive. Therefore, this situation is an example of dominant lethal inheritance.

The correct answer is "Two cotyledons, a tap root and a branched leaf veins." This answer is correct because it accurately lists the characteristics of a dicot. Dicots are plants that have two cotyledons, which are the embryonic leaves in a seed. They also have a tap root system, which is a main root that grows vertically into the ground, and branched leaf veins, which can be seen in the pattern of veins on the leaves.

Lizards and adult salamanders have jaws and lungs in common. Both reptiles have jaws that allow them to eat and catch prey, and lungs that enable them to breathe air. While lizards have scaly skin, and salamanders have wet skin, these are not traits they share in common. Similarly, neither lizards nor salamanders have fur or feathers, so these traits are not applicable to them.

Fungi and plants are the kingdoms that include both unicellular and multicellular organisms. Fungi include both unicellular yeasts and multicellular molds and mushrooms. Plants include both unicellular algae and multicellular land plants. Therefore, the correct answer is Fungi and plants.

The non-disjunction likely occurred in the father. Non-disjunction is the failure of chromosomes to separate properly during gamete formation. Since the child is a turner hemophiliac, it suggests that the father's sperm had an extra X chromosome, resulting in the child's condition.

Knowing the gender of an unborn child can be important in the context of a family history of genetic disorders because male children are more likely to have X-linked traits show up in their phenotype. This is because males have only one X chromosome, making them more susceptible to inheriting and expressing X-linked disorders. On the other hand, females have two X chromosomes, providing a potential protective mechanism against these disorders. Therefore, knowing the gender of an unborn child can help in understanding the likelihood of certain genetic disorders based on their inheritance pattern.

Animal C shares a common phylum with the animals in the picture because all the animals in the picture belong to the same phylum.

The correct answer is "Both incubate their eggs." This is because both the duck-billed and the goose share the characteristic of incubating their eggs. Incubation is the process in which the parent bird sits on the eggs to provide warmth and ensure proper development. This behavior is common among many bird species, including ducks and geese.

When both parents are heterozygous, it means that they carry one copy of the recessive disease allele and one copy of the dominant allele. In this case, each parent has a 50% chance of passing on the recessive allele to their child. Therefore, the chance of both parents passing on the recessive allele to their second child is 0.5 x 0.5 = 0.25, or 25%.

Based on the figure provided, it is not possible to determine the proper classification of the dog. The figure only shows the digits of one of the front legs, which is not enough information to classify the dog accurately. Therefore, the correct answer cannot be determined from the given information.

When crossing a heterozygous parent with a homozygous dominant parent, the heterozygous parent will contribute one dominant allele and the homozygous dominant parent will contribute two dominant alleles. This means that there is a 50% chance of producing heterozygous offspring, as there is a 50% chance of the offspring inheriting the dominant allele from the heterozygous parent.

Protistans were the first eukaryotes to evolve. Eukaryotes are organisms that have complex cells with a nucleus enclosed by a membrane. Protistans are a diverse group of eukaryotic microorganisms that include various single-celled organisms such as amoebas, paramecia, and algae. They are considered the first eukaryotes because they evolved from prokaryotes, which are simpler organisms without a nucleus. Protistans played a crucial role in the evolution of more complex organisms and are believed to be the ancestors of plants, animals, and fungi.

When the Rh+ve woman marries an Rh-ve man, there is a 50% chance that the woman is heterozygous for the Rh gene (Rh+ve/Rh-ve) and a 50% chance that she is homozygous for the Rh gene (Rh+ve/Rh+ve). If she is heterozygous, there is a 50% chance that each child will inherit the Rh+ve gene from her. If she is homozygous, all of her children will inherit the Rh+ve gene. Therefore, there is a 50% chance that each child will be Rh+ve.

