Exam 1 Target 1 PreAP Numbers 1-5

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1/5 Questions

Which of the following situations represents a positive displacement of a carton? Assume positive position is measured vertically upward along a y-axis.
- A. A delivery person waiting for an elevator lowers a carton onto a dolly.
- B. When the elevator doors open, the delivery person lifts the dolly over the threshold of the elevator.
- C. The delivery person pushes the dolly to the back of the elevator while pressing a floor button.
- D. The door closes and the elevator moves from the 10th to the 4th floors.

About This Quiz

This quiz assesses understanding of displacement concepts in physics, focusing on positive and negative displacements, and motion analysis.

Exam 1 Target 1 Preap Numbers 1-5 - Quiz

2.

What is the maximum negative displacement a dog could have if it started its motion at +3 m?
- A. +7 m
- B. +3 m
- C. -3 m
- D. -7 m
Correct Answer

A. C. -3 m

Explanation

The maximum negative displacement a dog could have if it started its motion at +3 m is -3 m. This means that the dog can move up to 3 meters in the negative direction from its starting point.

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3.

What is the correct description of any change of position farther to the right of zero?
- A. positive displacement
- B. positive distance
- C. positive position
- D. positive change of displacement
Correct Answer

A. A. positive displacement

Explanation

The correct description of any change of position farther to the right of zero is positive displacement. Displacement refers to the change in position of an object, and when the change is farther to the right of zero, it indicates a positive displacement.

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4.

A dog walks from +4 m to +2 m. Which of the following statements is true about the dog’s motion?
- A. xi = +2 m
- B. xf = +2 m
- C. delta x = +2 m
- D. vavg = 2 m/s
Correct Answer

A. B. xf = +2 m

Explanation

The correct answer is b. xf = +2 m. This statement is true because xf represents the final position of the dog, and in this case, the dog's final position is +2 m.

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5.

Rank in decreasing order the displacements of objects having the following pairs of average velocity and time of motion.I. v_avg = +2.0 m/s, Dt = 2.0 sII. v_avg = +3.0 m/s, Dt = 2.0 sIII. v_avg = -3.0 m/s, Dt = 3.0 s
- A. I, II, III
- B. II, III, I
- C. II, I, III
- D. III, II, I
Correct Answer

A. A. I, II, III

Explanation

The correct answer is a. I, II, III. This is because the displacement of an object is directly proportional to the product of its average velocity and the time of motion. Therefore, the object with the highest average velocity and shortest time of motion (I) will have the highest displacement, followed by the object with the second highest average velocity and second shortest time of motion (II), and finally the object with the lowest average velocity and longest time of motion (III).

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Feb 14, 2024

Quiz Edited by
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Aug 21, 2015

Quiz Created by
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Exam 1 Target 1 Preap Numbers 1-5

Which of the following situations represents a positive displacement of a carton? Assume positive position is measured vertically upward along a y-axis.

Quiz Preview

What is the maximum negative displacement a dog could have if it started its motion at +3 m?

What is the correct description of any change of position farther to the right of zero?

A dog walks from +4 m to +2 m. Which of the following statements is true about the dog’s motion?

Rank in decreasing order the displacements of objects having the following pairs of average velocity and time of motion.I. vavg = +2.0 m/s, Dt = 2.0 sII. vavg = +3.0 m/s, Dt = 2.0 sIII. vavg = -3.0 m/s, Dt = 3.0 s

Rank in decreasing order the displacements of objects having the following pairs of average velocity and time of motion.I. v_avg = +2.0 m/s, Dt = 2.0 sII. v_avg = +3.0 m/s, Dt = 2.0 sIII. v_avg = -3.0 m/s, Dt = 3.0 s