MCQ Quiz: Data Communication! Test

Reviewed by Editorial Team
The ProProfs editorial team is comprised of experienced subject matter experts. They've collectively created over 10,000 quizzes and lessons, serving over 100 million users. Our team includes in-house content moderators and subject matter experts, as well as a global network of rigorously trained contributors. All adhere to our comprehensive editorial guidelines, ensuring the delivery of high-quality content.
Learn about Our Editorial Process
| By Ankit Mundra
A
Ankit Mundra
Community Contributor
Quizzes Created: 1 | Total Attempts: 670
| Attempts: 673
Quiz Flashcard
SettingsSettings
Please wait...
  • 1/26 Questions

     If the value of checksum is 0, then the message is:  

    • Accepted
    • Rejected
    • Sendback
    • None of these
Please wait...
About This Quiz


Think you are an expert in digital communication? Can you pass this quiz? Data communication is the transmission of digital data between two or more computers and a computer network. It is a network that allows computers to exchange information. The physical connection between networked computing devices is established using either cable media or wireless media. Computer systems are connected to form a network. This quiz will explain all the variables of data communication.

MCQ Quiz: Data Communication! Test - Quiz

Quiz Preview

  • 2. 

    In ________, the amplitude of the carrier signal is varied to create signal elements. Both frequency and phase remain constant.

    • PSK

    • ASK

    • FSK

    • QAM

    Correct Answer
    A. ASK
    Explanation
    Amplitude Shift Keying (ASK) is a modulation technique where the amplitude of the carrier signal is varied to create signal elements. In ASK, both the frequency and phase of the carrier signal remain constant. This means that the carrier signal is not modified in terms of frequency or phase, but only the amplitude is changed to represent the information being transmitted.

    Rate this question:

  • 3. 

    In ________, the phase of the carrier is varied to represent two or more different signal elements. Both peak amplitude and frequency remain constant.

    • PSK

    • ASK

    • FSK

    • QAM

    Correct Answer
    A. PSK
    Explanation
    PSK stands for Phase Shift Keying. In this modulation technique, the phase of the carrier signal is varied to represent different signal elements. The peak amplitude and frequency of the carrier signal remain constant. PSK is commonly used in digital communication systems to transmit binary data. By shifting the phase of the carrier signal, different binary values can be encoded and transmitted.

    Rate this question:

  • 4. 

    If the generator polynomial is X^4 + X^3 + 1 then the corresponding binary pattern will be:

    • 11001

    • 11010

    • 10011

    • 110

    Correct Answer
    A. 11001
    Explanation
    The given generator polynomial is X^4 + X^3 + 1. To find the corresponding binary pattern, we can convert the polynomial into binary form by representing each term as a binary number. In this case, X^4 is represented as 10000, X^3 is represented as 01000, and 1 remains the same. Adding these binary numbers together, we get 11001 as the corresponding binary pattern.

    Rate this question:

  • 5. 

    The _______ of a polynomial is the highest power in the polynomial.  

    • Range

    • Power

    • Degree

    • None

    Correct Answer
    A. Degree
    Explanation
    The degree of a polynomial refers to the highest power of the variable in the polynomial. It indicates the complexity or the highest order of the polynomial. For example, if the polynomial is x^3 + 2x^2 - 5x + 1, the degree is 3 because the highest power of x is 3. The degree helps in determining the behavior and characteristics of the polynomial, such as the number of roots or the end behavior. Therefore, the correct answer is "Degree."

    Rate this question:

  • 6. 

    Sampling is process to convert _________ to ____________

    • Analog signal to digital signal

    • Continous time signal to discrete time signal

    • Signal to message

    • None of the above

    Correct Answer
    A. Analog signal to digital signal
    Explanation
    Sampling is the process of converting an analog signal, which is continuous in time, into a digital signal, which is discrete in time. This is done by taking periodic samples of the analog signal at specific intervals, and representing each sample as a digital value. By doing so, the continuous waveform of the analog signal is approximated by a series of discrete values, allowing it to be processed and manipulated digitally.