When a red-eyed male is crossed with a white-eyed female in Drosophila, all the male offspring would be white-eyed. This is because the gene for eye color is located on the X chromosome, and in Drosophila, females have two X chromosomes while males have one X and one Y chromosome. The red eye color is dominant and is carried on the X chromosome. Since males only inherit one X chromosome from their mother, if it carries the white eye color gene, they will express the white eye color. On the other hand, all the female offspring would be red-eyed because they inherit one X chromosome from each parent, so even if they inherit the white eye color gene from their mother, they will also inherit the red eye color gene from their father, resulting in red eye color.

The woman suffers from hair loss, which means she has the genotype for baldness. The fact that their daughter has no signs of hair loss suggests that she does not have the genotype for baldness. However, their son is bald, indicating that he inherited the genotype for baldness from his mother. Since the mother is known to have the genotype for baldness and the daughter does not, it is likely that the son has a pure or hybrid genotype for baldness. Therefore, the correct answer is "Pure or hybrid bald."

If a male inherits a sex-linked gene for color blindness, it will always be expressed. This is because males only have one X chromosome, and if they inherit a color blindness gene on that chromosome, they do not have another X chromosome to compensate for it. Unlike females, who have two X chromosomes and can have one normal gene to compensate for the color blindness gene, males do not have this option. Therefore, if a male inherits a sex-linked gene for color blindness, it will always be expressed.

When the father is Rh positive and the mother is Rh negative, there is a possibility of mother-fetus incompatibility problem because the fetus can inherit the Rh positive factor from the father. This can lead to the mother's immune system producing antibodies against the Rh positive factor, which can cause complications in future pregnancies. Therefore, there is at least a 50% chance of a mother-fetus incompatibility problem in this scenario.

In Mendel's F2 generation, one out of four plants had white flowers because both parents were heterozygous purple. This means that both parents carried the gene for purple flowers, but also carried a recessive gene for white flowers. When these two heterozygous parents are crossed, there is a 25% chance that their offspring will inherit two recessive genes for white flowers, resulting in white flowered plants.

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Homologous chromosomes may differ in allele composition. Alleles are alternative forms of a gene that occupy the same genetic locus on homologous chromosomes. Therefore, homologous chromosomes may have different alleles at the same genetic loci, resulting in variations in allele composition between the chromosomes. This variation in allele composition is one of the factors that contribute to genetic diversity and the differences observed among individuals.

The chances of this couple's having a child with blood type O are 25%. This is because both parents have a recessive allele for blood type O. The man has blood type A, which means he has one allele for blood type A and one allele for blood type O. The woman has blood type B, which means she has one allele for blood type B and one allele for blood type O. When they have a child, there is a 25% chance that both parents will pass on their O alleles, resulting in a child with blood type O.

Based on the information given, the yellow gene (A) dominates the green gene (a). This means that if an individual has at least one copy of the yellow gene (A), it will express the yellow phenotype. Therefore, the genotype of member number (1) can be either AA or Aa, as both genotypes have at least one copy of the dominant yellow gene (A).

The diagram shows the levels of classification for living organisms, with Order, Phylum, Class, and Family listed in order. The level (E) refers to the position in the classification hierarchy. Based on the diagram, the level (E) is Class.

Bryophytes are non-vascular plants, meaning they do not have specialized tissues for transporting water and nutrients throughout the plant. Vascular bundles, on the other hand, are present in gymnosperms, pteridophytes, and angiosperms. These bundles consist of xylem and phloem tissues that help in the transportation of water, minerals, and sugars. Therefore, the absence of vascular bundles in bryophytes is the correct answer.

The condition dystonia is caused by a recessive allele (t). The fact that none of their three children have the condition indicates that they are not homozygous recessive (tt). Therefore, the father must be heterozygous (Tt). The mother can either be homozygous dominant (TT) or heterozygous (Tt) since both genotypes would result in none of their children inheriting the condition. Therefore, the possible genotypes for the man and woman are the father being tt and the mother being either Tt or TT.

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