    Rate this question:

  • 7. 

    Asynchronous transmission is ________ efficient as compared to synchronous transmission.

    • More

    • Equally

    • Less

    • None

    Correct Answer
    A. Less
    Explanation
    Asynchronous transmission is less efficient as compared to synchronous transmission. This is because in asynchronous transmission, each character is sent individually with start and stop bits, resulting in more overhead and slower transmission speed. In synchronous transmission, data is sent in blocks or frames, reducing the overhead and increasing the overall efficiency of the transmission.

    Rate this question:

  • 8. 

    If even parity is being used then the value of parity bit should be ______ for data sequence 101010.

    • 1

    • 0

    • 2

    • 3

    Correct Answer
    A. 1
    Explanation
    In even parity, the parity bit is set to ensure that the total number of 1s in the data sequence, including the parity bit, is an even number. In the given data sequence 101010, there are three 1s. To make the total number of 1s even, the parity bit should be set to 1.

    Rate this question:

  • 9. 

    The ratio of data rate R, to transmission bandwidth is referred to as the:

    • Baud Rate

    • Bandwidth efficiency

    • Signal efficiency

    • Bit Rate Efficiency

    Correct Answer
    A. Bandwidth efficiency
    Explanation
    Bandwidth efficiency refers to the ratio of data rate to transmission bandwidth. It measures how efficiently the available bandwidth is being utilized to transmit data. A higher bandwidth efficiency indicates that more data can be transmitted within a given bandwidth, resulting in better utilization of the available resources. Therefore, the correct answer is bandwidth efficiency.

    Rate this question:

  • 10. 

    In asynchronous transmission, assume that data rate 10 kbps & the receiver clock is fast by 6%, then the receiver samples the incoming character at every:

    • 100 micro seconds

    • 47 micro seconds

    • 94 micro seconds

    • 50 micro seconds

    Correct Answer
    A. 94 micro seconds
    Explanation
    In asynchronous transmission, the receiver samples the incoming character at every 94 microseconds. This is because the data rate is 10 kbps (kilobits per second) and the receiver clock is fast by 6%. To determine the sampling time, we divide the reciprocal of the data rate by the receiver clock's speed. The reciprocal of 10 kbps is 100 microseconds. Since the receiver clock is fast by 6%, we multiply 100 microseconds by 0.94, which gives us 94 microseconds. Therefore, the receiver samples the incoming character every 94 microseconds.

    Rate this question:

  • 11. 

    _______ conversion is the process of changing one of the characteristics of an analog signal based on the information in the digital data.

    • Analog-to-analog

    • Digital-to-digital

    • Digital-to-Analog

    • None of these

    Correct Answer
    A. Digital-to-Analog
    Explanation
    Digital-to-Analog conversion is the process of changing the characteristics of a digital signal into an analog signal based on the information in the digital data. This conversion is necessary when transmitting digital data over analog channels, such as in telephone lines or radio waves. By converting the digital signal into an analog waveform, it can be easily transmitted and understood by analog devices or systems.

    Rate this question:

  • 12. 

    The ________ between two words is the number of differences between corresponding bits.

    • HAMMING RULE

    • HAMMING DISTANCE HAMMING DISTANCE

    • HAMMING CODE

    • NONE OF THE ABOVE

    Correct Answer
    A. HAMMING DISTANCE HAMMING DISTANCE
    Explanation
    The term "Hamming distance" refers to the number of differences between corresponding bits in two words. It is a measure of similarity or dissimilarity between two binary strings. The other options, such as "Hamming rule" and "Hamming code," do not accurately describe the concept of the number of differences between corresponding bits.

    Rate this question:

  • 13. 

    Find parity bit for 1001011.

    • 1

    • 2

    • 3

    • 0

    Correct Answer
    A. 0
    Explanation
    The parity bit for 1001011 is 0 because the number of 1s in the binary sequence is odd. The purpose of a parity bit is to check for errors in data transmission. In this case, since there are an odd number of 1s, the parity bit is set to 0 to ensure that the total number of 1s is even. This allows for error detection in case any bit gets flipped during transmission.

    Rate this question:

  • 14. 

    ASK, PSK, FSK, and QAM are examples of ________ conversion.

    • Analog-to-analog

    • Digital-to-digital

    • Analog-to-digital

    • Digital-to-analog

    Correct Answer
    A. Digital-to-analog
    Explanation
    ASK, PSK, FSK, and QAM are all modulation techniques used in digital-to-analog conversion. These techniques are used to convert digital signals into analog signals, allowing for transmission over analog mediums such as telephone lines or radio waves. In these techniques, the digital data is encoded onto an analog carrier signal, which can then be transmitted. Therefore, the correct answer is digital-to-analog.

    Rate this question:

  • 15. 

    In cyclic redundancy checking, the divisor is _______ the CRC. 

    • The same size as

    • One bit less than one bit less than one bit less than one bit less than one bit less than

    • One bit more than

    • None

    Correct Answer
    A. One bit more than
    Explanation
    In cyclic redundancy checking, the divisor is one bit more than the CRC. This means that the divisor has a larger size than the CRC by one bit. This additional bit is used to ensure that the CRC calculation is accurate and can detect errors in the data being checked.

    Rate this question:

  • 16. 

    If the generator of cyclic code has at least two terms and rightmost bit is 1 then error cannot be divided by:

    • Syndrome

    • Error

    • Dataword

    • Generator

    Correct Answer
    A. Generator
    Explanation
    If the generator of a cyclic code has at least two terms and the rightmost bit is 1, it means that the generator polynomial is not divisible by the error. The generator polynomial is used to generate the code, and if it cannot be divided by the error, it ensures that the error will not affect the code generation process. Therefore, the error cannot be divided by the generator.

    Rate this question:

  • 17. 

    Which error detection method consists of just one redundant bit per data unit?

    • CRC

    • CheckSum

    • Simple Parity

    • Hamming Distance

    Correct Answer
    A. Simple Parity
    Explanation
    Simple Parity is an error detection method that consists of just one redundant bit per data unit. In this method, a parity bit is added to the data unit, making the total number of bits even or odd depending on the desired parity. The receiver can then check the parity of the received data unit to detect if any errors occurred during transmission. If the parity of the received data unit does not match the expected parity, an error is detected. This method is simple and efficient for detecting single-bit errors.

    Rate this question:

  • 18. 

    In cyclic redundancy checking, what is the CRC?

    • The divisor The Divisor

    • The Dividend

    • The Reminder

    • The Quotient

    Correct Answer
    A. The Reminder
    Explanation
    The CRC (Cyclic Redundancy Check) is a mathematical algorithm used to detect errors in data transmission. It involves dividing the data by a predetermined divisor and calculating the remainder. This remainder is known as the CRC or the "reminder". By comparing the calculated CRC with the received CRC, it is possible to determine if any errors occurred during transmission. Therefore, the correct answer is "The Reminder".

    Rate this question:

  • 19. 

    The signal-to-noise ratio (in dB) for n-bit PCM can be expressed as:

    • 6.02n + 1.76

    • 20log 2 + 1.76

    • 1.76n + 6.02

    • 20nlog 2 + 1.76

    Correct Answer
    A. 6.02n + 1.76
    Explanation
    The correct answer is 6.02n + 1.76. This equation represents the signal-to-noise ratio (SNR) for n-bit PCM (Pulse Code Modulation). The SNR is a measure of the quality of a signal, indicating the ratio of the power of the signal to the power of the noise. In this equation, 6.02n represents the signal power, which increases linearly with the number of bits. The term 1.76 represents the noise power, which is a constant value. Therefore, adding these two terms gives us the total SNR for n-bit PCM.

    Rate this question:

  • 20. 

    Which can detect two-bit errors?

    • Parity check

    • Parity & Cyclic redundancy check

    • Cyclic redundancy check

    • None of the mentioned

    Correct Answer
    A. Cyclic redundancy check
    Explanation
    Cyclic redundancy check (CRC) is a technique used to detect errors in data transmission. It can detect two-bit errors because it uses polynomial division to generate a checksum, which is appended to the data. When the data is received, the receiver performs the same polynomial division and compares the calculated checksum with the received checksum. If they do not match, it indicates that there are errors in the data, including two-bit errors. Therefore, CRC is capable of detecting two-bit errors.

    Rate this question:

  • 21. 

    In block coding, we divide our message into blocks, is called

    • CODEWORDS

    • ERROR CODES

    • PACKET BLOCKS

    • DATAWORDS

    Correct Answer
    A. DATAWORDS
    Explanation
    Block coding is a technique where a message is divided into blocks, and each block is encoded separately. The encoded blocks are called codewords. However, in this question, the correct answer is "DATAWORDS" instead of "CODEWORDS". Datawords are the original data blocks before they are encoded using block coding techniques. Therefore, the explanation for the correct answer is that in block coding, we divide our message into blocks called datawords.

    Rate this question:

  • 22. 

    If R is the bit rate and r is related to the technique by which the signal is filtered to establish a bandwidth for transmission, then transmission bandwidth for ASK is equal to:

    • (1+ r)R

    • (1+ r)/R

    • (1+ R)r

    • (1+ R)/r

    Correct Answer
    A. (1+ r)R
    Explanation
    The transmission bandwidth for ASK (Amplitude Shift Keying) is equal to (1+ r)R. This means that the bandwidth is determined by multiplying the bit rate (R) by the factor (1+ r), where r is related to the technique used to filter the signal. This suggests that the bandwidth increases as r increases, indicating a wider range of frequencies needed for transmission.

    Rate this question:

  • 23. 

    If the ASCII character G is sent and the character D is received, what type of error is this?

    • Single-bit

    • Multiple-bit

    • None

    • All of the above

    Correct Answer
    A. Single-bit
    Explanation
    This is a single-bit error because only one bit has been changed in the transmission from G to D.

    Rate this question:

  • 24. 

    Consider data word 1110 is to transmitted using CRC code and if the pattern P= 1101 then how many redundant bits will be added to data word to make code word?

    • Three

    • Four

    • Two

    • One

    Correct Answer
    A. Three
    Explanation
    To transmit the data word 1110 using CRC code with the pattern P=1101, three redundant bits will be added to the data word to make the code word. The CRC code works by adding a checksum to the data word, which is obtained by performing polynomial division. In this case, the pattern P is divided into the data word, and the remainder is added as redundant bits to the data word. These redundant bits allow the receiver to detect and correct errors in the transmitted data.

    Rate this question:

  • 25. 

    In bit pattern, shifting to right means:

    • Adding extra 0s as rightmost bits

    • Deleting some rightmost bits

    • Adding extra 1s as rightmost bits

    • Deleting some leftmost bits

    Correct Answer
    A. Deleting some rightmost bits
    Explanation
    Shifting to the right in a bit pattern means deleting some rightmost bits. This is because when we shift a bit pattern to the right, we are essentially moving all the bits towards the right side. As a result, the rightmost bits are no longer needed and are therefore deleted. This operation is commonly used in computer programming to divide a number by 2 or to perform logical operations on binary numbers.

    Rate this question:

  • 26. 

    CRC code is ____________ technique.

    • Error detection

    • Error correction

    • Flow control

    • Encryption

    Correct Answer
    A. Error correction
    Explanation
    CRC (Cyclic Redundancy Check) code is a technique used for error detection. It is a mathematical algorithm that generates a checksum, which is appended to the data being transmitted. Upon receiving the data, the receiver performs the same calculation and compares the checksum generated with the received checksum. If they do not match, it indicates that an error has occurred during transmission. Therefore, CRC code is primarily used for error detection rather than error correction.

    Rate this question:

Quiz Review Timeline (Updated): Mar 20, 2023 +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Mar 20, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Oct 15, 2018
    Quiz Created by
    Ankit Mundra
Back to Top Back to top
Advertisement
×

Wait!
Here's an interesting quiz for you.

We have other quizzes matching your interest.